Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s average speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, then Riko will be behind Yuto when 0 ≤ t < 52.5, where t is time in minutes. Explain what this solution means and why t cannot be less than zero

Answer:

Step-by-step explanation:

r = d/2

r = 10.2/2 = 5.1

Area = pi * r^2

Area = 3.14 * 5.1^2

Area = 81.67 in^2

To the nearest 1/10, this is 81.7 in^2

1.4

2.3

3.7

solution 1

2+2+=4

solution 2

3

Answer:

380

Step-by-step explanation:

This is a bit nasty. It depends on how you read the 20 miles more and what you do with it. The best and most careful way to do it is do it a long way setting up the two equations carefully.

Second day

Let the time travelled = t

Let the speed travelled = 60 mph

d2 = 60*t

First Day

40*(t + 2) = d1

but d1 = d2 + 20 because he travelled 20 miles further on d1

40 * (t + 2) = d2 + 20

d2 however = 60*t

40*(t+2 ) = 60*t + 20          Remove the brackets

40t + 80 = 60t + 20           Subtract 20 from both sides

40t + 60 = 60t                   Subtract 40t from both sides

60 = 20*t                           Divide by 20

t = 60/20

t = 3 hours.

Day 2 = 60 + t = 180

Day 1 = 40*5  = 200

Total distance = 380

Where did that 20 miles go? It was just an observation about the difference in distance travelled between the 2 days.

The total distance the driver traveled in the two days is 260 miles

From the question, on the first day, the driver was going as a speed of 40 mph.

Let s be speed

∴ [tex]s_{1}= 40mph[/tex]

On the second day, he increased the speed to 60 mph

∴ [tex]s_{2}= 60mph[/tex]

From the statement- If he drove 2 more hours on the first day

Let time be t

Then

[tex]t_{1}= t_{2} + 2[/tex] hrs

and traveled 20 more miles

Let d be distance  

Then,

[tex]d_{1}= d_{2} + 20[/tex] miles

From the formula

Distance = Speed × Time

Then,

[tex]d = s \times t[/tex]

∴ [tex]d_{1} = s_{1} \times t_{1}[/tex]

From above,

[tex]d_{1}= d_{2}+20[/tex] miles

[tex]s_{1}= 40mph[/tex]

[tex]t_{1}= t_{2} + 2[/tex] hrs

Putting these into

[tex]d_{1} = s_{1} \times t_{1}[/tex]

[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex] ...... (1)

But,

[tex]Time = \frac{Distance}{Speed}[/tex]

∴ [tex]t_{2}= \frac{d_{2} }{s_{2} }[/tex]

From above, [tex]s_{2}= 60mph[/tex]

∴ [tex]t_{2}= \frac{d_{2} }{60}[/tex]

Put this into equation (1)

[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex]

[tex]d_{2} + 20 = 40\times (\frac{d_{2}}{60} +2)[/tex]

[tex]d_{2} + 20 = \frac{2}{3}d_{2} +80\\d_{2} = \frac{2}{3}d_{2} +80-20\\d_{2} = \frac{2}{3}d_{2} +60[/tex]

Multiply through by 3

[tex]3\times d_{2} = 3\times \frac{2}{3}d_{2} +3 \times 60\\3d_{2} = 2d_{2} + 120\\3d_{2} -2d_{2} = 120[/tex]

∴ [tex]d_{2} = 120[/tex] miles

∴The distance traveled on the second day is 120 miles

For the distance traveled on the first day,

Substitute [tex]d_{2}[/tex] into the equation

[tex]d_{1}= d_{2}+20[/tex] miles

∴ [tex]d_{1}= 120+20[/tex]

[tex]d_{1}= 140[/tex] miles

∴ The distance traveled on the first day is 140 miles

The total distance traveled in the two days = [tex]d_{1} + d_{2}[/tex]

The total distance traveled in the two days = 120 miles + 140 miles

The total distance traveled in the two days = 260 miles

Hence, the total distance the driver traveled in the two days is 260 miles

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Answer:

B

Step-by-step explanation:

Sin x°= opposite ÷ hypotenuse

Cos x°= adjacent ÷ hypotenuse

Tan x°= opposite ÷ adjacent

Ctg x°= adjacent ÷ opposite

The correct will bet cot x = adjacent ÷ opposite

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Using trigonometric properties we have

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Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.

