A mountain climber at the peak ha ___________ energy.
A.gravitational potential
B. Elastic potential
C.Kinetic
The distance from Atlanta to Macon is about 80 miles out of 58.5° south of east. What distance is dues east and dues south mustyou drive in order to travel from Atlanta to Macon?
Answer:
One must drive [tex]$41 \cdot 8\,miles$[/tex] north and [tex]$68 \cdot 24\,miles$[/tex] south, in order to travel from Atlanta to Macon.
Explanation:
• The distance of an object can be defined as the complete path travelled by an object.
• To find the distance, find its north component.
• For reference see the below graph:
[tex]$$\[\begin{align}& D_{south} = 80\sin \left( {58 \cdot {5^ \circ }} \right) \\& D_{north} = 80\cos \left( {58 \cdot {5^ \circ }} \right) \\\end{align}\]$$Since, $\sin \left( {58 \cdot {5^ \circ }} \right) = \cdot 853$ and $\cos \left( {58 \cdot {5^ \circ }} \right) = \cdot 5224$: therefore,$$\[\begin{align} D_{south} &= 80 \times \left( { \cdot {{853}^ \circ }} \right) \\ \Rightarrow {D_{south}} &= 68 \cdot 24\,miles \\ \end{align}\]$$[/tex]
And
[tex]$$\[\begin{align} D_{north}& = 80 \times \cdot 5224 \\ \Rightarrow D_{north}& = 41 \cdot 8\,miles \\ \end{align}\]$$[/tex]
• Hence, one must drive [tex]$41 \cdot 8\,miles$[/tex] north and [tex]$68 \cdot 24\,miles$[/tex] south, in order to travel from Atlanta to Macon.
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A car traveling at 90 m/s can stop in a distance of 110 m. What is the magnitude of the cars acceleration as it slows down?
I think I have already answer this question. Anyways please do let me know whether it is useful or not
Being willing to sincerely apologize for mistakes errors and blunders goes a long way toward
Answer:
All of the above ! Hope this helps! ♥
Explanation:
Being willing to sincerely apologize for mistakes, errors, and blunders goes a long way toward nurturing relationships with customers and retaining customers. Option (c) is correct.
What do you mean by Apology?Apology means to express regret for having done something that has caused another person problems or misery
Sincere apology aids in mending ties with those you've harmed. That may include coworkers, customers, friends, or family.
You can start a conversation with the other person by owning up to your error. You can then consider your actions and accept responsibility for them. Also, they can deal with their emotions, regain their composure, and refrain from taking responsibility for what transpired.
You may improve your behavior going forward, keep your dignity, and regain people's respect by apologizing.
Therefore, Option (c) is correct.
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Your question is incomplete, most probably the complete question will be;
Being willing to sincerely apologize for mistakes, errors, and blunders goes a long way toward:
Helping to learn from mistakes
Helping nurture the relationship with customers
Retaining customers
All of the above
A car is accelerating at 6 m/s2. How long would it take the car to go 12 m/s faster?
Answer:
2 seconds
Explanation:
Each second, it increases its speed by 6 m/s, so it will take 2 seconds for the speed to increase by 12 m/s.
10. What is a rule for determining the mass?
Answer:
Mass number is the sum of the protons and neutrons in the atomic nucleus.
The mass number (A) is the sum of the atomic number (Z), which is the number of protons, and the number of neutrons (N) in the atomic nucleus of an isotope of an element. A=Z+N
The primary coil of a transformer has 2650 volts and a current of 66 A. What current is in the secondary coil if it has 4700
volts?*
12 =
A
*Round your answer to the nearest thousandth if necessary.
Answer:
117.06 A
Explanation:
V = IR
2650 = 66(R)
2650/66 = R
40.15 = R
V = IR
4700 = I(40.15)
4700/40.15 = I
117.06 = I
If it takes Tanya 9.4 hours to get to her cousin's house while driving an average of 40 mph, how far away does her
cousin live?
