(x+1)(x−1)(x−5)=0 HELP

Answer:

Step-by-step explanation:

Hello,

[tex]f(g(x))=\dfrac{8}{x^2}+4[/tex]

So if we take

[tex]f(x)=\dfrac{8}{x}+4 \ \ and \\\\g(x)=x^2\\ \\f(g(x))=\dfrac{8}{g(x)}+4=\dfrac{8}{x^2}+4[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

x=2.86

Step-by-step explanation:

[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]

[tex] {24}^{2} + {32}^{2} = 40[/tex]

[tex]c = 40[/tex]

[tex]6x + 6 + 9x - 9 = 40[/tex]

[tex](6x + 9x) + (6 - 9) = 40[/tex]

[tex]15x - 3 = 40[/tex]

[tex]15x = 43[/tex]

[tex]x = 2.866[/tex]

[tex]23.16 + 16.74 = 39.9[/tex]

the

[tex]6(2.86) + 6 = 23.16[/tex]

[tex]9(2.86) - 9 = 16.74[/tex]

Answer:

14x+4

Step-by-step explanation:

17x-3x=14x

Answer:

At 3 hours, the trains will be equidistant from the station.

Step-by-step explanation:

The first train leaves at 75 miles per hour and has a 2 hour head start.  This will put the first train at mile marker 150 (75 * 2) when the second train leaves the station at 125 mph.

To solve when they will be near each other, we set up an equation to solve for t.

150 + 75t = 125t

150 = 50t

3 = t

So given this value, we know the trains will be equidistant from the train station on parallel tracks after 3 hours.

Cheers.

An expression is a set of numbers, variables, and mathematical operations. The correct option is C, r² + 1.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Since real numbers contain positive integers, negative integers, positive decimals, negative decimals, and zero.

Therefore, For any real number r, the expression that will be always greater than r will be (r²+1). This is because,

Hence, the correct option is C, r² + 1.

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Answer:

Three

Step-by-step explanation:

Assuming the grade score from 70 to 100 is A; for grade score from 60 to 69 is B and grade score from 50 to 59 is C. Well it is certain there are three peaks in the distribution of scores

Answer:

bgd=cgd+cgb

agf=cgd

50=cgd

cgd=50

bgd=90

so cgd=50

bgc=40

bgd=90

Answer:

C  90-degrees

Step-by-step explanation:

Using alternate interior angles, you can say m<CGD = 50 degrees.

From here, using the fact that line BE is a bisector of line CF, we know that the sum of degrees of the line BE would be 180 degrees.

So we can say m<EGD + m<CGD + m<BGC = 180.  Plug in our known values.

90 + 50 + m<BGC = 180

m<BGC = 40

And we can see that m<BGD = m<BGC + m<CGD

Thus, m<BGD = 40 + 50 = 90.

So the m<BGD = 90 degrees.

Cheers.

Answer: hey

Step-by-step explanation:

Answer:

20 days

Step-by-step explanation:

Renting a car costs $30 per day.

y = 30x

Renting a car costs $600 per month

y = 600

Set the two equations equal to each other.

30x = 600

(30x)/30 = (600)/30

x = 20

After 20 days, the two options have an equal cost.

Answer: A = 2,034.356 ≈ $2,034.36

$2,034.36 will be in the account in 3 years

Step-by-step explanation:

Given that ;

P = $1,700

Rate r = 6%

Time period (t) = 3 years

now to find how much money will be in the account in 3 years

we say;

A = P ( 1 + r/n )^nt

A = 1,700 ( 1 + 0.06/12) ¹²ˣ³

A = 1,700 ( 1.19668)

A = 2,034.356 ≈ $2,034.36  

Answer:

x = 7

Step-by-step explanation:

L and M would be parallel if angle 2x -3 and the angle x + 4 are equal.

