3х + 2 +(-5)? I need help pls

Answers

Answer 1

Answer:

3x + 2 - 5

3x - 3

x = 3 ÷ 3

x = 1

I hope this helped!


Related Questions

Please help me figure out if this truth table is equivalent or not. People who show their work and give a proper answer shall receive brainliest

Answers

Answer:

The statements are logically equivalent.

The 6th column is:

F T F F

The 7th column is:

F T F F

Step-by-step explanation:

The 6th column is just the opposite of the 5th column

The 7th column is T only if both the 1st and 4th are T

When Claire chooses a piece of fruit from a fruit bowl, there is a 22% chance that it will be a plum, an 18%
chance that it will be an orange, and a 60% chance that it will be an apple. Which type of fruit is she least likely
to choose?

Answers

Answer:

Orange

Step-by-step explanation:

As the chance of choosing orange is 18% which is the least.

Find, correct to the nearest degree, the three angles of the triangle with the given ven
A(1, 0, -1), B(4, -3,0), C(1, 2, 3)
o
CAB =
O
LABC =
O
LBCA =

Answers

9514 1404 393

Answer:

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

Step-by-step explanation:

This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.

The lengths of the sides are given by the distance formula.

  AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26

  BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43

  CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20

From the law of cosines, ...

  ∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))

  ∠A = arccos(3/(4√130)) ≈ 86°

  ∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))

  ∠B = arccos(49/(2√1118)) ≈ 43°

  ∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))

  ∠C = arccos(37/(4√215)) ≈ 51°

The three angles are ...

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

_____

Additional comment

This sort of repetitive arithmetic is nicely done by a spreadsheet.

Which equation could represent each grapes polynomial function?

Answers

9514 1404 393

Answer:

top graph: y = x(x +3)(x -2)bottom graph: y = x⁴ -5x² +4

Step-by-step explanation:

Each x-intercept at x=a corresponds to a polynomial factor of (x -a).

__

The top graph has x-intercepts of -3, 0, +2, so the factors of this cubic are ...

  y = (x +3)(x -0)(x -2)

  y = x(x +3)(x -2) . . . . . . . matches upper right tile

__

The bottom graph has x-intercepts of -2, -1, 1, 2, so the factors of this quartic are ...

  y = (x +2)(x +1)(x -1)(x -2) = (x² -4)(x² -1)

  y = x⁴ -5x² +4 . . . . . . . matches lower left tile

The sum of the first ten terms of an arithmetic progression consisting of

positive integer terms is equal to the sum of the 20th, 21st and 22nd term.

If the first term is less than 20, find how many terms are required to give

a sum of 960.

Answers

Answer: [tex]n=13[/tex]

Step-by-step explanation:

Given

Sum of the first 10 terms is equal to sum of 20, 21, and 22 term

[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]

No of terms to give a sum of 960

[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]

Value of first term is less than 20

[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]

Answer:

15

Step-by-step explanation:

In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))

Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.

When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.

To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.

Then in the expression: (n÷2)×(2a+(n-1)×d)

substitute:

n = 14 (must be an even number for the equation to work)

a = 15

d = 7

This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)

substituting:

n = 15

a = 15

d = 7

This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.

I hope this has helped you.

P.S. Everything in the previous solution was right apart from the start of the last section and the answer

every student from different schools planted as many plants of their number if they planted 4225 plants how many students were there

Answers

Answer:

65 students.

Step-by-step explanation:

Given that :

Every student planted as many plant as their number ;

Then let the number of student = x

Then the number of plant planted by each student will also = x

The total number of plants planted by all the students = 4225

The Number of students can be obtained thus ;

Total number of plants = Number of plants * number of plants per student

4225 = x * x

4225 = x²

√4225 = x

65 = x

Hence, there are 65 students

Work out the area of the shape,show working out
help me and I think I did the sides wrong

Answers

25 x 10 = 250
11 x 6 = 66
250 - 66 = 184 cm

At a bake sale, pies cost $8 each. One customer buys $64 worth of pies.

Answers

The customer bought 8 pies.

To find the total amount of pies the customer bought, simply divide 64 by 8 to recieve your answer of 8 pies.

I hope this is correct and helps!

