Answer:
(7*2 / 2*2) = 14/4 = 3.5
(7*3 / 2*3) = 21/6 = 3.5
(7*4 / 2*4) = 28/8 = 3.5
Step-by-step explanation:
just multiply or divide both number by the same quantity and you will maintain the ratio
Based on the information below, which statement provides a logical
conclusion?
On Monday, Suzanne got up at 6:00 a.m. and was on time for first period.
On Wednesday, Suzanne got up at 6:15 a.m. and was late to first period.
Answer:
It's A because on b it says is she gets up after 6:00 she will not be late and that's wrong cause she will be
which expression has a value of 15 when n=7?
Answer:
19 - 28/n
n=7
19 - 28/7
19 - 4
=15
anyone trying to help me pls?
9514 1404 393
Answer:
D. reals ≥ -4
Step-by-step explanation:
The range is the vertical extent of the graph. Here the graph goes down to -4 and includes all numbers greater than that. The range is ...
All real numbers greater than or equal to -4
In a sample of 400 students, 60% of them prefer eBooks.
A.Find 98% Confidence Interval for the proportion of all students that prefer ebooksb.
b. Find the margin of erro
Answer:
a) The 98% Confidence Interval for the proportion of all students that prefer ebooks is (0.55, 0.65).
b) The margin of error is of 0.05.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is of:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In a sample of 400 students, 60% of them prefer eBooks.
This means that [tex]n = 400, \pi = 0.6[/tex]
98% confidence level
So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.054[/tex].
Margin of error -> Question b:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]M = 2.054\sqrt{0.6*0.4}{400}}[/tex]
[tex]M = 0.05[/tex]
The margin of error is of 0.05.
A.Find 98% Confidence Interval for the proportion of all students that prefer ebooksb.
Sample proportion plus/minus the margin of error.
0.6 - 0.05 = 0.55
0.6 + 0.05 = 0.65
The 98% Confidence Interval for the proportion of all students that prefer ebooks is (0.55, 0.65).
Twain's decision to end "The War Prayer" with the townspeople ignoring what
the stranger said is a good example of
A. irony
B. polyptoton
C. coincidence
D. parallelism
SUBMIT
Answer:
Irony
Explanation:
I just took the test
2x + 3y = 7 and x + y = 3? *
Answer:
1) 7/2 - 3/2y,
2) 3-y, y
Step-by-step explanation:
See Image below for steps:)
In this diagram, a triangular prism is cut by a plane as shown. What is the shape of the cross section?
Answer: it’s a triangle
Step-by-step explanation:
Answer:
triangle
Step-by-step explanation:
PLZ HELP !!!
Solve for X
A) 6
B) 5
C) 4
D) 7
For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8
Answer:
[tex]q = 8[/tex]
[tex]r = 3[/tex]
Step-by-step explanation:
Given
[tex]n = dq + r[/tex]
[tex]0 \le r < d[/tex]
[tex]n = 67[/tex] --- not -67
[tex]d = 8[/tex]
Required
Find q and r
Substitute values for d and b
[tex]n = dq + r[/tex]
[tex]67 = 8 * q + r[/tex]
[tex]67 = 8q + r[/tex]
Make q the subject
[tex]q = \frac{67 - r}{8}[/tex]
[tex]0 \le r < d[/tex] means that r is less than 8 but greater than or equal to 0
And r and q are integers.
Let [tex]r = 3[/tex]
[tex]q = \frac{67 - 3}{8}[/tex]
[tex]q = \frac{64}{8}[/tex]
[tex]q = 8[/tex]
No other true values of r and q can be gotten.
a Dhruv sold one second-hand car for 1,10,500 and two second-hand scooters for 7,500 each.
Answer:i actually dunno
Step-by-step explanation:
wat
please answer !!! quickly thank you!
Answer:
B) this line has zero slope.
Step-by-step explanation:
it doesn't increase or decrease. it is a constant; zero
Answer:
This line has zero slope.
Step-by-step explanation:
The slope of the line doesn't change it just stays straight.
What is the value........
