3
Solve for x.
X =
8
20
35

9514 1404 393

Answer:

  x = 8/7

Step-by-step explanation:

The only real zero of this linear function is the value of x that makes y=0:

  0 = -7x +8

  7x = 8 . . . . . . add 7x

  x = 8/7 . . . . . .divide by 7

Answer:

4x^2 + 2x + 4

Step-by-step explanation:

5x^2 + 2x + 4 - x^2

4x^2 + 2x + 4

Answer:

2(2x^2 + x + 2)

Step-by-step explanation:

5x^2+2x + 4-x^2

Re arrange so like terms are next to each other

Keep the same symbol that is at the front of the term when moving it

5x^2 - x^2 + 2x + 4

We will just do the first part first

5x^2 - x^2

5x^2 - 1x^2 (is the same thing as above)

So because they are like terms (are both x^2)

We can just minus 1 from 5

5-1=4

So 4x^2

Now the equation is

4x^2 + 2x + 4

This is as small as it gets but you can also bring it to this

4, 2 and 4 all are divisible by 2 so

2(2x^2 + x + 2)

Solution :

Given :

Equation :

y = 6.3333 x + 53.0298

Here, x = number of hours studied

         y = the exam score

a). To predict the exam score, we have to replace x in the least square regression line by 2 :

   y = 6.3333 x + 53.0298

   y = 6.3333 (2) + 53.0298

      = 65.6964

Thus he predicted exam score is 65.6964

b). The slope is the co-efficient of x in the least squares regression line :

  Slope = 6.3333

 The slope represents the average increase in y as x increases by 1.

  The exam score increases on average by 6.3333 points per hour studied.

c). The mean score of the [tex]\text{ students who did not study}[/tex] (studied 0 hours) is obtained by replacing x in the least squares regression line by 0 :

  y = 6.3333 x + 53.0298        

 y = 6.3333 (0) + 53.0298

    = 53.0298

d). To predict the exam score of a student who studied 5 hours, we replace x in the least squares regression line by 2 :

   y = 6.3333 x + 53.0298

   y = 6.3333 (5) + 53.0298

   y = 84.6963

Thus the average exam score of a student who studied 5 hours is 84.6963

Since the actual exam score 81 is less than the average exam score of 84.6963 the student's exam score is below the average.

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

Answer: B

Step-by-step explanation:

Answer:

-5ºC < 5ºC is an inequality that compares temperatures.

B is the correct answer for the multiple choice question.

Answer:

[tex]4(3x)^{\frac{3}{2} }[/tex]

Step-by-step explanation:

Answer:

7x - 8

Step-by-step explanation:

Hope this helps!

Answer:

b. $0.02[tex]/in^3[/tex]

Step-by-step explanation:

Given

[tex]r =1in[/tex]

[tex]h = 10in[/tex]

[tex]Cost_{1pk} =\$3[/tex]

[tex]Cost_{2pk} =\$5[/tex]

Required

The difference in the price per [tex]in^3[/tex]

First, calculate the volume (V) of the cylinder

[tex]V = \pi r^2h[/tex]

[tex]V = 3.14 *1^2 * 10[/tex]

[tex]V = 31.4[/tex]

The unit cost of 1 pack is:

[tex]Unit_{1pk} = \frac{Cost_{1pk}}{V}[/tex]

[tex]Unit_{1pk} = \frac{\$3}{31.4in^3}[/tex]

The unit cost of 2 packs is:

[tex]Unit_{2pk} = \frac{Cost_{2pk}}{2*V}[/tex]

[tex]Unit_{2pk} = \frac{\$5}{2*31.4}[/tex]

[tex]Unit_{2pk} = \frac{\$5}{62.8in^3}[/tex]

The difference (d) is:

[tex]d = |Unit_{2pk} - Unit_{2pk}|[/tex]

[tex]d = \frac{\$3}{31.4in^3} - \frac{\$5}{62.8in^3}[/tex]

Take LCM

[tex]d = \frac{\$6 - \$5}{62.8in^3}[/tex]

[tex]d = \frac{\$1}{62.8in^3}[/tex]

[tex]d = \$0.0159/in^3[/tex]

Approximate

[tex]d = \$0.02/in^3[/tex]

Answer:

b)

Step-by-step explanation:

had it on my quiz also give other dude brainliest.

Answer:

y=-3x-5

Step-by-step explanation:

(-1, -2) (0, -5)

use slope formula

ΔY = (-5 – -2) = -3

ΔX = (0 – -1) = 1

m = -3

y=mx+b

-5 = -3(0)+b

b = -5

y=-3x-5

Answer:

Your answer would be B

Step-by-step explanation:

So right away you can get rid of a and d since they are positive numbers, there is no positive numbers in the graph were the line is.

