It looks like you're trying to evaluate the sum,
[tex]\displaystyle \frac2{4\times7} + \frac2{7\times10} + \frac2{10\times13}+\cdots+\frac2{49\times52}[/tex]
which can be written as
[tex]\displaystyle \sum_{n=1}^{16} \frac2{(3n+1)(3n+4)}[/tex]
Split up the summand into partial fractions:
[tex]\displaystyle \frac2{(3n+1)(3n+4)} = \frac a{3n+1} + \frac b{3n+4} \\\\ \implies 2 = a(3n+4)+b(3n+1) \\\\ \implies 2 = (3a+3b)n+4a+b[/tex]
so that
3a + 3b = 0, or a = -b
4a + b = 2
Solve for a and b :
4a + (-a) = 3a = 2 ==> a = 2/3 ==> b = -2/3
So the sum is
[tex]\displaystyle \frac23 \sum_{n=1}^{16} \left(\frac1{3n+1} - \frac1{3n+4}\right)[/tex]
Write out the first terms and observe that several terms cancel with each other:
2/3 (1/4 - 1/7)
+ 2/3 (1/7 - 1/10)
+ 2/3 (1/10 - 1/13)
+ …
+ 2/3 (1/43 - 1/46)
+ 2/3 (1/46 - 1/49)
+ 2/3 (1/49 - 1/52)
So the sum collapses and simplifies to
[tex]\displaystyle \sum_{n=1}^{16} \frac2{(3n+1)(3n+4)} = \frac23 \left(\frac14 - \frac1{52}\right) = \boxed{\frac2{13}}[/tex]
Help please…
If (tan^30-1/tan0-1)-sec^20+1=0, find cot0
Answer:
dl5fgtrrfhrruf ofender fkufgj jjgglr
Choose the inequality that could be used to solve the following problem.
Three times a number is at most negative six.
A. 3x ≥ -6
B. 3x < -6
C. 3x > -6
D. 3x ≤ -6
Fill the empty slots by dragging tiles from the left to show the next step for sloving the equation solve the two step equation negative nine and a mumber plus zero point four equals to four
Step-by-step explanation:
gjlhcohuguo
y.krgkyfjfhcxhhhxhhxfucuchhcjvgjjgvjvkvkx
Given m||n, find the value of x.
+
mm
(6x+4)
(4x-14)
Answer:
Submit Answer
attempt out of 2
Answer:
x = 19
Step-by-step explanation:
6x+4 + 4x - 14 = 180
10x - 10 = 180
10 X = 190
x = 19
what is 3^-8 x 3^-4 x 3^-2
Answer:
Value of given expression is 3⁻¹⁴
Step-by-step explanation:
Given expression:
3⁻⁸ x 3⁻⁴ x 3⁻²
Find:
Value of given expression
Computation:
⇒ 3⁻⁸ x 3⁻⁴ x 3⁻²
⇒ 3[⁻⁸⁻⁴⁻²]
⇒ 3⁻¹⁴
Value of given expression is 3⁻¹⁴
What makes a trapezoid an isosceles trapezoid
Answer:
A trapezoid is a quadrilateral with exactly one pair of parallel sides. A pair of angles that share a base as a common side are called a pair of base angles. A trapezoid with the two non-parallel sides the same length is called an isosceles trapezoid.
There is a bag filled with 4 blue, 3 red and 5 green marbles.
A marble is taken at random from the bag, the colour is noted and then it is
replaced.
Another marble is taken at random.
What is the probability of exactly 1 red?
Answer:
25%
Step-by-step explanation:
4+3+5=12
3/12 ×100=25
Suppose f(x)=x^3 what is the graph of f(x+3)
Answer:
[tex]f(x + 3) = {(x + 3)}^{3} [/tex]
Shifted left with x-intercept at (-3,0) and the y-intercept at (0,27)
hi these are geometry questions, :)
========================================================
Explanation:
For any inscribed quadrilateral like this, the opposite angles are always supplementary. This means the angles add to 180
B+D = 180
(2x-1) + (3x-59) = 180
(2x+3x) + (-1-59) = 180
5x-60 = 180
5x = 180+60
5x = 240
x = 240/5
x = 48
Use this x value to find angle A
A = 2x+4
A = 2*48+4
A = 96+4
A = 100
This then means,
A+C = 180
C = 180-A
C = 180-100
C = 80 degrees
Side note: The term "cyclic quadrilateral" is the same as "inscribed quadrilateral".
Complete table of values
Step-by-step explanation:
here's the answer to your question
Question 6 of 10
How much would $500 invested at 6% interest compounded monthly be
worth after 5 years? Round your answer to the nearest cen
(0) - P(144
A $674,43
B. $886,41
C, 5669.11
D. $512,68
9514 1404 393
Answer:
A. $674.43
Step-by-step explanation:
The account balance is given by ...
