x( 3x - 2y + 4z)x = -2, y = 4, and z = -3

Answers

Answer 1
Chick hhhfrtughgfghhgtyhhg

Related Questions

Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].

Answers

Answer:

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

Step-by-step explanation:

Midpoint of a segment:

The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.

Midpoint of s1:

Using the endpoints given in the exercise.

[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]

[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]

Thus:

[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]

Midpoint of s2:

[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]

[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]

Thus:

[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]

Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.

Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So

[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]

[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

Which two terms are interchangeable?

Answers

Answer: Axioms and Postulates

Step-by-step explanation:

Even if we draw more points on a line, It is an accepted statement of a fact that cannot be disproved - which which these are called Axioms or Postulates; and they are interchangeable.

I hope my explanation helped. Your welcome.

The senior classes at High School A and High School B planned separate trips to Yellowstone National Park. The senior class at High School A rented and filled 9 vans and 14 buses with 710 students. High School B rented and filled 13 vans and 5 buses with 371 students. Each van and each bus carried the same number of students. Find the number of students in each van and in each bus.

Answers

Answer:

Buses - 43 people

Vans - 12 people

19. Which of the following would best be solved using factoring the difference of squares?
O x^3 + 5x^2 - 9x - 45 = 0
O 3x² + 12x = 8
O x^2 - 25 = 0
O x^2 + 3x – 10 = 0


Please hurry!

Answers

Answer:

x² + 3x - 10 = 0

x² - 25 = 0


Given that yx is a diameter of V, find mZVX if mYVZ=(15r -1)", mWVX =(8x- 2).mUVW =(7x +15).
and mYVU = 3x + 5).
A 32
B 45°
C 70
D. 134

Answers

C

Answer: the answer is (C)

Express the following repeating decimal as a fraction in simplest form.

Answers

Answer:

[tex]0.\overline{369} = \frac{41}{111}[/tex]

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

[tex]x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}[/tex]

What number must you add to complete the square? x^2+26x=11

Answers

Answer:

[tex] {x}^{2} + 26x = 11 \\ x = 0.4 \: and \: - 26.4[/tex]

ASAP there are three marbles in a bag. One is red and two are black. What is the probability of picking a black marble first, putting it back in the bag and then picking a black marble? Use the following probability to find the answer.

Answers

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]p = \frac{favorable \: outcomes}{total \: outcomes} = \frac{4}{9} [/tex]

Answer:  Choice D)  4/9

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

When we expand (2x + 1/2)^6, what is the coefficient on the x^4 term?

Answers

Answer: The coefficient before x^4 is 60

Step-by-step explanation:

Hey! So I am not an expert at this, but you have to use the binomial theorem

I have attached of the Pascals Triangle (one shows the row numbering as well)

Basically in a pascal triangle, you add the two numbers above it to get the next number below

As you can see, the rows start from 0 instead of 1

The 6th row contains the numbers 1, 6, 15, 20, 15, 6, 1 which would be the coefficient terms

NOTE: the exponents always add to 6, the first term starts at 6 and decrease it's exponent by 1 each time (6, 5, 4, 3, 2, 1, 0) and the second term increases it's exponent by 1 each time (0, 1, 2, 3, 4, 5, 6)

Using this information the third term from the sixth row (15) would be where it is x^4 (I have circled it on the second image)

It would be 15 × 2^4 × (1/2)^2 = 60

The reason why it is 2^4 and (1/2)^2 is because the third term has the exponents 4 and 2 (bolded on the NOTE) which means that the first term must be put to the power of 4 and the second term must be put to the 2nd power

Sorry for the lousy explanation. I really hope this makes sense! Let me know if this helped :)

Which is correct?????????????

Answers

Answer:

It discusses the role of the God in influencing our decisions

Answer:

I believe it is choice D

Step-by-step explanation:

in the excerpt it talks about how sight gives us the ability to observe and experience. it also states "we prefer sight to almost everything else." hope I'm right! ☺️

What is the cube root of -1,000p12q3?
O-1004
O - 10pta
O 1004
O 10pta

Answers

Answer:

Your options are not clear

Step-by-step explanation:

[tex]\sqrt[3]{-1000 \times p^{12} \times q^3} \\\\(-1 \times 10^3 \times p^{12} \times q^3)^{\frac{1}{3} }\\\\(-1^3)^{\frac{1}{3} }\times 10^{3 \times \frac{1}{3} } \times p^{12 \times \frac{1}{3}} \times q^{3 \times \frac{1}{3}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ (-1)^3 = - 1 \ ] \\\\- 1 \times 10 \times p^4 \times q\\\\-10p^4q[/tex]

On each trial of an experiment, a participant is presented with a constant soft noise, which is interrupted at some unpredictable time by a slightly louder sound. The time it takes for the participant to react to the louder sound is recorded. The following list contains the reaction times (in milliseconds) for trials of this experiment.

