Yall pls help me out
Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.


L / T


No dimensions


M L / T^2


M


M / (L T^2)

Answers

Answer 1

Answer:

M·L/T²

Explanation:

The given equation for T is presented as follows;

[tex]T = \dfrac{M \cdot V^2 \cdot A}{L^3}[/tex]

Where;

m = Mass with dimension M

V = Velocity, having the dimensions L/T

A = Area, having the dimensions L²

l = Length, having the dimensions, L

Therefore;

[tex]The \ dimensions \ of \ T = \dfrac{M \times (L/T)^2 \cdot L^2}{L^3} = \dfrac{M \times L^4/T^2 }{L^3} = M \cdot L/T^2[/tex]


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In industrial and commercial installations, where large motors are often found, how is it necessary to power each motor? Using DC, Using AC, with a separate circuit, all on the same circuit

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In industrial and commercial installations, where large motors are often found, it is necessary to power each motor by: B. using AC.

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Answers

Answer:

The answer of this question is 19.89142857

Answer:

The number 222 is called the numerator or dividend, and the number 11 is called the denominator or divisor.

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Explanation:

Represent each of the following units as a combination of primitive
dimensions where M=mass, L=length, T=time

PLS show work

Watt

Newton

Horsepower

Answers

Some important and basic points:

Unit of time is second (s).

Unit of mass is kilogram (kg).

Unit of distance/displacement is meter (m).

P.S. Displacement and distance are nearly same things, their unit is same.

Speed/velocity = distance/time

So, its unit is m/s.

Acceleration = (final velocity-initial velocity)/time.

So, its unit is m/s² or m.s^-2

We know from the formula that,

Force = mass × acceleration

=> F = ma

Putting units:

Newton = kg.m/s² or kg.m.s^-2 _____(1)

Putting dimensions:

Newton = M.L.T^-2

________________________

We know from the formula that,

Work = force × displacement

=> W = Fs

Putting units:

Joule = Newton.m

=> Joule = kg.m.s^-2.m [from (1)]

=> Joule = kg.m².s^-2 ______(2)

Putting dimensions:

Joule = M.L².T^-2

________________________

We know from the formula that,

Power = work/time

Putting units:

Watt = joule/s

=> Watt = kg.m².s^-2/s [from (2)]

=> Watt = kg.m².s^-3 ______(3)

Putting dimensions:

Watt = M.L².T^-3

________________________

We know from the formula that,

Horsepower = 746 watt

=> Horsepower = 746kg.m².s^-3 [from (3)]

Putting dimensions:

Horsepower = 746M.L².T^-3

Hope it helps!!

The dimension of Watt, Newton and horsepower are ML²T⁻³, MLT⁻² and ML²T⁻³ respectively

Units and dimension

Units are measure of a quantity. Dimensions are derived from the units. Gi

Force = mass × acceleration

For Newton:

Another representation for unit of Newton is  kg.m/s². Writing in terms of the dimension

Newton = MLT⁻²

For Watts;

The unit of Watt is also kg.m².s⁻²/s which is equivalent to  kg.m².s⁻³

In terms of dimension

Dimension of Watt = ML²T⁻³

For Horse power:

The unit of horse power is  kg.m².s⁻³

Dimension of horsepower = ML²T⁻³

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Exam Guidelines
Exam Instructions
Question 8 of 15 :
Select the best answer for the question.
8. You've been contracted to install hardwood flooring on a basketball court. The court
measures 125' x 70'. How many square feet of flooring do you need to order for the job?
Allow 20% for waste.
k
O A. 10,500 sq. ft.
O B.234 sq. ft.
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Answers

Answer:

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Answer:

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Answers

Answer:

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Explanation:

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Pls help me, I really need to understand this
Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.


No dimensions


M


M / (L T^2)


L / T


M L / T^2

Answers

Answer:

ML/T^2

this is the correct answer

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PLS HELP
Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.



L / T



No dimensions



M L / T^2



M



M / (L T^2)

Answers

Answer:

T=kg·m^2/s^2

Explanation:

T = kg (m^2/s^2) m^3 /m^3

Here I wrote down the unit for every dimension.

T=kg m^2 / s^2

m^3 is divided between m^3, this is equal to 1.

Result: T=kg·m^2/s^2

PD: I'm not sure if this is what you ask for. I hope it helps

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Determine the dimensions for R if R = m V / (d^2 Q) where m is a mass, V is a velocity, d is a diameter, and the dimensions of Q are M/(LT).


No dimensions


M / (L T^2)


M L / T^2


M


L / T

Answers

Answer:

No dimension

Explanation:

The given equation is [tex]R = \dfrac{m \cdot V}{d^2 \cdot Q}[/tex], where;

m = Mass

V = Velocity

d = A diameter

The dimension of mass quantity = M

The dimension of the velocity quantity = L/T

The dimension of the dimeter quantity = L

The given dimension of Q = M/(L·T)

Therefore, we get;

[tex]The \ dimension \ of \ R = \dfrac{M \times L/T}{L^2 \times (M/LT)} = \dfrac{M \times L/T}{L \times M/T} = 1[/tex]

Therefore, R has no dimensions

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Pls help me Extra points
Represent each of the following units as a combination of primitive
dimensions where M=mass, L=length, T=time

Kilometer

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Pascal

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Newton

Horsepower

Answers

Kilometer = 1000m

Quart = 0.000946m³

Force = mass × acceleration

=> F = ma

Putting units:

Newton = kg.m/s² or kg.m.s^-2 _____(1)

Pressure = force/area

Putting units:

Pascal = Newton/m²

=> Pascal = kg.m.s^-2.m² [from (1)]

=> Pascal = kg.m^-1.s^-2

Work = force × displacement

=> W = Fs

Putting units:

Joule = Newton.m

=> Joule = kg.m.s^-2.m [from (1)]

=> Joule = kg.m².s^-2 ______(2)

Power = work/time

Putting units:

Watt = joule/s

=> Watt = kg.m².s^-2/s [from (2)]

=> Watt = kg.m².s^-3 ______(3)

Horsepower = 746 watt

=> Horsepower = 746kg.m².s^-3 [from (3)]

Hope it helps!!

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Answer:

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