102 - Harder brackets
Find an expression without brackets
for the area of each rectangle.
(x + 3)
area =
12)
No
calc
р
(-9)
Total
area =
121​

Answer:

For figure 1:

Area of rectangle = 7x + 21

For figure 2:

Area of rectangle = [tex]\mathbf{p^2-9p }[/tex]

Step-by-step explanation:

We need to find area of rectangle

The formula used is: [tex]Area\:of\:rectangle=Length\times Width[/tex]

For figure 1:

Length = 7

Width = x+3

Putting values in formula and finding area of rectangle

[tex]Area\:of\:rectangle=Length\times Width\\Area\:of\:rectangle=7\times (x+3)\\Now,\: multiply\:7\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=7(x)+7(3)\\Area\:of\:rectangle=7x+21\\[/tex]

So, area of rectangle = 7x + 21

For figure 2:

Length = p

Width = p-9

Putting values in formula and finding area of rectangle

[tex]Area\:of\:rectangle=Length\times Width\\Area\:of\:rectangle=p\times (p-9)\\Now,\: multiply\:p\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=p(p)-p(9)\\Area\:of\:rectangle=p^2-9p\\[/tex]

So, area of rectangle = [tex]\mathbf{p^2-9p }[/tex]

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