Answer:
$11,280
Step-by-step explanation:
Plug in 150 as p into the equation to solve for the cost, C:
C = 30 + 75p
C = 30 + 75(150)
C = 30 + 11,250
C = 11,280
= $11,280
Determine if the ordered pair (6, 4) is a solution to the inequality
Answer:
[tex]\Large \boxed{\mathrm{Option \ D}}[/tex]
Step-by-step explanation:
(6, 4)
x = 6 and y = 4
y > -1/2x + 7
Plug in the values to check if it is true.
4 > -1/2(6) + 7
4 > -3 + 7
4 > 4
This statement is false.
(6, 4) lies on the line.
What's the correct answer to this..? Need help
Answer:
A.
Step-by-step explanation:
All of those graphs represent functions. You are able to tell because they all pass the vertical line test. The vertical line test is conducted by drawing a line that goes vertically and intercepts any point of the line in question. If the function crosses the vertical line twice, it is not a function. If it only intercepts once, it is a function. In this case, every graph is a function because they would intercept a vertical line once.
I need help pls and I will give a 5 star rating and a big thank you comrades.
Answer:
Option (C) : y = 6 / 11
Step-by-step explanation:
To find Horizontal Asymptote of the function, you need to see degree of of numerator and denominator.
Since, the degrees of the numerator and denominator are the same,
Horizontal Asymptote = leading coefficient of the numerator divided byleading coefficient of the denominator
Therefore,
Horizontal Asymptote = 6 / 11
In the diagram, TC represents a vertical building. The points, A and B, are on the same level as the foot C of the building such that ATC = 40° and BTC = 56°. If BT is 29 m longer than AT, find
(a) the height of the building,
(b) the distance AB.
Answer:
(a) The height of the building is 60.06 m
(b) The distance AB is 139.43 m
Step-by-step explanation:
The given parameters are
Given that segment BT = segment AT + 29
By trigonometric ratios, we have;
cos∠ATC = CT/AT
cos∠BTC = CT/BT
Therefore, we have;
cos(40°) = CT/AT.................................(1)
cos(56°) = CT/BT = CT/(AT + 29).....(2)
cos(56°) = CT/(AT + 29)......................(3)
From equation (1)
CT = AT×cos(40°)
From equation (3)
AT×cos(56°) + 29 × cos(56°) = CT
Therefore;
AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)
AT×cos(40°) - AT×cos(56°) = 29 × cos(56°)
AT×(cos(40°) - cos(56°)) = 29 × cos(56°)
AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m
TC = CT = AT×cos(40°) = 78.4×cos(40°) = 60.06 m
The height of the building = 60.06 m
(b) BT = AT + 29 = 78.4 m + 29 m= 107.4 m
AB = AT×sin(∠ATC ) + BT×sin(∠BTC) = 78.4×sin(40°) + 107.4×sin(56°) = 139.43 m
The distance AB = 139.43 m.
Double a number decreased by 25.6 is equal to 90 Find the number
Answer:
Step-by-step explanation:
2x-25,6=90
2x=90+25,6
2x=115,6
x=57,8
Answer:
The number is 57.8
Step-by-step explanation:
Let x = number
2x -25.6 = 90
Add 25.6 to each side
2x-25.6 +25.6 = 90+25.6
2x=115.6
Divide by 2
2x/2 =115.6/2
x =57.8
Solve for 'x' in both of the following problems. Show all your work/explanations on your own paper and then submit a picture of your work and answers in the dropbox below.
Answer/Step-by-step explanation:
1. <B is an inscribed angle intercepting arc CA.
Therefore, m<B = ½*128 (inscribed angle theorem)
m<B = 64°
x = 180 - (m<B + m<A) (sum of angles in a triangle)
x = 180 - (64 + 43)
x = 180 - 107 = 73°
2. [tex] KH*HI = JH*HG [/tex] (intersecting chords theorem)
[tex] 10*x = 14*5 [/tex]
Solve for x
[tex] 10x = 70 [/tex]
[tex] \frac{10x}{10} = \frac{70}{10} [/tex]
[tex] x = 7 [/tex]
Find the value of cotA x sinA x secA.
Answer:
The value = 1
Step-by-step explanation:
Here in this question, we are interested in calculating the product of the trigonometric identities given.