Answer:

C on Edge or (1,-9)

Step-by-step explanation:

Step-by-step explanation:

The first thing we have to do before we can actually do the problem is turn the words into a math equation.

If we use x as our "number," we see that "The sum of a number and 2" can also be written as x+2. The word "Is" almost always means (=), so now we have (x+2) = . The very last part, "6 less than twice that number," means 2x - 6.

So, our whole equation is, (x + 2) = (2x - 6), which simplifies to -x = -8, or

x = 8

Answer:

y = 8

Step-by-step explanation:

number = y

y + 2 = 2y - 6

y + 2 - 2 = 2y - 6 - 2

y = 2y - 8

y - 2y = 2y - 2y - 8

- y = - 8

- y × - 1 = - 8 × - 1

y = 8

Answer:

-2x^2-8x+12

Step-by-step explanation:

f(x) = 3x^2-2x+4

g(x) = 5x^2+6x-8

(f-g)(x)= 3x^2-2x+4 -(5x^2+6x-8)

Distribute the minus sign

(f-g)(x)= 3x^2-2x+4 -5x^2-6x+8

Combine like terms

          =-2x^2-8x+12

Answer: (f+g)(x)=8x^2+4x-4

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Basically, the period of a sinusoidal graph is the distance between one cycle to another. As can be visually seen, this is 2.

Answer:

2

Step-by-step explanation:

its right on Acellus

Answer:

Mutal fund because its a formerly greatest instruments

The name of an investment that pools money from many investors in order to acquire a large variety of stocks, bonds, and other investments is Mutual fund.

Investment is traditionally defined as the "commitment of resources to achieve later benefits

A mutual fund is a type of investment vehicle that pools money from multiple investors to invest in a diversified portfolio of stocks, bonds, and other securities.

Mutual funds are managed by professional fund managers who use the pooled funds to purchase a range of investments, with the goal of generating a return for the investors.

Investors in mutual funds own shares in the fund, and the value of their investment is based on the performance of the underlying securities held by the fund.

Mutual funds offer investors the benefits of diversification, professional management, and ease of investment, as well as the ability to invest in a variety of asset classes with relatively low minimum investment requirements.

Hence, the name of an investment that pools money from many investors in order to acquire a large variety of stocks, bonds, and other investments is Mutual fund.

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Answer:

50

Step-by-step explanation:

Given,

96 + 2² / 2

96 + 4 / 2

100 / 2

50

Answer: A. 20 is the answer.

Step-by-step explanation:

x+40 = 3x

or, 40 = 3x-x

or, 2x = 40

or, x = 40/2

so, x = 20

Answer:

1. the area of the triangle minus the area of the small, inner rectangle. what did you not understand there ?

the standard formula (hi, internet !) for the area of a triangle is baseline×height/2.

the standard formula (hi, first grade !) for the area of a rectangle is length×width.

that's it.

1.a.

the volume of an object regularity shaped like a silo is always ground area times height.

for this object we only need to imagine to stand the object up sideways on the triangle side.

and don't forget - an area is always a square unit (like cm²,m², ft², ...). and a volume is always a cubic unit (like cm³, m³, ft³, ...).

so then, the triangle area is the ground area. and the original long side line of the object is is height.

as we said in 1. above, the area of a triangle is baseline×height (of the triangle, not of the overall object) divided by 2.

so, we have here 6×4/2 = 6×2 = 12 m²

and now the ground area × object height = 12×8=96 m³

b.

the standard formula for the volume of a ball (hi, internet !) is pi×r³.

so, we have here pi×9³. can you calculate that with your calculator ? that is pi×729 = 2290.221 cm³

2a.

the height of the cone is (as the drawing already suggests) determined via the right-angled triangle of the radius (half of the diameter) of the ground circle, the height of the cone and the length of the sideline on the outside mantle of the cone. this sideline is the Hypotenuse (the baseline of the triangle opposite of the 90 degree angle).

so, we use Pythagoras

c² = a² + b² (c being the Hypotenuse, a and b being the sides).

