YES I AM GIVING A BRAINLST

YES I AM GIVING A BRAINLST

Answers

Answer 1

Answer:

it's the third one!

Step-by-step explanation:

ur welcome :)

Answer 2
Thanks for giving out brainlist

Related Questions

if y varies inversely as n and m = 8 when n = 3 find m whenn =12

Answers

Answer:

24

Step-by-step explanation:

m=8x4 n=3x4 so that is the answer

the perimeter of this triangle is 46cm find x​

Answers

Answer:

the value of x is 12

......

Juan envasa 60 bombones en cajas iguales y otros 60 en otras cajas más pequeñas, con cinco bombones menos en cada una. ¿Cuántas cajas ha llenado, si de las pequeñas hay una más que de las grandes?

Answers

Juan llenó 3 cajas grandes y 4 cajas pequeñas.

En esta pregunta debemos derivar ecuaciones algebraicas a partir de la información dada en el enunciado:

Diferencia entre cajas grandes y cajas pequeñas

[tex]m - n = 1[/tex] (1)

Donde:

[tex]m[/tex] - Cantidad de cajas pequeñas.[tex]n[/tex] - Cantidad de cajas grandes.

Diferencia entre la cantidad de bombones en una caja grande y la cantidad de bombones en una caja pequeña

[tex]x-y = 5[/tex] (2)

Donde:

[tex]x[/tex] - Cantidad de bombones en una caja grande.[tex]y[/tex] - Cantidad de bombones en una caja pequeña.

Total de bombones en cajas grandes

[tex]x\cdot m = 60[/tex] (3)

Total de bombones en cajas pequeñas

[tex]y\cdot n = 60[/tex] (4)

By (3) and (4) in (2):

[tex]\frac{60}{m} - \frac{60}{n} = 5[/tex]

[tex]60\cdot n - 60\cdot m = 5\cdot m\cdot n[/tex] (5)

By (1):

[tex]m = 1 + n[/tex]

(1) in (5):

[tex]60\cdot n - 60\cdot (1+n) = 5\cdot (1+n)\cdot n[/tex]

[tex]60 = 5\cdot n +5\cdot n^{2}[/tex]

[tex]5\cdot n^{2}+5\cdot n -60 = 0[/tex]

[tex]n^{2}+n-12 = 0[/tex]

[tex](n+4)\cdot (n-3) = 0[/tex]

La única raíz que encaja con el enunciado es [tex]n = 3[/tex]. Por (1) tenemos que [tex]m = 4[/tex].

Juan llenó 3 cajas grandes y 4 cajas pequeñas.

Invitamos cordialmente a ver este problema sobre sistemas de ecuaciones: https://brainly.com/question/12149981

Solve for x x^2 + 6x + 1 = 0

Answers

Answer:

x = -.1715 ≈ - .172    or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square   Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9  = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

[tex]\sqrt{(x + 3)^{2}[/tex]  = [tex]\sqrt{8}[/tex]

 x + 3 = ±  [tex]\sqrt{8}[/tex]

  x = -3 ± [tex]\sqrt{8}[/tex]

   x = -3 + [tex]\sqrt{8}[/tex]   or x = -3 - [tex]\sqrt{8}[/tex]

   x = -.1715 ≈ - .172    or x = -5.83

Please helppppppppppppp

Answers

Answer:

101

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

Suplemetary angles

180-79=101

1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)

Answers

Answer:

a

Step-by-step explanation:

write a peacewise function for the graph
please help me

Answers

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

Name 2 of the same side interior angle.

Answers

Answer:

d & e

Step-by-step explanation:

I'm assuming  by "same side interior angle" they mean consecutive interior angles. I'll attach a document explaining what that is.

Which best describes the error in finding the area of the parallelogram?


15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.

8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.

The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.

The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.

Question 2
Correct the error.

A=

=
m2

Answers

Answer:

104

Step-by-step explanation:

Write the equation for 5x + 2y = 3 in slope-intercept form..