To adequately calculate this correctly, we shall need to express the trigonometric identities in their normal division form which is as follows ;
Mathematically;
cotA = 1/tanA
let’s leave sin A
sec A = 1/cos A
So inputing the values of the following, we have ;
1/tan A * sin A * 1/cos A
This can be written as;
1/tan A * sin A/cos A
Mathematically; sinA/cos A = tan A
making that substitution, we have;
1/tan A * tan A
= tan A/tan A = 1
if a man works 400km in 6 minutes.How long will he work in 9 minutes
Answer:
600 kmStep-by-step explanation:
400 km = x
6 min 9 min
cross multiply:
6x = 400 ( 9)
x = 3600 / 6
x = 600 km
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Answer:
A: 2:30
B: 13:15.
C: 4:05 A.M
D: 3:25 P.M
Step-by-step explanation:
Answer:
a) 0230 hours
b) 1315 hours
c) 4:05 am
d) 3:25 pm
Step-by-step explanation:
To change a 12 hour clock to a 24 hour clock, note that when it hits p.m., anything over 12 p.m. will have the number added to it.
a) 2:30 am
2:30 am is earlier than 12 pm, therefore, 0230 is your answer. Remember, you must place the 0 in the front to not confuse a user that the 2 is in the tens place value.* *Essentially, use military time:
b) 1:15 pm
1:15 pm is later than 12 pm, therefore, add 12 to the 1 in the hours. Use military time:
0115 + 1200 = 1315
1315 hours is your answer.
To change a 24 hour clock to a 12 hour clock, note the time frame in which the time is given. if over 1200, then subtract by 12, and add the p.m.
0405 = 4:05 am.
1525 = 12 pm + 3:25 = 3:25 pm.
~
WILL GIVE BRAINLIEST
intercept is the length from origin to intersection point of respective axis,
it intersects x axis at -7.5 and y is 0 so x intercept is (-7.5,0)
and similarly, y intercept is (0,5.5)
Answer:
(- 7.5, 0 ) and (0, 5.5 )
Step-by-step explanation:
The x- intercept is the value of x on the x- axis where the line crosses.
Here the line crosses the x- axis at - 7.5 , thus the coordinates of x- intercept
(- 7.5, 0 )
The y- intercept is the value of y on the y- axis where the line crosses.
Here the line crosses the y- axis at 5.5 thus the coordinates of the y- intercept
(0, 5.5 )
*This Question Has 3 Questions in it
Question 1 Use a calculator to find [tex]\sqrt{61.6}[/tex] to the nearest hundredth.
Question 2 Which of the following statements is true?
Refer to Question 2 . PNG
Question 3 simplify [tex]\sqrt{0.81}[/tex]
Answer:
Ques 1: 7.85
Ques 2: both [tex]\sqrt{0.25}[/tex] and [tex]-\sqrt{16}[/tex] are rational.
Ques 3: 0.9
Step-by-step explanation:
Ques 1:
Solving the [tex]\sqrt{61.6}[/tex], we get 7.8485.
Rounding off to nearest hundredth, we see that next digit is 8, so we increase the previous digit by 1.
So, the answer to nearest hundredth is 7.85.
Ques 2:
[tex]\sqrt{0.25}[/tex] and [tex]-\sqrt{16}[/tex]to be checked whether they are rational or irrational.
We know that [tex]\sqrt{16}[/tex] is equal to 4.
[tex]-\sqrt{16}[/tex] = -4 which is a rational value.
Let us solve [tex]\sqrt{0.25}[/tex] now.
[tex]\sqrt{0.25} = \sqrt{\dfrac{25}{100}}\\\Rightarrow \dfrac{5}{10}[/tex]
Which is a rational value.
So, both are rational.
Ques 3:
Simplify [tex]\sqrt{0.81}[/tex]
0.81 can be written as [tex]\frac{81}{100}[/tex] in rational form.
Now, taking the square root, we need to take the square root for both Numerator and Denominator and then we can divide to get the desired square root.
[tex]\sqrt{0.81} = \sqrt{\dfrac{81}{100}}\\\Rightarrow \dfrac{9}{10} = \bold{0.9}[/tex]
So, the answers are:
Ques 1: 7.85
Ques 2: both [tex]\sqrt{0.25}[/tex] and [tex]-\sqrt{16}[/tex] are rational.
Ques 3: 0.9
Rodrigo and his cousin have 8 bags of marbles. Some of the bags contain 5 white marbles. The rest of the bags contain 7 pink marbles. They have 48 marbles in all. How many bags of each color marble do the cousins have?