Thus, 2x - 3 = x + 4, so that x = 7

Answer:

(x + 3i) * (x - 3i) = x^2 + 3xi - 3xi - 9(i^2) = x^2 + 9

Step-by-step explanation:

Answer:

Use the student t distribution

Step-by-step explanation:

Here is the formula

t = (x - u) ÷(s/√N)

From the information we have in the question:

n = 150

s = 550

x = 3400

u = mean = 2400

= 3400 - 2400÷ 500/√150

= 1000/44.9

= 22.27

At 0.05 significance level, df = 149 so t tabulated will be 1.65.

Answer:

a = 9

Step-by-step explanation:

3a - 27 = 0

3a = 27

a = 27/3

a = 9

3*9  -  27 = 0

27 - 27 = 0

Answer:

a = 9

Step-by-step explanation:

3a-27=0

Add 27 to each side

3a = 27

Divide by 3

3a/3 = 27/3

a = 9

Answer:

Perimeter=60.18cm

Area=215.495cm^2

Step-by-step explanation:

Given:

Length of book=18.34cm

Breadth=11.75cm

Solution:

Perimeter=2(l +b)

P=2(18.34+11.75)

P=2 x 30.09

P=60.18cm

Area=l x b

A=18.34 x 11.75

A=215.495 cm^2

Thank you!

Answer:

12 inches by 12 inches = 15 dollars

48 inches by 48 inches = 80 dollars

Step-by-step explanation:

12 inches = 1 ft

so 12 inch by 12 inches  is 1 ft * 1 ft

1 ft* 1 ft

1 ft^2

This is smaller than 3 ft^2 so they will get charged for 3 ft^2

3 ft^2 = 3 ft^2 * $5 / ft^2 = 15 dollars

48 inches = 48/12 = 4 ft

4ft * 4 ft = 16 ft^2

16 ft^2 = 16 ft^2 * $5 / ft^2 = 80 dollars

Complete Question

On the uploaded image is a similar question that will explain the given question

Answer:

The value of k is  [tex]k = 214285.7[/tex]

The percentage  of the oil that will be cleaned is [tex]x = 80.77\%[/tex]

Step-by-step explanation:

From the question we are told that

   The  cost of cleaning up the spillage is  [tex]C = \frac{ k x }{100 - x }[/tex]  [tex]x \le x \le 100[/tex]

     The  cost of cleaning x =  70% of the oil is  [tex]C = \$500,000[/tex]

Now at  [tex]C = \$500,000[/tex] we have  

       [tex]\$ 500000 = \frac{ k * 70 }{100 - 70 }[/tex]

       [tex]\$ 500000 = \frac{ k * 70 }{30 }[/tex]

      [tex]\$ 500000 = \frac{ k * 70 }{30 }[/tex]

      [tex]k = 214285.7[/tex]

Now  When  [tex]C = \$900,000[/tex]

       [tex]x = 80.77\%[/tex]

Answer: [tex]-44\dfrac{4}{9}[/tex]

Step-by-step explanation:

The given expression: [tex]-36\dfrac{4}{9}-(-10\dfrac{2}{9})-(18\dfrac{2}{9})[/tex]

Here, [tex]36\dfrac{4}{9}=\dfrac{36\times9+4}{9}=\dfrac{328}{9}[/tex]

[tex](10\dfrac{2}{9})=\dfrac{92}{9}\\\\(18\dfrac{2}{9})=\dfrac{9\times18+2}{9}=\dfrac{164}{9}[/tex]

That is

[tex]-36(\dfrac{4}{9})-(-10\dfrac{2}{9})-(18\dfrac{2}{9}) = -\dfrac{328}{9}-(-\dfrac{92}{9})-\dfrac{164}{9}\\\\=-\dfrac{328}{9}+\dfrac{92}{9}-\dfrac{164}{9}\\\\=\dfrac{-328+92-164}{9}\\\\=\dfrac{-400}{9}\\\\=-44\dfrac{4}{9}[/tex]

Answer:

Step-by-step explanation:

[tex]12-8x=5\\\\Collect\:like\:terms\\\\-8x =5-12\\\\-8x = -7\\\\Divide\:both\:sides\:by -8\\\frac{-8x}{-8} \\=\frac{-7}{-8} \\\\x = 0.875\\\\x = 0.88[/tex]

Answer:

[tex]\large \boxed{x\° = 130}[/tex]

Step-by-step explanation:

The triangle is an isosceles triangle. The base angles are equal.

