Answer:
10 hours at job (1)
2 hours at job (2)
Step-by-step explanation:
As per the given information, one earns ($8) dollars at one of their jobs, and ($10) hours at the other. One must earn a total of ($100) dollars, and can work no more than (12) hours. Let (x) be the hours worked at job 1 and (y) be the hours worked at job two.
Since one can work no more than (12) hours, the sum of (x) and (y) must be (12), therefore the following equation can be formed;
[tex]x+y=12[/tex]
One earns ($8) dollars at one of their jobs and ($10) at the other, but one earns a total of (100) one can form an equation to represent this situation. Multiply the hours worked by the money earn per hour for each job, add up the result and set it equal to (100).
[tex]8x+10y=100[/tex]
Now set up these equations in a system;
[tex]\left \{ {{x+y=12} \atop {8x+10y=100}} \right.[/tex]
Use the process of elimination to solve this system. The process of elimination is a method of solving a system of equations. One must first manipulate one of the equations in the system such that one of the variable coefficients is the additive inverse of the other. That way, when one adds the equation, the variable cancels, one can solve for the other variable then back solve to find the value of the first variable,
[tex]\left \{ {{x+y=12} \atop {8x+10y=100}} \right.[/tex]
Manipulate,
[tex]= \left \{ {{(*-8)(x+y=12)} \atop {8x+10y=100}} \right.\\\\[/tex]
Simplify,
[tex]= \left \{ {{-8x-8y=-96} \atop {8x+10y=100}} \right.\\[/tex]
Add,
[tex]=2y=4[/tex]
Inverse operations,
[tex]y=2[/tex]
Backsolve for (x), use equation one to achieve this,
[tex]x+y=12\\[/tex]
Substitute,
[tex]x+2=12[/tex]
Inverse operations,
[tex]x=10[/tex]
How is the graph of y = 8x2 − 1 different from the graph of y = 8x2?
It is shifted 1 unit down.
It is shifted 1 unit to the right.
It is shifted 1 unit to the left.
It is shifted 1 unit up.
Answer:
since it's the lhs we are concerned about, i. e., Y axis, so it must be either up or down. now look at the question, it says 8x2 - (1), it means one lower value of y i. e., 1 unit down
Answer:It is shifted 1 unit down.
Step-by-step explanation:
The Home Cleaning Company charges $312 to power-wash the siding of a house plus
$12 for each window. Power Clean charges $36 per window, and the price includes
power-washing the siding. How many windows must a house have to make the total
cost from The Home Cleaning Company less expensive than Power Clean?
Answer:
14
Step-by-step explanation:
take 312 + 12×14 then take 36×14
Match the metric measurement on the left with an equivalent unit of measurement on the right
Answer:
ans:
0.3 hectoliter = 3000 centiliters0.03 liter = 30 milliliterMatch the metric measurement on the left with an equivalent unit of measurement on the right are as follows;
0.3 hectoliter 3 deciliters
0.03 liters 30 milliliters
30 centimeter 3 Deciliters
3000 Milliliters 0.3 Decaliters
What is the unit measurement?A standard unit of measurement is a quantifiable language that describes the magnitude of the quantity.
Match the metric measurement on the left with an equivalent unit of measurement on the right is determined in the following steps given below.
1. 0.3 hectoliter = 0.3 × 10 = 3 deciliters
2. 0.03 liters = 0.03 × 1000 = 30 mililiters
3. 3 Centiliters = 0.3 Deciliters then 30 centimeter = 3 Deciliters
4. 3000 Milliliters = 0.3 Decaliters
Learn more about unit measurement here;
https://brainly.com/question/15402847
#SPJ2
Katy spent $2834 on a washing machine and a dryer. The dryer cost $875 less than the washing machine. How much did the dryer cost ?
Answer:
the answer is 1959
Step-by-step explanation:
2834-875=1959
ASAP!!! There are three marbles in a bag. One is red and two are black. What is the probability of picking a red marble first, putting it back in the bag and then picking a black marble? Use the following probably need to find the answer.
Answer:
The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)
Step-by-step explanation:
Hey there!
The probability of first getting a red marble is 1/3 since we have 1 red marble out of 2 + 1 = 3 total.
We put the marble back. The probability of then choosing a black marble is 2/3, since we have 2 black marbles out of 3 total.
So we get 1/3 * 2/3 = 2/9
The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)
Hope this helps, please mark brainliest if possible. Have a nice day. :)
a tank is 2m long, 1.4m wide and 1.8m high.find the volume of water in the tank when it is half full.
Answer:
2.52m³
Step-by-step explanation:
volume=L x W x H
V=2 x 1.4 x 1.8
V=5.04
WE DIVIDE 5.04m³ by 2 to get 2.52m³
Have a nice day
parabola
Given that tanθ= [tex]-\frac{9}{4}[/tex] and [tex]\frac{\pi }{2\\}[/tex]<θ<π , find the exact values of the trigonometric functions.
