X 5.2.24-E Question Help Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes. If 15 adult smartphone users are randomly selected, find the probability that fewer than 5 of them use their smartphones in meetings or classes. The probability is (Type an integer or decimal rounded to four decimal places as needed)​

Solution :

Here the subintervals of equal length will be :

[tex][6:00, 6:30], [6:30, 7:00], [7:00, 7:30], [7:30, 8:00], [8:00, 8:30], [8:30, 9:00][/tex]

So thee mid points are

[tex]x_1 = 6:15, \ x_2=6:45, \ x_3=7:15, \ x_4=7:45, \ x_5, 8:15, \ x_6 = 8:45[/tex]

The length of each sub-interval is = [tex]\frac{9-6}{6} = \frac{3}{6} = 0.5[/tex]

So, total amount of rainfall will be :

[tex]$=0.5 \sum^6_{i=1} f(x_i)$[/tex]

[tex]$=0.5\left( f(x_1)+f(x_2)+....+ f(x_6)\right)$[/tex]

= 0.5 (2.8 + 3.5 + 4.2 + 5.6 + 3.3 + 0.4)

= 0.5 (19.8)

= 9.9

The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.

Given that,

The rate of rainfall (mm per hour) over time.

Rate of rainfall;

6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00

Time  

2.0  2.8   3.0   3.5    3.8    4.2   4.8   5.6   4.0   3.3   1.8  0.4   1.2  

We have to determine,

0.4 9:00 am 1.2.

The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is?

According to the question,

Rate of rainfall;

6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00

Time  

2.0  2.8   3.0   3.5    3.8    4.2   4.8   5.6   4.0   3.3   1.8  0.4   1.2  

Here, the midpoints sum with 6 equal subintervals are,

[tex]\rm x_1 = 6;15, \ x _2 = 6;45, \ x_3 = 7;15, \ x_4 = 7;45, x_5 = 8;15 , \ x_6 = 8;45[/tex]

Then, the length of each subinterval is,

[tex]= \dfrac{9-6}{6}\\\\= \dfrac{3}{6}\\\\= \dfrac{1}{2}[/tex]

The total amount of rainfall that falls between 6;00 to 9;00 am using the midpoint subinterval is,

[tex]\rm = \dfrac{1}{2} \sum^{6}_{i=0} f(x_i)\\\\= \dfrac{1}{2} \sum^{6}_{i=0} f(x_1)+ f(x_2) + f(x_3) + f(x_4) +f(x_5)+f(x_6)\\\\= \dfrac{1}{2} (2.8+ 3.5+4.2+ 5.6+3.3+0.4}\\\\= \dfrac{1}{2} \times 19.8\\\\= 9.9[/tex]

Hence, The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.

For more details refer to the link given below.

https://brainly.com/question/795909

Answer:

158 m^2

Step-by-step explanation:

l = 5 m, w = 3 m, h = 8 m

S.A. = [tex]2(lw+wh+lh)[/tex]

S.A. = 2{(5)(3) + (3)(8) + (5)(8)}

S.A. = 2(15 + 24 + 40)

S.A. = 2(79)

S.A. = 158 m^2

Hope this help!!!

Have a nice day!!!

Answer:

≈ 5.5 minutes.

Step-by-step explanation:

Let m = number of minutes on the trampoline.

[tex]1.45m+7.25=15.23\\1.45m=7.98\\m=5.5[/tex]

She was on the trampoline for approximately 5.5 minutes.

Answer:

= 5.5 minutes

Step-by-step explanation:

1.45  + 7.25  = 15. 23

1. 45 = 15. 23 - 7. 25

1. 45 = 7 . 98

m = 5.5

Hope this answer helps you :)

Have a great day

Mark brainliest

Answer:

The x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.

Step-by-step explanation:

We have the function:

[tex]\displaystyle y=\frac{x^2 -1}{x}[/tex]

And we want to find the x-coordinates for which the gradient (or slope) at the point is 5.

The gradients of a curve at a point is given by its derivative. Find the derivative:

[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\frac{x^2-1}{x}\right][/tex]

Use the quotient rule:

[tex]\displaystyle \frac{dy}{dx}=\frac{(x^2-1)'(x)-(x^2-1)(x)'}{(x)^2}[/tex]

Simplify:

[tex]\displaystyle \frac{dy}{dx}=\frac{(2x)(x)-(x^2-1)(1)}{x^2}[/tex]

Simplify:

[tex]\displaystyle \frac{dy}{dx}=\frac{x^2+1}{x^2}[/tex]

Since the gradient is 5, substitute 5 for dy/dx and solve for x:

Multiply both sides by x² (x ≠ 0):

[tex]5x^2=x^2+1[/tex]

Subtract x² from boths sides:

[tex]4x^2=1[/tex]

Solve for x:

[tex]\displaystyle x=\pm\sqrt{\frac{1}{4}}=\frac{1}{2}\text{ or } -\frac{1}{2}[/tex]

So, the x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.

