312/132 (fraction simplified as a mixed number)

[tex]\huge\bold{Given:}[/tex]

Length of the base = 8

Length of the hypotenuse = 17

[tex]\huge\bold{To\:find:}[/tex]

The length of the third side ''[tex]x[/tex]".

[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]

[tex]\longrightarrow{\purple{x\:=\: 15}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

Using Pythagoras theorem, we have

(Perpendicular)² + (Base)² = (Hypotenuse)²

[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] + (8)² = (17)²

[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] + 64 = 289

[tex]\longrightarrow{\blue{}}[/tex]  [tex]{x}^{2}[/tex] = 289 - 64

[tex]\longrightarrow{\blue{}}[/tex]  [tex]{x}^{2}[/tex] = 225

[tex]\longrightarrow{\blue{}}[/tex]  [tex]x[/tex] = [tex]\sqrt{225}[/tex]

[tex]\longrightarrow{\blue{}}[/tex]  [tex]x[/tex] = [tex]15[/tex]

Therefore, the length of the missing side [tex]x[/tex] is [tex]15[/tex].

[tex]\huge\bold{To\:verify :}[/tex]

[tex]\longrightarrow{\green{}}[/tex] (15)² + (8)² = (17)²

[tex]\longrightarrow{\green{}}[/tex] 225 + 64 = 289

[tex]\longrightarrow{\green{}}[/tex] 289 = 289

[tex]\longrightarrow{\green{}}[/tex] L.H.S. = R. H. S.

Hence verified.

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}[/tex]

(√3 - i ) / (√3 + i ) × (√3 - i ) / (√3 - i ) = (√3 - i )² / ((√3)² - i ²)

… = ((√3)² - 2√3 i + i ²) / (3 - i ²)

… = (3 - 2√3 i - 1) / (3 - (-1))

… = (2 - 2√3 i ) / 4

… = 1/2 - √3/2 i

… = √((1/2)² + (-√3/2)²) exp(i arctan((-√3/2)/(1/2))

… = exp(i arctan(-√3))

… = exp(-i arctan(√3))

… = exp(-iπ/3)

By DeMoivre's theorem,

[(√3 - i ) / (√3 + i )]⁶ = exp(-6iπ/3) = exp(-2iπ) = 1

Answer:

x = 30

F = 130

G =  50

Step-by-step explanation:

f and g are supplementary which means they add to 180

5x-20 + 3x - 40 = 180

Combine like terms

8x - 60 = 180

Add 60 to each side

8x-60+60 = 180+60

8x = 240

Divide by 8

8x/8 = 240/8

x = 30

F = 5x -20 = 5*30 -20 = 150 -20 = 130

G = 3x-40 = 3*30 -40 = 90-40 = 50

Answer:

Because a straight line = 180, we can find x like this :

(5x - 20) + (3x - 40) = 180

Step 1 - collect like terms

8x - 60 = 180

Step 2 - Move terms around to isolate x

8x = 180 + 60

Step 3 - Divide both sides by 8

x = 30

Now you can find the value of the angles by plugging in x

∠f = (5 x 30) - 20

     = 130 degrees

∠g = (3 x 30) - 40

      = 50 degrees

We can check to see if this works by adding them up

130 + 50 = 180, so this is correct

Hope this helps! I would really appreciate a brainliest if possible :)

Answer:25

Step-by-step explanation:

Answer:

We can conclude that her walking speed is 2.1 miles per hour.

Step-by-step explanation:

We have the relation:

Speed = distance/time.

Here we know:

She walked for 44 miles.

And she ran along the same route, so she ran for 44 miles.

The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:

T + T' = 22 hours.

If we define: S = speed runing

                     S' = speed walking

Then we know that:

"and she ran 33 miles per hour faster than she walked."

Then:

S = S' + 33mi/h

Then we have four equations:

S'*T' = 44 mi

S*T = 44 mi

S = S' + 33mi/h

T + T' = 22 h

We want to find the value of S', the speed walking.

To solve this we should start by isolating one of the variables in one of the equations.