9514 1404 393
Answer:
sin(θ) = (9√97)/97cos(θ) = (-4√97)/97csc(θ) = (√97)/9sec(θ) = (-√97)/4cot(θ) = -4/9Step-by-step explanation:
The angle is in the 2nd quadrant, where the sine is positive and the cosine is negative.
tan^2(θ) +1 = sec^2(θ) = (-9/4)^2 +1 = 97/16 ⇒ sec = -(1/4)√97
cot(θ) = 1/tan(θ) = -4/9
csc^2(θ) = cot^2(θ) +1 = (-4/9)^2 +1 = 97/81 ⇒ csc = (1/9)√97
sin(θ) = 1/csc(θ) = (9√97)/97
cos(θ) = 1/sec(θ) = (-4√97)/97
11. f(x) = 4x4 - x2 + 9. Find f(-4).
Answer:
f ( -4 ) = 1024 + 8 + 9
Step-by-step explanation:
f ( x ) = 4x⁴ - x² + 9
If f ( - 4 ) then we get
f ( -4 ) = 4 ( -4)⁴ - ( - 4)² + 9
Expand the exponents
f ( - 4 ) = 4 ( 256 ) + 8 + 9
multiply the numbers
f ( -4 ) = 1024 + 8 + 9
{ →
Shari drew several lines. Which lines are perpendicular to AC ?
Select all that apply.
Find the coefficient of the t4
term in the expansion of
(4t – 375
a
9514 1404 393
Answer:
-3840t^4
Step-by-step explanation:
The k-th term, counting from k=0, is ...
C(5, k)·(4t)^(5-k)·(-3)^k
Here, we want k=1, so the term is ...
C(5, 1)·(4t)^4·(-3)^1 = 5·256t^4·(-3) = -3840t^4
__
The program used in the attachment likes to list polynomials with the highest-degree term last. The t^4 term is next to last.
Arrange the following numbers in order from smallest to largest. 0.89, 0.098 ,0.98
Answer:
0.098 , 0.89, 0.98
Step-by-step explanation:
0.098 is the smallest, 0.98 is the closest to 1 so it's the biggest
An College student complained that the cost of textbooks was too high. She randomly surveyed 36 other students and found that the mean amount of money spent for textbooks was $121.60. If the standard deviation of the population was $6.36, find the best point estimate. Show your work.
Answer:
The best point estimate for the mean amount of money spent for textbooks for all students at the College is of $121.60.
Step-by-step explanation:
Best point estimate:
The best point estimate of a population mean is the sample mean.
In this question:
The sample mean amount of money spent for textbooks was $121.60, which means that the best point estimate for the mean amount of money spent for textbooks for all students at the College is of $121.60.
|x| =3 means that the distance between x and 0 is 3 / true or false
Answer:
True
Step-by-step explanation:
if |x| is 3 then x is either -3 or 3. Either way, the distance from 0 is 3.
Hole this helps! :)
please help thx steps too
Step-by-step explanation:
IN first triangle multiplier factor is 4
and IN second triangle multiplier factor is
[tex] \frac{3}{2} [/tex]
w= 2hx - 11x Solve for X. Please and Thank you
Answer:
[tex]{ \tt{ w = 2hx - 11x}} \\ \\ { \bf{w = x(2h - 11)}} \\ \\ { \bf{x = \frac{w}{2h - 11} }}[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = \frac{w}{(2h - 11)} }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]w = 2hx - 11x[/tex]
[tex]✒ \: w = x \: (2h - 11)[/tex]
[tex]✒ \: x = \frac{w}{(2h - 11)} [/tex]
[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]
How to solve this math question
Answer:
x = 16
y = 5
Step-by-step explanation:
The three sides of an equilateral triangle are equal. Therefore:
3x + 1 = 49
Solve for x.
3x + 1 - 1 = 49 - 1
3x = 48
3x/3 = 48/3
x = 16
Also
18y - 41 = 49
Solve for y.
18y - 41 + 41 = 49 + 41
18y = 90
18y/18 = 90/18
y = 5
An American tourist visits South Africa with $3000. The exchange rate when she arrives is
$1 = 12.90. She changes all her dollars into rands and then spends R900 per day for seven
days. She changes the rands she has left back into dollars at a rate of $1 = R12.93. How much
does she get in dollars? show your working.
9514 1404 393
Answer:
$2505.80
Step-by-step explanation:
After the first exchange, the tourist has ...
$3000(12.90 R/$) = R38,700
After 7 days, she has ...
R38,700 -7(R900) = R32,400
After the second exchange, she has ...
R32,400 × ($1/R12.93) = $2505.80
She gets $2505.80 at the second exchange.