Answers

Answer:

[tex]y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Step-by-step explanation:

[tex]5x+2y=3\\\\2y=-5x+3\\\\y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Answer:

Step-by-step explanation:

Slope-intercept from: y = mx + b

5x + 2y = 3

       2y = -5x + 3

Divide the whole equation by 2

[tex]\dfrac{2y}{2}=\dfrac{-5x}{2}+\dfrac{3}{2}\\\\y=\dfrac{-5}{2}x +\dfrac{3}{2}[/tex]

Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12

Answers

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

solve pls brainliest

Answers

Answer:

first put 2 in the numerator for the first blank and 2/9 in the second blank

Step-by-step explanation:

1/3 equals 3/9 and 3/9-1/9=2/9

Answer:

[tex]\frac{3}{9}[/tex]

Step-by-step explanation:

What is the constant of proportionality for the data in the table?

Answers

Answer:

30

Step-by-step explanation:

50 POINTS PLS HELP ME I'LL MARK BRAINLIEST

Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)


x = −3, 8; n = 3



Thank you so much!!

Answers

Answer:

Step-by-step explanation:

Here we need to find a 3rd degree polynomial that has only two distinct zeros:  {-3, 8}.  

Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:

f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)

One such polynomial is thus

f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient.  This polynomial has a double zero at x = 8 and a third zero at x = -3.

Step-by-step explanation:

The polynomial has degree 3 and two zeros: - 3 and 8.

Since it has degree 3 it should have 3 zero's.

Two possible scenarios

1. -3 has multiplicity of two:

a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant

2. 8 has multiplicity of two:

a(x + 3)(x - 8)² - is the factored form of the polynomial

find the value of 4x-6y when x=3 and y= -2

Answers

Answer:

here the answer is 24

Step-by-step explanation:

answerrrrrerrr issss hereeeeeee

Answer:

0

Step-by-step explanation:

4 multiply by x(3) = 12

6 multiply by y(2) = 12

12 -12 =0

The diameter of the rear tire of a bike is 34 inches. In low gear, you need to rotate the pedals 3 times to make the rear tire rotate 360° all the way around. How far will you travel in low gear each time you rotate the pedals? (Hint: find the circumference of the tire, then divide it by the number of rotations needed of the pedals.) Round the answer to the nearest hundredth. *
PLEASE DO NOT PUT INAPPROPIATE CONTENT!!!

Answers

34pi/3 ……………………………………..

Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)

Answers

y=8x+14

0-(-8)/-1-(-2)= 8/1 =8
8=m

-2=2(-8)+b
-2=-16+b
+16 +16
14=b

Write 2.04 × 10 ⁴ as an ordinary number

Answers

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84​

Answers

Answer:

4x - 12 = 84

Step-by-step explanation:

The last answer choice is correct because when you cross-multiply:

[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]

you get 4x - 12 = 84.

Therefore, the last option is correct.

Answer:

D would be the answer (4x-12=84)

Step-by-step explanation:

4/7=12/x-3

=>1/7=3/x-3

=>x-3=21

Multiplying both sides by 4

4(x-3)=4x21

=>4x-12=84

Hope this helped :)

- Rectangle MNOP with vertices M(-7.-2).
M(-5, -1), 0(-27), and P(-4,-8):
90° counterclockwise about the origin

Answers

Answer:

M’ = (2, -7)

N’ = (1, -5)

O’ = (7, - 2)

P’ = (8,- 4)

Step-by-step explanation:

Swap the x and y coordinates and negate the y coordinate.

M(-7, -2) swap = (- - 2, -7) = (2,-7)

N(-5, - 1) swap = (- - 1, - 5) = (1, - 5)

O(-2,-7) swap = (- -7, -2) = (7, - 2)

P(-4,-8) swap = (- - 8, - 4) = (8, - 4)

A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST

Answers

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J

Write two Pythagorean triplets each having one of the numbers as 5.