Eight pies would be the answer

HELP PLEASE!!! So for this problem is got 0.48 however I just wanted to confirm that my answer is correct. Can someone please help me if the answer is wrong and how to solve it. Thank your for your time

Answers

Answer:

ur answer is correct

A =xy

A = 1.6×0.3 = 0.48

How high up the wall can a 12-foot ladder reach if its base is 4 feet from the wall? Round your answer to the nearest tenth of a foot if necessary.

Answers

Answer: 24 ft I think

Step-by-step explanation:

The catch-up effect says that low-income countries can grow faster
higher income countries. However, in statistical studies covering many countries
differences, we do not observe the catch-up effect unless we control for the
other variables affecting productivity. Consider the factors that determine productivity, list and solve
I like the reasons why a poor country can't keep up with rich countries.

Answers

worldwide markets are already established with bis stakeholders like McD, Appe, MS, Aldi Car Manufacturers etc.

so seeing a big corporation emerging from an underdeveloped country would be kind of a suprising thing to happen.

also, economically developed countries are likely to have stable trade relationships with other countries. giving them an edge over outsiders.

Already existing infrastructure might also be a concern to keep in mind when planning your business. It's nice to have mobility, internet, electricity, water at you tap.

I guess there could even be some kind of language barrier for many countries with an insufficient educational system. that might hinder individuals to participate in the global market and community.

The following data were collected from a simple random sample from an infinite population.
13 15 14 16 12
The point estimate of the population standard deviation is _____.
a. 1.581
b. 2.500
c. 2.000
d. 1.414

Answers

Answer:

1.581

Step-by-step explanation:

Given the data:

13 15 14 16 12

The point estimate of the standard deviation will be :

√Σ(x - mean)²/n-1

Mean = Σx / n = 70 / 5 = 14

√[(13 - 14)² + (15 - 14)² + (14 - 14)² + (16 - 14)² + (12 - 14)² / (5 - 1)]

The point estimate of standard deviation is :

1.581

The mean monthly car payment for 121 residents of the local apartment complex is $372. What is the best point estimate for the mean monthly car payment for all residents of the local apartment complex

Answers

Answer:

Needed point estimate is $372

Step-by-step explanation:

Given:

Number of houses in resident area = 121

Monthly mean car payment = $372

Find:

Best point estimate for the mean monthly car payment

Explanation:

The "best point estimate" for such average monthly automobile payment for all inhabitants of the nearby apartment complex is used as the "sample mean." In this example, a $372 sample was obtained on 121 residents.

As a result, the needed point estimate is $372.

Please help, I’m running out of time. Please.

Answers

Answer:

which standard questions is it

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targeted and destroyed, what is the probability that more than 1 vessel transporting nuclear weapons was destroyed

Answers

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Fleet of 17 means that [tex]N = 17[/tex]

4 are carrying nucleas weapons, which means that [tex]k = 4[/tex]

9 are destroyed, which means that [tex]n = 9[/tex]

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

[tex]P(X > 1) = 1 - P(X \leq 1)[/tex]

In which

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294[/tex]

[tex]P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412[/tex]

[tex]P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588[/tex]

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

which represents the value of point D on the number line?

Answers

Answer:

The answer would be D, -(-4)

Step-by-step explanation:

This is because two negatives equal a positive.

Answer:

D shawtay

Step-by-step explanation:

the answers d cus negatives cancel eachother out

If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360

Answers

i think the answer is 1/36 because 1/6 times 1/6

2.6.5 A plant physiologist grew birch seedlings in the green-house and measured the ATP content of their roots. (See Example 1.1.3.) The results (nmol ATP/mg tissue) were as follows for four seedlings that had been handled identically.39 1.45 1.19 1.05 1.07 Calculate the mean and the S

Answers

Answer:

[tex](a)\ \bar x = 1.19[/tex]

[tex](b)\ \sigma_x = 0.18[/tex]

Step-by-step explanation:

Given

[tex]n = 4[/tex]

[tex]x: 1.45\ 1.19\ 1.05\ 1.07[/tex]

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{1.45 + 1.19 + 1.05 + 1.07}{4}[/tex]

[tex]\bar x = \frac{4.76}{4}[/tex]