Answer:
The cousins have 4 bags of white marbles and 4 bags of pink marbles.
Step-by-step explanation:
If x is the number of bags with white marbles and y is the number of bags with pink marbles, we can write the following system:
x + y = 8 -- Equation 1
5x + 7y = 48 -- Equation 2
5x + 5y = 40 -- Equation 3 (Multiply Equation 1 by 5)
2y = 8 -- (Subtract Equation 3 from 2)
y = 4 -- (Divide both sides by 2)
x + 4 = 8 -- (Substitute y = 4 into Equation 1)
x = 4 -- (Subtract 4 from both sides)
I need help please :(
Answer:
[tex] 5^{-3} = \dfrac{1}{125} [/tex]
Step-by-step explanation:
Rule of negative exponents:
[tex] a^{-n} = \dfrac{1}{a^n} [/tex]
This problem:
[tex] 5^{-3} = \dfrac{1}{5^3} = \dfrac{1}{5 \cdot 5 \cdot 5} = \dfrac{1}{125} [/tex]
Answer:
[tex]\boxed{\frac{1}{125}}[/tex]
Step-by-step explanation:
[tex]5^{-3}[/tex]
Apply rule:
[tex]\displaystyle a^{-b}=\frac{1}{a^b}[/tex]
[tex]\displaystyle 5^{-3}=\frac{1}{5^3}= \frac{1}{125}[/tex]
Donny has three times as many candy canes as Marc. Marc has thirty more candy canes than Bob. They have 500 candy canes altogether. How many candy canes does Donny have?
Answer:
318
Step-by-step explanation:
Bob=x
Marc=x+30
Donny=3(x+30)
x+x+30+3x+90=500
5x=500-120
5x=380
x=76
Bob has x = 76
Marc has x+30=106
Donny has 3*112=318
318+106+76=500
Do the ratios 2/3 and 12/18 form a proportion?
yes
no
Answer:
Yes
Step-by-step explanation:
Because 12/18 = 2/3..(cancel 12 and 18 by 6)
Answer:
yes
Step-by-step explanation:
2x6=12
3x6=18
6 is the multiplying number
( the 2 equations are the same amount )
Write an expression that can be used to find the price of a television that is on sale for 20% off the regular price of p dollars. Can you write a second expression equivalent to the one you wrote in the last questions.
Answer:
The expression that could help calculate the price of the TV is;
$P - 20% of $P
Step-by-step explanation:
Here, we want to write an expression that corresponds to the price of a television set that is on sale at a price which is 20% off the regular price.
From the question, we can see that the regular price is $P
So now we are having 20% off;
This corresponds to;
20/100 * p = p/5 = 0.2p
So in the expression form, we can have;
$P - 20% of $P
A student earned grades of , , , , and . Those courses had the corresponding numbers of credit hours , , , , and . The grading system assigns quality points to letter grades as follows: A4; B3; C2; D1; F 0. Compute the grade point average (GPA) as a weighted mean and round the result with two decimal places. If the Dean's list requires a GPA of 3.00 or greater, did this student make the Dean's list
Answer:
grade point average (GPA) as a weighted mean = 3.14
Yes, student makes the Dean's list.
Step-by-step explanation:
Since the data is not given I will explain the question with a relevant example:
For example
Data:
Students grades are: A, C, B, A, D
The corresponding number of credit hours: 3, 3, 3, 4, 1
The grading system assigns quality points to letter grades as:
A = 4
B = 3
C = 2
D = 1
F = 0
To find:
grade point average (GPA) as a weighted mean
If the Dean's list requires a GPA of 3.00 or greater, did this student make the Dean's list?