So we know that the y-intercept is -2 (as you can see the line pass through (0,-2))

And we know the y intercept is -8 (since the line pass through (-8,0))

so you are left with b and c, c is incorrect because the -2 goes through the y-intercept not the x.

The right choice is b, it states that the x-intercept -8 pass through the line, the y-intercept is -2

Your welcome and hoped this helped!

Answer:

y - 2 = 1/3(x - 3)

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the slope:

y - y1 = m(x - x1)

y - y1 = 1/3(x - x1)

Plug in the given point:

y - y1 = 1/3(x - x1)

y - 2 = 1/3(x - 3)

So, the correct answer is y - 2 = 1/3(x - 3)

Answer:

Step-by-step explanation:

Given that:

[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]

at point (0, -2)

[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]

Taking the differential from the equation above with respect to x;

[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]

Collect like terms

[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

Hence, the slope of the tangent line m can be said to be:

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

At point (0,-2)

[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]

[tex]\dfrac{dy}{dx}= 0[/tex]

m = 0

So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:

(y - y₁ = m(x - x₁))

y + 2 = 0(x - 0)

y + 2 = 0

y = -2

Answer:

x = -5y

Step-by-step explanation:

x = ay

-10 = 2a

a = -5

x = ay

-15 = 3a

a = -5

x = ay

-25 = 5a

a = -5

Answer:

"there is exactly one output for each input" is cotrrect

"the graph of a linear function" is correct

Step-by-step explanation:

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

[tex]Volume = 565L[/tex]

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

[tex]Volume = Length^3[/tex]

This gives:

[tex]565L= Length^3[/tex]

Express as [tex]m^3[/tex]

[tex]\frac{565m^3}{1000} = Length^3[/tex]

[tex]0.565m^3 = Length^3[/tex]

Take cube roots of both sides

[tex]0.8267m = Length[/tex]

Rewrite as:

[tex]Length = 0.8267m[/tex]

Approximate

[tex]Length = 0.83m[/tex]

Answer:

The length is 8 cm. Since its a square, so the length of both its sides are equal.

l^2=64

where l=length of side

square root both sides

then, l=8

Answer:

8cm is the length of its side.

Step-by-step explanation:

Answer:

x - 8>-4-x

Step-by-step explanation:

Looking at x - 8>-4-x

Collect the like terms;

x+x > -4 + 8

2x < 4

x > 4/2

x < 2

Since the values of x are greater than 2,this shows that they are positive values and will be farther from -8 than -4

Answer:

[tex]\displaystyle x \approx 9.9[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 64°

Opposite Leg = x

Hypotenuse = 11

Step 2: Solve for x

Answer:

D. 3

Step-by-step explanation:

Distance between A and D = AD = 9 units

Distance between A and B = AB = 3 units

[tex] \frac{AD}{AB} = \frac{9}{3} [/tex]

Simplify by dividing

[tex] \frac{AD}{AB} = \frac{3}{1} [/tex]

[tex] \frac{AD}{AB} = 3 [/tex]

The answer is 3

Answer:

F(-2)= g(-2)

Step-by-step explanation:

F(-2)= g(-2), both function have the same points of intersect.

Answer:

Hi, there the answer is

These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Hope This Helps :)

Step-by-step explanation:

First degree equations

A first degree equation has the form

ax + b = 0

There are some special cases where the equation can have one, infinitely many or no solution

If , the equation has exactly one solution

If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0

If a=0 and  the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.

We have been given some equations, we only need to put them in standard form

-5x + 12 = –12x – 12

Rearranging

7x + 24 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x + 12

Rearranging

-10x + 0 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x – 5

Rearranging

-10x + 17 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = -5x – 12

Rearranging

0x + 24 = 0

It has no solution, no matter what the value of x is, it's impossible that 24=0

Answer: These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Step-by-step explanation:

we can simplify the stuff inside the parentheses to

[tex] \frac{ {x}^{3} }{2y} [/tex]

now we need to multiply it with itself, giving us

[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]

so yeah, D is the correct answer

Answer:

after 10 months

Step-by-step explanation:

Let x be the number of months and y be the amount they still owe.

Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.

Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in

b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.

They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:

-60x+ 1000 = -20x+ 600

1000 = 40x+ 600

400 = 40x

10=x

They will then owe the same amount after 10 months.

Answer:

No choices listed.

Step-by-step explanation:

9514 1404 393

Answer:

  5/8

Step-by-step explanation:

Since the ratio is common, it can be found from the ratio of any pair of adjacent terms.

  r = 480/768 = (5·96)/(8·96) = 5/8

The common ratio is 5/8.

Answer:

11.7

Step-by-step explanation:

39.1 - 9.2 = 29.9

29.9 - 18.2 = 11.7

Answer:

The answer is C

Hope this helped!