what is the range of the funcion y=x^2
Answer:
Range = [0, infinity)
Step-by-step explanation:
Minimum point of the graph is at (0,0) and it is a u shaped graph. Hence, range is 0 inclusive to infinity
Which is the graph of f(x) = 4(1/2)^x
Answer:
B.
Step-by-step explanation:
f(x) = 4(1/2)^x
Let's find the value of the function for x = 0 and for x = 1.
f(0) = 4(1/2)^0 = 4(1) = 4
f(1) = 4(1/2)^1 = 4(1/2) = 2
The only graph that has both points (0, 4) and (1, 2) is the second graph.
Answer: B.
The durations (minutes) of 26 electric power outages in Shah Alam over the past five years are shown below. 32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17 (a) Find the mean, median and mode.
Answer:
Mean = 33.31
Median = 26
Mode = 17
Step-by-step explanation:
Given the data:
32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17
Reordered data : 2, 4, 9, 12, 12, 17, 17, 17, 18, 21, 24, 25, 25, 27, 30, 30, 32, 35, 44, 50, 51, 53, 62, 66, 84, 99
The mean, xbar = Σx / n = 866 /26 = 33.31
The median = 1/2(n+1)th term
Median = 1/2(27)th term = 13.5th term
Median = (13 + 14)th / 2
Median = (25 + 27) / 2 = 26
The mode = 17 (highest frequency)
the admission fee for a charity event is $7 for children and 10$ for adults. The event was attended by 700 people, and the total amount collected in admissions was $6,400.
Answer:
200 kids and 500 adults
Step-by-step explanation:
x+y=700
7x+10y=6,400
(200,500)
kids=200
adults=500
Can someone please help me with this math problem.
Answer:
8 + 30 ÷ 2 + 4 = 27
8 + 30 ÷ (2 + 4 ) = 13
(8 + 30) ÷ 2 + 4 = 23
Step-by-step explanation:
Please help solve this problem.
Answer:
Ang hirap naman niyan bakit kaya lahat na module mahirap
Give two examples of subtraction of fractions ( between 0-1) with different denominators.
SHOW ALL STEPS
Answer:
3/4-1/2=1/4 4/5-3/15
Step-by-step explanation:
3/4-1/2
=3/4-2/4
=1/4
4/5-3/15
=4/5-1/5
=3/5
the voltage in a lightbulb is given by the equation V= IR. in this equation V is the voltage, I is the current , and R is the resistance. what is the current in a lightbulb with a voltage of 35.0 V and a resistance of 175
Answer:
a
Step-by-step explanation:
The weight gain of beef steers were measured over a 140 day test period. the average daily gains (lb/day) of 10 steers on the same diet were as follows. The tenth steer had a weight gain of 4.02 lb/day.
3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
determine the mean and median.
Answer:
[tex]\bar x = 3.545[/tex]
[tex]Median = 3.435[/tex]
Step-by-step explanation:
Given
[tex]x:3.89, 3.51, 3.97, 3.31, 3.21, 3.36, 3.67, 3.24, 3.27[/tex]
[tex]10th: 4.02[/tex]
Solving (a): The mean
This is calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x = \frac{3.89 +3.51 +3.97 +3.31 +3.21 +3.36 +3.67 +3.24 +3.27+4.02}{10}[/tex]
[tex]\bar x = \frac{35.45}{10}[/tex]
[tex]\bar x = 3.545[/tex]
Solving (b): The median
First, we sort the data; as follows:
[tex]3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97, 4.02[/tex]
[tex]n = 10[/tex]
So, the median position is:
[tex]Median = \frac{n + 1}{2}th[/tex]
[tex]Median = \frac{10 + 1}{2}th[/tex]
[tex]Median = \frac{11}{2}th[/tex]
[tex]Median = 5.5th[/tex]
This means that the median is the average of the 5th and 6th item
[tex]Median = \frac{3.36 + 3.51}{2}[/tex]
[tex]Median = \frac{6.87}{2}[/tex]
[tex]Median = 3.435[/tex]
x - 3y +3=0
a) The length of the perpendicular drawn from the point (a, 3) on the line
3x + 4y + 5 = 0 is 4. Find the value of a.
Answer:
We know that for a line:
y = a*x + b
where a is the slope and b is the y-intercept.
Any line with a slope equal to -(1/a) will be perpendicular to the one above.
