5. Add the polynomials.
(3k² + 2k - 3) + (- 2k² + 8k + 11).

Answers

Answer 1

k² + 10k + 8 is the sum of (3k² + 2k - 3) + (- 2k² + 8k + 11).

Define addition.

The act of combining two or more items is known as addition. The process of computing the sum of two or more numbers in mathematics is called addition. It is a fundamental mathematical procedure that is frequently used in daily life. When we work with money, figure out our food bills, or figure out the time, we frequently employ addition. Mathematicians employ the action of addition to combine numbers. The sum of the given numbers is the outcome of addition, or the total of the inputted numbers. For instance, when we add the numbers 2 and 3, we get the number 5. Here, we added the two numbers 2 and 3 to obtain the result, which is 5.

Given

Polynomials

(3k² + 2k - 3) + (- 2k² + 8k + 11)

Adding the polynomials with same exponents

3k² + 2k - 3 - 2k² + 8k + 11

3k² - 2k² + 2k + 8k - 3 + 11

k² + 10k + 8

k² + 10k + 8 is the sum of (3k² + 2k - 3) + (- 2k² + 8k + 11).

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Related Questions

Solve the following equation by first writing the equation in the form a x squared = c: t squared minus 49 = 0 a. t = 49 b. t = plus-or-minus 49 c. t = 7 d. t = plus-or-minus 7 Please select the best answer from the choices provided A B C D

Answers

By solving the equation we get ,t = ± 7 using concept of square roots.

How to find the square roots ?

Square root, in mathematics, a factor of a number that, when multiplied by itself, gives the original number. For example, both 3 and –3 are square roots of 9.

For example, 2 is the square root of 4, and this is expressed as √4 = 2.

We know that every squared number has two square roots one is positive and another is negative.

In given que,

given condition is t squared minus 49 = 0

Form of equation is ax^ 2 = c.

given condition can also be written as t^2 - 49 = 0

                                                          i.e. t^2 = 49

where a = 1

x = t

c = 49

So, the square root are 7 and -7.

So, equation become t = ± 7.

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Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that involves mailing discount coupons to all their credit card customers. This promotion will be considered a success if more than 10% of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of 100 credit card customers.
Develop hypotheses that can be used to test whether the population proportion of those who will use the coupons is sufficient to go national.

Answers

The null hypothesis set up for the hypothesis test of the population parameter is given by H₀: p ≥ 0.1 .

We would set up the hypothesis test.

For the null hypothesis,

H₀: p ≥ 0.1

For the alternative hypothesis,

Hₐ: p < 0.1

This is a two-tailed test.

Taking into account the population proportion, p = 0.1 q = likelihood of failure = 1 - p

q = 1 - 0.1 = 0.9

b) In light of the sample,

P = x/n = sample proportion

Where x = the number of successes, n = the number of samples, and p = 13/100 = 0.13

The test statistic, the z score, would be calculated as z = (P - p)/pq/n z = (0.13 - 0.1)/(0.1 0.9)/100 = 1.

The determined test statistic is 1 for the right tail and - 1 for the left tail.

Since α = 0.05, the critical value is calculated using the normal distribution table.

α₂ = 0.51/2 = 0.025 on the left

The z score for an area to the left of 0.025 is - 1.96

α₂ = 1 - 0.025 = 0.975 for the right

1.96 is the z score for an area to the right of 0.975.

The test statistic must be less than - 1.96 or larger than 1.96 in order to reject the null hypothesis.

We cannot reject the null hypothesis since - 1 > - 1.96 and 1 1.96.

As a result of the hypothesis test results, Eagle Outfitter should take the promotion national.

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Graph the equation below by plotting the
y-intercept and a second point on the
line. When you click Done, your line will
appear.
3
y=-x+3
Click on the point(s). To change your selection, drag the
marker to another point. When you've finished, click Done.
8 64-2
Done
8
-6-
NA
2
สี
-2
4
-6-
-8-
2 4
6 8
Edit

Answers

By plotting y-intercept (0, -5) and any one of the points given in the table we can get the required line.

What is equation of the line?

The equation y = mx + c is the general equation of any straight line where m is the gradient of the line (how steep the line is) and c is the y -intercept (the point in which the line crosses the y -axis).

Equation of the line has been given as,

[tex]y=\frac{3}{2} x-5$$[/tex]

By comparing this equation with the y-intercept form of the equation,

y=m x+b

Slope of the line ' m '[tex]$=\frac{3}{2}$[/tex]

and y-intercept ' b ' = -5

Table for the points to be plotted on a graph will be,

Table for the points to be plotted on a graph will be,

x              y

-4           -11

-2           -6

0            -5

2            -4

4            -3

By plotting y-intercept (0, -5) and any one of the points given in the table we can get the required line.

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look at attached photo

Answers

The correct answer is A) y = 9000x + 65,000.

Find a linear equation that models the value of the house after x years?

The correct answer is A) y = 9000x + 65,000.

This is an equation in slope-intercept form, where "y" is equal to the value of the house after x years, "9000x" is the slope (or rate of change) of the equation, and 65,000 is the y-intercept (or the initial value of the house). The equation can be derived from the given information.The initial value of the house is 65,000, so the y-intercept must be 65,000. To find the slope, we can use the formula "rise/run", or change in y/change in x.

The house has increased in value by 54,000 ($119,000 - $65,000) over 6 years (change in x), so the slope must be 9000 (54,000/6).

The equation y = 9000x + 65,000

models the value of the house after x years, where y is the value of the house,

9000x is the slope of the equation,

and 65,000 is the y-intercept.

