4ml of NaOH is required for neutralization of KHP.
The chemical reaction is as follows:
NaOH + КНР → NaKP + H₂O
The mass of KHP used is 0.1509g, Molar mass of KHP is 204.29g/mol
Then moles of KHP used are given by
Moles of KHP used = 0.1509/204.29
Moles of KHP = 7.35 x 10⁻⁴ moles
The molarity of NaOH is 0.2 M Let the volume of NaOH required for neutralization be V.
Moles of NaOH needed = Molarity x volume of NaOH (L)
= 0.2 x V
As 1 mole of NaOH requires 1 mole of KHP, then
Moles of NaOH required = Molarity of NaOH x volume of NaOH (L)
On substituting the values we get,
0.2 V = 7.35×10⁻⁴
V = 7.35x10⁻⁴/0.2
= 3.675 X 10⁻³L
V = 3.675 mL
≈ 4mL
Therefore, 4 ml of NaOH is required for neutralization.
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Write a balanced half-reaction for the reduction of nitrate ion to gaseous nitrogen dioxide in acidic aqueous solution. Be sure to add physical state symbols where appropriate.
To determine the number of atoms of each element we need to multiply stoichiometry that is written in front of the molecule to the number that is written on the foot of the element. Hence, the balanced chemical equation for the reduction of nitrate ion to gaseous nitrogen dioxide in acidic aqueous solution is NO₂ (g) + H₂O (l) → NO³⁻ (aq) + 2H⁺ + e⁻.
Balanced chemical equation
Balanced equation is defined as the reaction where the number of atoms of each species is same on reactant and product side. In balanced equation mass can neither be destroyed nor be created.
The skeletal equation can be written as:
NO₂ (g) + H₂O (l) → NO³⁻ (aq) + 2H⁺ + e⁻.
The number atoms of N on reactant and product side is 1 so N is balanced.
The number of atoms of H is 2 on reactant and on product side it is 2. So, H is balanced.
The number of atoms of O is 3 on reactant and on product side it is 3. So, O is balanced.
Hence, the balanced chemical equation for the reduction of nitrate ion to gaseous nitrogen dioxide in acidic aqueous solution is:
NO₂ (g) + H₂O (l) → NO³⁻ (aq) + 2H⁺ + e⁻
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Consider the buffer system of hydrofluoric acid, HF, and its salt, NaF. HF(aq)+H2O(l)?H3O+(aq)+F?(aq) 1) The purpose of this buffer system is to: a) maintain [HF] b) maintain [F?] c) maintain pH 2) If OH? is added, it is neutralized by: a) the salt b) H2O c) H3O+
Buffer is a solution used to stabilize the pH (acidity) of a liquid.
A buffer system in chemistry is a type of solution that is able to resist changes in its pH when small amounts of an acidic or basic substance is added to it.
Many chemical reactions are carried out at a constant pH. In nature, there are many systems that use buffering for pH regulation
According to this question, a buffer system of hydrofluoric acid, HF, and its salt is given. The purpose of the buffer system is to stabilise the pH of the hydrofluoric acid solution.
Also, hydroxide ion (OH) can be added to the solution to neutralise the acid content of the solution as characterized by the presence of hydronium ions (H₃O⁺).
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If the reaction of 150. G of ammonia with 150. G of oxygen gas yields 87. G of nitric oxide (no), what is the percent yield of this reaction?.
The percentage yield of the given reaction is 77.33%.
What is percentage yield?
Reactants frequently produce fewer product quantities than predicted by the chemical reaction's formula. The percentage of a theoretical yield that's been produced in a reaction is calculated using the percent yield formula. Working through a stoichiometry problem yields the theoretical yield, which is the ideal quantity of the final product. The actual yield is determined by calculating the volume of the product formed. We can determine the percentage yield by dividing the actual yield by the theoretical yield.