Answers

Answer:

3, 4, 5 and 5, 12, 13

Step-by-step explanation:

The square of the largest side is equal to the sum of the squares of the other 2 sides.

5² = 3² + 4²

13² = 5² + 12²

The 2 triplets are (3, 4, 5 ) and (5, 12, 13)

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Prove that ~

[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]


by using first principle of differentiation ~​

Answers

Answer:

METHOD I:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

Substituting these in eqn. (i)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

sec x can be written as 1/ cos(x)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

Taking LCM

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

By Cosines sum to product formula, i.e.,

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

2/ h can also be written as 1/(h/ 2)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

We have limₓ→₀ (sin x) / x = 1.

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

h→0 means h/ 2→0

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

METHOD II:

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

sec x can also  be written as (cos x)⁻¹

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

Any base with negative exponent is equal to its reciprocal with same positive exponent

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

The inner function that remains is cos x whose derivative is -sin x.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

cos²x can also be written as (cos x).(cos x)

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

sin x/ cos x is tan x, while 1/ cos x is sec x

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Hence, Proved!

Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =​

Answers

Step-by-step explanation:

f(x) = -3x - 8

f(-3) = -3(-3) - 8

f(-3) = 9 - 8

f(-3) = 1

A person in car, travelling at 90 kilometers per hour, takes 2 seconds to go past the building on the side of the road. Calculate the length of the building in meters help

Answers

Step-by-step explanation:

very simple thought experiment :

he is going 90 km/h (90 kilometers per hour), so, he moving 90 km in 1 hour.

how far is he going in just 2 seconds ?

so, we get two ratios.

90km/1 hour = 90,000 meter / 1 hour

x meter / 2 seconds

we need to bring both ratios (they are fractions) to the same dimension of the denominators, so that we can then bring them to the same denominator.

the first is dealing with an hour.

the second one with (2) seconds.

so, how many seconds are in 1 hour ?

60 seconds per minute, 60 minutes in the hour.

60×60 = 3600 seconds.

so, now we know, the first ratio is also

90,000 meter / 3600 seconds

now we need the factor to to multiply numerator and denominator with to bring 3600 down to 2.

3600 × f = 2

f = 2/3600 = 1/1800

now we get

90,000 / 3600 × (1/1800) / (1/1800) =

(90000 / 1800) / (3600 / 1800) = 50 / 2

so, 90km/h is the same speed as 50 meter / 2 seconds.

and therefore we know, the building was 50 meters long.

find the value of x. only type the “number”

Answers

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

Please help xxxxxxxx

Answers

Answer:

a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]

Step-by-step explanation:

a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]

[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]

[tex]=45000\times \:10^7[/tex]

b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]

[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]

[tex]\frac{10^5}{10^2} = 10^3[/tex]

[tex]\frac{7\times \:10^3}{2}[/tex]

[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]

[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]

[tex]\frac{2^3}{2}=2^2[/tex]

[tex]7\times \:2^2\times \:5^3=3500[/tex]

If we convert 0.14 x10^3 to scientific notation, which direction should the

decimal move and how spaces should it move?

Answers

Answer:

Move it to the right by 3 spaces.

Step-by-step explanation:

10^3 is 1000

On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140

help!! !,
is it right or not ​

Answers

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

Yep!!! Your correct

1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5

Answers

-3x-8=-14 Answer: x=2
4x-6=14 Answer x=5
-3-3x=-30 Answer x=9
-5x+5=5 Answer x=0

Answer:

1.) x = 2

2.) x = 5

3.) x = 9

4.) x = 0

Step-by-step explanation:

1.) -3x - 8 = -14

-3x = -6

x = 2

2.) 4x - 6 = 14

4x = 20

x = 5

3.) -3 - 3x = -30

-3x = -27

x = 9

4.) -5x + 5 = 5

-5x = 0

x = 0

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