Answer:
376 miles
Explanation:
speed = distance / time
therefore distance = speed * time
distance = 40 miles/hr * 9.4 hr
then
distance = 375 miles
Any two importance of measurement
Answer:
to sell and to buy
Explanation:
measurement is a comparison between unknown quantity with a known quantity
If you are given force and time, you can determine power if you can know
(a) watts
(b) energy
(c) distance
Answer:
joules/energy.
Explanation:
power is defined as the rate of work. Hence power=work/time, then you obtain Watts.
Work is the product of force and displacement.
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Answer:
[tex]thank \: you[/tex]
Identify the parts of the body based on the medical terminology given:
1. mr. heart describes pain that is midline, superior to the chest but inferior to the chin.
2. miss triangle says that she has a ‘tweak’ that is superior to the waist, inferior to the breast bone, lateral to the umbilicus on the left side of the body on the anterior surface.
3. mr. square states that he has pulled a muscle, inferior to the buttocks, superior to the knee, medial to the right side of the body on the posterior surface.
4. miss circle complains of a sharp pain inferior to her ears, superior to the scapula at midline on the posterior side of her body.
5. mr. x says that he has numbness and tingling on the anterior side of his left arm, distal to the wrist.
6. mrs. diamond describes a throbbing pain on the posterior side of her body, inferior to her shoulder blades and superior to her waist.
7. miss arrow states that she has had a pain on the left side of her body, superior to her neck and inferior to her forehead, lateral to her nose.
8. mr. teardrop says that he has been bitten by a spider lateral to his umbilicus on the anterior aspect of his body, superior to his hip on the right side of his body.
9. miss eight describes a burning sensation on the posterior side of her body, lateral to the spine on the left side of the body inferior to the shoulder blade, inferior to the waist but anterior to the knee.
10. mr. four shows you a deep wound on the anterior side of his body, medial to the left hip, lateral to the umbilicus, inferior to the collarbone and anterior to the waist.
Answer:
1. Right hypochondriac region (upper, right).
2. Epigastric region (upper, middle).
3. Left hypochondriac region (upper, left).
4. Right lumbar region (middle, right).
5. Umbilical region (centre).
6. Left lumbar region (middle, left).
7. Right iliac region (lower, right).
8. Hypogastric region (lower, middle).
9. Left iliac region (lower, left).
Explanation:
1. Right hypochondriac region (upper, right)- Liver, gallbladder, right kidney, small intestine.
2. Epigastric region (upper, middle)- stomach, liver, pancreas, duodenum, spleen, adrenal glands
3. Left hypochondriac region (upper, left)- Spleen, colon, left kidney, pancreas
4. Right lumbar region (middle, right)- Gallbladder, liver, right colon
5. Umbilical region (centre)- Umbilicus, parts of the small intestine, duodenum
6. Left lumbar region (middle, left)- Descending colon and left kidney
7. Right iliac region (lower, right)- Appendix and cecum
8. Hypogastric region (lower, middle)- Bladder, reproductive organs, sigmoid colon
9. Left iliac region (lower, left)- Descending and sigmoid colon.
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A shot putter puts the shot at a velocity of 14 m/s (assume this represents a constant horizontal
velocity). The shot is in the air for 1.4 seconds. How far did the shot travel?
S = (v-u)t/2
s = (14)1.4/2
s = 9.8m
The range of the shot will be "19.6 m". A complete solution is provided below.
The given values in the question are:
Horizontal velocity,
v = 14 m/s
Time,
t = 1.4 sec
Now,
The Range will be:
= [tex]Velocity\times Time[/tex]
By putting the given values, we get
= [tex]14\times 1.4[/tex]
= [tex]19.6 \ m[/tex]
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I NEED THE ANSWER TO PASS SO I CAN GET MY PHONE BACK HELPPPPPPPPPPPPPP
Answer:
it would be c.