Angles in a triangle add to 180 degrees.

[tex]y+65+65=180\\y+130=180\\y=50[/tex]

Angles on a straight line add up to 180 degrees.

[tex]x+50=180\\x=130[/tex]

Answer:

[tex]\huge\boxed{\sf x = 130\ degrees}[/tex]

Step-by-step explanation:

The measure of exterior angle is equal to the sum of non-adjacent interior angles.

So,

x = 65 + 65

x = 130 degrees

Answer:

12). LM = 37.1 units

13). c = 4.6 mi

Step-by-step explanation:

12). LM² = 23² + 20² - 2(23)(20)cos(119)°

    LM² = 529 + 400 - 920cos(119)°

    LM² = 929 - 920cos(119)°

    LM = [tex]\sqrt{929+446.03}[/tex]

          = [tex]\sqrt{1375.03}[/tex]

          = 37.08

          ≈ 37.1 units

13). c² = 5.4² + 3.6² - 2(5.4)(3.6)cos(58)°

    c² = 29.16 + 12.96 - 38.88cos(58)°

    c² = 42.12 - 38.88cos(58)°

    c = [tex]\sqrt{42.12-20.603}[/tex]

    c = [tex]\sqrt{21.517}[/tex]

    c = 4.6386

    c ≈ 4.6 mi

Answer:

1365

Step-by-step explanation:

We figure out combinations using this formula:    n!

                                                                              r!(n-r)!

n=15

r=4

So n!= 15x14x13x12x11x0x9x8x7x6x5x4x3x2x1

r! = 4x3x2x1 times 15-4!, which is 11! = 11x10x9x8x7x6x5x4x3x2x1

Put this together and you have 15x14x13x12/4x3x2x1=

There are 1365 different ways to award the 4 door prizes to 4 guests from a group of 15 guests.

Combinations are the procedures used in mathematics to pick k things from n different items without replacement.

The following formula computes the combinations of k items from n:

(n, k) = n! / k!×(n-k)!

The number of ways to award the 4 door prizes to 4 guests out of a group of 15 guests is a combinatorial problem that can be calculated using the formula.

Here, n = 15 (the total number of guests) and k = 4 (the number of prizes to be awarded).

So, the number of ways to award the prizes is:

C(15, 4) = 15! / (4! (15 - 4)!)

= 15! / (4! 11!)

= 15 x 14 x 13 x 12 / (4 x 3 x 2 x 1)

= 1365.

Therefore, there are 1365 different ways to award the 4 door prizes to 4 guests from a group of 15 guests.

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From your earlier questions, we found

[tex]2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)[/tex]

so the wave has amplitude √29. The weight's maximum negative position from equilibrium is then -√29, so you are solving for t in the given interval for which

[tex]\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)=-\dfrac{\sqrt{29}}2[/tex]

Divide both sides by √29:

[tex]\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)=-\dfrac12[/tex]

Take the inverse sine of both sides, noting that we get two possible solution sets because we have

[tex]\sin\left(\dfrac{7\pi}6\right)=\sin\left(\dfrac{11\pi}6\right)=-\dfrac12[/tex]

and the sine wave has period 2π, so [tex]\sin x=\sin(x+2\pi)=\sin(x+4\pi)=\cdots[/tex].

[tex]\implies 4\pi t+\tan^{-1}\left(\dfrac52\right)=\dfrac{7\pi}6+2n\pi[/tex]

OR

[tex]\implies 4\pi t+\tan^{-1}\left(\dfrac52\right)=\dfrac{11\pi}6+2n\pi[/tex]

where n is any integer.

