1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should be added to the barrel to result in the required SO2 level

Answers

Answer 1

Answer:

The appropriate answer is "9.225 g".

Explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

= [tex]Required \ level -Initial \ concentration[/tex]

= [tex]63-22[/tex]

= [tex]41 \ ppm[/tex]

The amount of free SO₂ to be added will be:

= [tex]41\times 225[/tex]

= [tex]9225 \ mg[/tex]

∵ 1000 mg = 1 g

So,

= [tex]9225\times \frac{1}{1000}[/tex]

= [tex]9.225[/tex]

Thus,

"9.225 g" should be added.


Related Questions

D
Question 2
1 pts
How many moles of carbon tetrachloride are present in
18.Og of CC14?

Answers

i think .117018

now to get to the 20charaeactrs minimum.

Voltages listed in textbooks and handbooks are given as standard cell potentials (voltages). What is meant by a standard cell?

Answers

Answer:

Find the definition below.

Explanation:

A standard cell is a group of transistors that have a regular electromotive force flowing through them. They follow either the boolean function or the storage function. A technology library that is made up of a collection of standard cells can be used to facilitate the placement, routing, and synthesis of the Application-specific Integrated Circuit (ASIC).

Electronic Design Automation is an example of an apparatus that implements this functionality.

A 46.6-mgmg sample of boron reacts with oxygen to form 150 mgmg of the compound boron oxide. Part A What is the empirical formula of boron oxide

Answers

Answer:

B₂O₃

Explanation:

Step 1: Calculate the mass of oxygen in 150 mg of boron oxide

Of 150 mg of boron oxide, 46.6 mg belong to boron. The mass of oxygen is:

150 mg - 46.6 mg = 103.4 mg

Step 2: Calculate the percent by mass of each element

We will use the following expression.

%Element = mElement/mCompound × 100%

%B = 46.6 mg/150 mg × 100% = 31.1%

%O = 103.4 mg/150 mg × 100% = 68.9%

Step 3: Divide each percentage by the atomic mass of the element

B: 31.1/10.81 = 2.88

O: 68.9/16.00 = 4.31

Step 4: Divide both numbers by the smallest one (2.88)

B: 2.88/2.88 = 1

O: 4.31/2.88 ≈ 1.5

Step 5: Multiply both numbers by 2 so that they are integers

B: 1 × 2 = 2

O: 1.5 × 2 = 3

The empirical formula is B₂O₃.

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Write the symbol for every chemical element that has atomic number less than 14 and atomic mass greater than 23.2 u.

Answers

Answer:

8 oxygen. 9 flourine. 10. Neon. 5 Boron

During a reaction, ΔH for reactants is −750 kJ/mol and ΔH for products is 920 kJ/mol. Which statement is correct about the reaction? (5 points)

Group of answer choices

It is endothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed.

It is endothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed.

It is exothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed.

It is exothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed.

Answers

Answer: The statement it is endothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed, is true.

Explanation:

A chemical reaction in which heat energy  is released is called an exothermic reaction. For exothermic reactions, the value of [tex]\Delta H[/tex] is always negative.

A chemical reaction in which heat energy is absorbed is called an endothermic reaction. For endothermic reaction, the value of [tex]\Delta H[/tex] is always positive.

In endothermic reactions, energy required for breaking the bonds between reactants is less than the energy when products are formed due to which the value of [tex]\Delta H[/tex] remains positive.

Thus, we can conclude that the statement it is endothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed, is true.

It is endothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed. The correct option is B.

The above reaction is endothermic because more energy is produced when new bonds form in the products (H = 920 kJ/mol) than is required to break bonds in the reactants (H = -750 kJ/mol).

In an endothermic process, more energy than is generated during bond creation is absorbed from the environment to dissolve existing bonds. This causes a net absorption of energy, which cools the system.

The reaction takes more energy than it releases, proving its endothermic nature, as seen by the positive difference between the energy needed to dissolve bonds and the energy released during bond formation.

Thus, the correct option is B.

For more details regarding endothermic process, visit:

https://brainly.com/question/28909381

#SPJ3

Your question seems incomplete, the probable complete question is:

During a reaction, ΔH for reactants is −750 kJ/mol and ΔH for products is 920 kJ/mol. Which statement is correct about the reaction? (5 points)

Group of answer choices

A. It is endothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed.

B. It is endothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed.

C. It is exothermic because the energy required to break bonds in the reactants is less than the energy released when the products are formed.

D. It is exothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed.

Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.)

