x + y = 15
5x - y = 9
Elimination method

(4, ? )

what number is the ?​

Answer:

B.

Step-by-step explanation:

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex], x= -5 - 5[tex]\sqrt{97}[/tex]

Step-by-step explanation:

Since this quadratic is set to zero, we can use the quadratic formula to solve this.

x^2 + 10x - 2400 = 0​

Quadractic formula =  x= -b +- [tex]\sqrt{b^2 - 4ac}[/tex] /2a

For this equation:

a= 1, b=10, c=-2400

Plug these numbers into the equation and solve.

x= -10 +- [tex]\sqrt{10^2 - 4(1)(-2400}[/tex])/2(1)

x= -10 +- [tex]\sqrt{100 + 9,600}[/tex]/2

x= -10 +- [tex]\sqrt{9,700}[/tex]/2

x= -10 +- [tex]\sqrt{2^2 * 5^2 * 97}[/tex]/2

x= -10 +- 5 * 2[tex]\sqrt{97}[/tex]/2

x= -10 +- 10[tex]\sqrt{97}[/tex] / 2

Divide by 2.

x= -5 +- 5[tex]\sqrt{97}[/tex]

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex] or x= -5 - 5[tex]\sqrt{97}[/tex]

Answer:

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Step-by-step explanation:

The given expression to us is ,

[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]

Now take the LCM as ( x - 1 ) and Simplify , we have ,

[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]

Simplifying further , we get ,

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Hence the second option is correct.

Answer:

[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1)}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2} \\ \frac{ - 4x + 7}{2(x - 1)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]

Answer:

x = 3

Step-by-step explanation:

Step-by-step explanation:

3(8x-8)/2=64

3(8x-8)=64×2

24x-24=128

24x=128+24

24x=152

24x/24=152/24

x=6.3

Answer:

In picture

Step-by-step explanation:

Brainliest please~

[tex](0,3)[/tex] and [tex](1,-2)[/tex]

Equation: (refer the image below)

Slope:

[tex]m=\frac{3+2}{0-1}[/tex]

[tex]m=-5[/tex]

Equation:

[tex]y=5x-b[/tex]

[tex]3=b[/tex]

Substitute (0,3)

Point: [tex](1,-2)[/tex]

Answer:

Traversable because it has exactly two odd nodes

Step-by-step explanation:

There is a rule that says it is traversable if it has exactly 2 odd nodes. The are other rule where it can be traversable is if has no odd nodes.

Also if we let the starting point be D and the ending point be B we can travel the network in such way that each edge is only traveled once which is the definition that the network is traversable.

So I will do this by starting at D, then travel to A using the outside edge, then travel to back to D using inside edge, then travel to C, then travel to B, then travel to A using outside edge, and then back to B from A using inside edge.

Answer: x = 17

Step-by-step explanation: Since ray SQ bisects <TSR, we know

that the m<TSQ ≅ m<QSR by the definition of an angle bisector.

So we can setup the equation (3x - 9) + (3x - 9) = 84

using the angle addition postulate.

Simplifying on the left gives us 6x - 18 = 84.

Now add 18 to both sides to get 6x = 102.

Now divide both sides by 6 so x = 17.

Answer:

Step-by-step explanation:

Perimeter of the rectangle = P

Base = b

Height = h

Area = A

P = 2b + 2h

P = 66

STEP 1:

2(2x + 1) + 2(x + 5) = 66

Distribute

4x + 2 + 2x + 10 = 66

STEP 2:

Combine like terms and isolate the variable

6x + 12 = 66

6x = 54

x = 9

STEP 3:

Plug in x

A = (2(9) + 1) * (9 + 5)

STEP 4:

Simplify

A = (18 + 1) * (14)

A = (19)(14)

A = 266

[tex]\displaystyle\bf P=2(2x+1+x+5)=66\\\\6x+12=66\\\\6x=54\\\\\boxed{x=9}\\\\2x+1=19\\\\x+5=14 \\\\S=ab=14\cdot19=266 cm^2[/tex]

Answer:

y = 4x² - 43x + 178

Step-by-step explanation:

Given that data:

1 __ 137

2 __ 110

3 __ 93

4 __ 70

5 __ 65

6 __ 77

Usibg technology, the quadratic regression equation obtained is written in the form:

Ax² + Bx + C

A = 4.34 = 4 ( nearest whole number)

B = - 43.46 = - 43 (nearest whole number)

C = 178.3 = 178 ( nearest whole number)

Hence, the quadratic model is

y = 4x² - 43x + 178

By rounding the coefficients to the nearest whole number, the quadratic function that models the data is[tex]f(x) = 5x^2 - 42x + 174[/tex]

To find a quadratic function that models the data,  use a quadratic equation of the form:

[tex]f(x) = ax^2 + bx + c[/tex]

Let's use the given data points to form a system of equations and solve for the coefficients a, b, and c.