Moles is calculated by using the formula:
Moles of Ammonia:
Given mass of ammonia = 150g
Molar mass of ammonia = 17 g/mol
Putting values in above equation, we get:
Moles of Oxygen
Given mass of oxygen = 150g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:
For the given chemical equation:
By Stoichiometry,
5 moles of oxygen reacts with 4 moles of ammonia.
So, 4.6875 moles of oxygen will react with = of ammonia
As, moles of ammonia required is less than the calculated moles. Hence, ammonia is present in excess and is termed as excess reagent.
Therefore, oxygen is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the given reaction:
5 moles of oxygen gas produces 4 moles of nitric oxide
So, 4.6875 moles of oxygen gas will produce = of nitric oxide
Now, to calculate the theoretical amount of nitric oxide, we use equation 1: Molar mass of nitric oxide = 30 g/mol
Given mass of nitric oxide = 112.5 g
Now, to calculate the percentage yield, we use the formula:
Experimental yield = 87 g
Theoretical yield = 112.5 g
Putting values in above equation, we get:
Hence, the percentage yield of the given reaction is 77.33%.
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suppose 7.26 g of ammonium chloride is dissolved in 150. ml of a 0.50 mm aqueous solution of potassium carbonate.
Mass of ammonium chloride (NH4Cl) = 11.4 grams
Volume of 0.3 M aqueous solution of potassium carbonate (K2CO3) = 250 mL = 0.250L
Step 2: The balanced equation
2NH4Cl + K2CO3 → 2KCl + (NH4)2CO3
Step 3: Calculate moles of (NH4)Cl
moles (NH4)Cl = 11.4 grams /53.49 g/mol
Moles (NH4)Cl = 0.213 moles
Step 4: Calculate moles of K2CO3
Moles K2CO3 = Molarity * Volume
Moles K2CO3 = 0.3M * 0.250 L = 0.075 moles
Step 5: Calculate moles (NH4)Cl at the equilibrium
For 2 moles (NH4)Cl consumed, we need 1 mole of K2CO3 to produce 2 KCl and 1 mole of (NH4)2CO3
(NH4)2CO3l will dissolve in 2NH4+ + CO32-
Moles (NH4)2Cl = 0.213 moles - 2*0.075 = 0.063 moles
Moles NH4+ = moles (NH4)Cl = 0.063 moles
Step 6: Calculate Molarity of NH4+
Molarity = Moles / volume
Molarity of NH4+ = 0.063 moles / 0.250 L
Molarity of NH4+ = 0.252 M
Therefore, the molarity of the final ammonium cation is 0.252M
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nh2ch2co2h lewis structure
The Lewis structure of the compound is shown in the image attached to this answer.
What is Lewis structure?We know that the Lewis structure shows us what a compound looks like. The two parts of the Lewis structure would include the symbol of the element as well as the electron dots that can be used to show the number of valence electrons. This is why we call the Lewis structire the Lewis dot structure of a compound.
We can see that the compound here has an amine group as well as a carboxylic group and the Lewis structure would tell us the number of electron pairs that we have on the valence shell of each of the atoms.
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item 3 select the representation(s) for the solution that results when dimethyl ether is dissolved in water
When dimethyl ether is dissolved in water results in,
CH₃OCH₃(aq)(g) + H2O(l) ⇌ CH₃OCH₃(aq)
What is Dimethyl ether?
Dimethyl ether (also known as DME) is a colorless, flammable gas with a faint, ether-like odor. It is the simplest ether, a derivative of methane, and is a promising alternative fuel for diesel engines. It is produced from the reaction of methanol and hydrogen or by steam reforming of natural gas.
What are Ethers?
Ethers are organic compounds containing an oxygen atom connected to two alkyl or aryl groups. Generally, ethers are colorless and have low boiling points, making them volatile. Ethers are widely used in the production of pharmaceuticals, fragrances, and other chemicals.
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Produces pyruvate. The multienzyme complex catalyzes the oxidative of pyruvate to yield carbon dioxide and acetyl coa. The overall equation for the reaction is acetyl coa is the main form in which carbon compounds enter the.