So here we start with the line:
3x + 4y + 5 = 0
let's rewrite this as:
4y = -3x - 5
y = -(3/4)*x - (5/4)
So a line perpendicular to this one, has a slope equal to:
- (-4/3) = (4/3)
So the perpendicular line will be something like:
y = (4/3)*x + c
We know that this line passes through the point (a, 3)
this means that, when x = a, y must be equal to 3.
Replacing these in the above line equation, we get:
3 = (4/3)*a + c
c = 3 - (4/3)*a
Then the equation for our line is:
y = (4/3)*x + 3 - (4/3)*a
We can rewrite this as:
y = (4/3)*(x -a) + 3
now we need to find the point where this line ( y = -(3/4)*x - (5/4)) and the original line intersect.
We can find this by solving:
(4/3)*(x -a) + 3 = y = -(3/4)*x - (5/4)
(4/3)*(x -a) + 3 = -(3/4)*x - (5/4)
(4/3)*x - (3/4)*x = -(4/3)*a - 3 - (5/4)
(16/12)*x - (9/12)*x = -(4/3)*a - 12/4 - 5/4
(7/12)*x = -(4/13)*a - 17/4
x = (-(4/13)*a - 17/4)*(12/7) = - (48/91)*a - 51/7
And the y-value is given by inputin this in any of the two lines, for example with the first one we get:
y = -(3/4)*(- (48/91)*a - 51/7) - (5/4)
= (36/91)*a + (153/28) - 5/4
Then the intersection point is:
( - (48/91)*a - 51/7, (36/91)*a + (153/28) - 5/4)
And we want that the distance between this point, and our original point (3, a) to be equal to 4.
Remember that the distance between two points (a, b) and (c, d) is:
distance = √( (a - c)^2 + (b - d)^2)
So here, the distance between (a, 3) and ( - (48/91)*a - 51/7, (36/91)*a + (153/28) - 5/4) is 4
4 = √( (a + (48/91)*a + 51/7)^2 + (3 - (36/91)*a + (153/28) - 5/4 )^2)
If we square both sides, we get:
4^2 = 16 = (a + (48/91)*a + 51/7)^2 + (3 - (36/91)*a - (153/28) + 5/4 )^2)
Now we need to solve this for a.
16 = (a*(1 + 48/91) + 51/7)^2 + ( -(36/91)*a + 3 - 5/4 + (153/28) )^2
16 = ( a*(139/91) + 51/7)^2 + ( -(36/91)*a - (43/28) )^2
16 = a^2*(139/91)^2 + 2*a*(139/91)*51/7 + (51/7)^2 + a^2*(36/91)^2 + 2*(36/91)*a*(43/28) + (43/28)^2
16 = a^2*( (139/91)^2 + (36/91)^2) + a*( 2*(139/91)*51/7 + 2*(36/91)*(43/28)) + (51/7)^2 + (43/28)^2
At this point we can see that this is really messy, so let's start solving these fractions.
16 = (2.49)*a^2 + a*(23.47) + 55.44
0 = (2.49)*a^2 + a*(23.47) + 55.44 - 16
0 = (2.49)*a^2 + a*(23.47) + 39.44
Now we can use the Bhaskara's formula for quadratic equations, the two solutions will be:
[tex]a = \frac{-23.47 \pm \sqrt{23.47^2 - 4*2.49*39.4} }{2*2.49} \\\\a = \frac{-23.47 \pm 12.57 }{4.98}[/tex]
Then the two possible values of a are:
a = (-23.47 + 12.57)/4.98 = -2.19
a = (-23.47 - 12.57)/4.98 = -7.23
9. Mariah has 28 centimeters of reed
and 10 meters of reed for weaving
baskets. How many meters of reed
does she have? Write your answer as a
decimal and explain your answer.
Mischa wrote the quadratic equation 0=_x2+4x-7 in standard form. If a = -1, what is the value of c in her equation?
C=-7
C= 1
c=4
c=7
Answer:
A. c = -7
Step-by-step explanation:
Standard form of a quadratic equation is given as ax² + bx + c = 0, where,
a, b, and c are known values not equal to 0,
x is the variable.
Given a quadratic equation of -x² + 4x - 7, therefore,
a = -1
b = 4
c = -7
he parent function f(x) = x3 is represented by graph A. Graph A is transformed to get graph B and graph C. Write the functions represented by graph B and graph C.