Using the first data point (month 1 with 137 births):

[tex]f(1) = a(1)^2 + b(1) + c = 137[/tex]

a + b + c = 137 (Equation 1)

Using the second data point (month 2 with 110 births):

[tex]f(2) = a(2)^2 + b(2) + c = 110[/tex]

4a + 2b + c = 110 (Equation 2)

Using the third data point (month 3 with 93 births):

[tex]f(3) = a(3)^2 + b(3) + c = 93[/tex]

This simplifies to:

9a + 3b + c = 93 (Equation 3)

Solve this system of equations will give us the values of a, b, and c.

Subtract Equation 1 from Equation 2

3a + b = -27 (Equation 4)

Subtract Equation 1 from Equation 3

8a + 2b = -44 (Equation 5)

Now  solve Equations 4 and 5 simultaneously.

Multiply Equation 4 by 2 and subtracting it from Equation 5:

8a + 2b - (6a + 2b) = -44 - (-54)

2a = 10

Divide both sides by 2:

a = 5

Now substitute the value of a back into Equation 4:

3(5) + b = -27

15 + b = -27

Subtract 15 from both sides:

b = -42

Finally, substitute the values of a and b into Equation 1

5 + (-42) + c = 137

-37 + c = 137

Add 37 to both sides:

c = 174

Therefore, the quadratic function that models the data is:

[tex]f(x) = 5x^2 - 42x + 174[/tex]

Rounding the coefficients to the nearest whole number, the quadratic function becomes:

[tex]f(x) = 5x^2 - 42x + 174[/tex]

Learn more on quadratic on https://brainly.com/question/1214333

#SPJ3

Answer:

1.12 Units

Step-by-step explanation:

1. Use cos(56°) = x/2

Make sure your calculator mode is in deg (degree) not rad(radians)

2.  2(cos(56°)) = x

3. x = 1.118385807

4. Round up to get 1.12 Units

Within similar triangles, the angles are the same. So, we need to look at the side lengths then.

72 to 12

66 to 11

42 to 7

In each pair of corresponding side lengths, the original side length from triangle ABC is divided by 6 (or multiplied by 1/6) to get the smaller side length on triangle DEF.

The scale factor from ABC to DEF is 1/6.

Hope this helps!

Answer:

Step-by-step explanation:

Cross multiplication can be used but not in the beginning. First x should be isolated.

[tex]3 +\frac{5}{x}=\frac{7}{x}\\\\[/tex]

Now subtract [tex]\frac{5}{x}[/tex] from both sides

[tex]3 = \frac{7}{x}-\frac{5}{x}\\\\3=\frac{7-5}{x}\\\\3=\frac{2}{x}[/tex]

In this stage, cross multiplication can be used.

[tex]\frac{3}{1}=\frac{2}{x}\\\\3*x=2*1\\\\x = \frac{2}{3}[/tex]

Answer:

x =0 and x =2/3

Step-by-step explanation:

as is no

but if you put an x under the 3 to make 3x/x

then you'd have 3x+5/x = 7/x

to make

3x^2 + 5x = 7x

this makes

3x^2 -2x =0

using the quadratic formula

answers

x =0 and x =2/3

Answer:

15 x 150 = 2250

2250 + 1000 = 3250

you make $3250,00

Answer:

x = 9

Step-by-step explanation:

The ratios of corresponding sides are equal, that is

[tex]\frac{BC}{MN}[/tex] = [tex]\frac{AB}{LM}[/tex] , substitute values

[tex]\frac{x}{15}[/tex] = [tex]\frac{6}{10}[/tex] ( cross- multiply )

10x = 90 ( divide both sides by 10 )

x = 9

Answer:

124°

I hope it's helps you

Answer:

r can be 0.5

Step-by-step explanation:

Here, we want to get a possible value of r

From the question, the value of r is between 0 and 3

Mathematically, we know that in degrees pi is the same as 180 degrees

In a case where we have r = 1/2

we have it that;

cos(pi/2) = 2 cos (pi/2)

Since pi/2 is 90 and cos 90 is zero; then we have it that the two sides of the equation is the same and r can be 1/2

Answer:

Mean = 2.33

Step-by-step explanation:

Given that,

conceded goals : 0 1 2 3 4

Frequency : 2 8 4 10 6

Mean,

[tex]M=\dfrac{\Sigma fx}{\Sigma f}\\\\M=\dfrac{0\times 2+1\times 8+2\times 4+3\times 10+4\times 6}{2+8+4+10+6}\\\\=\dfrac{70}{30}\\\\M=2.33[/tex]

So, the required mean is 2.33.