Pyruvate is produced by the reaction of a glycolysis. The multienzyme complex catalyzes the oxidative of pyruvate to yield carbon dioxide and acetyl coa. Its reaction is given as
Pyruvate+CoA+NAD⁺→acetyl CoA+NADH+H⁺+CO₂
Acetyl CoA→Citric acid cycle
Glycolysis process is defined as the conversion of a glucose(C₆H₁₂O₆) into the pyruvate(CH₃COCO₂H). In the glycolysis reaction, high energy ATP molecules and reduced nicotinamide adenine dinucleotide is created. The series of ten enzyme-catalyzed process makes up glycolysis.
One of the metabolic route which does not require is glycolysis(In anaerobic conditon, pyruvate is converted to lactic acid). It is occurred in various species, which tells us that it is old metabolic route.
Therefore, the glycolysis reaction produces pyruvate and its complete reaction is
Pyruvate+CoA+NAD⁺→acetyl CoA+NADH+H⁺+CO₂
Acetyl CoA→Citric acid cycle
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B. The Lewis diagram for AsO2 is: :0-as=0 Recall that for predicting geometry, double and triple bonds count as only one electron pair region. The electron-pair geometry around the As atom in AsO2 is trigonal plantar There are unshared pair(s) around the central atom, so the geometry of the AsO2 molecule is bent
The Lewis structure of the arsenite is shown in the image attached.
What is the Lewis structure?We know that the Lewis structure of a compound can help us to be able to see the way that there can be a good arrangement of the atoms that we have in the compound.
There are two parts of the Lewis structure and they are;
-The symbol of the element
-The electrons in the elements shown as dots
For the arsenite, we can see tat we have one atom of arsenic and then we have two atoms of oxygen in the Lewis structure of the compound. The compound is linear in molecular geometry but the electron domain geometry is trigonal planar.
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If 3.45 l of a 0.35 m h3po4 to be diluted to a volume of 10.00 l, what is the concentration of the resulting solution
When 3.45 L of a 0.35 M H₃PO₄ to be diluted to a volume of 10.00 L, The concentration of H₃PO₄ resulted is 0.1207 M
The concentration of H₃PO₄ can be calculated as follows:
Dilution is the process of reducing the concentration of a solute in solution, usually by simply mixing the solute with more solvent by adding water to the solution.
The formula (M1V1=M2V2) represents the dilution formula in chemistry.
M1V1=M2V2
3.45 L x 0.35 M = M2 X 10.00 L
M2 = 3.45 L x 0.35 M
10.00 L
M2 = 0.1207 M
Therefore, when 3.45 L of a 0.35 M H₃PO₄ to be diluted to a volume of 10.00 L, The concentration of H₃PO₄ resulted is 0.1207 M
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The ideal gas law is represented by pv=nrt . as volume is held constant and the temperature increases, how would the pressure be expected to change?
If in a gas the volume is held constant and the temperature increases, pressure exerted by the gas also increases.
Ideal gas law
The gas law which relates the macroscopic properties of ideal gases is known as ideal gas law. A gas is known as an ideal gas when its particles (a) do not attract or repel one another and (b) take up no space (have no volume). The ideal gas law equation is given as the following,
(PV = nRT)
Where,
P is pressure
V is volume
R is the universal gas constant
T is the temperature and
n is the number of moles
As we can see from the equation that T is directly proportional to P so when V is kept constant and T increases P also increases.
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larry made this picture to represent a chemical reaction: there are two circles on the left, one white and the other gray, and there is a plus sign between them. the white circle is labeled x and the gray circle is labeled y. an arrow pointing right is shown on the right of the circles. two circles, one white and the other gray are shown on the right. a small portion of the two circles overlap and the label below the circles is xy. which of the following statements best explains the type of chemical reaction represented by larry's picture? it represents a synthesis reaction because two reactants form one product. it represents a synthesis reaction because the total mass of the product is less than the mass of the reactants. it represents a decomposition reaction because one reactant breaks apart and forms two products. it represents a decomposition reaction because the same atoms are present in the reactants and products.
