13 In a school, students must study at least one language from German, French and Spanish.
DO NOT WRITE IN THIS AREA
There are 30 students in a class of this school.
Of these students
7 study all three of the languages
10 study both German and French
12 study both Spanish and German
9 study both French and Spanish
16 study Spanish
18 study German
Work out the total number of the students in the class who study French.
You may use the Venn diagram to help with your calculations.

Answer:

38sq yards

Step-by-step explanation:

Separate it into parts

3x2 for the top section

8x4 for the bottom

6+32=38

Answer:

$4

Step-by-step explanation:

2/100 x 200 = 4

Step-by-step explanation:

first number=x

second number=x+2

third number=x+4

(x+2)(x+4)=35

x(x+4)+2(x+4)=35

x²+4x+2x+8=35

x²+6x+8=35

x²+6x=35-8

x²+6x=33

x²+6x-33=0

using that, you can find the first number,

then use the data to find the other two.

Answer:

3+(4*3)=15.....................

Answer:

21

Step-by-step explanation:

3+4=7

7×3=21

you are going to add 3 and 4.

After adding, you multiply 7by 3

giving yout 21

Answer:

Step-by-step explanation:

Start by looking at the face that is closest to the bottom left. It is a hexagon and it makes 1 face.

It is connected to a similar hexagon on the upper right by 6 tiles. So that adds 7 more faces.

The total is 2 hexagons + 6 rectangles = 8 faces.

Step-by-step explanation:

3.92 - uwuehehrvgrsiehhehehhe

Answer:

He has $3.92.

Hope this helps!

Answer:

447 ft

Step-by-step explanation:

Add 417 and 30 together. That will give you the total direct distance between the two. 417+30=447

Answer:

B

Step-by-step explanation:

y = 2x - 4

y + 4 = 2x

x = y/2 + 4/2

x = y/2 + 2

—-

y = x/2 + 2

Answer:

y = x/2 + 2

This is the answer because I got it right on my test.

Answer:

f'(x)=2

Step-by-step explanation:

[tex]if~y=ax^n\\where~a~is~constant.\\\frac{dy}{dx} =a nx^{n-1}\\f(x)=2x-1\\f'(x)=2*1x^{1-1}-0\\=2x^0\\=2*1\\=2[/tex]

1 5/6 + 1 1/3 = 3 1/6

3 1/6 * 60 = 190

Answer:

[tex]A(w) = (40 - w) * w[/tex]

Step-by-step explanation:

Given

[tex]P = 80[/tex] ---- perimeter

Required

Write the area as a function of width

The perimeter of a rectangle is:

[tex]P =2(l + w)[/tex]

Where

[tex]l \to length\\ w \to width[/tex]

So, we have:

[tex]80 = 2*(l+w)[/tex]

Divide by 2

[tex]40 = l + w[/tex]

Make l the subject

[tex]l =40 - w[/tex]

The area of a rectangle is:

[tex]A = l * w[/tex]

Substitute: [tex]l =40 - w[/tex]

[tex]A = (40 - w) * w[/tex]

Hence, the function is:

[tex]A(w) = (40 - w) * w[/tex]

e is the the answer.....

Answer:

BC = 16 B=85 E=85 D=30 C=65

Step-by-step explanation:

Step-by-step explanation:

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

Answer:

6×square + 5× - 4 =o

6×square+(8-3)×-4=0

6×square+8×-3×-4=0

2×(3×+4)-1(3×+4)=0

(3×+4)(2×-1)=0

either,

3x+4=0

3×=-4

×= -4/3

or,

2x-1=0

×=1/2,,

Answer:

every other student who enters the school

Step-by-step explanation:

It is given that the middle school students have an average height of 5.25 feet. The students belongs to Seton Grove School.

It means that every student who comes to this school or enters the school has a height that is around 5 feet or more.

Thus we can say that every other student who enters the school has a average height of 5.25 feet.

This sample makes the generalization about the heights of the school students valid.