______________ → BaBr2 + H2O

Answers

Answer:

Ba(OH)₂ + 2 HBr ⇒ BaBr₂ + 2 H₂O

Explanation:

We have the products of a reaction and we have to predict the reactants. Since the products are binary salt and water, this must be a neutralization reaction. In neutralizations, acids react with bases. The acid that gives place to Br⁻ is HBr, while the base the gives place to Ba²⁺ is Ba(OH)₂. The balanced chemical equation is:

Ba(OH)₂ + 2 HBr ⇒ BaBr₂ + 2 H₂O

In the titration of 82.0 mL of 0.400 M HCOOH with 0.150 M LiOH, how many mL of LiOH are required to reach the equivalence point

Answers

Answer:

218.7 mL

Explanation:

The reaction that takes place is:

HCOOH + LiOH → LiCOOH + H₂O

First we calculate how many HCOOH moles reacted, using the given volume and concentration:

82.0 mL * 0.400 M = 32.8 mmol HCOOH

As 1 HCOOH mol reacts with 1 LiOH mol, 32.8 mmoles of LiOH are needed to react with 32.8 mmoles of HCOOH.

Finally we calculate how many mL of a 0.150 M solution would contain 32.8 mmoles:

32.8 mmol / 0.150 M = 218.7 mL

Identify the intermolecular attractions for dimethyl ether and for ethyl alcohol. Which molecule is expected to be more soluble in water? Explain.

Answers

Answer:

See explanation

Explanation:

All molecules possess the London dispersion forces. However London dispersion forces is the only kind of intermolecular interaction that exists in nonpolar substances.

So, the only kind of intermolecular interaction that exists in dimethyl ether is London dispersion forces.

As for ethyl alcohol, the molecule is polar due to the presence of polar O-H bond. In addition to London dispersion forces, dipole-dipole interactions and specifically hydrogen bonding also occurs between the molecules.

Because ethyl alcohol is polar, it is more soluble in water than dimethyl ether.

Give the name of the molecular compound and the name of the aqueous solution for each of the binary compounds below.

a. HCN
b. HF
c. H2S

Answers

Explanation:

A compound containing only two elements is called a binary compound.

(a). The compound HCN contains a hydrogen ion and cyanide ion. Hence, the name of HCN is hydrogen cyanide.

An aqueous solution of hydrogen cyanide is known as hydrogen cyanide solution.

(b). The compound HF contains a hydrogen ion and a fluorine ion. The suffix -ide will be added to its name. So, the name of this compound is hydrogen fluoride.

An aqueous solution of HF is known as hydrogen fluoride.

(c). The compound [tex]H_{2}S[/tex] contains two hydrogen atoms and one sulfur atom. The suffix -ide will be added to its name. So, the name of this compound is hydrogen sulfide.

An aqueous solution of this compound is known as hydrogen sulfide solution.

Observe as equações e de acordo com Brönsted-Lowry, os compostos destacados são, respectivamente

Answers

answer

j'ai besoin d'aide

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g A sample of chlorine gas starting at 681 mm Hg is placed under a pressure of 991 mm Hg and reduced to a volume of 513.7 mL. What was the initial volume, in mL, of the chlorine gas container if the process was performed at constant temperature?

Answers

Answer:

747.5 mL

Explanation:

Assuming ideal behaviour, we can solve this problem by using Boyle's law, which states that at constant temperature:

P₁V₁ = P₂V₂

Where in this case:

P₁ = 681 mm HgV₁ = ?P₂ = 991 mm HgV₂ = 513.7 mL

We input the data given by the problem:

681 mm Hg * V₁ = 991 mm Hg * 513.7 mL

And solve for V₁:

V₁ = 747.5 mL

Why ethanol is used in pectin extraction

Answers

Explanation:

is responsible for interrupting the interaction between pectins and solvent molecules

The first law of thermodynamics defines chemical energy. defines entropy. is a statement of conservation of energy. provides a criterion for the spontaneity of a reaction.

Answers

Answer: The first law of thermodynamics is a statement of conservation of energy.

Explanation:

According to the first law of thermodynamics, heat provided to a system is actually the sum of internal energy and work done by the system or on the system.

Mathematically, [tex]\Delta Q = \Delta U + \Delta W[/tex]

The first law of thermodynamics also means that energy can neither be created nor it can be destroyed. Hence, energy is conserved.

Thus, we can conclude that the first law of thermodynamics is a statement of conservation of energy.

How do you predict the geometrical shape of NH3 on VSEPR model

Answers

Answer:

NH3 Ammonia

Explanation:

Ammonia has 4 regions of electron density around the central nitrogen atom (3 bonds and one lone pair). These are arranged in a tetrahedral shape. The resulting molecular shape is trigonal pyramidal with H-N-H angles of 106.7°.