The statement which best represents chemical change carried out by Larry is that it represents a synthesis reaction because two reactants form one product.
Chemical changes are defined as changes that occur when a substance combines with another substance to form a new substance.Alternatively, when a substance decomposes or breaks down to give new substances which is also considered to be a chemical change.
There are several characteristics of chemical changes like change in state, change in color , change in composition and change in odor . During chemical change there is even formation of precipitate which is an insoluble mass of substance or even evolution of gases.
As two reactants are combining to form a product it represents a synthesis reaction.
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Insoluble sulfide compounds are generally black in color. which of the following combinations could yield a black precipitate?
a.Na2S(aq)+KCl(aq)
b.Li2S(aq)+Pb(NO3)2(aq)
c.Pb(CIO3)2(aq)+NaNO3(aq)
d.AgNO3(aq)+KCl(aq)
e.K2S(aq)+Sn(NO3)4(aq)
Answer:
the answer for the question is B and E
Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.
We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").
The first two electrons contribute to bonding. The next two are anti-bonding.
The next six contribute to bonding, and the following six are anti-bonding.
So, if we start with CN+, which has 4+5-1 (8) valence electrons, we note that the first two electrons contribute to bonding, while the next two cancel this out; the next four contribute to bonding, so the bond order is 4/2 = 2.
If we add one more electron to get CN, there are now 5 bonding electrons, giving bond order 5/2=2.5.
Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)
Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:
CN+ < CN < CN-
Lewis structures will verify that CN- has a triple bond, but they do not work particularly well for CN+ and CN.
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Produces pyruvate. The multienzyme complex catalyzes the oxidative of pyruvate to yield carbon dioxide and acetyl coa. The overall equation for the reaction is acetyl coa is the main form in which carbon compounds enter the.
The Glycolysis produces pyruvate.
What is pyruvate?
Pyruvate is a three-carbon molecule which is the end product of glycolysis, the first step in the breakdown of glucose for energy. It is also the starting point for the Krebs cycle, the second stage of cellular respiration. Pyruvate is formed from the cleavage of the six-carbon sugar molecule, glucose, and is then further oxidized to form acetyl-CoA and enter the Krebs cycle. The enzymes responsible for pyruvate production are known as pyruvate kinases and are found in most eukaryotic cells. Pyruvate is an important molecule in the production of energy within the cell, as it acts as both a source of energy and a precursor to other metabolic pathways. Additionally, pyruvate is involved in the synthesis of fatty acids, amino acids, and other biomolecules. Pyruvate is also used in the fermentation process to produce lactic acid and ethanol.
The pyruvate dehydrogenase (PDH) enzyme is part of the multienzyme PDC, which catalyzes the physiologically irreversible decarboxylation of pyruvate to acetyl-CoA and is often referred to as a 'gatekeeper' in the oxidation of carbohydrate.
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which one of the equation pairs illustrates a favorable energetic coupling in a cell? (i.e. one reaction releases sufficient energy to drive the other to completion). select all that apply.
Equations 1 & 2, Equations 2&3, and Equations 1&3 illustrate a favorable energetic coupling in a cell.
What is the non-spontaneous reaction?
A nonspontaneous reaction is one that under the specified conditions, does not favour the formation of products. A reaction needs to be endothermic, accompanied by the a drop in entropy, or both to qualify as nonspontaneous. The majority of the gases that make up our atmosphere are a combination of nitrogen and oxygen.
If G is positive, the reaction is not spontaneous and will need external energy. The reaction seems to be spontaneous and will happen on its own if G is negative.