Answer:

c

Step-by-step explanation:

correct on edmentum / plato

Step-by-step explanation:

x²– 8x - 7 = 0

(x²-8x+16) -7 = 16

(x²-8x+16) = 16+7

(x-4)² = 23

x-4 = √23

so x= 4+√23 or x= -4√23

Answer:

(5x-8)(x-3)

Step-by-step explanation:

The factor of this equation is 5x-8

So, after the factorization is (5x-8)(x-3)

Answr 2.(1.3)^x

Step-by-step explanation:

Answer:

Step-by-step explanation:

We know that:

We can find one side by distance formula:

Then the perimeter is:

Answer:

b = -6 (Answer d)

Step-by-step explanation:

The slope-intercept equation is y = -2x + b, and we know that the line passes through (-5, 4).  Substitute -5 for x and 4 for y, to obtain:

4 = -2(-5) + b, or

4 = 10 + b, or

b = -6 (Answer d)

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

[tex]v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s[/tex]

Also,

[tex]v=r\omega[/tex]

Where

[tex]\omega[/tex] is the angular speed

So,

[tex]\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s[/tex]

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

Answer:

out of the 100% they took away 15% leaving u with 85% to pay I think, sorry if I'm wrong

Answer:

Yes and Yes

Step-by-step explanation:

If you fold them over on both sides then they overlap perfectly, therefore they are reflective.

Answer:

Nope it isn't linear.

Step-by-step explanation:

Use a coordinate plane. The slope is y = -4x+12. if you plug that in, you will get all of the lines correctly

for instance you put 2,4

4 = -4(2)+12

4 = -8+12

that is true

but if you put in (5,-1)

-1 = -4(5)+12, which is not true

if all of them is true, then it would be true.

if even ONE of them is not true, then the who line is not linear

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete; However, one can deduce from the options that the question refers to percentage change.

I will give two illustrations that shows how to calculate percentage change.

Illustration 1

Consider goods x with the following price change.

[tex]Old = \$45[/tex]

[tex]New = \$55[/tex]

The percentage change is:

[tex]\%Change = \frac{New - Old}{Old} * 100\%[/tex]

[tex]\%Change = \frac{55-45}{45} * 100\%[/tex]

[tex]\%Change = \frac{10}{45} * 100\%[/tex]

[tex]\%Change = \frac{1000}{45} \%[/tex]

[tex]\%Change = 22.22\%[/tex]

This means there is a 22.22% increase

Illustration 2

Consider goods x with the following price change.

[tex]Old = \$45[/tex]

[tex]New = \$35[/tex]

The percentage change is:

[tex]\%Change = \frac{New - Old}{Old} * 100\%[/tex]

[tex]\%Change = \frac{35-45}{45} * 100\%[/tex]

[tex]\%Change = \frac{-10}{45} * 100\%[/tex]

[tex]\%Change = -\frac{1000}{45} \%[/tex]

[tex]\%Change = -22.22\%[/tex]

The negative sign indicates percentage decrease

So, this means there is a 22.22% decrease

Answer: The area, in square feet, of the piece of wood is [tex]32 ft^{2}[/tex].

Step-by-step explanation:

Give: Length = 8 feet

Width = [tex]\frac{1}{2} \times 8[/tex] = 4 feet

As piece of wood is similar to that of a rectangle. Hence, formula to calculate area is as follows.

[tex]Area = length \times width[/tex]

Substitute the values into above formula as follows.

[tex]Area = length \times width\\= 8 feet \times 4 feet\\= 32 ft^{2}[/tex]

Thus, we can conclude that the area, in square feet, of the piece of wood is [tex]32 ft^{2}[/tex].

Answer: x=2

Step-by-step explanation:

15x-10=10 + 6+ 2x

15x-2x=20+6

13x=26

X=2

Answer:

x = 2

Step-by-step explanation:

2.5(6x - 4) = 10 + 4(1.5 + 0.5x)

Distribute the 2.5

15x - 10 = 10 + 4(1.5 + 0.5x)

Distribute the 4

15x - 10 = 10 + 6 + 2x

Combine like terms

15x - 10 = 16 + 2x

Add 10 to both sides

15x = 26 + 2x

Subtract 2x from both sides

13x = 26

Divide both sides by 13x

x = 2

Answer:

B., E.

Step-by-step explanation:

what was the difficulty ? this is just to understand the movement of a thrown rock.

what happens, when you throw a rock through the air ? it will first move up a little bit, reaches a maximum height, and then drops down again.

that is what the graphic shows.

so, can A. be correct ? no. as we move from 0 seconds to the right (time passes) the height of the rock increases first (before decreasing again later on).

can C. be correct ? no, it would mean that the function would look the same on both sides of the x-axis. this is clearly impossible.

can D. be correct ? no, nowhere in the graph is the height (= the functional value, the y to the x) negative.

can F. be correct ? no, we clearly see the maximum height at 1.5 seconds. at 3 seconds the height is actually at its minimum.