[tex]\bar x = 1.19[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma_x = \sqrt{\frac{\sum(x - \bar x)^2}{n - 1}}[/tex]

So, we have:

[tex]\sigma_x = \sqrt{\frac{(1.45 -1.19)^2 + (1.19 -1.19)^2 + (1.05 -1.19)^2 + (1.07 -1.19)^2}{4 - 1}}[/tex]

[tex]\sigma_x = \sqrt{\frac{(0.1016}{3}}[/tex]

[tex]\sigma_x = \sqrt{0.033867}[/tex]

[tex]\sigma_x = 0.18[/tex]

I NEED HELP!!!!
If, XYZ~EDF the measure of angle F is

Answers

Answer:

63°

Step-by-step explanation:

∠F is equal to ∠Z

If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2

Answers

Hey there!

We are given two functions - one is Exponential while the another one is Linear.

[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]

1. Operation of Function

(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:

[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]

2. Substitution

Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.

[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]

3. Evaluate/Simplify

Cancel out the brackets and combine like terms.

[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]

4. Final Answer

(f+g)(x) = 4^x+5x-2

Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated samplingg distribution.

The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.5 years and a standard deviation of 2.1 years. Random samples of size 17 are drawn from the population and the mean of each sample is determined.

a. 1.33 years, 2.1 years
b. 5.5 years, 0.12 years
c. 5.5 years, 0.51 years
d. 1.33 years, 0.51 years

Answers

Answer:

c. 5.5 years, 0.51 years

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Mean of 5.5 years and a standard deviation of 2.1 years.

This means that, for the population, [tex]\mu = 5.5, \sigma = 2.1[/tex]

Random samples of size 17.

This means that [tex]n = 17[/tex]

Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.

The mean is the same as the mean for the population, that is, 5.5 years.

The standard deviation is:

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{17}} = 0.51[/tex]

This means that the correct answer is given by option c.

Find the length of an arc of a circle with a 8-cm radius associated with a central angle of 240 degrees. Give your answer in exact and approximate form to the nearest hundredth.

Answers

Answer:

l = 1920 cm

Step-by-step explanation:

Given that,

The radius of circle, r = 8 cm

The central angle is 240 degrees

We need to find the length of the arc. We know that,

[tex]l=r\theta[/tex]

Where

l is the length of the arc

So,

[tex]l=8\times 240[/tex]

[tex]\implies l=1920\ cm[/tex]

so, the length of the arc is equal to 1920 cm.


Domain and range

O Function
O Not a function

Answers

Answer:

Radiation 1- Function

Radiation 2- Not a function

Radiation 3- function

Radiation 4- function

Answer:

1 - Function  

2 - Not a function

3 - function

4 - function

Step-by-step explanation:

Learning Task No. 1 Randy, Manny and Jan put 3 As, 4 Bs and 5 Cs in the box. They will take turns in getting a letter from the box. They are trying to test the probability of getting their favourite letter.

Randy - A
Manny-B
Jan-C

1. What is the probability of getting each boy's favourite letter? a. Randy b. Manny c. Jan
2. If you are next to Jan to pick up a letter and your favourite letter is A , What is the probability of getting your favourite letter?
3. Who is most unlikely to get his favourite letter.​

Answers

Answer:

1. A = 3/12

B= 4/12

C = 5/12

2......

3. Randy

Step-by-step explanation:

3+4+5 = 12

therefore there are 12 letters in the box

we can say that there are 3/12 A's in the box and do the same for the remaining letters

question two does not make sense

3. the person who has the lowest fraction in value which is A

what is the value of digit 6 in9.78265.​

Answers

Answer: uhh I think 60?

Step-by-step explanation:

the answer is 6p because after any value place is zero hoped I helped

To find the quotient of 8 divided by one-third, multiply 8 by
O One-eighth
O One-third
O 3
O 8

Answers

Answer:

3

Step-by-step explanation:

Skip,Flip,Multiply Method

[tex] \frac{8}{ \frac{1}{3} } = \frac{8}{1} \times 3 = 24[/tex]

Answer:

3

Step-by-step explanation:


A driver must decide whether to buy a new car for $24,000 or lease the same car over a four-year period. Under the terms of the lease, she can make a down payment
of $3000 and have monthly payments of $150. At the end of the four years, the leased car has a residual value (the amount she pays if she chooses to buy the car at
the end of the lease period) of $11,000. Assume she can sell the new car at the end of the four years at the same residual value. Is it less expensive to buy or
to lease?