Coupling of reactions-
Equations 1 and 2-
∆G1=-7kcal/mol, ∆G2=-14.8kcal/mol
∆G total= -21.8kcal/mol( favourable reaction)
Equation 2&3-
∆G2=-14.8kcal/mol, ∆G3=+3.3kcal/mol
∆G total=-11.5kcal/mol(favourable)
Equations 3 and 4-
∆G3=+3.3kcal/mol, ∆G4= +7kcal/mol
∆G total=+10.3kcal/mol(unfavorable)
Equations 1 and 4-
∆G1=-7kcal/mol, ∆G4=+7kcal/mol
∆G total= 0(reaction will be in equilibrium)
Equations 1 and 3-
∆G total=(-7+3.3)kcal/mol
=-4.3 kcal/mol(favorable)
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what is cation and anion for
CrS2
The cations and anions are ions. They possess opposite electrical charge, so they get attracted to each other. Here the cation of the compound is Cr²⁺ whereas the anion is S²⁻.
What are cations and anions?A cation can be defined as the atom or molecule which is positively charged and an anion can be defined as the atom or molecule which is negatively charged. All the cations are found to be metal and the anions are non-metal.
The cation repels other cation whereas the anion repels another anion. The number of protons is more than the number of electrons in a cation whereas the number of electrons is more than the number of protons in an anion.
Here in the given compound CrS₂, the positively charged ion is Cr²⁺ which is the cation and the negatively charged ion is S²⁻ which is the anion.
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any of the series of unsaturated hydrocarbons containing a double bond, including ethylene and propylene
Any of the series of unsaturated hydrocarbons containing a double bond, including ethylene and propylene are called Alkenes.
What are Unsaturated Hydrocarbons?
Unsaturated hydrocarbons are organic compounds that contain one or more double or triple bonds between carbon atoms. They are also known as alkenes or alkynes depending on the number of double bonds present. Examples of unsaturated hydrocarbons include ethene (C2H4), propene (C3H6) and butadiene (C4H6).
Define Alkenes?
Alkenes are a class of hydrocarbons that contain a carbon-carbon double bond. They are also known as olefins or unsaturated hydrocarbons. Alkenes are used in the production of polymers, fuels, lubricants, and solvents.
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hi
i need help with this
The dissociation equations are shown as;
a) [tex]HCl ------ > H^+ + Cl^-[/tex]
b) [tex]H C_{2} H_{3}O_{2} ---- > C_{2} H_{3}O_{2} ^- +H^+[/tex]
C) [tex]NH_{4} ----- > NH_{3} + H^+[/tex]
D) [tex]C_{6} H_{5} NH_{3} ^+ ------- > C_{6} H_{5} NH_{2} + H^+[/tex]
E) [tex][Al(H_{2} O)_6}] ^{3+} ------ > Al^{3+}[/tex]
What is dissociation?The term dissociation has to do with the procedure by which a substance can be broken up into its components. The components of a substance are those that have to come together so as to form the compound.
When the compound is to be broken up, the components that came together to make up the compound can broken up and then we have the original compounds tat we have at the start of the reaction. In this case, the decomposition equations have been shown with the exclusion of water.
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patterns of reactivity quick check
Reactivity decreases as you move from left to right. The farther to the left and down the periodic chart you move, easier it is for electrons to be given or taken away, hence resulting in higher reactivity.
What is the pattern of reactivity in periodic table?Reactivity decreases as we move down the column. As you learn more about the table, you will be able to find that this pattern is true for other families.
The atoms get bigger, as the atomic number increases. The chemical properties change slightly when compared to the element right above them on the table. The non-metal elements in Group 7 that are known as the halogens, get less reactive as you move to the down of the group.
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predict the major product for the reaction shown.
The product of the reaction is m-nitrobenzaldehyde, option B.
What is m-nitrobenzaldehyde?M-nitrobenzaldehyde, also known as meta-nitrobenzaldehyde is an organic aromatic compound that contains a nitro-group which is meta substituted to an aldehyde. It is soluble in water at 2.34 mg/ml and a temperature of 25° C. It is also soluble in ethanol, benzene and slightly in ether. M-nitrobenzaldehyde production process is prepared by nitration.