22 hours. A
Silas ran 100 m race at a speed of 8 m/s. How long did it take him to com-
plete the race?
Answer:
100/8 = 12.5 (s)
Step-by-step explanation:
hmm bro
Answer:
[tex]{ \boxed{ \tt{formular : { \bf{ \green{time = \frac{distance}{speed} }}}}}} \\ time = \frac{100}{8} \\ { \boxed{time = 12.5 \: seconds}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]
what does $42,690e(0.03)(20) equal
Answer:
77,786.251
Step-by-step explanation:
WILL GIVE BRAINLIEST IF CORRECT
Answer:
The second answer.
Step-by-step explanation:
Tim is correct. Absolute value is just the distance away from 0. In this case, both P and Q are 3/8 away from zero, even though they have opposite signs. In fact, opposites signs of the same number will always have the same absolute value because they are the same distance from 0.
So, it is the second one.
Hope this helps!
Answer:
2nd answer choice:
Tim, because each point is 3/8 unit away from 0
Step-by-step explanation:
The absolute value of a number is how far it is from 0 in the number line, not including direction.
On this number line, point P is -3/8 and point Q is 3/8.
In the number line, count how many units each point is away from 0. You will find that they each have a distance of 3/8 from the number line. Therefore they have the same absolute values.
PS: absolute values are NEVER negative.
Hope this helps!
please help out
3/2÷5
Answer:
0.3Step-by-step explanation:
[tex] \frac{3}{2} \div 5[/tex]
[tex] = \frac{3}{2} \times \frac{1}{5} [/tex]
[tex] = \frac{3}{10} [/tex]
= 0.3 (Ans)
Answer:
3/10
Step-by-step explanation:
3/2÷5
3/2÷5/1
3/2÷10/2 ( LCM of denominators)
3/2×2/10 ( Reciprocal of 10/2)
3/10 (Cancelling 2 by 2)
please calculate this limit
please help me
Answer:
We want to find:
[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}[/tex]
Here we can use Stirling's approximation, which says that for large values of n, we get:
[tex]n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n[/tex]
Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}[/tex]
Now we can just simplify this, so we get:
[tex]\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\[/tex]
And we can rewrite it as:
[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}[/tex]
The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:
[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}[/tex]
describe when it is and when it is not necessary to use a common denominator when adding, subtracting, multiplying, and dividing rational expressions.
Step-by-step explanation:
For Adding and Subtraction:
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD. 7. simplify or reduce the rational expression of you can. Remember, to reduce rational expressions, the factors must be exactly the same in both the numerator and the denominator.
To Multiply:
first determine the GCF of the numerator and denominator. Then, regrouping the fractions to make fractions equal to One. Then, multiply any remaining factors.To Divide:
First, rewriting the division as multiplication by the reciprocal of the denominator. The remaining steps are the same for multiplication.9514 1404 393
Answer:
necessary: addition and subtractionnot necessary: multiplication and divisionStep-by-step explanation:
For multiplication and division, the denominator of the result is developed as part of the algorithm for performing these operations on rational expressions. For example, ...
(a/b)(c/d) = (ac)/(bd)
(a/b)/(c/d) = (ad)/(bc)
It is not necessary to make the operands of these operations have a common denominator before the operations are performed. That being said, in some cases, the division operation can be simplified if the operands do have a common denominator or a common numerator:
(a/b)/(c/b) = a/c
(a/b)/(a/c) = c/b
__
If the result of addition or subtraction is to be expressed using a single denominator, then the operands must have a common denominator before they can be combined. That denominator can be developed "on the fly" using a suitable formula for the sum or difference, but it is required, nonetheless.
(a/b) ± (c/d) = (ad ± bc)/(bd)
This formula is equivalent to converting each operand to a common denominator prior to addition/subtraction:
[tex]\dfrac{a}{b}\pm\dfrac{c}{d}=\dfrac{ad}{bd}\pm\dfrac{bc}{bd}=\dfrac{ad\pm bc}{bd}[/tex]
Note that the denominator 'bd' in this case will not be the "least common denominator" if 'b' and 'd' have common factors. Even use of the "least common denominator" is no guarantee that the resulting rational expression will not have factors common to the numerator and denominator.
For example, ...
5/6 - 1/3 = 5/6 -2/6 = 3/6 = 1/2
The least common denominator is 6, but the difference 3/6 can still be reduced to lower terms.
If we were to use the above difference formula, we would get ...
5/6 -1/3 = (15 -6)/18 = 9/18 = 1/2
Consider the following data representing the price of plasma televisions (in dollars).
1325, 1266, 1123, 1233, 1387, 1249, 1120, 1140, 1347, 1337, 1402, 1259, 1421, 1351, 1452, 1277, 1309, 1232, 1112, 1243, 1429
Copy Data Price of Plasma Televisions (in Dollars) Class Frequency Class Boundaries Midpoint Relative Frequency Cumulative Frequency
1067–1126 1127–1186 1187–1246 1247–1306 1307–1366 1367–1426
Determine the class width of the classes listed in the frequency table.