We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:

S'*T' = 44mi

(S' + 33mi/H)*T = 44mi

T + T' = 22h

Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:

T = 22h - T'

if we replace that in the other equations we get:

S'*T' = 44mi

(S' + 33mi/h)*(  22h - T') = 44 mi

Now we can isolate T' in the first equation to get:

T' = 44mi/S'

And replace that in the other equation so we get:

(S' + 33mi/h)*(  22h -44mi/S' ) = 44 mi

Now we can solve this for S'

22h*S' + (33mi/h)*22h + S'*(-44mi/S')  + 33mi/h*(-44mi/S') = 44mi

22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi

If we multiply both sides by S' we get:

22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'

We can simplify this to get:

22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0

22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0

This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:

[tex]S' = \frac{-628mi \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)} }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}[/tex]

Then the two solutions are:

S' = (-628mi - 721mi)/44h = -30.66 mi/h

But this is a negative speed, so this has no real meaning, and we can discard this solution.

The other solution is:

S' = (-628mi + 721mi)/44h = 2.1 mi/h

We can conclude that her walking speed is 2.1 miles per hour.

Answer:

bbbbbhbbvcgccfggfgggggggggihh

Answer:

H0 : μ = 1220

H1 : μ > 1220

Test statistic = 1.30

Step-by-step explanation:

Sample mean, x = 1235.91

Standard deviation, σ = 211.67

Sample size, n = 300

The hypothesis :

Null ; H0 : μ = 1220

Alternative ; H1 : μ > 1220

Tbe test statistic :

(x - μ) ÷ (σ/√(n))

(1235.91 - 1220) ÷ (211.67/√(300))

15.91 / 12.220773

= 1.3018

= 1.30

Answer:

Option (3)

Step-by-step explanation:

Track is shaped as a rectangle with a semicircle on either side.

Therefore, length of the track = 2(Length of rectangle) + perimeter of a complete circle formed by joining the semicircles on each side.

= 2(96) + 2πr

= [tex]192+2\pi (\frac{35}{2})[/tex]

= 192 + 35π

= 192 + 109.9

= 301.9 m

Since, Jake plans to run four laps.

Therefore, distance covered by Jake = 4 × 301.9

                                                              = 1207.6 m

Option (3) will be the correct option.

Answer:

C

Step-by-step explanation:

i did the test and got it right :D

Answer:

se supone que debes usar el SINE RATIO ya que se trata del lado opuesto y la hipotenusa.

Answer:

All real number greater than equal to zero.

Step-by-step explanation:

The function is given by

[tex]f(x) = \frac{4}{5}\sqrt x[/tex]

The domain is defined as the input values so that the function is well defined.

here, the values of x should be all real number and zero also.

So, the correct option is  (d).

Answer:

D

Step-by-step explanation:

Answer:

£8520

Step-by-step explanation:

1 Bahraini dinar = £2.13

Multiply both sides of the equation by 4000.

4000 * 1 Bahraini dinar = 4000 * £2.13

4000 Bahraini dinar = £8520

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

Answer:

32%

Step-by-step explanation:

3 girls like biology, 8 like chem and the rest prefer physics. 28 people like chemistry, and 24 boys like physics. This leaves 29 boys and 3 girls liking bio.

Given:

A fair die is rolled.

It pays off $10 for 6, $7 for a 5, $4  for a 4 and no payoff otherwise.

To find:

The expected winning for this game.

Solution:

If a die is rolled then the possible outcomes are 1, 2, 3, 4, 5, 6.

The probability of getting a 6 is:

[tex]P(6)=\dfrac{1}{6}[/tex]

The probability of getting a 5 is:

[tex]P(5)=\dfrac{1}{6}[/tex]

The probability of getting a 4 is:

[tex]P(4)=\dfrac{1}{6}[/tex]

The probability of getting other numbers (1,2,3) is:

[tex]P(\text{Otherwise})=\dfrac{3}{6}[/tex]

[tex]P(\text{Otherwise})=\dfrac{1}{2}[/tex]

We need to find the sum of product of payoff and their corresponding probabilities to find the expected winning for this game.

[tex]E(x)=10\times P(6)+7\times P(5)+4\times P(4)+0\times P(\text{Otherwise})[/tex]

[tex]E(x)=10\times \dfrac{1}{6}+7\times \dfrac{1}{6}+4\times \dfrac{1}{6}+0\times \dfrac{1}{2}[/tex]

[tex]E(x)=\dfrac{10}{6}+\dfrac{7}{6}+\dfrac{4}{6}+0[/tex]

[tex]E(x)=\dfrac{10+7+4}{6}[/tex]

[tex]E(x)=\dfrac{21}{6}[/tex]

[tex]E(x)=3.5[/tex]

Therefore, the expected winnings for this game are $3.50.

