Answer:
45.6
Step-by-step explanation:
45.55
We want to round to the tenths place
we look at the hundredths place
.x5 Since the number in the hundredths place is 5 or greater, we round up 1
45.55 becomes 45.6
Answer:
the answer is 45.6
Step-by-step explanation:
[tex]\sf{}[/tex]
♛┈⛧┈┈•༶♛┈⛧┈┈•༶
Simplify the following, leaving your answer with a positive exponent:
x^-12/ x^-7
Answer:
[tex]\frac{1}{x^{5} }[/tex]
Step-by-step explanation:
x^-12/ x^-7
= x^(-12-(-7))
= x^-5
= 1/x^5
Solve T=L(2+RS) for R
Answer:
Step-by-step explanation:
I would begin by distributing the L. It will be easier in the end to do it this way. There are a couple of ways you can do this, but distribution is the easiest. After you distribute the L you have
T = 2L + LRS
Next subtract the 2L to get
T - 2L = LRS. Lastly, to isolate the R, divide away the LS to get
[tex]\frac{T}{LS}-\frac{2L}{LS}[/tex] = R In that second term, the L's cancel each other out, leaving us with
[tex]\frac{T}{LS}-\frac{2}{S}[/tex] = R
Find the area and perimeter of the given plain figure
This shape is the rhombus, then ;
Rhombus area = side length × heightA= b × h
A= Rhombus area
h = height ; b = side length ( length of any side)
h= 3 inch ; b= 4.5 inch ; A=?
A= b × h
A= 4.5 × 3 = 13.5 inch²
____o__o_____
The perimeter of a rhombus = 4 × side of lengthP = 4× a
P = The perimeter of a rhombus ; a = side of length
p= ? ; a = 4.5 inch
P = 4× a
P = 4× 4.5 = 18 inch
I hope I helped you^_^
Please help with this question
Answer:
-3.662rad × 180/π = -209.8°
Step-by-step explanation:
Answer:
1 degree = .01745329 radians
1 radian = 57.2957877856 degrees
-209.8 degrees = .01745329 * -209.8 =
-3.66170024200 radians
Step-by-step explanation:
The access code for a cars security system consists of 4 digits. The first digit cannot
be 0 and the last digit nust be even. How many different codes are available?
Answer:
4500
Step-by-step explanation:
The first digit can't be 0. so it will be a number from 1000 to 9999. That's a total of 9000 numbers (9999-1000+1=9000). Since the last digit must be an even number that is one half of the 9000 numbers which is 4500.
If I have 180$ and a pack of dvds cost 18 how much can I buy
Answer:
10 packs of dvds
Step-by-step explanation:
$180 / $18 = 10 packs
You can buy a maximum of 10 dvd packs
Answer:
you can buy 10 dvds that is thr answer
Can someone please help me?
Answer:
The equation of the perpendicular line (PR) to line PQ is; y = -0.5x - 1.5
Step-by-step explanation:
The line is perpendicular to line adjoined by points P(-3,0) and Q(0,6)
The slope of line PQ is;
Slope = change in y ÷ change in x = [tex]\frac{6 - 0}{0 -- 3}[/tex] = 2
The product of slopes of two perpendicular lines = -1
Hence the slope of line PR = -1 ÷ slope of line PQ = -1/2
Taking another point (x,y) and point P(-3,0) the equation of line PR is;
Slope = [tex]\frac{y - 0}{x - -3} = -\frac{1}{2}[/tex]
Cross-multiplying gives;
2y = -x - 3 , y = -x/2 - 3/2 , y = -0.5x - 1.5
x²+y²+6x+8y+24=0 asap reply plss.. Sana umabon ng 1 makasagot
Answer:
3
Step-by-step explanation:
Algunos granos de maíz al ser calentados revientan y pierden agua de manera explosiva.
En promedio se puede considerar que tienen una masa de 125 mg y cuando explotan (palomitas
de maíz) su masa es de 106 mg. ¿Cuántos granos de maíz pira se requerirán para obtener una
libra de palomitas de maíz?
Answer:
Step-by-step explanation:
4280 granos de maíz pira se requerirán para obtener una libra de palomitas de maíz.
CálculoDado que algunos granos de maíz al ser calentados revientan y pierden agua de manera explosiva, y en promedio se puede considerar que tienen una masa de 125 mg y cuando explotan (palomitas de maíz) su masa es de 106 mg, para determinar cuántos granos de maíz pira se requerirán para obtener una libra de palomitas de maíz se debe realizar el siguiente cálculo:
453592 mg = 1 lb453592 / 106 = X4279.16 = XPor lo tanto, 4280 granos de maíz pira se requerirán para obtener una libra de palomitas de maíz.