Answers

Answer:

3000 is the answer this question.

A loan of £1000 has a compound interest rate of 2.7% charged monthly. Express the original loan as a percentage of the total amount awed after 2 months if no payment are made

Answers

Answer:

£1054.729

Step-by-step explanation:

To find compound interest you need to use the equation 1000(1.027)^x.

To find the interest rate (1.027):

100 + 2.7 = 102.7

102.7 / 100 = 1.027

The value of x is the amount of months if no payment is made in this situation, so 2 would be the x value for this problem.

Hope this helps!  

The Sureset Concrete Company produces concrete. Two ingredients in concrete are sand (costs $6 per ton) and gravel (costs $8 per ton). Sand and gravel together must make up exactly 75% of the weight of the concrete. Also, no more than 40% of the concrete can be sand and at least 30% of the concrete be gravel. Each day 2000 tons of concrete are produced. To minimize costs, how many tons of gravel and sand should be purchased each day

Answers

Answer:

The Sureset Concrete Company

The tons of gravel and sand that should be purchased each day are:

Sand = 800 tons

Gravel = 700 tons

Step-by-step explanation:

Two ingredients for producing concrete = sand and gravel

Cost of sand per ton = $6

Cost of gravel per ton = $8

Sand and gravel = 75% of the concrete

Therefore 25% (100 - 75%) will be made up of cement and water

Tons of concrete produced each day = 2,000

Sand and gravel = 1,500 (2,000 * 75%)

Sand <= 40% of 2,000 = 800 tons

Gravel => 30% of 2,000 = 700 (1,500 - 800) tons

To minimize costs,  800 tons of gravel and 700 tons of sand should be purchased each day.

Total cost incurred daily for both sand and gravel = $10,400 (800 * $6 + 700 * $8)

If $3000 is invested at 3% interest, find the value of the investment at the end of 7 years if the interest is compounded as follows. (Round your answers to the nearest cent.)
(i) annually
(ii) semiannually
(iii) monthly
(iv) weekly
(v) daily
(vi) continuously

Answers

Answer:

annualy=$3689.62

semiannually=$3695.27

monthly=$3700.06

weekly=$3700.81

daily=$3701.00

Continuously=$3701.03

Step-by-step explanation:

Given:

P=3000

r=3%

t=7 years

Formula used:

Where,

A represents Accumulated amount

P represents (or) invested amount

r represents interest rate

t represents time in years

n represents accumulated or compounded number of times per year

Solution:

(i)annually

n=1 time per year

[tex]A=3000[1+\frac{0.03}{1} ]^1^(^7^)\\ =3000(1.03)^7\\ =3689.621596\\[/tex]

On approximating the values,

A=$3689.62

(ii)semiannually

n=2 times per year

[tex]A=3000[1+\frac{0.03}{2}^{2(4)} ]\\ =3000[1+0.815]^14\\ =3695.267192[/tex]

On approximating the values,

A=$3695.27

(iii)monthly

n=12 times per year

[tex]A=3000[1+\frac{0.03}{12}^{12(7)} \\ =3000[1+0.0025]^84\\ =3700.0644[/tex]

On approximating,

A=$3700.06

(iv) weekly

n=52 times per year

[tex]A=3000[1+\frac{0.03}{52}]^3^6 \\ =3000(1.23360336)\\ =3700.81003[/tex]

On approximating,

A=$3700.81

(v) daily

n=365 time per year

[tex]A=3000[1+\frac{0.03}{365}]^{365(7)} \\ =3000[1.000082192]^{2555}\\ =3701.002234[/tex]

On approximating the values,

A=$3701.00

(vi) Continuously

[tex]A=Pe^r^t\\ =3000e^{\frac{0.03}{1}(7) }\\ =3000e^{0.21} \\ =3000(1.23367806)\\ =3701.03418\\[/tex]

On approximating the value,

A=$3701.03

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