Answer:
[tex]a_5 = 120[/tex]
Step-by-step explanation:
Given
[tex]a_1 = 1[/tex]
[tex]a_n = n(a_{n-1})[/tex]
Required
[tex]a_5[/tex]
This is calculated as:
[tex]a_5 = 5(a_{5-1})[/tex]
[tex]a_5 = 5*a_4[/tex]
Calculate [tex]a_4[/tex]
[tex]a_4 =4(a_{4-1})[/tex]
[tex]a_4 =4*a_3[/tex]
Calculate [tex]a_3[/tex]
[tex]a_3 =3*a_2[/tex]
Calculate [tex]a_2[/tex]
[tex]a_2 = 2 * a_1[/tex]
[tex]a_2 = 2 * 1[/tex]
[tex]a_2 = 2[/tex]
So:
[tex]a_3 =3*a_2[/tex]
[tex]a_3 = 3 * 2 = 6[/tex]
So:
[tex]a_4 =4*a_3[/tex]
[tex]a_4 = 4 * 6 =24[/tex]
Lastly;
[tex]a_5 = 5*a_4[/tex]
[tex]a_5 = 5 * 24[/tex]
[tex]a_5 = 120[/tex]
What is the sum of the interior angle measures of a polygon that has 11 sides?
HINT: Sum= (n-2)180
Answer:
Step-by-step explanation:
no of sides (n)=11
sum=(n-2)180
=(11-2)180
=9*180
=1620
therefore sum of the interior angles of a polygon having 11 sides id 1620°.
Answer:
n= 1620
Step-by-step explanation:
I know the answer is correct I got the exact same question during the lessons.
The weight of a product is normally distributed with a mean of 4 ounces and a variance of .25 squared ounces. What is the probability that a randomly selected unit from a recently manufactured batch weighs more than 5 ounces
Answer: 0.0228
Step-by-step explanation:
Let x be the weight of a product.
The probability that a randomly selected unit from a recently manufactured batch weighs more than 5 ounces:
[tex]P(X>5)\\\\=P(\dfrac{X-Mean}{\sqrt{Variance}}>\dfrac{5-4}{\sqrt{0.25}})\\\\=P(Z>\dfrac{1}{0.5}) \ \ \ [z=\dfrac{X-Mean}{\sqrt{Variance}}]\\\\=P(z>2)\\\\=1-P(Z<2)\\\\=1-0.9772\ \ [\text{Using p value table}]\\\\=0.0228[/tex]
Hence, the required probability = 0.0228
Pls help I’ll brainlest ASAP
Answer:
D
Step-by-step explanation:
because in standard form the first number is only up to 10 and above 10 it is decimal places e.g.6.12×10^5
hope this helps u understand :)
Four expressions are written in the table.
What value of n makes all of the expressions equivalent?
0
1
10
100
What is the decay factor that corresponds to a product that decreases its value first by 20%, and than decreases by 40% of its value, and finally decreases by 62% of its value?
a.
0.22
c.
0.1824
b.
0.0496
d.
0.62
Answer:
c.
0.1824
Step-by-step explanation:
The computation of the decay factor is as follows;
= (1 - decrease percentage) × (1 - decrease percentage) × (1 - decrease percentage)
= (1 - 0.2) × (1 - 0.4) × (1 - 0.62)
= (0.8) × (0.6) × (0.38)
= 0.1824
hence, the decay factor is 0.1824
Therefore the option c is correct
Find the value of X and Y
Answer:
y=60 degrees ; x=120 degrees.
Step-by-step explanation:
All triangles' angles must add up to 180 degrees. An equilateral triangle has 3 equal sides and degrees. If it gives the angle of one all the other angles are the same. For x you see the parallel line below it with the line to the left going through with the same angle as the one below. The angles are the same and if it is labeled in one then it is the same in the other.
The area of a rectangle is three times the area of a square. What is the width of the rectangle if it's length is 24 in. and the side of the square is 12 in?
Answer:
18 in
Step-by-step explanation:
Area of rectangle = 3 times the area of the square
Area of square = a² ; a = side length
a = 12 in
Area of square = 12² = 144 in²
Area of rectangle = 3 * 144 = 432 in²
Length of rectangle = 24 in
Width = x
Area of rectangle = length * width
432 = 24 * x
x = 432 / 24
x = 18 in
If the measure of arc CB is 8/3 units, what is the measure of CAB?
Question:
If the measure of arc CB is [tex]\frac{8}{3} \pi[/tex] units, what is the measure of ∠CAB?
Answer:
120°
Step-by-step explanation:
The figure has been attached to this response.
The figure shows a circle centered at A and has a radius of 4 units.
Also, the length of the arc CB (as given in the question) is [tex]\frac{8}{3} \pi[/tex] units.