Graph B represents the function g(x) =
.
Graph C represents the function h(x) =
.
which multiple choice answer is correct?
A, B, C or D?
Answer:
C
Step-by-step explanation:
ABD and CDB are both half of ABC
m∠ABD = m∠CBD
Because BD is the bisector of ∠ABC, so it divides it into 2 equal parts.
Suppose X and Y are two independent exponential variables. The mean of X is twice the mean of Y. If the probability of X exceeding 50 is 0.7788, what is the probability of Y exceeding 40
If X ~ Exponential(µ), then the mean of X is 1/µ. So if the mean of X is twice the mean of Y, then the mean of Y is 1/(2µ), so that Y ~ Exponential(2µ).
We're given that
P(X > 50) = 1 - P(X ≤ 50) = 1 - Fx (50) ≈ 0.7788
==> Fx (50) = P(X ≤ 50) ≈ 0.2212
where Fx is the CDF of X, which is given for 0 ≤ x < ∞ to be
Fx (x) = 1 - exp(-µx)
Solve for µ :
1 - exp(-50µ) ≈ 0.2212 ==> µ ≈ -ln(0.7788)/50 ≈ 0.005
Then we have
P (Y > 40) = 1 - P (Y ≤ 40) = 1 - Fy (40)
where Fy is the CDF of Y,
Fy (y) = 1 - exp(-2µy)
so that
P (Y > 40) ≈ 1 - exp(-2 × 0.005 × 40) ≈ 0.3297
The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect
at x = -2. True or false?
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Answer:
False
Step-by-step explanation:
f(-2) = (1/2)(-2) -3 = -1 -3 = -4
g(-2) = -2(-2) +2 = 4 +2 = 6
The function values are not the same at x=-2, so the graphs do not intersect there.
__
The graphs intersect at x=2.
A motel in New Orleans charges $90 per day for double occupancy and $80 per day for single occupancy during off-season. If 80 rooms are occupied for a total of $6,930, how many rooms of each kind are occupied?
double occupancy room=x
single occupancy room=y
x + y = 80,
90x + 80y = 6930
x=53
y=27
For all positive integers n, let *n* equal the greatest prime number that is a divisor of n. What does *10*/*12* equal?
9514 1404 393
Answer:
5/3
Step-by-step explanation:
The prime factorizations are ...
10 = 2·5
12 = 2·2·3
Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.
Find the mean of the following data set.
8, 5, 15, 12, 10
A. 12.5
B. 10
C. 14
D. 50
Answer:
10
Step-by-step explanation:
the sum of 8,5,15,12,10 is 50 and there are 5 numbers so 50 divided by 5 is 10 and it's mean is also 10
hope this helps !
25 x 2
help me
plz understand me by opening
Answer:
[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]
really?! :|
Suppose f(x)=x^2 and g(x)=(1/2x)^2. Which statement best compares the graph of g(x) with the graph of f(x)?
Answer:
"A"
Step-by-step explanation:
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you have passed subject A, the probability of passing subject B is 0.8. Find the probability that the student passes both subjects? Find the probability that the student passes at least one of the two subjects
Answer:
0.64 = 64% probability that the student passes both subjects.
0.86 = 86% probability that the student passes at least one of the two subjects
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Passing subject A
Event B: Passing subject B
The probability of passing subject A is 0.8.
This means that [tex]P(A) = 0.8[/tex]
If you have passed subject A, the probability of passing subject B is 0.8.
This means that [tex]P(B|A) = 0.8[/tex]
Find the probability that the student passes both subjects?
This is [tex]P(A \cap B)[/tex]. So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64[/tex]
0.64 = 64% probability that the student passes both subjects.
Find the probability that the student passes at least one of the two subjects
This is:
[tex]p = P(A) + P(B) - P(A \cap B)[/tex]
Considering [tex]P(B) = 0.7[/tex], we have that:
[tex]p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86[/tex]
0.86 = 86% probability that the student passes at least one of the two subjects
Respond to each of the four questions.
Describe the steps to graphing a linear equation. Be sure to provide an example to illustrate your description.
Describe the steps to graphing a quadratic equation. Be sure to provide an example to illustrate your description.
Describe how to solve a linear equation. Be sure to provide an example to illustrate your description.