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Which is the graph of y = RootIndex 3 StartRoot x EndRoot?
Given:
The equation is:
[tex]y=\sqrt[3]{x}[/tex]
To find:
The graph of the given equation.
Solution:
We have,
[tex]y=\sqrt[3]{x}[/tex]
The table of values is:
x y
-8 -2
-1 -1
0 0
1 1
8 8
Plot these points on a coordinate plane and connect them by a free hand curve as shown in the below graph.
Answer:
D
Step-by-step explanation:
edge 2020
Hailey is making pizzas for a pizza party. Each pizza requires 1/2 pound of cheese. How many pounds of cheese does she need to make 19 pizzas? Express your answer in simplest form.
Cheese required for 1 pizza = ½ pound
So, cheese required for 19 pizzas
= 19 × ½ pounds
= 19/2 pounds
= 9½ pounds
So, Hailey needs 9½ pounds of cheese to make 19 pizzas.
The solution is 9.5 pounds
The number of pounds of cheese Hailey need to make 19 pizzas is 9.5 pounds
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the number of pounds of cheese for 19 pizzas be A
Now , the equation will be
The number of pounds of cheese for 1 pizza = 1/2 pounds
So , the number of pounds of cheese for 19 pizzas = 19 x number of pounds of cheese for 1 pizza
Substituting the values in the equation , we get
The number of pounds of cheese for 19 pizzas = 19 x ( 1/2 )
The number of pounds of cheese for 19 pizzas = 19/2
The number of pounds of cheese for 19 pizzas = 9.5 pounds
Therefore , the value of A is 9.5 pounds
Hence , the number of pounds of cheese is 9.5 pounds
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Evaluate: 2-4 А. =100 В. -8 ОО С. -16 D. 1 16
Answer:
D. 1/16
Step-by-step explanation:
Evaluate: 2^-4
А. =100
В. -8ОО
С. -16
D. 1/16
Given
2^-4
= 1 / 2⁴
= 1 / (2 * 2 * 2 * 2)
= 1 / 16
Therefore,
2^-4 = 1/16
D. 1/16
The probability of drawing a red candy at random from a bag of 25 candies is 2/5. After 5 candies are removed from tehe bag, what is the probability of randomly drawing a red candy from the bag?
Given:
The probability of drawing a red candy at random from a bag of 25 candies is [tex]\dfrac{2}{5}[/tex].
To find:
The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.
Solution:
Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:
[tex]P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}[/tex]
[tex]\dfrac{2}{5}=\dfrac{n}{25}[/tex]
[tex]\dfrac{2}{5}\times 25=n[/tex]
[tex]10=n[/tex]
After removing the 5 candies from the bag, the number of remaining candies is [tex]25-5=20[/tex] and the number of remaining red candies is [tex]10-5=5[/tex].
Now, the probability of randomly drawing a red candy from the bag is:
[tex]P(Red)=\dfrac{5}{20}[/tex]
[tex]P(Red)=\dfrac{1}{4}[/tex]
Therefore, the required probability is [tex]\dfrac{1}{4}[/tex].
Solve for a.
-4a – 2a – 7 = 11
a =
[?]
Answer:
or, -4a - 2a -7 = 11
or, -4a -2a =11 +7
or, - 6a = 18
or, a= 18÷ -6
a= -3
plz help me ans fast for 10 pts
Answer:
universal set is the right answer
We have two fractions, 3/4 and 7/6 , and we want to rewrite them so that they have a common denominator (and whole number numerators). What numbers could we use for the denominator?