Answer:

F

Step-by-step explanation:I just took the test

Answer:

51= 1/2(160-x)

102=160-x

x=160-102=58

Step-by-step explanation:

Answer:

O d. (7,5)

Step-by-step explanation:

x – 3y = -8 (1)

3x + 2y = 31 (2)

From (1)

x = -8 + 3y

Substitute x = -8 + 3y into (2)

3x + 2y = 31 (2)

3(-8 + 3y) + 2y = 31

-24 + 9y + 2y = 31

-24 + 11y = 31

11y = 31 + 24

11y = 55

y = 55/11

y = 5

Substitute y = 5 into (1)

x – 3y = -8 (1)

x - 3(5) = -8

x - 15 = -8

x = -8 + 15

x = 7

(x, y) = (7, 5)

Answer:

The probability of a person getting their own hat is 1/5 or 20%.

Step-by-step explanation:

If each person has one hat the chances (the probability) of them getting their own hat would be 20%. The chances (the probability) of them getting a hat that belongs to one of the other four students would be 80%. Due to there being 5 hats each person owns 1 hat so there would be a 1 out of 5 chance of them getting their own hat.

Answer:

5 years

Step-by-step explanation:

(x+15)=4x

15=4x-x

15=3x

5=x

Answer:

2x+5x^2=1

2x+5x*5x=1

2x+25x=1

27x=1

1/27=x

Hope This Helps!!!

Answer:

D. 24

Hope it helps!

Answer:

Probably 10

Step-by-step explanation:

10/5=2

Answer:

If you are talking about inequalities, t < r.

Step-by-step explanation:

Since s is bigger than t and r is bigger than s,

r should be bigger than t obviously.

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Answer:

Step-by-step explanation:

If the product of 2 integers is -12, then that equation looks like this:

xy = -12

If the sum of those same 2 integers in 1, then that equation looks like this:

x + y = 1

Let's solve the second equation for x and plug it into the first equation. Solving the second equation for x gives us

x = 1 - y and plug that into the first equation in place of x to get:

(1 - y)y = -12 and

[tex]y-y^2=-12[/tex] Now move everything over to one side and factor to find y:

[tex]-y^2+y+12=0[/tex] and the 2 values for y are

y = -3 and y = 4. Let's see what happens when we solve for x.

If xy = -12 and y is -3:

x(-3) = -12 so

x = 4

If xy = -12 and y is4:

x(4) = -12 so

x = -3

So it looks like the 2 integers are -3 and 4

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

Answer:

Step-by-step explanation:

[tex]\sf \bf {\boxed {\mathbb {GIVEN:}}}[/tex]

Sum of three consecutive odd integers = [tex]27[/tex]

[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]

The values of the three integers.

[tex]\sf \bf {\boxed {\mathbb {SOLUTION:}}}[/tex]

[tex]\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

Let us assume the three consecutive odd integers to be [tex]x[/tex], [tex](x+2)[/tex] and [tex](x+4)[/tex].

As per the condition, we have

[tex]Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27[/tex]

[tex]➺ \: x + (x + 2) + (x + 4) = 27[/tex]

[tex]➺ \: x + x + 2 + x + 4 = 27[/tex]

Now, collect the like terms.

[tex]➺ \: (x + x + x) + (2 + 4) = 27[/tex]

[tex]➺ \: 3x + 6 = 27[/tex]

[tex]➺ \: 3x = 27 - 6[/tex]

[tex]➺ \: 3x = 21[/tex]

[tex]➺ \: x = \frac{21}{3} \\[/tex]

[tex]➺ \: x = 7[/tex]

Therefore, the three consecutive odd integers whose sum is [tex]27[/tex] are [tex]\boxed{ 7 }[/tex], [tex]\boxed{ 9 }[/tex] and [tex]\boxed{ 11 }[/tex] respectively.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]⇢ 7 + 9 + 11 = 27[/tex]

[tex]⇢ 27 = 27[/tex]

⇢ L. H. S. = R. H. S.

[tex]\sf\blue{Hence\:verified.}[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]