Answer:
m = image distance/object distance
m=35/15=7/3
f=uv/(u+v)
35*15/(35+15)
f=10.5cm
1.How many significant digits are in 101,407,063?
Answer:
= 9
Explanation:
just count the numbers :D
I need help answering this question. Thanks!
Answer:
459.195 (N).
Explanation:
in order to calculate the required value of the Fₓ:
Fₓ=F*cos(37°); Fₓ=575*0.7986≈459.195 (N).
For more info see the attachment (note, the required force Fₓ is marked with red colour).
Lois Price came up with a brilliant idea of creating a 1,500m perfectly circular track. In order to do so she wanted
to know her distance and displacement at four different locations. Starting at the TOP of the circle, what are her
distance and displacement if she travels... (HINT - Remember the circumference of a circle)
a. quarter way around the track
Isoo
b. half way around the track
4
Р A
C. 4 around the track
d. an entire lap
dist = 375
Her distances and displacement are;
[tex]\begin{array}{|l|c|c|}\mathbf{Location}&\mathbf{Displacement}&\mathbf{Distance}\\&&\\a. \ Quarter \ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m &375 \ m\\&&\\b. \ Half \ way \ around&\dfrac{1500}{\pi} m&750 \ m\\&& \\C. \ Three \ quarter\ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m&1,125 \ m\\&&\\d. \ Entire \ lap&0&1,500 \ m\\\end{array}\right][/tex]
The reason the above values are correct are as follows:
The known details are:
The length of the circular track, C = 1,500 m
The required details;
Her distance and displacement at four locations starting at the top of the circle, as follows;
At the top, the starting point, the displacement = The distance = 0
a. A quarter way round the track;
The radius of the circular track, r = C/(2·π)
∴ r₁ = 1,500 m/(2·π) = (750 m)/π
The displacement a quarter way round the track, s₁² = r² + r²
∴ s₁² = ((750 m)/π)² + ((750 m)/π)²
s₁ = ((750 m)/π)·√2
The displacement a quarter way round the track, s₁ = ((750·√2)/π) m
The distance a quarter way round the track, d₁ = C/4
∴ d₁ = 1,500 m/4 = 375 m
The distance a quarter way round the track, d₁ = 375 m
b. The displacement half way around the track, s₂ = r + r
∴ s₂ = r + r = (750 m)/π + (750 m)/π = (1,500 m)/π
The distance moved half way round the circular track, d₂ = C/2
∴ d₂ = 1,500 m/2 = 750 m
The distance moved half way round the circular track, d₂ = 750 m
C. The displacement 3/4 way round the track, s₃ = s₁ = (750 m)/π)·√2
The distance moved 3/4 way round the circular track, d₃ = (3/4) × 1,500 m = 1,125 m
D. The displacement for an entire lap, which is back to starting point at the TOP, s₄ = 0
The distance traveled in one lap = The circumference of the track, C = 1,500 m
Therefore, we have the following displacement and distances at the four different locations;
[tex]\begin{array}{|l|c|c|}\mathbf{Location}&\mathbf{Displacement}&\mathbf{Distance}\\&&\\a. \ Quarter \ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m &375 \ m\\&&\\b. \ Half \ way \ around&\dfrac{1500}{\pi} m&750 \ m\\&& \\C. \ Three \ quarter\ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m&1,125 \ m\\&&\\d. \ Entire \ lap&0&1,500 \ m\\\end{array}\right][/tex]
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If I am trying to test which brand of battery lasts the longest, what is my independent variable? My dependent variable?
Answer:
• Independent - brands of battery• Dependent - how long is time that the battery will lastExplanation:
Independent variable is the one you manipulate.Dependent variable is the one that you observe.Answer the following below.
Answer:
1. Radiation
2.Conduction
3.Radiation
4.Convertion
5.Convection
6.Conduction
7.Convertion
8.Conduction
Calculate the velocity of the object in the graph above using the equation for a slope.
Answer:
v=d/t
50/5
=10m
is the velocity
1.How many significant digits are in 101,407,063?
Answer:
There are 9 significant digits in 101,407,063.
Explanation:
Significant figures are the digits of a number that are meaningful in terms of accuracy. The include any non-zero digit, zeros between non-zero digits, and trailing zeros only when there is a decimal point.
Explain why circular motion includes continuous
acceleration even when the speed does not change
A helicopter flies 25 km north, 5 km east, then 5 km S, then 15 km W. What is the resultant displacement and direction of the helicopter? Solve using graphical or mathematical methods. Be sure to either show work or explain your graphical methods.
Answer:
Explanation:
Plotting the original location of the helicopter before it flies 25 km north, it would be at the origin, (0,0) then after it flies north, the y vertex gains 25 points, so it would be (0,25)
After it flies east, the x coordinate gains 5 points, so it would now be (5,25)
After it flies south, the y coordinate loses or is subtracted by 5 points. so it would now be (5,20)
After flying west, the x coordinate loses 15 points. So the final vertex would be at (-10,20)
East = Right
West = Left
South= Down
North = Up
I used mainly mathematical methods by adding and subtracting the x and y coordinate values, but this could be graphed easily since I gave the coordinates just incase!