A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years
A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)
A ≈ $674.43
The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of the box is Rs 52 more than of the pen, calculate the profit or loss percent in the whole.
Answer:
3.803% Profit
Step-by-step explanation:
First let us calculate total sales, then calculate the total cost, and then divide the two.
Sale: 120*1.1=132 and 52*.9=46.8
Cost: 120 and 52
Profit equation:
[tex]\frac{Net sales-COGS}{Net Sales} =Profit[/tex]
[tex]\frac{(132+46.8)-(120+52)}{(132+46.8)}[/tex]
Simplify:
[tex]\frac{6.8}{178.8} =.03803[/tex] or 3.803% Profit
What is the perimeter of the rectangular narrow on the aircraft carrier HMS Queen Elizabeth
Answer:
dddjshsbs zhzusushwbsgzyzhsbssbs s hsbd d dhd ssbshebebs shyshs s sbshss s s
Step-by-step explanation:
shshshsnsnsjzj shsjs s sjsn s s snsnsbzbznnz ssjs s snsnsmkzkxnz
Pedro signed up for a streaming music service that costs $13 per month. The service
allows Pedro to listen to unlimited music, but if he wants to download songs for
offline listening, the service charges $0.75 per song. How much total money would
Pedro have to pay in a month in which he downloaded 45 songs? How much would he
have to pay if he downloaded s songs?
Cost with 45 songs:
Cost with s songs:
Answer:
Cost with 45 songs: $46.75
Cost with s songs: $13 + (s * $0.75)
Step-by-step explanation:
First multiply the number of songs by the cost per song (45 * $0.75 = $33.75), then add the monthly service cost to that number ($13 + $33.75 = $46.75) to get the total monthly cost to Pedro.
simplify: 5 (6 - ab) + 2 (-7 + 3ab)
Answer:
30-5ab-14+6ab
16-ab ans
Answer:
[tex] \boxed{ab + 16} [/tex]
Step-by-step explanation:
5 (6 – ab) + 2 (-7 + 3ab)
[distribution property]
(6)(5) – (ab)(5) + (-7)(2) + (3ab)(2)
30 – 5ab – 14 + 6ab
[group like terms]
(6ab – 5ab) + (30 – 14)
ab + 16
tanA × cosecA = secA
Step-by-step explanation:
L.H.S
tanA * cosecA
=sinA/cosA * 1/sinA
now cancel sinA and sinA
then,
1/cosA
= secA
= RHS
hence proved
state the dimensions of the matrix. identify the indicated element
Answer:
D; 2 * 3; -4
Step-by-step explanation:
The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column
In a row, we have 2 elements, in a column , we have 3 elements
So the matrix is of 2 * 3 dimension
a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4
If triangle LMQ is similar to triangle LNP, calculate the length of segment LP.
Answer:
LP = 15
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values
[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]
[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )
5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )
3LQ = 18 ( divide both sides by 3 )
LQ = 6
Then
LP = LQ + QP = 6 + 9 = 15
can someone help me with the question?
Find the measure of the missing angle using the triangle angle sum theorm.
Answer:
65°
Step-by-step explanation:
The sum of angles in a triangle =180
53°+62°+?°=180°
115°+?°=180°
?°=180°-115°
Rate the answer If you love everything I did n explanation
Answer:
65 degrees
Step-by-step explanation:
Angles in a triangle add up to 180, so 180 - 53 - 62 = 65.
Can someone help me with this math homework please!
Answer:
Below
Step-by-step explanation:
From the graph the first local minimum is -16.18
The local maximum is 3.75
The second local minimum is -3.
Answer:
Over the interval (-3,0), the local minimum is -16.18Over the interval [0,3], the local maximum is -3.75Over the interval [0,3], the minimum is -3----------------------
Hope it helps..
Have a great day!!
1. What is the sum of 3/4 and 4/5?
please me in the math
Find the H.C.F
[tex] {x}^{2} - 4 \\ {x}^{3} + 8 \\ {x}^{2} + 5x + 6[/tex]
it so simple
Step-by-step explanation:
Solution
First equation x ² - 4
= (x+2) (x-2)
Second equation = x ³ +8 + = x³+2^3
= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)
3 Third equation = x ² + 5x + 6
= x² + 6x= x +6 = x(x+6)-1(x+6)
(x-1) (x+6)
H.C. F= x-2
May someone explain to me how to do this?
Answer:
All you gotta do is go to "desmos" and type in all of the 4 solutions. A, B, C, and D. and see which answer matches the graph
Step-by-step explanation:
Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus, 5 p=p=p, equals
Given:
The given equation is:
[tex]16-3p=\dfrac{2}{3}p+5[/tex]
To find:
The value of p.