Answer:

17x+12=12

17x=12-12

17x=0

divide both sides by 17

x=0

rough check

17(0) = 12-12

0=0

I hope this helps

Answer:

— Ang salitang entrepreneur ay hango sa salitang French na entrepende na nangangahulugang?

Answer:

3

Step-by-step explanation:

Numbers between 21 and 30 divisible by 3 are 24 and 27. so you get the HCF of the two.

Mary expects to pay $954 at this rate for 35 calculators

If you have a rate, such as a price per a certain number of things, and the denominator quantity is not 1, you may determine the unit rate or price per unit by dividing the numerator by the denominator.

Five 5 scientific calculators are being sold for $135.

then the per calculator's cost is 135/5= $27.

And Mary needs to buy 35 calculators for her students

then 35 calculators is 35×27 = $954.

Hence she expects to pay $954.

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Answer:

The quadrilateral is Rhombus

B=70°

Step-by-step explanation:

110+110+z+z=360

220+2z=360

2z=360-220

2z=140

z=140/2

Therefore, z=70

So Angle B=70

Since z= Angle B=Angle D

The missing side 'a' of the triangle ABC is 96.80 units.

What is a triangle?

A triangle is a flat geometric figure that has three sides and three angles. The sum of the interior angles of a triangle is equal to 180°. The exterior angles sum up to 360°.

For the given situation,

Let ABC be the triangle and a,b,c be the respective sides of the triangle.

The diagram below shows that the triangle with their dimensions.

The dimensions are

A=60°, b=50, c=48.

The two sides and one angle of the triangle are given.

The missing side a can be found by using the law of cosines,

[tex]a=\sqrt{b^{2}+c^{2} -2abcosA }[/tex]

Substitute the above values,

⇒ [tex]a=\sqrt{50^{2}+48^{2} -2(50)(48)cos60 }[/tex]

⇒ [tex]a=\sqrt{2500+2304-4800(-0.9524)}[/tex]

⇒ [tex]a=\sqrt{2500+2304+4571.58}[/tex]

⇒ [tex]a=\sqrt{9375.58}[/tex]

⇒ [tex]a=96.82[/tex] ≈ [tex]96.80[/tex]

Hence we can conclude that the missing side 'a' of the triangle ABC is 96.80 units.

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Answer:

Step-by-step explanation:

Sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

If, sinθ = -[tex]\frac{1}{2}[/tex] and π < θ < [tex]\frac{3\pi }{2}[/tex]

Since, sinθ is negative, angle θ will be in IIIrd quadrant.

And the measure of angle θ will be (180° + 30°)

θ = 210°

It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.

Therefore, cos(210°) = [tex]-\frac{\sqrt{3} }{2}[/tex]

tan(210°) = [tex]\frac{1}{\sqrt{3} }[/tex]

csc(210°) = [tex]-\frac{1}{2}[/tex]

sec(210°) = [tex]-\frac{2}{\sqrt{3} }[/tex]

cot(210°) = √3

Answer:

B. The distance of an archer's shots from the center of a target

C. The time it takes for an airliner to fly from Los Angeles to New York

Step-by-step explanation:

According to the Question,

B & C should each have a range of values that cover most occurrences with outlying values that decrease in number as they move further away from the dominant value range, which is the definition of a normal distribution.

Step-by-step explanation:

everything can be found in the picture

As per the given angle values, the value of sin θ = √19 / 10, cot θ = 9 / √19 and csc θ = 10 / √19.

Let's begin by labeling the sides of the right-angled triangle. The hypotenuse is the side opposite the right angle and has a length of 10 units. The adjacent side, which is the side adjacent to the angle θ, has a length of 9 units.

Using these side lengths, we can apply the trigonometric definitions to find the required values:

Sine (sin θ):

The sine of an angle θ in a right-angled triangle is defined as the ratio of the length of the side opposite the angle (opposite side) to the length of the hypotenuse. The formula for sine is: sin θ = opposite / hypotenuse.

In our case, the opposite side is the side we want to find, and the hypotenuse is 10 units. Therefore, sin θ = opposite / 10.