The carboxylic group is meta directing and has an ortho-para deactivating group therefore, during nitration of benzaldehyde, meta position gains an attachment from the nitro group forming m-nitrobenzaldehyde as product.
The full question is:
Predict the major product for the reaction shown.
a. o-cyanonitrobenzene & p-cyanonitrobenzene
b. m-nitrobenzaldehyde
c. o-cyanonitrobenzenesulphonic acid & p-cyanonitrobenzenesulphonic acid
d. m-cyanonitrobenzenesulphonic acid
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how might a natural disaster such as a forest fire affect the elements of the hydrosphere
Answer:
A fire could cause an increase in evaporation of water from surface water near the fire.
Explanation:
Answer:
Explanation:
Wildfires can compromise water quality both during active burning and for months and years after the fire has been extinguished. Burned watersheds are prone to increased flooding and erosion, which can negatively affect water-supply reservoirs, water quality, and drinking-water treatment processes.
Wildfires can have immediate and long term effects on rivers, lakes, and streams. After burning vegetation, the ground's soil becomes hydrophobic and is unable to absorb any water. This creates what is known as stormwater runoff. Stormwater runoff is rainflow that travels over the surface of the ground.
please give me brainiest.
How Many Carbonyl Groups Are Generated Upon Treatment Of The Molecule Below With Ozone, Followed By Zinc Metal And Water? A) 1 B) 2 C) 3 E) 8
The answer will be E if the query is correct. Following the treatment of the molecule below with ozone, zinc metal, and water, eight carbonyl groups are produced.
Exactly what is a carbonyl group?
A double bond connecting a carbonyl carbon atom and a carbonyl oxygen atom makes up a carbonyl group. Two of the six valence electrons that the carbonyl oxygen atom has are shared with the carbonyl carbon atom. Two sets of electron lone pairs make up the four valence electrons that are still present.
How many different kinds of carbonyl groups exist?
Aldehydes, ketones, carboxylic acids, acid chlorides, acid anhydrides, esters, lactones, amides, and lactams are examples of compounds that include carbonyl groups..
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FILL IN THE BLANK. a science teacher adds water to a strong acid for use in the lab with students. this makes the concentration___, because the amount of solute per volume of solvent
A science teacher adds water to a strong acid for use in the lab with students. this makes the concentration weaker, because the amount of solute per volume of solvent decreases.
What is meant by concentration of the solution?
There are two components in an aqueous solution: the solute and the solvent. You must be familiar with these two fundamental terminology for solution concentration. The amount of solute in the solution must always be recorded. The quantity of a solute in a solvent is what we refer to in chemistry as the concentration of a solution. We refer to a solution as being concentrated when there is more solute present. Conversely, we refer to a solution as being diluted when it contains more solvent.
There are various methods of expressing the concentration of a solution. You will usually see Chemists working with the number of moles. Pharmacists will use percentage concentrations instead of the number of moles.
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How does the rate of today's warming compare to previous episodes of
rapid climate change on Earth?
A. Today's climate warming is about as fast as the temperature swings that have
happened in Earth's past.
B. Past changes in the climate have been faster than the changes we're seeing today.
C. Today, the Earth's climate is changing much faster than it has changed in the past.
Answer:
B. Past changes in the climate have been faster than the changes we're seeing today
Explanation:
The Earth is warming abnormally quickly . Over the past century it has warmed roughly 10 times faster than the average increase in temperature after each ice age .
so the answer is B.Past changes in the climate have been faster than the changes we're seeing today.
A substance has a half-life of 2. 045 minutes. If the initial amount of the substance was 132. 8 grams, how many half-lives will have passed before the substance decays to 8. 3 grams? what is the total time of decay?.
The total time of decay is 8.18 min.