11² = 8² + h²

121 = 64 + h²

h² = 57

h = 7.55 cm

2b.

the standard formula for the volume of a cone (hi, internet !) is

pi×r²×h/3

pi×8²×7.55/3 = pi×64×7.55/3 = 506 cm³

Step-by-step explanation:

all of that you could easily search on the internet and since it yourself way faster than putting things in here and waiting for responses.

as there is really nothing to explain but just to use the standard formulas with the given numbers.

Answer:

16 pair of shoes

Step-by-step explanation:

If Gayle donated x pairs, it means he is left with 30 - x pair of shoes.

Bonnie donated half as many as Gayle as donated.

We know Gayle donated x pairs, so Bonnie must have donated x/2.

Bonnie is left with 22 - (x/2) pairs after donation.

The question says, after donation they have the same number of pair of shoes.

It means, 30 - x = 22-(x/2),

If you will manipulate this equation and make x the subject,

you will get x=16.

I hope it helps.

Gayle donated 16 shoes

Number of shoes Gayle has after the equation can be represented with this equation : 30 - x

Where x = number of shoes she donated

Number of shoes Bonnie donated = 0.5x

Number of shoes Bonnie has after the equation can be represented with this equation : 22 - 0.5x

If Bonnie and Gayle ended with the same amount of shoes after the donation, this can be represented as:

30 - x = 22 - 0.5x

Combine similar terms

30 - 22 = x - 0.5x

8 = 0.5x

Divide both sides of the equation by 0.5

x = 16

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The area covered by the roof would be 84.5 square yards.

To calculate the area covered by the roof the formula that should be used would be the formula for the area of a square;

That is ;

Area = 2(length×width)

= 2(6.5×6.5)

= 2(42.25)

= 84.5 yards²

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Answer:

40 days

Step-by-step explanation:

w1*h1*d1=w2*h2*d

15*8*20=10*6*d

2400=60d

d=2400/60

d=40

Answer:

j+2

Step-by-step explanation:

combine like terms

3k - 3k = 0

8j - 7j = 1j or j

6 - 4 = 2

put it all together

j + 2

Answer:

j + 2

Step-by-step explanation:

= 8j - 3k + 6 - 7j + 3k - 4

= 8j - 7j - 3k + 3k + 6 - 4

=j + 2

Answer from Gauth math

Answer:

A. 11.18

Step-by-step explanation:

(1, -2) will be x1 and y1.

(-9, 3) will be x2 and y2

The formula is

Distance = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute in all the variables.

[tex]\sqrt{(-9-1)^2+(3-(-2))^2}[/tex]

Solve.

[tex]\sqrt{(-10)^2+5^2}[/tex]

[tex]\sqrt{100+25}[/tex]

[tex]5\sqrt{5}[/tex]

11.18033988.....

I hope this helps!

pls ❤ and mark brainliest pls!

Step-by-step explanation:

Arlington is increasing because it has 1.027, if it was 0.27 it would be decreasing

If p(6)= 4107 that means after 6 years there would be a total population of 4107

hopefully this answer can help you to answer the next question.

Answer: 825

Step-by-step explanation:

Plug in the values for v = π*r²*h

So, your new equation is v = π*5²*11 (I got 5 because 10 is the diameter, the radius is half the diameter, therefore r = 5.)

The question is also telling us to replace π with 3.

now we solve, after gathering all of our information.

v = 3*5²*11

v=3*25*11

v=75*11

v=825

Answer:

D 1,433.25

Step-by-step explanation:

1/2(10)(7)=35

35*13=455

455*3.15=1,433.25

Answer:

D

Step-by-step explanation:

You need to find the volume of the attic (I would find the surface area myself -- but this is math. You just have to obey the rules of the question no matter how silly).