170, 206, 218, 232, 238, 248, 254, 264, 268, 281, 281, 281, 316, 320, 320, 329, 336, 365, 399, 400, 438, 438, 452, 524, 724, 806

1. measures of central tendency do not exist for this data set?
a. Mean
b. Median
c. Mode
d. None of these measures

2. Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169. Which measures of central tendency would be affected by the change? Choose all that apply.

Answers

Answer:

1.d. None of these measures  (do not exist interpreted as all of these exist)

2.The mean is increased from 346.8 to 361.32

Step-by-step explanation:

After calculations we find that all the measures of central tendency exist for this data. The mean , median and mode can be easily calculated .

The mean is 346.8

The mode is 281

The median is 316

Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169.  The mean would be affected by the change.

The mean is 361.32

The mode is 281

The median is 316

The mean is increased from 346.8 to 361.32

21(2-y)+12y=44 find y​

Answers

Answer: y= -2/9
Explanation:
21(2-y)+12y=44
42-21y+12y=44
42-9y=44
-9y=2
y=-2/9

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]21\left(2-y\right)+12y=44[/tex]

[tex]42-21y+12y=44[/tex]

[tex]~add ~similar\:elements[/tex]

[tex]42-9y=44[/tex]

[tex]Subtract~42~from~both~sides[/tex]

[tex]42-9y-42=44-42[/tex]

[tex]-9y=2[/tex]

[tex]Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]

[tex]y=-\frac{2}{9}[/tex]

----------------------

hope it helps...

have a great day!

What’s the solution

Answers

Answer:

x ≥ 12

Step-by-step explanation:

-3/4x +2 ≤ -7

Subtract 2 from each side

-3/4x +2-2 ≤ -7-2

-3/4x  ≤ -9

Multiply each side by -4/3, remembering to flip the inequality

-3/4x * -4/3 ≥ - 9 *(-4/3)

x ≥ 12

Answer:

x>=12

Step-by-step explanation:

-3/4x + 2<=-7

-3/4x <= -7 -2

-3/4x<=-9

cross multiply

-3x<=-36

dividing throughout by -3

x>=12

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Khan Academy
Dependent probability
In a class of 7, there are 4 students who play soccer.
If the teacher chooses 3 students, what is the probability that none of the three of them play soccer?

Answers

Answer:

[tex]\frac{12}{49}[/tex]

Step-by-step explanation:

[tex]\frac{4}{7} *\frac{3}{7} = \frac{12}{49}[/tex]

Hope this helps.

Simplify the expression

Answers

Answer:

6

Step-by-step explanation:

3 sqrt(20) / sqrt(5)

We know that sqrt(a) /sqrt(b) = sqrt(a/b)

3 sqrt(20/5)

3 sqrt(4)

3 *2

6

what the person above me said

Simplify -4 + (-3) + 6.

Answers

Answer:3/6 in simplest fraction form is 1/2.

Step-by-step explanation:EASY and my chanel is FireFlameZero if u can check dat out

What is the solution to the inequality x(x – 3) > 0?

Answers

Answer:

The solution to the inequality is [tex](-\infty, 0) \cup (3, \infty)[/tex]

Step-by-step explanation:

We have a product, which is positive if both terms is positive or if both is negative.

Both positive:

[tex]x > 0[/tex]

[tex]x - 3 > 0 \rightarrow x > 3[/tex]

Then the intersection of these two is: [tex]x > 3[/tex]

Both negative:

[tex]x < 0[/tex]

[tex]x - 3 < 0 \rightarrow x < 3[/tex]

Then the intersection of those two is: [tex]x < 0[/tex]

Then:

Union of two solutions:

[tex]x < 0[/tex] or [tex]x > 3[/tex]

Then

[tex](-\infty, 0) \cup (3, \infty)[/tex]

What is the median of the following set of numbers?
1 5
12 1 121
1
121
13
O A. 27
ОВ.
COIN
OC. .
12
OD.