Now solve for t :

[tex]t=\dfrac{\frac{7\pi}6+2n\pi-\tan^{-1}\left(\frac52\right)}{4\pi}[/tex]

OR

[tex]t=\dfrac{\frac{11\pi}6+2n\pi-\tan^{-1}\left(\frac52\right)}{4\pi}[/tex]

We get solutions between 0 and 0.5 when n = 0 of t ≈ 0.196946 and t ≈ 0.363613.

Answer:

Cohen's d : 1.00

Step-by-step explanation:

We know that M₁ = 18, and M₂ = 14. Given that the pooled variance for the these two samples are 16, S²Pooled = 16, and therefore S - pooled = 4.

The formula to solve for the value of Cohen's d is as follows,

d = M₁ - M₂ / S - pooled,

d = 18 - 14 / 4 = 4 / 4 = 1

Therefore the value of Cohen's d = 1

Answer:

positively skewed to the right

Step-by-step explanation:

The measure of the central tendency is a profound way to describe the mean, median and mode. The measure of central tendency indicates where the center of distribution tends to be. The measure of central tendency provide a validity and answers whether the scores are high or generally low.

In this measure,The mean is usually pulled to the tail. The skewed is determined by where the tail goes, to the right side , it is positively skewed  and to the left side , it is known as negatively skewed distribution.

Given that:

In a frequency of distribution of 290 scores,

the mean  = 99

the median = 86

One would expect this distribution to be; positively skewed to the right  since the mean value is greater than the median value.

Answer:

The correct option is (d).

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired-samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

We use the paired t-test if we have 2 measurements on the same item, person or thing. We should also use this test if we have 2 items that are being measured with a unique condition.

For instance, an experimenter tests the effect of a medicine on a group of patients before and after giving the doses.

In this case, the same participants are selected for both the trials.

And the difference between the endurance before and after the usage of the new sports drink are noted.

Thus, the analysis that would be used on the data is the Dependent samples t-test.

Answer:

c

Step-by-step explanation:

c. a descriptive technique

Answer:

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Step-by-step explanation:

We formulate the null and alternative hypotheses as

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

For a two tailed test the significance level ∝= 0.1 the critical region is given by

t ≤ t ( ∝/2) (n-1) and t > t ( ∝/2) (n-1)

So the critical region will be

t≤ t ( ∝/2) (n-1) =2.353

where

t= x` - u / s/ √n

Sr. No X X²

1 150 22500

2 150 22500

3 180 32400

4 170 28900

∑ 650 106,300

X`= ∑x/n = 650/4= 162.5

s²= 1/n-1 (x-x`)²= 1/n-1 [ ∑x² -(∑x)²/n ]

= 1/3[106,300 -650²/4] = 225

s= 15

Putting the values in the above equation

t= 162.5- 140/ 15/ √4

t= 3

So calculated value of t= 3

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. a 90% confidence interval based on the calculated values will be

x`± 1.645 (s)/ √n

Putting the values

162.5 ±1.645 ( 15/2)

162.5 ±12.3375

174.84 , 150.163

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Answer:

  145 degrees

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary.

  d2 = 180° -d1 = 180° -35°

  d2 = 145°

Answer:

C

Step-by-step explanation:

An arithmetic sequence has a common difference d between consecutive terms.

Sequence a

30 - 10 = 20

90 - 30 = 60

270 - 90 = 180

This sequence is not arithmetic

Sequence b

200 - 100 = 100

300 - 200 = 100

400 - 300 = 100

This sequence is arithmetic but is finite, that is last term is 400

Sequence c

300 - 150 = 150

450 - 300 = 150

600 - 450 = 150

This sequence is arithmetic and infinite, indicated by ........ within set

Sequence d

2 - 1 = 1

4 - 2 = 2

8 - 4 = 4

This sequence is not arithmetic

Thus the infinite arithmetic sequence is sequence c