X, Y and Z are three points on a map. Y is 75km and on a bearing of 200° from X. Z is on a bearing of 150°, from Y. Z is due south of X. Calculate the distance between X and Z rounded to 1 DP.

Answers

Answer 1

Answer:

The distance between X and Z is approximately 114.9 km

Step-by-step explanation:

The given parameters are;

The distance of Y from X = 75 km

The bearing of Y from X = 200°

The bearing of Z from Y = 150°

The bearing of Z from X = 180°

In triangle XYZ, we have;

∠YZX = 180° - (130° + 20°) = 30°

By sine rule, we have;

(75 km)/sin(30°) = XZ/(sin(130°))

XZ = sin(130°) × (75 km)/sin(30°) ≈ 114.9 km

The distance between X and Z ≈ 114.9 km. to one decimal place.

X, Y And Z Are Three Points On A Map. Y Is 75km And On A Bearing Of 200 From X. Z Is On A Bearing Of

Related Questions

Sarah had 36 free throw attempts during a game and made at least 75% of the free throws.

What is the greatest number of free throws Sarah could have missed during the game?

Answers

Answer:

9 free-throws

Step-by-step explanation:

75% of 36 = 27

36-27=9

She could have missed up to nine free throws

Answer:

3

Step-by-step explanation:

25% of 12 is 3. Brainliest pls :)

What is an equation in slope-intercept form for the line that passes through the points (1, -3) and (3, 1)?

A. y= 3x + 1
B. y= x-3
C. y= 2x + 5
D. y= 2x-5


° ♡ ₒ ♡ °
thank you!

Answers

D.y=2x-5


I think, i hope this helps
The slope intercept form is y= 2x-5

Can you please mark BRAINLEST
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