Answers

1 5

12 1 121

1

121

13

O A. 27

ОВ.

COIN

OC. .

12

OD. ????????????????

Median of the given data is 8.5.

What is median?

In statistics, the median is the middle value of the given list of data in order. Data or observations can be sorted in ascending or descending order.

Given data,

1 , 5, 12, 1, 121, 1, 121, 13

Arranging in ascending order

1, 1, 1, 5, 12, 13, 121, 121

Number of elements N = 8

When number of elements is odd

Median = (N/2 th term + (N/2)+1 th term)/2

Median = (8/2 th term + (8/2)+1 th term)/2

Median = (4th term + 5th term)/2

Median = (5+12)/2

Median = 17/2

Median = 8.5

Hence, 8.5 is the median of the given data.

Learn more about median here:

https://brainly.com/question/28060453

#SPJ7

The following data represents the number of days absent and the final grade for a sample of college students in a general education course at a large state university.
No. of absences 0 1 2 3 4 5 6 7 8 9
Final Grade 89.2 86.4 83.5 81.1 78.2 73.9 64.3 71.8 65.5 66.2
a) Which variable is the explanatory variable?
b) Draw a scatter plot and describe your scatter plot (Direction, Strength, Form).
c) Compute the correlation coefficient
d) Does a linear relation exist between the number of absences and the final grade? Justify your answer.
e) Write out the least-squares regression line equation.
f) Compute and draw the residual (on your scatter plot) for a student who misses 5 class meetings.
g) Explain the slope in context.
h) Is the y-intercept meaningful in this situation? Explain.
i) Compute and interpret the coefficient of determination.
j) Construct a residual plot to verify the requirements of the least-squares regression model.

Answers

Option a? I think maybe

if ABCD is a cyclic quadrilateral and A,B,C,D are its interior angles , then prove that
tanA/2+tanB/2=cotC/2+cotD/2

answer the question plz
dont spam or else i will report that ​

Answers

9514 1404 393

Explanation:

In a cyclic quadrilateral, opposite angles are supplementary. This means ...

  A + C = 180°   ⇒   A/2 +C/2 = 90°   ⇒   C/2 = 90° -A/2

  B + D = 180°   ⇒   B/2 +D/2 = 90°   ⇒   D/2 = 90° -B/2

It is a trig identity that ...

  tan(α) = cot(90° -α)

so we have ...

  tan(A/2) = cot(90° -A/2) = cot(C/2)

and

  tan(B/2) = cot(90° -B/2) = cot(D/2)

Adding these two equations together gives the desired result:

  tan(A/2) +tan(B/2) = cot(C/2) +cot(D/2)

Consider the following graph:

What is the limit as it is approaching -1 from the right, what is the limit?

Answers

Answer:

The limit is 0, and the answer is given by option E.

Step-by-step explanation:

Limit to the right:

The limit of a function approacing a value of x to the right is given by the value of the function quite close to the point, looking to the right.

In this question:

Approacing by the right(x quite close, but more than -1, that is, -0.9999...), y tends to 0, so the limit is 0, and the answer is given by option E.

Rewrite the equation by completing the square.
x^2 + 7x + 12 = 0

Answers

Answer:

x^2 + 7x + 12 = 0

x^2 + 7x  = -12

(+3)(+4)=0

=−3

=−4

I also love r        o      blox

Hope This Helps!!!

Answer:

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

Step-by-step explanation:

Given

x² + 7x + 12 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + 7x

x² + 2([tex]\frac{7}{2}[/tex] )x + [tex]\frac{49}{4}[/tex] - [tex]\frac{49}{4}[/tex] + 12 = 0

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{49}{4}[/tex] + [tex]\frac{48}{4}[/tex] = 0 , that is

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

A review of combination

Answers

Answer:

What is a Combination? A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order. Combinations can be confused with permutations.

#happylearning

Find the difference of (4.2x10^3)-(2.7x10^3)
Show work!

Answers

Step-by-step explanation:

Is it helpful ?

plz let me know

Find the value of y and show work

Answers

Answer:

75

Step-by-step explanation:

∠K and ∠ R are congruent (equal)

Triangle Sum Theory - angles of all triangles add to 180

180 - 79 - 26 = 75

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