Answer:

Step-by-step explanation:

Hope this helps u!!

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Explanation:

The y is a placeholder for a number. In this case, we'll replace it with 4.

So [tex]5y^2 - 10[/tex] becomes [tex]5(4)^2-10[/tex]

Use the order of operations PEMDAS to simplify

[tex]5(4)^2-10\\\\5(16)-10\\\\80-10\\\\70\\\\[/tex]

Therefore, [tex]5y^2-10\\\\[/tex] evaluates to 70 when y = 4.

Put another way, the equation [tex]5y^2-10 = 70\\\\[/tex] has one solution that is y = 4.

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Explanation:

For any two vectors defined as follows

u = <a,b>

v = <c,d>

the dot product is computed by

u dot v = a*c + b*d

If the dot product of the vectors is 0, then the vectors are orthogonal. Meaning they are perpendicular to one another.

-------------------

Let's find the dot product of these two given vectors

u = < 2, -4 >

v = < 6, 3 >

u dot v = 2*6 + (-4)*3

u dot v = 12 - 12

u dot v = 0

Therefore, these two vectors form a right angle and are orthogonal

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Extra info:

If we can show that u = <a, b> and v = <ka, kb> for some real number k, then we have shown that vectors u and v are parallel.

Answer:

Yeah buddy

Step-by-step explanation:

Cabs here cabs here cabs here cabs here cabs here

Answer:

6x +24

Step-by-step explanation:

you factor out the 6 so 6x and 6*4 is 24

answer:

ABCD is not congruent to KLMN

ABCD cannot be mapped onto KLMN

9514 1404 393

Explanation:

Divide the figure into areas for which you have a surface area formula. Use the appropriate formula for each area, then add up the results.

Formulas are available for surface areas of a cone, cylinder, sphere, pyramid, rectangular prism, and for plane shapes that are circles, ellipses, triangles, rectangles, trapezoids, and regular polygons.

Most of the figures for which you are asked to find the area will decompose to some subset of these shapes. Take care to identify the relevant dimensions of each of the constituent parts of the area, and to make sure that all parts are accounted for. Do not allow your parts of the area to overlap, unless you intend to account for that overlap by subtracting the area that is counted more than once.

Also, use your common sense. A semicircle will have half the area of a circle, for example.

In some cases, it may be expedient to compute the area of a larger figure than the one you have, then subtract the part of that area that is missing from your figure.

Answer: 4/5

Step-by-step explanation:

Step-by-step explanation:

pool = 1600 sq.cm

1600 sq.sm = 50cm × 32cm

AB = 50cm

the area of the park of A'B' :

50cm×4=200 sq.cm

Answer:

The median number of days absent is zero (0)

The mean number of days absent is 1.0 day

(b) The proportion of the population that has absenteeism greater than 4 days is 6.34 %

Step-by-step explanation:

total number of students, n = 284

The total number of students is even, the median number of days absent will in (n/2).

n/2 = 284/2 = 142

The cumulative frequency that falls in 148 students = 0 day

The median number of days absent is zero (0)

For mean:

Let the days absent = x  

let the number of students = f

[tex]mean (\bar x) = \frac{\sum fx}{\sum f}\\\\\bar x = \frac{(158\times 0)+ (64\times 1)+(18\times 2)+(22\times 3)+(4\times 4)+(5\times 7)+(6\times 8)+(9\times 2)+(13\times 1)}{284} \\\\\bar x = \frac{296}{284} \\\\\bar x = 1.0 \ day[/tex]

(b) the number of students with absenteeism greater than 4 dyas;

= 7 + 8 + 2 + 1

= 18

The proportion of these students;

[tex]= \frac{18}{284} \\\\= 0.0634 \\\\= 6.34 \ \%[/tex]

Using statistical concepts, it is found that:

Question a:

Then, the mean is:

[tex]M = \frac{0(158) + 1(64) + 2(18) + 3(22) + 4(4) + 5(7) + 6(8) + 9(2) + 13(1)}{284} = 1[/tex]

158 > 142, hence, the median is 0.