Answer:
12,24 etc
Step-by-step explanation:
4 and 6 both go into 12 evenly
4*3 = 12
6*2 = 12
12 is the least common denominator
We could also use 24
4*6 = 24
It is a common denominator, but not the least common denominator
We can use any multiple of 12
points V W X Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ find the indicated length
21.) WX 22.) VW 23.) WY 24.) VX 25.) WZ 26.) VY
Answer:
WX=10; VW=22; WY=20; VX=32; WZ=30;VY=42
Step-by-step explanation:
1)WX=XY=XZ/2=20/2=10
2)VW=VZ-WX-XY-YZ=VZ-3*WX=52-3*10=52-30=22
3)WY=WX+XY=2*WX=2*10=20
4)VX=VW+WX=22+10=32
5)WZ=WX+XY+YZ=3*WX=3*10=30
6)VY=VZ-YZ=52-10=42
The points V, W, X, Y and Z are collinear. The indicated lengths are
[tex]WX=10\\VW=22\\WY=20\\VX=32\\WZ=30\\VY=42[/tex]
Given :
points V, W, X, Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ
Lets make diagram using the given information
The diagram is attached below
XY=YZ
XZ=20, so [tex]XY+YZ=20\\Both XY and YZ are same\\XY+XY=20\\2XY=20\\Divide \; by \; 2\\XY=10[/tex]
[tex]WX=XY=YZ \\XY=10\\WY=10\\YZ=10\\[/tex]
Now we find out VW
[tex]VW+WX+XY+YZ=52\\VW+10+10+10=52\\VW+30=52\\Subtract \; 30\\VW=52-30\\VW=22[/tex]
Now we find the indicated length
[tex]WX =10[/tex]
[tex]VW=22\\WY=WX+XY=10+10=20\\VX=VW+WX=22+10=32\\WZ=WX+XY+YZ=10+10+10=30\\VY=VW+WX+XY=22+10+10=42[/tex]
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Consider this equation. tan) 19 17 If 8 is an angle in quadrant II, what is the value of Cos() OA. 19 6 OB. 17 6 O c. V18 6 OD. 17
Using trigonometric identities, it is found that the value of [tex]\cos{\theta}[/tex] is given by:
B. [tex]\cos{\theta} = \frac{\sqrt{17}}{6}[/tex]
What is the tangent of an angle?It is given by the division of it's sine by it's cosine, that is:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
In this problem, the equation given is:
[tex]\tan{\theta} = -\sqrt{\frac{19}{17}}[/tex]
That is:
[tex]\frac{\sin{\theta}}{\cos{\theta}} = -\sqrt{\frac{19}{17}}[/tex]
[tex]\sin{\theta} = -\sqrt{\frac{19}{17}}\cos{\theta}[/tex]
The following identity is applied:
[tex]\sin^2{\theta} + \cos^2{\theta} = 1[/tex]
Then:
[tex]\left(-\sqrt{\frac{19}{17}}\cos{\theta}\right)^2 + \cos^2{\theta} = 1[/tex]
[tex]\frac{36}{17}\cos^2{\theta} = 1[/tex]
[tex]\cos^2{\theta} = \frac{17}{36}[/tex]
[tex]\cos{\theta} = \frac{\sqrt{17}}{6}[/tex]
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Answer:
Hi sorry I just wanted to ask is it B or D? positive or negative?
Step-by-step explanation:
edmentum is the worst
Geometry, please answer question ASAP
Answer:
I'm going to say A and B (I think)
Select the correct answer. Consider this system of equations, where function f is quadratic and function g is linear:
y = f(x)
y = g(x)
Which statement describes the number of possible solutions to the system?
A. The system may have no, 1, 2, or infinite solutions.
B. The system may have no, 1, or infinite solutions.
C. The system may have 1 or 2 solutions.
D. The system may have no, 1, or 2 solutions
Answer:
C is the answer
Step-by-step explanation:
Quadratic equations have at most 2 solution, and linear equations only have 1 solution, and since y is equal to both of them, it can only have 1 or 2 solutions.
The correct answer is option D. The system may have no, 1, or 2 solutions
What is quadratic equation?A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .
f(x) is a quadratic function and g(x) is linear function
y=f(x)
y=g(x)
Quadratic equations have at most 2 solution
linear equations only have 1 solution,
f(x)=g(x)=y
y is equal to both of them, it can only have 1 or 2 solutions.
A line and a parabola can intersect zero, one, or two times
Therefore, a linear and quadratic system can have zero, one, or two solutions
Hence, the correct answer is option D. The system may have no, 1, or 2 solutions
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arrange0.2,¼,30%,10%in ascending and descending order
Answer:
Ascending- 10%, 0.2, 1/4, 30%
Descending- 30%, 1/4, 0.2, 10%
Step-by-step explanation:
0.2 = 2/10 = 4/20
1/4 = 5/20
30% = 30/100 = 6/20
10% = 10/100 = 2/20
Ascending
-2/20, 4/20, 5/20, 6/20
- 10%, 0.2, 1/4, 30%
Descending
- 6/20, 5/20, 4/20, 2/20
- 30%, 1/4, 0.2, 10%
a car can complete journey of 300 km with the average speed of 60 km per hour how long does it take to complete the journey what is the speed of the car if it covers only 200 km in the same interval of the time
please I need help urgent
Answer:
a. 5 hours
b. 40 kph
Step-by-step explanation:
300 km ÷ 60 km = 5 hours
200 km ÷ 5 hours = 40 kilometers per hour
In a large midwestern university (the class of entering freshmen being on the order of 6000 or more students), an SRS of 100 entering freshmen in 1999 found that 20 finished in the bottom third of their high school class. Admission standards at the university were tightened in 1995. In 2001 an SRS of 100 entering freshmen found that 10 finished in the bottom third of their high school class. The proportion of all entering freshmen in 1999 and 2001, who graduated in the bottom third of their high school class, are p1 and p2, respectively.Is there evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced, as a result of the tougher admission standards adopted in 2000, compared to the proportion in 1999? To determine this, you test the hypothesesH0 : p1 = p2 , Ha : p1 > p2.The P-value of your test isA. 0.976.B. 0.024.C. 0.048.D. 0.001.