Explanation:
starts at zero and isn't a straight shot up
Bắt đầu từ giá trị nào của động năng của các electron thì sai số về bước sóng de Broglie trong quá trình tính toán theo cổ điển sẽ vào cỡ 10%
Answer:
no idea what this means
Explanation:
yeah
2. Determine the units of the quantity described by each of the following
combinations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)
We have that the unit of the quantities are described
a.kg (m/s) (1/s)=Newton
b. (kg/s) (m/s^2)=Newton
c. (kg/s) (m/s)^2=Newton
d. (kg/s) (m/s)=Newton
From the question we are give the units
a.kg (m/s) (1/s)
b. (kg/s) (m/s^2)
c. (kg/s) (m/s)^2
d. (kg/s) (m/s)
a)
Generally
kg (m/s) (1/s) is Represented as Newton
Where Newton is the unit Force and Weight
b)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
c)
kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
d)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
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N2 + 3H2 + 2NH3
What type of reaction is this
Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia
Explanation:
This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.
A car accelerates from rest to 100 m/s in 20 s. What is its acceleration?
[tex]\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}[/tex]
[tex]\\ \sf\longmapsto Acceleration=\dfrac{100-0}{20}[/tex]
[tex]\\ \sf\longmapsto Acceleration=\dfrac{100}{20}[/tex]
[tex]\\ \sf\longmapsto Acceleration=5m/s^2[/tex]
Answer:
[tex]initial \: velocity \: = 0 \\ final \: velocity \: 100 \frac{m}{s} \\ time = 20 \\ here \: we \: want \: to \: find \: accelaration \\ accelaration \: = \frac{final \: velocity - initial \: velocity}{time} \\ accelaration \: = \frac{100 - 0}{20} = \frac{100}{20} = 5 \frac{m}{ {s}^{2} } \\ thank \: you[/tex]
Convert the following in to SI units without changing its values
A. 4000 g
b. 2.4 km
A. The S.I unit of mass is kg . therefore we have to convert 4000g into kg from gram
i.e 4000g = 4 kg
B. The S.I unit of length is meter. so we have to convert 2.4 km into meters,
i.e 2.4 km = 2400 m
#A
[tex]\boxed{\sf 1kg=1000g}[/tex]
[tex]\\ \sf\longmapsto 4000[/tex]
[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]
[tex]\\ \sf\longmapsto 4kg[/tex]
#B
[tex]\boxed{\sf 1km=1000m}[/tex]
[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]
[tex]\\ \sf\longmapsto 2400m[/tex]
How do we know how much
gravitational force objects have?
Answer:
With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.
Explanation:
i hope this helps
An object is launched at a 60 degree angle with an initial velocity of 100
m/s. What is the objects height? How long is the object in the air? What is
the objects's range (distance)? *
PLS HELP QUICK LOL
Answer:
Explanation:
The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:
[tex]v^2=v_0^2+2a[/tex]Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:
[tex]v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}[/tex]
And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:
[tex]0=(90)^2+2(-9.8)[/tex]Δx
[tex]0=8000-20[/tex]Δx and
-8000 = -20Δx so
Δx = 400 m
Now for the time it was in the air...we will use the simple equation
[tex]v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9[/tex]
So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:
Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.
[tex]v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}[/tex]
And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:
Δx = [tex]50(9)+\frac{1}{2}(0)(9)^2[/tex]
Δx = 500 m
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Question:-
Convert 4cm to m
Solution:-
Lets do
First note down the below formula
[tex]\boxed{\sf 1m=10^{2}cm}[/tex]
Then
[tex]\boxed{\sf 1cm=10^{-2}cm}[/tex]
Now we are given 4cm
So convert
[tex]\\ \sf\longmapsto 4\times 10^{-2}m[/tex]
If we simplify to decimal
[tex]\\ \sf\longmapsto 4cm=0.04m[/tex]
Hence done .