Question b:

[tex]p = \frac{18}{284} = 0.0634[/tex]

0.0634 = 6.34% of the population has an absenteeism greater than 4 days.

To learn more about mean and median, you can take a look at https://brainly.com/question/24732674

Answer:

x => y

0 => 0

2 => 3

4 => 6

-2 => -3

Step-by-step explanation:

The equation of a proportional relationship is represented as y = kx,

where, k = y/x

We are given that k = ³/2

This means that, equation of the relationship therefore would be:

y = ³/2x

Use this equation to solve for each missing value on the table given:

✔️Where, y = 0, substitute y = 0 into y = ³/2x to find x:

0 = ³/2x

0 * 2 = 3x

0 = 3x

0/3 = x

x = 0

✔️Where, x = 2, substitute x = 2 into y = ³/2x to find y:

y = ³/2(2)

y = 3

✔️Where, y = 6, substitute y = 6 into y = ³/2x to find x:

6 = ³/2x

6 * 2 = 3x

12 = 3x

12/3 = x

x = 4

✔️Where, x = -2, substitute x = -2 into y = ³/2x to find y:

y = ³/2(-2)

y = -3

Answer:

the answer is the first one

Answer: razon de ser

Step-by-step explanation:

Tu eres como agua Clara que lluvi del suelo

Answer:

11/18

Step-by-step explanation:

Directly between 5/9 and 6/9 would be 5.5/9 (or 5 and half ninths. However, you’re not supposed to mix regular fractions and decimal fractions.

So, the easiest way to get the proper answer would be to convert the fractions to eighteenths, which would give you a whole number numerator between the two given fractions.

So, 5/9 = 10/18 and 6/9 = 12/18. What number is directly exactly between 10 and 12? 11.

Hi my name is Fabian and 69% because 69 is a man which is multi colour hair

Answer:

Step-by-step explanation:

12. To find the carpet needed. Find the area :

   The figure is combination of semi circle and a rectangle.

   So Area = Area of semi circle + Area of rectangle

      [tex]Area \ of \ semi \ circle = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi \times 25 = 39.25 \ ft^2 \\\\Area \ of \ rectangle = Length \times Breadth = 15 \times 10 =150 \ ft^2[/tex]

     Area = 150 + 39.25 = 189.25 sq ft

13.   Cost per square feet = $$9.95

     Therefore cost for 189.25 square feet = 9.95 x 189.25 = $1883.04

Answer:

Step-by-step explanation:

1. Title of the graph → Comparison of the Plant Growth

2. y-axis represents the height of the plants in centimeters.

3. On day 2:

   Height of plant A (plant outside) = 5.1 cm

   Height of plant B (plant near the window) = 2.25 cm

4. Plant outside shows great increase in the height.

    On day 5,

    Height of the plant outside = 6.75 cm

    Growth in height from day 2 to day 5 = 6.75 - 5.1

                                                                   = 1.65 cm

    Height of the plant near the window = 2.5 cm

    Growth in height of the plant from day 2 to day 5 = 2.5 - 2.25

                                                                                        = 0.25 cm

    Therefore, plant outside shows the great increase in height.

5. Plant near the window grew 0.25 cm in height.

Answer:

It's B (1÷13=3) for Part a

1 whole is equal to 3/3. One batch of brownies uses up to 1/3 of butter. So 1 ÷ 1/3 = 3.

Step-by-step explanation:

Answer:

a big number

Step-by-step explanation:

point D is the answer

________

Answer:

m∠ACD = 130

Step-by-step explanation:

If ABC is an isosceles, AB = AC and m∠A = 80°, then m∠B and m∠C is equal to 50°.

This is because angles in a triangle adds up to 180°.

180° - 80° = 100°/2 = 50°

∴ m∠ACD = 130°, this is because the interior opposite angles in a triangle is supplementary to the opposite exterior angle:

50° + 80° = 130°

Or

Angles on a straight line adds up to 180°.

180° - 50° = 130°

The answer is 28 ez.

Answer:

the answer is 28

Step-by-step explanation:

Answer:

The normal overlaps with the diameter, so it passes through the center.

Let's find the center of the circle:

The center is:

Since the line passes through (-g, -f) the equation of the line becomes:

This is the required condition

Rewrite equations and find centers and radius of both circles.

Circle 1

Circle 2

The distance between two centers is same as sum of the radius of them:

Sum of radiuses:

Since they are same we have:

Square both sides:

Square both sides:

Divide both sides by a²b²c²:

Proved

Answer:

Answer is in the picture