Answer:
[tex]Width = 59[/tex]
Step-by-step explanation:
Given
The above data
Required
The class width
To do this, we simply calculate the difference between the class limits of any one of the classes.
Taking 1187–1246 as a point of reference, the class width is:
[tex]Width = 1246 - 1187[/tex]
[tex]Width = 59[/tex]
What is the measure of each exterior angle of the right triangle?
x =
y =
z =
Answer:
x = 90
y = 134
z = 136
Step-by-step explanation:
Sum of interior angles of a triangle are 180
Linear angles are 180
So 180 - 90 = 90
180 - 44 = 136
180 - 90-44 = 46
180 - 46 = 134
4. Write an equation for the line that is parallel to the given line and that passes
through the given point.
y = 5/2x-10;(-6,-29)
Answer:
[tex]y=\frac{5}{2}x-14[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)Parallel lines always have the same slope1) Determine the slope (m)
[tex]y=\frac{5}{2}x-10[/tex]
In the given equation, [tex]\frac{5}{2}[/tex] is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of [tex]\frac{5}{2}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=\frac{5}{2}x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=\frac{5}{2}x+b[/tex]
Plug in the given point (-6,-29) and solve for b
[tex]-29=\frac{5}{2}(-6)+b[/tex]
Simplify -6 and 2
[tex]-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b[/tex]
Add 15 to both sides to isolate b
[tex]-29+15=-15+b+15\\-14=b[/tex]
Therefore, the y-intercept is -14. Plug this back into [tex]y=\frac{5}{2}x+b[/tex]:
[tex]y=\frac{5}{2}x-14[/tex]
I hope this helps!
The pie chart below shows the percentage of total revenue that a publisher receives from various types of publications. Use this chart to answer the questions
below.
Answer:
a. Cookbooks
b. 50%
c. 30%
Step-by-step explanation:
According To the Question,
We have a total revenue of a publisher describe in a circle (360°).a. Now, Approximately Cookbooks & Textbooks revenue Form 180°, but textbook revenue is more than cookbooks as clearly visible in the diagram
Thus, cookbooks are less than 90°.
Now, we have to find 1/5th of total publisher revenue which is 360°/5= 72°. & the Cookbooks is nearest to 72° ( less than 90°)
So, Answer For (a) is Cookbooks
b. Here in Diagram Clearly Visible that The Cookbooks & Textbooks Revenue Form 180° which is Approximately 50% of total Publisher's Revenue.
So, the Total Revenue Comes From Textbooks & Cookbooks is 50%.
c. Now We know the Cookbooks + Textbooks Revenue form 180° Approximately & Cookbook is approximately equal to 72° (as we solve above)
So, textbooks are 180°-72° = 108°, which is 30% of 360° ∴ 30% Revenue Come From Textbooks.
Solve the equation by completing the square. Round to the nearest hundredth x^2 + 2x = 15
Answer:
x = 3, x = -5
Step-by-step explanation:
A perfect square trinomial is represented in the form a^2 + 2ab + b^2. We are already given the a^2 term, x^2, and the 2ab term, 2x. From this we can say:
a^2 = x^2
a = x
Now, we can substitute x for a in the other expression to create the equation:
2ab = 2x
2(x)b=2x
b = 1
From this, b^2 is one, so, to get our trinomial all on one side, we add 1 to both sides:
x^2 + 2x = 15
x^2 + 2x + 1 = 16
Now, we can factor. The perfect square trinomial factors into (a + b)^2. In this case, a is x, and b is one. We can factor and get:
(x + 1)^2 = 16
Now, we take the square root of both sides:
x + 1 = ± 4
We can separate this into two equations and solve:
x + 1 = 4
x = 3
x + 1 = -4
x = -5
Answer:
Step-by-step explanation:
x^2 + 2x = 15
x^2 + 2x + [1/2(2)]^2 = 15 + [1/2(2)]^2
(x + 1/2(2) )^2 = 15 + [(1/2)(2)]^2
(x + 1)^2 = 15 + 1^2
(x + 1)^2 = 15 + 1
(x+1)^2 = 16 Take the square root of both sides.
sqrt( (x + 1)^2 ) = sqrt(16)
x + 1 = +/- 4
x + 1 = 4
x = 4 - 1 = 3
x + 1 = -4
x = -4 - 1
x = - 5
So the roots are 3 and - 5
plz answer I don't have a long time
Answer: x=52
Step-by-step explanation:
x+72=34+90
x+72=124
124-72=x
x=52
the probabilities that Kojo and Adwoa will pass an examination are 3/4 and 3/5 respectively. Find the probability that both will fail the examination