Using the Pythagorean theorem:

opposite² + 9² = 10²

opposite² + 81 = 100

opposite² = 100 - 81

opposite² = 19

opposite = √19 (taking the positive square root as the length cannot be negative)

Now, we can calculate sin θ:

sin θ = √19 / 10

Cotangent (cot θ):

The cotangent of an angle θ in a right-angled triangle is defined as the ratio of the length of the adjacent side to the length of the opposite side. The formula for cotangent is: cot θ = adjacent / opposite.

In our case, the adjacent side is 9 units, and we have already found the length of the opposite side, which is √19. Therefore, cot θ = 9 / √19.

Cosecant (csc θ):

The cosecant of an angle θ in a right-angled triangle is defined as the ratio of the length of the hypotenuse to the length of the opposite side. The formula for cosecant is: csc θ = hypotenuse / opposite.

Again, the hypotenuse is 10 units, and the opposite side is √19. Thus, csc θ = 10 / √19.

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9514 1404 393

Answer:

  it depends on the accuracy and resolution required of the answer

Step-by-step explanation:

The shaded portion appears to be about half the length of the unshaded portion, suggesting the shaded amount is 1/3.

__

Using a pair of dividers, one could determine the number of times the shaded portion fits into the whole bar. Depending on how much is left over, the process could repeat to determine the approximate size of the remaining fraction relative to the bar or to the shaded portion. (Alternatively, one could replicate the length of the bar to see what integer number of shaded lengths fit into what integer number of whole lengths.)

One could measure the shaded part and the whole bar with a ruler, then determine the relative size of the shaded part by dividing the first measurement by the second. The finer the divisions on the ruler, the better the approximation will be.

Answer:

( - infinity, -3 ] [ -2, infinity )

square bracket means it includes the end point.

Step-by-step explanation:

(-∞, -3]U [-2,∞)

Answer:

Hence the cost of adult tickets is $8

and the cost of child ticket is $4

Step-by-step explanation:

Given data

Let the cost per adult be x

and the cost per child be y

So

3x+2y= 32------------1

8x+5y= 84------------2

Now solving 1 and 2 simultaneously, we have

3x+2y= 32------------1X  5

8x+5y= 84------------2 X 2

 15x+ 10y= 160

 16x+ 10y= 168

-x+0)=-8

-x= -8

x= 8

Put x= 8 in 1 to find y

3*8+2y= 32

24+2y= 32

2y= 32-24

2y= 8

y= 4

Answer:

C(min)  =  277.95 $

Container dimensions:

x = 2.822 m

y = 1.411 m

h = 3.52 m

Step-by-step explanation:

Let´s call x  and  y the sides of the rectangular base.

The surface area for  a rectangular container is:

S = Area of the base (A₁) +  2 * area of a lateral side x (A₂) + 2 * area lateral y (A₃)

Area of the base is :

A₁ =  x*y       we assume, according to problem statement that

x  =  2*y      y  = x/2

A₁  =  x²/2

Area lateral on side x

A₂  = x*h           ( h  is the height of the box )

Area lateral on side y

A₃ = y*h        ( h  is the height of the box )

s = x²/2  + 2*x*h + 2*y*h

Cost  =  Cost of the base + cost of area lateral on x + cost of area lateral on y

C = 10*x²/2  + 8* 2*x*h  + 8*2*y*h

C as function of x is:

The volume of the box is:

V(b) = 14 m³  = (x²/2)*h       28 = x²h      h = 28/x²

C(x) = 10*x²/2  + 16*x*28/x² + 16*(x/2)*28/x²

C(x)  =  5*x²  +  448/x  + 224/x

Taking derivatives on both sides of the equation we get:

C´(x)  =  10*x  -  448/x² - 224/x²

C´(x)  =  0             10x  -  448/x² - 224/x² = 0     ( 10*x³ - 448 - 224 )/x² = 0

10*x³ - 448 - 224 = 0       10*x³ = 224

x³  =22.4

x = ∛ 22.4

x = 2.822 m

y = x/2  =  1.411 m

h = 28/x²  =  28 /7.96

h =  3.52 m

To find out if the container of such dimension is the cheapest container we look to the second derivative of C

C´´(x) = 10 + 224*2*x/x⁴

C´´(x)  =  10 + 448/x³    is positive then C has a minimum for x = 2.82

And the cost of the container is:

C = 10*(x²/2) +  16*x*h + 16*y*h

C = 39.82 +  158.75  + 79.38

C =  277.95 $