Solution:
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]
Here
Using the earned grades of A, C, B, A, D and corresponding quality points to these letter grades we get:
A = 4
C = 2
B = 3
A = 4
D = 1
So the values in x[tex]_{i}[/tex] are:
x
4
2
3
4
1
Now the number of credit hours are represented as weights w[tex]_{i}[/tex] :
w
3
3
3
4
1
In order to calculate weighted mean first multiply x[tex]_{i}[/tex] with w[tex]_{i}[/tex]
x[tex]_{i}[/tex] w[tex]_{i}[/tex]
4 * 3 = 12
2 * 3 = 6
3 * 3 = 9
4 * 4 = 16
1 * 1 = 1
The sum of x[tex]_{i}[/tex] w[tex]_{i}[/tex] is :
Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 12 + 6 + 9 + 16 + 1 = 44
Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 44
Now compute the sum of w[tex]_{i}[/tex]
Σw[tex]_{i}[/tex] = 3 + 3 + 3 + 4 + 1 = 14
Σw[tex]_{i}[/tex] = 14
Putting the values in the weighted mean formula:
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]
= 44 / 14
= 3.1429
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex] = 3.14
Since the Dean's list requires a GPA of 3.00 or greater and the grade point average (GPA) as a weighted mean of the student is 3.14 so the student makes the Dean's list because his/her GPA is higher than 3.00
A radioactive substance decays exponentially. A scientist begins with 350 milligrams of a radioactive substance. After 14 hours, 175 mg of the substance remains. How many milligrams will remain after 20 hours
Answer:
N(t)=N∗.5t/h where n(t) is amount of substance left, N = initial amount, t = current time, and h = half-life time.h = 24 hours t= 45 hours, N = 130mg
therefore, N(t)=130∗.545/24=35.44mg
Step-by-step explanation:
N(t)=N∗.5t/h where n(t) is amount of substance left, N = initial amount, t = current time, and h = half-life time.h = 24 hours t= 45 hours, N = 130mg
therefore, N(t)=130∗.545/24=35.44mg
Answer:
≈ 130 mg
Step-by-step explanation:
This is about the half-life of the substance.
There is a formula for this kind of calculations:
N(t)= N₀*(0.5)^(t/T), where
N(t) = substance left after time period of t,t = time passed,N₀ = initial amount of the substance,T = hal-life time of the given substance.In our case, we have:
N₀ = 350 mg,t= 20 hours,T = 14 hours as half of substance decays during this time period,And the calculation:
N(20)= 350*(0.5)^(20/14)N(20) ≈ 130 mgAnswer: about 130 mg of substance remains after 20 hours
look at the image to get ur question thank u for ansering
Answer:
y = 3x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate the slope using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (- 1, 0) ← 2 points on the line
m = [tex]\frac{0-3}{-1-0}[/tex] = [tex]\frac{-3}{-1}[/tex] = 3
The line crosses the y- axis at (0, 3) ⇒ c = 3
y = 3x + 3 ← equation of line
what is the square root of 450
Answer:
[tex]15\sqrt{2}[/tex] or 21.2132
Step-by-step explanation:
[tex]\sqrt{450}[/tex]
[tex]\sqrt{15^{2} }[/tex] (root of a product is equal to the product of the roots of each factor)
[tex]\sqrt{15^{2} } \sqrt{2}[/tex] (simplify)
[tex]15\sqrt{2}[/tex] or ≈ 21.2132
Answer:
[tex]15\sqrt{2}[/tex] or 21.213
Step-by-step explanation:
For radical form: think of multiples of 450. Think of a pair that contains one perfect square, particularly the higher, the better . These 2 numbers are 25 and 18. 25 is the perfect square number since the two numbers that multiply to be 25 is 5 and 5.
Now take the perfect square of 25 and put it outside of the radical. The 18 remains inside: [tex]5\sqrt{18}[/tex]
Now, since 18 is a high number that needs to get reduced, do the same for 18 as we did for 450--find two numbers, one of which is a perfect square. These two numbers are 9 and 2.
Now take the perfect square of 9. This is 3. Take it out of the radical so that only the two remains inside. The 3 will now multiply with the 5: [tex]5*3\sqrt{2}[/tex]
Multiply 5 and 3 to get 15. The 15 stays outside the radical. Your answer is:
[tex]15\sqrt{2}[/tex]
Whats the volume of a ball if diameter is 17
Answer:
818.8333333 *pi
or
Using the pi button on the calculator
2572.440785
Using 3.14 for pi
2571.13666666
Step-by-step explanation:
We need the radius
r = d/2
r = 17/2 = 8.5
We can find the volume using
V = 4/3 pi r^3
V = 4/3 pi ( 8.5)^3
V =818.8333333 *pi
Using the pi button on the calculator
2572.440785
Using 3.14 for pi
2571.13666666
In the expression 3x^2+y+-5 which of the following choices is the exponent in the term 3x^2?
A. 3
B. 2
C. X
D. None of these choices
Answer:
2
Step-by-step explanation:
3x^2
The coefficient is 3
The variable is x
The exponent is 2
commom difference of an AP -4 , -4 , -4 ,............is...