Describe how to solve a quadratic equation. Be sure to provide an example to illustrate your description.
Answer:hello
Step-by-step explanation:
1+1
Use the P (A + B) = P (A) x P (B) rule to find the probability of system failure. Let A and B be the events that the first alarm and second alarm, respectively, fail. Do you get the same answer you did in the earlier question?
Answer:
answer is in the pic Mark me brainliest plz
Step-by-step explanation:
Answer:
The probability of the first alarm failing is (1 - 0.8) = 0.2
The probability of the second alarm failing is (1−0.9)=0.1.
Using the multiplication rule (since A and B are independent), the probability of failure is 0.2 * 0.1 = 0.02
Step-by-step explanation:
Divide the following quantities in the following ratios £100 1:3
Find the interquartile range of the data set represented by this box plot.
25
20
45
35
Answer:
25
Step-by-step explanation:
im pretty sure i think only ok i think no saying bad things in the comment
A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)
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Answer:
$10
Step-by-step explanation:
Price is proportional to the number of rings, so Zack will spend D dollars, where ...
dollars/rings = D/50 = 1/5
D = 50/5 = 10
Zack will spend $10 to buy 50 toy rings.
Type the standard form of "three thousand four hundred eight."
The solution is
Answer:
the standard form of "three thousand four hundred eight is
3408hope it is helpful to you ☺️
In standard form we can write 3408 as 3.408 x [tex]10^{3}[/tex].
We have the following statement - three thousand four hundred eight
We have to write it in standard form.
What do you understand by Standard form of a Number ?A number when expressed as a decimal number, between 1 and 10, multiplied by a power of 10, is said to be in standard form.
According to the question, we have -
three thousand four hundred eight.
In the digit form, we can write it as - 3408.
In Standard form, we can write it as -
3408 = 3.408 x [tex]10^{3}[/tex]
Hence, in standard form we can write 3408 as 3.408 x [tex]10^{3}[/tex].
To solve more questions on Standard form, visit the link below -
https://brainly.com/question/17136267
#SPJ2
A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Find the 95% confidence interval of the mean score of all bowlers.
Answer:
[tex]CI=189.5,194.5[/tex]
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=40[/tex]
Mean [tex]\=x =192[/tex]
Standard deviation[tex]\sigma=8[/tex]
Significance Level [tex]\alpha=0.05[/tex]
From table
Critical Value of [tex]Z=1.96[/tex]
Generally the equation for momentum is mathematically given by
[tex]CI =\=x \pm z_(a/2) \frac{\sigma}{\sqrt{n}}[/tex]
[tex]CI =192 \pm 1.96 \frac{8}{\sqrt{40}}[/tex]
[tex]CI=192 \pm 2.479[/tex]
[tex]CI=189.5,194.5[/tex]
The annual demand for a product is 16,400 units. The weekly demand is 315 units with a standard deviation of 90 units. The cost to place an order is $31.00, and the time from ordering to receipt is four weeks. The annual inventory carrying cost is $0.20 per unit.
a. Find the reorder point necessary to provide a 95 percent service probability.
b. Suppose the production manager is asked to reduce the safety stock of this item by 55 percent. If she does so, what will the new service probability be?
Answer:
a) The reorder point necessary to provide a 95 percent service probability is 1557 units.
b) The Z value of 0.74 corresponds to 77% service probability.
Step-by-step explanation:
Average weekly demand (d) = 315 units
The standard deviation of weekly demand (\sigmad) = 90 units
Lead time (L) = 4 weeks
At 95% service level value of Z = 1.65
Reorder point = d x L + safety stock
[tex]= d \times L + (Z \times \sigma d \times \sqrt L)\\\\= 315 x 4 + (1.65 x 90 x \sqrt 4)\\\\= 1260 +(1.65 x 90 x 2)\\\\= 1260 + 297\\\\= 1557 units[/tex]
b) Earlier the safety stock was 297 units(calculated in part a)
Now the safety stock is reduced to 55%.so,55% of 297 = 163.35 units
So the new safety stock = 297 - 163.35 = 133.65
[tex]Safety stock = Z \times \sigma d \times \sqrt L\\133.65 = Z x 90 x 2\\133.65 = 180Z\\ Z = 133.65/180\\Z = 0.74[/tex]
The Z value of 0.74 corresponds to 77% service probability.