Hope this helps!
Answer:
Explanation:
D = Xf - X
D = 15km West - 25km North
D = -10km West
An alternating voltage of 25.0 V is connected across the primary coil of a transformer.
Input Voltage 25 V
ind Output Voltage
50 V Output Current
Input Current 5 A
What is the current across the secondary coil? A 2.5 A C 250 A B D 5.0 A 500 A
Answer:
A
Explanation:
Wattage = E * I
E = 25
I = 5
Wattage = 25 * 5
Wattage = 125
The secondary, in an ideal transformer has the same wattage.
125 = 50 * I Divide by 50
125/50 = I
I = 2.5
a grey kangaroo can lead a distance of 10m on horizontal ground. what is the minimum takeoff speed for such a leap?
show your work please!!
The minimum speed with which a projectile will travel a range is given by the speed when the given range is taken as the maximum range for the given speed
The minimum takeoff speed for such a leap is approximately 9.9 m/s
The known parameter is the distance a grey kangaroo can leap = 10 meters
The required information is the minimum takeoff speed for the leap
Solution:
The path of motion of the kangaroo as they leap is the path of a projectile
The distance of the leap is the range of the projectile
The formula for the maximum range is presented as follows;
[tex]Maximum \ range, R = \mathbf{ \dfrac{v_0^2 }{g}}[/tex]
v₀ = The initial speed of the kangaroo
g = The acceleration due to gravity ≈ 9.81 m/s²
The minimum speed to reach a maximum range of, R = 10 meters is found as follows;
[tex]\mathbf{ Maximum \ range, R} = 10 \, m = \dfrac{v_0^2 }{9.81 \ m/s^2}[/tex]
Therefore;
v₀² = 10 m × 9.81 m/s² = 98.1 m²/s²
v₀ = √(98.1 m²/s²) ≈ 9.9 m/s
The minimum takeoff speed for the kangaroo to leap 10 meters on horizontal ground, v₀ ≈ 9.9 m/s
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Write electronic configuration of calcium on the basis of sub shell?
Answer:
Use Aufbau's principle,
1s^2,2s^2,2p^6,3s^2,3p^6,4s^2
Fill 20 electrons,
Max number of electrons that sub shells can hold,
s=2
p=6
d=10
f=14
The satellite in the diagram has gravitational potential energy because of which of the following? Choose all that apply.
It has mass.
It is moving around Earth.
It has height above Earth's surface.
It is attracted by gravity toward Earth.
This question deals with the concept of Gravitational Potential Energy.
The gravitational potential energy of an object is the energy possessed by the object due to its position in the gravitational field.
The value of gravitational potential energy of an object is given by the following formula:
P.E = mgh
where,
P.E = Gravitational Potential Energy
m = mass of the object
g = acceleration due to gravity
h = height of the object in the gravitational field
According to this formula, the object (satellite) has gravitational potential energy due to the following:
It has mass (m).
It has a height above Earth's surface (h).
It is attracted by gravity toward Earth (g).
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723 grams to kilograms
Answer:
we know that 1 kg = 1000g
therefore ;
1g = 1/1000 kg
723g = 723/1000
= 0.723kg is answer
.Why does the tension in each chain of a
carrying a child increase as an adult pulls the
swing backward?
PLEASE ANSWER!!!!!!!!! WILL GIVE BRAINLIEST!!!
Physical Science is the study of ____.
energy
matter
how matter and energy interact
all answers are true
Physics is the study of matter, energy and the interactions between them. So, all the answers are true.
What is meant by energy ?Energy is defined as the measurement of ability to do work.
Here,
Energy is the measurement of ability do work, which is a physical property of matter. Energy is of various types such as kinetic energy, potential energy, thermal energy, electrical energy, heat energy, etc. Energy and its applications are associated with many laws. The study of energy and the laws associated with them is one of the main branch of physics.
Matter is defined as the substance that has a specific mass and occupies physical space. Atomic particles such as electrons, protons and others are material particles. Thus the study of these matter and material particles is an important branch of physics.
Matter and energy in nature interacts in many ways. Material particles moving moving with particular kinetic energy is an example of matter-energy interactions. These interactions and their studies comes under physics.
Hence,
Physics is the study of matter, energy and the interactions between them. So, all the answers are true.
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#SPJ2
Abigail Folgers’s dying words were ?
Answer:
"My God is an amazing God."
What’s important about physical health
Answer:
Physical activity or exercise can improve your health and reduce the risk of developing several diseases like type 2 diabetes, cancer and cardiovascular disease. Physical activity and exercise can have immediate and long-term health benefits. Most importantly, regular activity can improve your quality of life.
Explanation:
hope it is helpful for you keep smilingA baseball player hits a ball out of the park and runs the bases which are 90 ft apart. What are the distance and displacement traveled?
Answer:
The distance is [tex]360[/tex] feet, and the displacement is [tex]0[/tex].
Explanation:
A baseball player hits a ball out of the park and runs the bases which are [tex]90[/tex] feet apart.
Distance [tex]=4(90)[/tex]
[tex]= 360[/tex] feet.