Answer:
0
Step-by-step explanation:
Common Difference = Difference between any two consecutive terms
= - 4 - (-4)
= - 4 + 4
= 0
or what value of g does the function f(g) = g2 + 3g equal 18?
Answer:
The 2 values that makes the function equal to 18 is 3 and -6
Step-by-step explanation:
First you can convert the quadratic equation from standard form to root form
Step 1: Substitute f(g) = 18
Step 2: Move 18 to the other side to create
0 = g² + 3g - 18
Step 3: Now we rearrange equation from standard form into root form
Step 4: Find what adds to 3 and multiples to -18
-3 and 6 adds to 3 and multiples to -18
Step 5: Now we substitute -3 and 6 into the root equation
0 = (g-3)(g+6)
Step 6: Set the brackets to 0 and solve
g - 3 = 0
g = 3
g + 6 = 0
g = -6
The fraction subtracted from 5/3 to get 1 is_____
Answer:
2/3
Step-by-step explanation:
I am not sure
Answer:
2/3Step-by-step explanation:
[tex]Let \:the \: unknown \: fraction \: be \: x\\\\\frac{5}{3} -x = 1\\\\\frac{5}{3}-x=1\\\\\mathrm{Subtract\:}\frac{5}{3}\mathrm{\:from\:both\:sides}\\\\\frac{5}{3}-x-\frac{5}{3}=1-\frac{5}{3}\\\\\frac{5}{3}-x-\frac{5}{3}=-x\\\\1-\frac{5}{3}=-\frac{2}{3}\\-x=-\frac{2}{3}\\\\x=\frac{2}{3}\\[/tex]
if the side length of a square can be represented by 4x + 4 and its area is 1024 square units, find the value of x
Answer:
x = 7
Step-by-step explanation:
Since it’s the area of a square, we can simply do square root of 1024. (Because to get area of square you do side x side). Which is 32.
So basically 4x + 4 = 32... x = 7
Answer:
x = 7
Step-by-step explanation:
A = 1024
side length of a square = 4x + 4
A = s²
s = √A
s = √1024
s = 32
using the side length to get the value of x
s = 32
4x + 4 = 32
4x = 32 - 4
x = 28 / 4
x = 7
check:
A = side length * side length
A = (4x + 4) * (4x + 4)
A = (4*7 + 4) * (4*7 + 4)
A = 32 * 32
A = 1024 ok
What’s the difference between rational and irrational numbers?
Answer:
rational numbers are perfect squares irrational numbers are non terminating/go on forever
Step-by-step explanation:
Owen made 60% of the shots he attempted during his hockey practice. He made 18 shots. How many shots did Owen attempt during his hockey practice?
Answer:
11 shots
Step-by-step explanation:
60% of 18 = 10.810.8 rounded = 11Why we did this:
Owen made 60% of the shots he made, and he made 18 shots in total. Therefore, we would take 60% of 18.The answer we get is 10.8, but we can't have a part of a shot. That wouldn't make sense. Therefore, we have to round up to 11 shots.So therefore, Owen made 11 of 18 shots he attempted.
Owen attempted 11 shots during the hockey practice.
Number of shots attempted by Owen = 18
Percentage of shots made = 60%
Then, the number of shots made will be calculated as:
= Percentage of shots made × Number of shots attempted
= 60% × 18
= 60/100 × 18
= 0.6 × 18
= 10.8 shots
= 11 shots approximately
In conclusion, Owen made 11 shots
Read related link on:
https://brainly.com/question/18298965
A set of furniture was sold for GH cedis 3000 at a profit of 25%. Find the cost price.
Answer:
2400GH CedisStep-by-step explanation:
[tex]Selling \:price = 3000gh Cedis\\Profit \% = 25\%\\Cost\:price =?\\\\CP =\frac{ ( Selling\:price \times 100 )}{ ( 100 + percentage profit)} \\\\C.P = \frac{3000\times 100 }{100+25}\\\\ C.P = \frac{300000}{125} \\\\Cost\: Price = 2400gh Cedis[/tex]
You move at 45/mph and a bullet is shot at you, the bullet is moving at 44/mph
Would you be able to dodge the bullet, you factor in the fight or flight or freeze response
Answer:
See explanation below.
Step-by-step explanation:
A bullet shot at you will definitely hit you because of the direction it is travelling.
Your fight and flight response won't be activated either because of the speed of the event (bullet) or if you don't know how harmful a gun is (you'll remain calm/ignorant in this case)?
Try to post academic problems.
Best Regards!