The Volume is found by V = B * h1

The base is a triangle.

b = 7 m

h1 = 10 m

Area = 1/2 * 7 * 10

area = 35 m^2

The volume of the attic is

V = B * h

V = 35 * 13

V = 455 m^3

The cost = cost /m^3  * m^3

m^3 = 455

Cost = 3.15 * 455

Cost = 1433.25

Answer:

Step-by-step explanation:

The supplement of the exterior angle is 180 - 75 = 105

In a cyclic quadrilateral (a four sides figure where all the vertices touch the circumference of a circle), the opposite angles are supplementary. Therefore <a = 180 - 105 = 75

But I think you already knew that.

Answer:

Step-by-step explanation:

The rule is that opposite angles are supplementary. Therefore, angle A plus angle C = 180:

angle A + 43 = 180 and

angle A = 180 - 43 so

angle A = 137

Answer:

4 1/3 of her hair

Step-by-step explanation:

Just add 2 1/6 + 2 1/6 and there you go

There is the total amount of her hair she cut

Answer:

the third option=C -2,3

Step-by-step explanation:

solve simultaneously

Answer:

(-2,3)

Step-by-step explanation:

The solution to the system is where the two lines cross

x= -2

y = 3

(-2,3)

Answer:

Letter B. Hyperbole is your answer

Answer:

the answer is 3.81

but rounding it it will be 3.8 meters

Step-by-step explanation:

Pythagorean theorem says

a²+b²=c²

so,

take take the Lowest measurement as a² which will be 7 and take 8 as the hypotenuse or the longest side which is c²

then put it all together you get

7²+x²=8²

we made b as x because we will be finding b

then substitute the values

x²=8²-7²

x²=64-49

x²=15

to remove that square from the x you then put square root in both

✓x²=✓15

press in the calculator, root of 15 will be about 3.81

now we got

x=3.81

x is the missing measurement

Answer:

g(x) = 4 - x^2

at x-intercept, y=0

0=4-x^2

x^2=4

x = ± 2

=> two x- intercepts, (-2,0) and (2,0)

at y-intercept, x = 0

g(x) = y = 4 - 0 = 4

y-intercept = (0,4)

The x-intercept is ( ±2 , 0 ) and y- intercerpt is (0,4).

A y-intercept, also known as a vertical intercept, is the location where the graph of a function or relation intersects the coordinate system's y-axis.

This is done in analytic geometry using the common convention that the horizontal axis represents the variable x and the vertical axis the variable y. These points satisfy x = 0 because of this.

g(x) = 4 - x²

At x-intercept, y = 0

0=4-x²

x² = 4

x = ± 2

Two x- intercepts, (-2,0) and (2,0)

at y-intercept, x = 0

g(x) = y = 4 - 0 = 4

y-intercept = (0,4)

Therefore, the x-intercept is ( ±2 , 0 ) and y- intercerpt is (0,4).

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Answer:

According to the graph presented within the proposed interrogate, the answer to such is identified as ‘C’: 2, 3, 5, 5, 6, 7, 8, 10, 11.

Step-by-step explanation:

To evaluate for such a problem, a comprehension of the “Whisker” plots is obligated.

- The box geometric figure with the vertical line contained within represents the average of the numbers presented.

* In this peculiar case, 6 is acknowledged as the individual value responsible for the mean.

Thus far, browsing at such answer choices, we are obligated to appoint an answer where 6 is the standard deviation or the mean (where 6, and only 6, is found in the middle of the set of numbers provided).

The only answer choice in which certifies to all conditions thus far declared is disseminated as “C”.

*I hope this helps.

Let's do

[tex]\\ \sf\longmapsto 2sin^260cos60tan^245[/tex]

[tex]\\ \sf\longmapsto 2\left(\dfrac{\sqrt{3}}{2}\right)^2\times \dfrac{1}{2}\times (1)^2[/tex]

[tex]\\ \sf\longmapsto 2\times \dfrac{(\sqrt{3})^2}{2^2}\times \dfrac{1}{2}\times 1[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{2}\times \dfrac{1}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{4}[/tex]

Trigonometric values

[tex]\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}[/tex]