Solution:
We have,
[tex]16-3p=\dfrac{2}{3}p+5[/tex]
Multiply both sides by 3.
[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]
[tex]48-9p=2p+15[/tex]
Isolating the variable terms, we get
[tex]48-15=2p+9p[/tex]
[tex]33=11p[/tex]
Divide both sides by 11, we get
[tex]\dfrac{33}{11}=p[/tex]
[tex]3=p[/tex]
Therefore, the required solution is [tex]p=3[/tex].
Answer:
p=3
Step-by-step explanation:
i got it right on khan
HELP ASAP ILL GIVE BRAINLIST
Imagine that your best friend missed the lesson on how to solve a system of equations using the substitution method. You want to help him or her catch up in their math class, so you decide to write an e-mail describing what they missed. Write an email to your friend including:
An explanation of what a system of equations is
A general description of how to use the substitution method
An example of a system of equations
Your solution steps and explanations including the substitution method
Your final answer for the system
I'm just going to start writing the email XD (btw, bold = non-email parts/me talking)
Hey (Friend name),
You kinda missed math the other day, and being the nice friend I am, I decided to catch you up on what we learned.
We learned how to solve a system of equations using the substitution method.
A system of equations is a set of two or more equations with common variables. We use those two equations to solve for the variables.
One example might be:
3x+y=3
4x+3y=10
Solving each of these two equations by themselves would be impossible, so this is where the substitution method comes in.
Solving by substitution means that you first solve one equation for a variable, and then you substitute the value of that variable into the other equation. You might understand better if you see how I use this method to solve the previous system.
Step 1: Solve for y.
3x+y=3
Subtract 3x from each side.
y=3-3x
Step 2: Use the substitution method (plug in the y value).
4x+3y=10
4x+3(3-3x)=10
See how we plugged in the right side of the equation that is equal to y? Now only the x variable is left and we can easily solve it!
Step 3: Simplify to get x.
4x+9-9x=10
-5x=1
x=-1/5
Step 4: Use the substitution method AGAIN (for the y).
Now we plug in the x value into the equation for y.
y=3-3x
y=3-3(-1/5)
y=3-(-3/5)
y=18/5
The final answer is x=-1/5, y=18/5.
As you can see, using the substitution method to solve two impossible equations is how we can get the values of the variables they share! It's simple, quick, and easy!
Sincerely,
(your name)
I hope this helped! :D
A block is being dragged along a horizontal surface by a constant horizontal force of size 45 N. It covers 8 m in the first 2 s and 8.5 m in the next 1 s. Find the mass of the block.
Answer: 15kg
Can anyone please explain this sum with proper working?
Answer:
Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a
F
=m
a
. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form
(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S
1
=v
1
⋅t
1
+a
2
t
1
2
, where S_1=8m, t_1=2s S
1
=8m,t
1
=2s , other quantities we don't know. The similar equation we can write for next time interval
(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S
2
=v
2
⋅t
2
+a
2
t
2
2
. where S_2=8.5m, t_2=1s S
2
=8.5m,t
2
=1s
Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.
(3) v_2=v_1+a\cdot t_1v
2
=v
1
+a⋅t
1
Substitute (3) to (2) we get
(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S
2
=(v
1
+a⋅t
1
)⋅t
2
+a
2
t
2
2
=v
1
⋅t
2
+a⋅t
1
⋅t
2
+a
2
t
2
2
From equation (1) and (4) we can exclude unknown quantity v_1v
1
, then remain only one unknown aa. For determine aa we dived (1) by t_1t
1
, (4) by t_2t
2
to find the average speed at time intervals and subtract (1) from (4).
(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-
t
2
S
2
−
t
1
S
1
=v
1
+a⋅t
1
+a
2
t
2
−(v
1
+a
2
t
1
)=a
2
t
1
+t
2
− For acceleration we get
(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(
t
2
S
2
−
t
1
S
1
)/(t
1
+t
2
)=2⋅
3s
(8.5m/s−4m/s)
=3ms
−2
For mass from second Newton's law we get
(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=
a
F
=
3ms
−2
45N
=15kg
Answer: The mass of the block is 15 kg
Determine whether the equation represents direct, inverse, joint, or combined variation.
y = 4x^3z^3
Explain this to me I don't understand
Answer:
26.124
Step-by-step explanation:
SOH CAH TOA
tan 43 = about 0.933
than times it by 28 and get
26.124
Given that $x < 5$, rewrite $5x - |x - 5|$ without using absolute value signs. WILL GIVE BRAINLIEST
Answer:
6x-5 if x<5
Step-by-step explanation:
If x<5, then x-5<0.
If x-5 is negative, then |x-5)=-(x-5) or -x+5.
5x - |x - 5|
5x-(-x+5) provided x<5
5x+x-5 by distributive property
6x-5 combined liked terms