When a photon of red light hits metal X, an electron is ejected. Will an electron be ejected if a photon of yellow light hits metal X?
A. Yes
B. No
C. Can't tell

Answers

no i do not believe so because of the different wave lengths that are immersed from the colour spectrum

A student dropped a pea size amount of K2CO3 into a solution of HCl(aq). He observed the formation of gas bubbles and collected the gas into another test tube. The student performed a splint test and observed that the splint was extingished when he placed the splint into the test tube of the gas. What can be said about the results of this students experiment?

a. The student completed the experiment correctly and there were no errors in the experiment.
b. The experiment was performed incorrectly. K2CO3 doesn't react with HCl. Therefore, the student picked up the wrong compound when conducting the experiment.
c. The student performed the splint test incorrectly. He should of observed the splint flare up when the splint was placed in the test tube.
d. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.

Answers

Answer:

The student completed the experiment correctly and there were no errors in the experiment.

Explanation:

When a pea size amount of K2CO3 is dropped into a solution of HCl, the following reaction occurs;

K2CO3(s) + 2HCl(aq) ----> 2KCl(aq) + CO2(g) + H2O(l)

The gas CO2 does not support burning hence, when the student performed a splint test and observed that the splint was extinguished when he placed the splint into the test tube of the gas.

Hence, the experiment was properly conducted and the student completed the experiment correctly and there were no errors in the experiment.

Sugar is added to water and initially completely dissolves, but eventually solid sugar collects on the bottom of the container. Sugar and water are ________partially miscible . This produces a dynamic equilibrium. Ethanol (a liquid) is added to water and only a single layer is observed no matter how much ethanol is added. Ethanol and water are__________

Answers

Answer: Sugar is added to water and initially completely dissolves, but eventually solid sugar collects on the bottom of the container. Sugar and water are both partially miscible. This produces a dynamic equilibrium. Ethanol (a liquid) is added to water and only a single layer is observed no matter how much ethanol is added. Ethanol and water are miscible.

Explanation:

When a substance (solute) dissolves partially in a solvent then it is known as partially miscible in the solvent. In such cases, a small amount of solute remains at the bottom of solution.

If a solute dissolves completely in solvent like water such that only one layer is seen in the solution then it means that the solute is miscible in solvent.

Thus, we can conclude that sugar is added to water and initially completely dissolves, but eventually solid sugar collects on the bottom of the container. Sugar and water are both partially miscible. This produces a dynamic equilibrium. Ethanol (a liquid) is added to water and only a single layer is observed no matter how much ethanol is added. Ethanol and water are miscible.

11th grade chemistry question will mark brainliest
2.50 g of CO2 gas is confined in a rigid cylinder at a pressure
of 4.65 atm. If 0.42 g of gas is released from the cylinder,
what is the new pressure?

Answers

Answer:

3.88 atm

Explanation:

We'll begin by calculating the number of mole of CO₂ in each case. This can be obtained as follow:

For 2.50 g of CO₂:

Mass of CO₂ = 2.5 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mole of CO₂ =?

Mole = mass / molar mass

Mole of CO₂ = 2.5 / 44

Mole of CO₂ = 0.06 mole

For 0.42 g of CO₂:

Mass of CO₂ = 2.5 g

Molar mass of CO₂ = 44 g/mol

Mole of CO₂ =?

Mole = mass / molar mass

Mole of CO₂ = 0.42 / 44

Mole of CO₂ = 0.010 mole

Finally, we shall determine the new pressure. This can be obtained as follow:

Initial mole (n₁) = 0.06 mole

Initial pressure (P₁) = 4.65 atm

Final mole (n₂) = 0.06 – 0.010 = 0.05 mole

Final pressure (P₂) =?

NOTE: Temperature and volume is constant.

P₁ / n₁ = P₂ / n₂

4.65 / 0.06 = P₂ / 0.05

Cross multiply

0.06 × P₂ = 4.65 × 0.05

0.06 × P₂ = 0.2325

Divide both side by 0.06

P₂ = 0.2325 / 0.06

P₂ = 3.88 atm

Thus, the new pressure is 3.88 atm.

A hypnotist's watch hanging from a chain swings back and forth every 0.98 s. What is the frequency (in Hz) of its oscillation?

Answers

Answer:

1.02 Hz

Explanation:

frequency= (1/t) = (1/0.98) = 1.02 hz

Water has a density of 1.00 g/mL. If you put an object that has a density of 0.79 g/mL into water, it will sink to the bottom.
ANSWER please
True
False

Answers

Answer:

False

Explanation:

An object with a density less than the density of water will float.

And an object that is denser than water (more than 1.00g/mL) will sink when placed in water.

The chemical formula is different from the empirical formula in

Answers

Answer:be careful and relax

Explanation:

Answer:

Hahaha be careful and relax

Draw bond-line formulas of all monochloro derivatives that might be formed when 1,1-dimethylcyclobutane is allowed to react with Cl2 under UV irradiation. For each structure, indicate, with an asterisk, any stereocenters that might be present.