The displacement is [tex]0[/tex] since the player begins and ends at home plate.
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A basket contains 7 white cats and 15 black cats. What is the ratio of the number of white cats to the number of black cats?
A liquid has a
constant temperature
definite shape
crystal structure
definite volume
The right answer is : Definite Volume
You must be the change you wish to see in the world
Light travels at a speed if 186,000 miles per second. A light-year is the distance that light travels in one year. What is the distance of a light year (in miles)?
Answer:
5,865,696,000,000 miles
Explanation:
one year = 31536000 second
31536000 × 186000 = 5,865,696,000,000
which diagram shows the correct path of light through the glass
Explanation:
When light travels from a rarer to a denser medium, it bends towards the normal. And when light travels from denser to rarer medium, it bends away from the normal. Also, from the diagram, it is clear that emergent ray will always be parallel to the incident ray.
Plz answer this question
The answer will be pressure.
Pressure is force per unit area.
What is the difference between the temperatures on Earth and the moon?
Answer:
The earth is hotter
Explanation:
the average temperature on earth is 57 degrees Fahrenheit the average on the moon is -298 degrees Fahrenheit
In Hindu chronology, the longest time measure is a para. One para equals 311 040 000 000 000 years. Calculate this value in megayears, hours and in seconds. Write your answers in scientific notation.
A para equals [tex]3.110\times 10^{8}[/tex] megayears, [tex]2.725\times 10^{18}[/tex] hours and [tex]9.809\times 10^{21}[/tex] seconds, respectively.
This is an unit conversion problem, in this question we need to convert a value in Hindu units into SI units. A megayear equals [tex]10^{6}[/tex] years, a year equals 8760 hours and a hour equals 3600 seconds. Now we proceed to perform all required conversions:
Megayears
[tex]x = 1\,para \times \frac{311040000000000\,yr}{1\,para} \times \frac{1\,Myr}{10^{6}\,yr}[/tex]
[tex]x = 311040000\,Myr[/tex]
[tex]x = 3.110\times 10^{8}\,Myr[/tex]
Hours
[tex]x = 1\,para \times \frac{311040000000000\,yr}{1\,para} \times \frac{8760\,h}{1\,yr}[/tex]
[tex]x = 2.725\times 10^{18}\,h[/tex]
Seconds
[tex]x = 1\,para \times \frac{311040000000000\,yr}{1\,para} \times \frac{8760\,h}{1\,yr} \times \frac{3600\,s}{1\,h}[/tex]
[tex]x = 9.809\times 10^{21}\,s[/tex]
A para equals [tex]3.110\times 10^{8}[/tex] megayears, [tex]2.725\times 10^{18}[/tex] hours and [tex]9.809\times 10^{21}[/tex] seconds, respectively.
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Which two types of energy does a book have as it falls to the floor?
A. Kinetic energy
B. Nuclear energy
C. Light energy
D. Magnetic energy
E. Potential energy
Answer:
A and E
Explanation:
because of gravitational pull
Answer:
Its A and E :))
Explanation:
Engineers design a system for heating the air in a house. They want the
heater to bring the temperature to a comfortable level and then maintain it.
Which option describes how the engineers should design the system?
O A. Include a control in the system that minimizes the difference
between the amounts of input and output.
B. Build in a control that uses negative feedback to minimize the
amount of change in the system.
C. Build a control into the system that causes input to always be
slightly less than output.
D. Include a control in the system that provides positive feedback
between the input and the output.
SUBMIT
can someone please help me with these
Answer:
1000mg = 1g
160cm = 1600mm
109g = 0.109kg
250m = 0.25km
14km = 14000m
1L= 1000ml
480cm = 4.8m
27g = 0.027kg
198g = 0.198kg
75ml = 0.075L
50cm = 0.5m
5L = 5000mL
16cm = 160mm
65g = 65000mg
2500m = 2.5km
355ml = 0.355L
8mm = 0.8cm
6.3cm = 63mm
5.6m = 560cm
26000cm = 260m
56500mm = 0.0565km
27.5mg = 0.0275g
923cm = 9.23m
0.025km = 2500cm
First Column
1. 1000mg = 1g
2. 160cm = 1600mm
3. 109g = 0.109kg
4. 250m = 0.25km
5. 14km = 14000m
6. 1L= 1000ml
7. 480cm = 4.8m
8. 27g = 0.027kg
Next column
9. 198g = 0.198kg
10. 75ml = 0.075L
11. 50cm = 0.5m
12. 5L = 5000mL
13. 16cm = 160mm
14. 65g = 65000mg
15. 2500m = 2.5km
16. 355ml = 0.355L
Last Column
17. 8mm = 0.8cm
18. 6.3cm = 63mm
19. 5.6m = 560cm
20. 26000cm = 260m
21. 56500mm = 0.0565km
22. 27.5mg = 0.0275g
23. 923cm = 9.23m
24. 0.025km = 2500cm
Which of the following quantities are vectors?
Distance
Displacement
Velocity
Speed
Force
Fores
O
Height
Acceleration
Answer:
Displacement
Velocity
Acceleration are the vector quantity....
Explanation:
hope this was helpfull....