Answer:
B. 0.024
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
1999:
Of 100, 20 were in the bottom thid. So
[tex]p_B = \frac{20}{100} = 0.2[/tex]
[tex]s_B = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]
2001:
Of 100, 10 were in the bottom third, so:
[tex]p_A = \frac{10}{100} = 0.1[/tex]
[tex]s_A = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]
To determine this, you test the hypotheses H0 : p1 = p2 , Ha : p1 > p2.
Can also be rewritten as:
[tex]H_0: p_B - p_A = 0[/tex]
[tex]H_1: p_B - p_A > 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the sample:
[tex]X = p_B - p_A = 0.2 - 0.1 = 0.1[/tex]
[tex]s_A = \sqrt{s_A^2+s_B^2} = \sqrt{0.03^2+0.04^2} = 0.05[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.1 - 0}{0.05}[/tex]
[tex]z = 2[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a difference of proportions of at least 0.1, which is 1 subtracted by the p-value of z = 2.
Looking at the z-table, z = 2 has a p-value of 0.976.
1 - 0.976 = 0.024, so the p-value is given by option B.
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
I just need the numbers anyone help ?
Answer:
See below & pic.
Step-by-step explanation:
Start by plotting the given point. Then use the slope to find two more points. From the given point go up 2 and right 4. GO back to the given point. Go down 2 and left 4. Now you have 3 points. Connect them with a line.
Sam ordered 2 tons of crushed stone. How many pounds of crushed stone does she have?
Answer:
4000
Step-by-step explanation:
1 ton = 2000 pounds
2 tons = ? pounds
Multiply:
2000 × 2 = 4000
There will be 4000 pounds of crushed stone.
Hope this helped.
Sam ordered 2 tons of crushed stone. How many pounds of crushed stone does she have?
S O L U T I O N :Here, we need to convert the tons into pounds to get the desired result
✪ According to the question :
We know that,
1 ton = 2000 pounds
2 tons = 2(1000 pounds) = 2000 pounds
Hence, she have 2000 pounds of crushed stoneA tank contains 150 liters of fluid in which 20 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.
Answer:
the number A(t) of grams of salt in the tank at a time is A(t)=150-110e-t/50
Can you please answer this answer with a step by step explanation?
the BEST answer gets the BRAINLIEST answer mark!
Answer:
Step-by-step explanation:
If K is square number, then exponents in number N are even.
find the x- and y-intercept of the graph of -9x+7y=27 . State tour based as a whole number of as a improper fraction in simplest form
answer:
is this cool? or explanation?
TWO TEST
23. Evaluate 4b2 for b
= -1/2
4b² when b = -1/2
[tex] = {4( \frac{ - 1}{2})}^{2} \\ = 4( \frac{1}{4}) \\ = \frac{4}{4} \\ = 1[/tex]
Answer:
-4
Step-by-step explanation:
4b x 2 when b = -1/2
1) put -1/2 where b is.
4 x -1/2 x 2
2) solve.
-2 x 2
-4
If you apply the changes below to the absolute value parent function, 1(x) = 1X, what is the equation of the new function? Shift 8 units left. • Shift 3 units down. O A. g(x) = (x + 81 - 3 O B. g(x) B. g(x) = (x - 3| + 8 O c. g(x) = [X - 31- 8 D. g(x) = (x - 8 - 3
Answer:
A. g(x) = |x + 8| - 3Step-by-step explanation:
If the function is f(x), then shift 8 units left and 3 units down will result in:
g(x) = f(x + 8) - 3Apply to the given function to get:
g(x) = |x + 8| - 3Correct choice is A