Answers

Answer:

Attached below

Explanation:

Diagram of Bond-line formulas of all monochloro derivatives formed when 1,1-dimethylcyclobutane is allowed to react with c12 under UV

attached below

Typhoon signals rise due to what? wind speed or wind strength or both?​

Answers

Both it’s based on intensity, size of circulation and the forecast direction, and speed

g Elimination reaction simulation, Kim had tried to prepare cyclohexene from cyclohexanol using HCl as a catalyst, but he got a weird side product cyclohexyl chloride. Cyclohexyl chloride is formed possibly from the side reaction called A. SN1 substitution reaction B. E2 reaction C. E1 reaction D. SN2 substitution reaction

Answers

Answer:

SN1 substitution reaction

Explanation:

cyclohexanol is a secondary alkanol. The mechanism of acid catalysed dehydration of cyclohexanol involves the protonation of the -OH group.

This is followed by loss of water which is a good leaving group. At this stage, a proton could be abstracted to yield cyclohexene by E1 mechanism or an SN1 substitution reaction may occur to yield Cyclohexyl chloride.

The both reactions are equally likely.

Which term can be used to describe the process in the reaction below? 2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)

Answers

Answer:

Decomposition

Explanation:

If we look at the process;

2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)

We can see that NaHCO3 was broken down into Na2CO3, H2O and CO2.

The breakdown of one compound to yield other chemical compounds is known as decomposition.

Hence the NaHCO3 was decomposed in the process above.

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to lowest. CoCl3, NH4Cl, Li2SO4

Answers

Answer:

NH4Cl > Li2SO4 > CoCl3

Explanation:

Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.

Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.

Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.

What happens when Sulphur dioxide (so2) gas is passed through an acidified solution of hydrogen . sulfide (H₂S) gas : ​

Answers

Answer:

When SO

2

is passed through an acidified solution of H

2

S, sulphur is precipitated out according to the reaction.

2H

2

S+SO

2

→2H

2

O+3S

Is it better to use graphite or carbon electrodes during electrolysis if I am trying to investigate volume of gas produced ?​

Answers

Answer:

yes

Explanation:

it is important for electrolysis

43.0 mL of 1.49 M perchloric acid is added to 14.0 mL of calcium hydroxide, and the resulting solution is found to be acidic.

29.1 mL of 0.498 M barium hydroxide is required to reach neutrality.

What is the molarity of the original calcium hydroxide solution?

Answers

Answer:

2.29 M

Explanation:

Equation of the reaction;

Ca(OH)2(aq) + 2HClO4(aq) → 2H2O(l) + Ca(ClO4)2(aq)

Concentration of acid CA = 1.49 M

Concentration of base CB= ????

Volume of acid VA= 43.0 ml

Volume of base VB= 14.0 ml

Number of moles of acid NA = 2 moles

Number of moles of base NB = 1 mole

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

CB= CAVANB/VBNA

CB= 1.49 × 43.0 × 1/14.0 × 2

CB= 2.29 M

A sealed container was filled with 0.300mol H2(g), 0.400mol I2(g), and 0.200mol HI(g) at 870K and total pressure 1.00bar. Calculate the amounts of the components in the mixture at equilibrium given that K.= 70 for the reaction H2(g)+I2(g) --> 2HI(g).

Answers

Answer:

[HI] = 0.704mol

[H2] = 0.048mol

[I2] = 0.148mol

Explanation:

Based on the equilibrium:

H2(g)+I2(g) --> 2HI(g)

The equilibrium constant, K, is defined as:

K = 70 = [HI]² / [H2] [I2]

Where [] could be taken as the moles in equilibrium of each reactant

To know the direction of the equilibrium we need to find Q with the initial moles of each species:

Q = [0.200mol]² / [0.300mol] [0.400mol]

Q = 0.333

As Q < K, the reaction will shift to the right producing more HI. The equilibrium moles are:

[HI] = 0.200mol + 2X

[H2] = 0.300mol - X

[I2] = 0.400mol - X

Replacing in K:

70 = [0.200 + 2X ]² / [0.300 - X] [0.400 - X]

70 = 0.04 + 0.8 X + 4 X² / 0.12 - 0.7 X + X²

8.4 - 49 X + 70 X² = 0.04 + 0.8 X + 4 X²

8.36 - 49.8X + 66X² = 0

Solving for X:

X = 0.252 moles. Right solution

X = 0.502 moles. False solution. Produce negative moles.

Replacing:

[HI] = 0.200mol + 2*0.252 mol

[H2] = 0.300mol - 0.252 mol

[I2] = 0.400mol - 0.252 mol

[HI] = 0.704mol

[H2] = 0.048mol

[I2] = 0.148mol

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