The length L of an arc is given by;
L = [tex]\frac{\beta }{360} * 2\pi * r[/tex] -----------------(i)
Where;
β = angle subtended by the arc at the center of the circle and measured in degrees
r = radius of the circle
From the question;
β = ∠CAB
r = 4 units
L = [tex]\frac{8}{3} \pi[/tex]
Substitute these values into equation (i) as follows;
[tex]\frac{8}{3} \pi[/tex] = [tex]\frac{\beta }{360} * 2\pi * 4[/tex]
=> [tex]\frac{8}{3} \pi[/tex] = [tex]\frac{\beta }{360} * 8\pi[/tex]
Cancel 8[tex]\pi[/tex] on both sides
[tex]\frac{1}{3}[/tex] = [tex]\frac{\beta }{360}[/tex]
Cross multiply
3 x β = 360 x 1
3β = 360
Divide both sides by 3
[tex]\frac{3\beta }{3} = \frac{360}{3}[/tex]
β = 120°
Therefore, the measure of ∠CAB is 120°
Identify the relationship between sampling error and sample size.
Answer:
as the sample size increases, the margin of error decreases
Which of the following is not a property of zero?
Answer:
D is not correct
Step-by-step explanation:
"If you add zero to a number, the answer will be that same number" is incorrect
Answer: Option
2 (or B)
Step-by-step explanation:
You can't divide by 0.
Madelyn needs to order some new supplies for the restaurant where she works. The restaurant needs at least 518 glasses. There are currently 314 glasses. If each set on sale contains 8 glasses, which inequality can be used to determine s, the minimum number of sets of glasses Madelyn should buy? Submit Answer 518 < 8(314 + 8) O 518 > 8(314+ s) O 314 +8s < 518 314 +8s > 518
Answer:
(D)
314 + 8s >= 518
Step-by-step explanation:
Answer: 314 + 8s ≥ 518
Hao has a container in the shape of a right rectangular prism with dimensions 3 feet by 5 feet by 8 feet. What is the
volume, in cubic feet, of the container?
Answer:
120 [tex]{ft}^{3}[/tex]
Step-by-step explanation:
To find the volume of a rectangular prism, multiply the lengths of all of the sides
3 x 5 x 8 = Ans --> 3 x 40 = Ans -->120 = Ans
Therefore, the volume of the rectangular prism is 120 [tex]{ft}^{3}[/tex]
H Н
Which two statements are both true?
Di Ta and KFT
EH I TĞ and KT | TG
Di I K and Di 1 ET
ET I TĞ and KF | DI
HELP PLEASE!!!!
By which rule are these triangles congruent?
A) AAS
B) ASA
C) SAS
D) SSS
Answer:
ASA
Step-by-step explanation:
Both triangles contains two angles which indicate that it can only be the top 2 options.
Find the area
76 sq meters
60 sq meters
30.5 sq meters
65 sq meters
Step-by-step explanation:
2*10+((4+10)x8)/2
=20+14*8/2
=76 sq meters
what is the standard form of 365.05
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Answer:
it depends. 365.05 or 3.6505×10²
Step-by-step explanation:
In the US, 365.05 is already in standard form.
In the UK, "standard form" is the same as "scientific notation", so the number would be ...
3.6505×10²
Xavier shoots a basketball in which the height, in feet, is modeled by the equation,h(t) = -4t2 + 10 + 18, where t is time, in
seconds. What is the maximum height of the basketball?
Answer:
The maximum height of the basketball is of 24.25 feet.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:
[tex]f(x) = ax^{2} + bx + c[/tex]
It's vertex is the point [tex](x_{v}, y_{v})[/tex]
In which
[tex]x_{v} = -\frac{b}{2a}[/tex]
[tex]y_{v} = -\frac{\Delta}{4a}[/tex]
Where
[tex]\Delta = b^2-4ac[/tex]
If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].
Height of the basketball:
Given by the following function:
[tex]h(t) = -4t^2 + 10t + 18[/tex]
Which is a quadratic function with [tex]a = -4, b = 10, c = 18[/tex]
What is the maximum height of the basketball?
y(in this case h) of the vertex. So
[tex]\Delta = b^2-4ac = 10^2 - 4(-4)(18) = 388[/tex]
[tex]y_{v} = -\frac{388}{4(-4)} = 24.25[/tex]
The maximum height of the basketball is of 24.25 feet.
find The derivative of:(cosx/1+sinx)^3
Answer:
[tex]-\frac{3 \cdot cos^2x}{(1+sinx)^3}[/tex]
Step-by-step explanation:
[tex]y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})[/tex] [tex][ y = x^n\ \ \ => \ \ \ \frac{dy}{dx} = b \cdot x^{n-1} \ ][/tex]
[tex]= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\[/tex] [tex][\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ][/tex]
[tex]= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\[/tex]
[tex]= -3 \cdot \frac{cos^2x}{(1+sinx)^3}[/tex]