The microwave portion of the spectrum has wavelengths ranging from 1 mm to 1 m. Find the corresponding frequencies. g
Answer:
f = c / y where y is the wavelength
f1 = 3 *10E8 m/s / .001 m = 3 * 10E11 / s
f2 = 3 * 10E8 m/s / 1 m = 3 * 10E8 / s
What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a
velocity of 3 m/s?
What’s the answer
Answer:
kinetic energy = 1/2mv²
k.E =1/2 X 0.5 X 3²
k.e = 9/4
K.E = 2.25j
A vehicle starts from rest and travels 50 m in 5 s. What is its acceleration?
Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?
Average Velocity=Total Distance/Total Time
[tex]\\ \sf\longmapsto \dfrac{2.5}{9.1}[/tex]
[tex]\\ \sf\longmapsto 0.3m/s[/tex]
show that Newton's first law is the special case of Newton's second law of motion
Please find attached photograph for your answer. Please do comment whether it is useful or not.
find the final velocity of the initial velocity of 8m/s with an acceleration of 7 m/s2 over 3 second interval
Please find attached photograph for your answer. Hope it helps! Please do comment.
explain 3points to be taken into consideration while measuring the length of a body
Answer:
Y T and v
Explanation:
The graph below shows the position of an ant as it crawls over a flat picnic blanket. The total time for the ant to go from the start to the end position takes 1 minute and 45 seconds.
What is the average speed and average velocity of the ant?
A.) Average speed is 0.200 cm/s and average velocity is 0.0988 cm/s to the upper right.
B.) Average speed is 0.152 cm/s and average velocity is 0.910 cm/s to the upper right.
C.) Average speed is 0.975 cm/s and average velocity is 1.95 cm/s to the upper right.
D.) Average speed is 0.276 cm/s and average velocity is 0.136 cm/s to the upper right.
The average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.
The correct answer is option D.
In the given graph, we can deduce the following;
the total time of the motion, = 1 mins + 45 s = 60 s + 45 s = 105 sThe average speed of the ant is calculated as;
[tex]average \ speed = \frac{total \ distance }{total \ time }[/tex]
The total distance from the graph is calculated as follows;
first horizontal distance from 2 cm to 8 cm = 8 - 2 = 6 cmfirst upward distance from 3 cm to 5 cm = 5 - 3 = 2 cmsecond horizontal distance from 8 cm to 6 cm = 8 - 6 = 2 cmsecond upward distance from 5 cm to 12 cm = 12 - 5 = 7 cmthird horizontal distance from 6 cm to 13 cm = 13 - 6 = 7 cmfourth downward distance from 12 cm to 9 cm = 3 cmfinal horizontal distance from 13 cm to 15 cm = 2cmThe total distance = (6 + 2 + 2 + 7 + 7 + 3 + 2) cm = 29 cm
[tex]average \ speed = \frac{total \ distance }{total \ time } = \frac{29 \ cm}{105 \ s} = 0.276 \ cm/s[/tex]
The average velocity is calculated as the change in displacement per change in time.
The displacement is the shortest distance between the start and end positions.
This shortest distance is the straight line connecting the start and end position. Call this line PFrom the end position at x = 15 cm, draw a vertical line from y = 9 cm, to y = 3 cm. The displacement = 9 cm - 3 cm = 6 cmAlso, draw a horizontal line from start at x = 2 cm to x = 15 cm. The displacement = 15 cm - 2 cm = 13 cmNotice, you have a right triangle, now calculate the length of line P.
↓end
↓
↓ 6cm
↓
start -------------13 cm------------
Use Pythagoras theorem to solve for P.
[tex]P^2 = 6^2 + 13^2\\\\P^2 = 36 + 169\\\\P^2 = 205\\\\P= \sqrt{205} \\\\P = 14.318 \ cm[/tex]
The average velocity of the ant is calculated as;
[tex]average \ velocity= \frac{\Delta displacemnt }{total\ time }= \frac{14.318 \ cm}{105 \ s} = 0.136 \ cm/s \\\\[/tex]
Thus, the average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.
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