The half life is the time to takes a substance to decay. so, we half to find out the number of half lives that have passed for initial amount of 132.8 g.
number of half -lives amount of substances in g
0 132.8
1 66.4
2 33.2
3 16.6
4 8.3
so. it will take 4 half -lives for the substance to decay to 8.3 g.
the total time decay = 4 × 2.045 = 8.18 min.
Thus, A substance has a half-life of 2. 045 minutes. If the initial amount of the substance was 132. 8 grams, half - life will have passed before the substance decays to 8. 3 grams. the total time of decay is 8.18 min.
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predict the ordering, from shortest to longest, of the bond lengths in co, co2, and co2−3. but why does (CO3)2− have a longer bond length than CO2?
The bond length order becomes: CO < CO₂ < CO₃⁻².
What is bond order?The total amount of covalent bonds that two atoms have together. A single bond exists when two atoms share one pair of electrons (bond order = 1). Two pairs of electrons make up a double bond (bond order = 2), whereas three pairs of electrons form a triple bond (bond order = 3).
CO has triple bond.
CO₂ has double bond and
CO₃⁻² has a nature in between double and triple bond.
Thus, the bond length order becomes: CO < CO₂ < CO₃⁻².
As, we all know, bond order has an inverse relationship with bond length. That is, longer bonds are stronger bonds. CO has a bond order of 3 (triple bond), CO₂ has a bond order of 4 (two double bonds), and CO₃⁻² has a bond order of 1.33. ( bond nature between single and double bonds). That's why CO₃⁻² have a longer bond length than CO₂.
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what is the conjugate acid for ch3coo-
Answer:
The conjugate acid is CH3COOH
h3no lewis structure
Answer:
It is attached below.
Explanation:
The Lewis structure for H₃NO, also known as ammonia oxide or nitroxyl is given in the image.
Count the total number of valence electrons:
Hydrogen (H) has 1 valence electron.
Nitrogen (N) has 5 valence electrons.
Oxygen (O) has 6 valence electrons.
Total valence electrons = (3 × 1) + 5 + 6 = 14
Determine the central atom:
In this case, nitrogen (N) is the central atom, as it is less electronegative than oxygen (O) and hydrogen (H).
Connect the atoms with single bonds:
Place a single bond (represented by a line) between nitrogen (N) and each hydrogen (H). This accounts for 3 electrons.
Distribute the remaining electrons:
Place the remaining 11 electrons as lone pairs around the atoms to satisfy the octet rule. In this case, nitrogen (N) will have a lone pair, and oxygen (O) will have a lone pair.
Each line represents a single bond, and the lone pairs are represented by pairs of dots or dashes. The hydrogen atoms are bonded to the nitrogen atom, and the oxygen atom has a lone pair.
Hence, the Lewis structure is in the image.
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How would an increase in temperature affect evaporation?
F) it would end evaporation
G) it would speed up evaporation
H) it would slow down evaporation
J) temperature does not affect evaporation
Answer:
G) It would speed up evaporation.
Explanation:
As the temperature increases, the rate of evaporation also increases.
Write "true" or "false" for each statement. A mole of horses contain a mole of horse legs.
The given statement is false, as a mole of horses contain 4 mole of horse legs.
What is the conversion factor?The ratio of moles of molecules (or formula units) to moles of atoms can be used as a conversion factor. To create the conversion factor from this equation, write the magnitude on one side of the equal sign in the numerator of the fraction and the other magnitude on the denominator. Note that a second conversion factor can be created by interchanging the spelling of each quantity for the fraction bar. A conversion factor is an expression of the relationship between units used to change the units of a measured quantity without changing the value. The conversion factor (or unit factor) is always equal to 1, the numerator and denominator have the same value, and are expressed in different units.
Start with the number of horses in moles.
As every horse has has four legs. Use it as a conversion factor to convert the moles on the horse to the moles on the legs.
1 mol horse = 1 mol legs / 4 mol legs
1 mol horse × (4 mol legs / 1 mol legs) = 4 mol legs
4 mol legs ≠ 1 mol legs, so this is false.
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