This equation can be used to calculate the value of the house after any given number of years.

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Height (in inches) Mean Minimum Q1 Median Q3 Std Dev 4.21 Maximum 79 68.2 67 , 71 , Which conclusion about the distribution is most plausible? (A) 50% of the students are taller than 68.2 inches. (B) 75% of the students are taller than 71 inches. (C) There are more students between 67 inches and 79 inches than are between 62 inches and 67 inches (D) Less than 25% of the students have heights between 68.2 and 71 inches. (E) The height that occurs most frequently is 67 inches. Height (in inches) Q3 Mean 68. 2 Std Dev .21 Minimum 62 4 Q1 63 Median 67 Maximum 79 Which conclusion about the distribution is most plausible? (A) 50% of the students are taller than 68.2 inches. (B) 75% of the students are taller than 71 inches. (C) There are more students between 67 inches and 79 inches than are between 62 inches and 67 inches. (D) Less than 25% of the students have heights between 68.2 and 71 inches. (E) The height that occurs most frequently is 67 inches.

Answers

Standard deviation will be √3.3516 .

To calculate the standard deviation for the given data first we have to calculate the total number of students , mid value , fiXi , fiXi².

After that , we have to calculate the Xbar by using

Xbar = ∑fiXi / N

for which we need the value of fi , Xi and N

N = 100

fiXi = 6478

we have calculated the values from the given data ,

Therefore ,

Xbar = 6478 / 100

= 64.78

Var(X) = αx² - ∑fiXi² / N - (Xbar²)

= 419980 / 100 - (64.78)²

= 4199.80 -4196.4484

=3.3516

Thus,

standard deviation ax = √var(X)

= √3.3516

Therefore , the standard deviation will be  √3.3516

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for which of the three intervals do you have the most confidence that the interval captures the population mean

Answers

it can be inferred that there is a 95% probability that the true value falls within that range.

A confidence interval, in statistics, refers to the probability that a population parameter will fall between a set of values for a certain proportion of times. Analysts often use confidence intervals than contain either 95% or 99% of expected observations.

Thus, if a point estimate is generated from a statistical model of 10.00 with a 95% confidence interval of 9.50 - 10.50,

it can be inferred that there is a 95% probability that the true value falls within that range.

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Solve. Write answers as an imaginary number
y^2+11=2

Answers

The solution of the equation written as an imaginary number is y =  3i or -3i

How to solve an equation and write the answer as an imaginary number?

An imaginary number is a number of the form ai, where a is a real number and i is the square root of -1. Imaginary numbers are often denoted with the letter "i".

Given: y² + 11 = 2

y² + 11 = 2

y² = 2 - 11

y² = -9

y = ±√-9                      

y = ± 3i

y = 3i or -3i

(Note: √9 = 3 and √-9 = 3i)

Thus, the solution is y =  3i or -3i

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what is equivalent to (32−−√5)13

Answers

Answer:

Your answer is 416 + 13 [tex]\sqrt{5}[/tex].

Step-by-step explanation:

You brought popular game on sale for $20 and want to sell it on eBay. You want to mark up the toy 60%. What did you sell it for?

Answers

Answer is $32

20*.6=12
12+20=32

In this triangle, what is the value of x?

Enter your answer, rounded to the nearest tenth, in the box.

Answers

Answer:

70

Step-by-step explanation:

Write a quadratic function in standard form whose graph has a vertex of (2, 6) and passes through the point (4, 10) .

Answers

A quadratic function in standard form is of the form y = ax^2 + bx + c, where a, b, and c are constants. The vertex of the graph of a quadratic function is at the point (h, k), where h is the x-coordinate of the vertex and k is the y-coordinate of the vertex.

To write a quadratic function in standard form with a vertex of (2, 6) and that passes through the point (4, 10), we can first use the coordinates of the vertex to determine the values of h and k. We know that h = 2 and k = 6, so we can substitute these values into the formula for the vertex to find the value of a:

k = a(h^2) + bh + c
6 = a(2^2) + b(2) + c
6 = 4a + 2b + c

We can then use the coordinates of the point (4, 10) to find the value of b:

10 = a(4^2) + b(4) + c
10 = 16a + 4b + c

Solving the system of equations formed by these two equations, we find that a = -1, b = 6, and c = 4. Therefore, the quadratic function in standard form whose graph has a vertex of (2, 6) and passes through the point (4, 10) is y = -x^2 + 6x + 4.

Need Awnser asap
Right Awnser gets branliest

Answers

Answer:

x1,y16 is the rate of change

Step-by-step explanatI subtracted 13-32 which gives me 16, then I added 16 to 32 to be sure and it gave me 48 so the change on the Y axis is going up by 16 and x axis is going up by 1

The length of a rectangular poster is 8 more inches than three times its width. The area of the poster is 256 square inches. Solve for the dimensions (length and width) of the poster
The dimensions are
inches ___ by ____ inches.

Answers

When the area of the poster is 256 square inches, the measurements are 32 inch and 8 inch.

What is area?

The quantity area indicates the extent of a region on a planar or curved surface. Surface area refers to the area of an open surface or the border of a three-dimensional object, whereas area of a plane region or plane area refers to the area of a form or planar lamina. The total space occupied by a flat (2-D) surface or the form of an item is defined as its area. The area is the region defined by an object's form. The area of a form is the space covered by a figure or any two-dimensional geometric shape in a plane.

Here,

let length be l and width be w.

l=3w+8

l*w=256

(3w+8)*w=256

3w²+8w=256

3w²+32w-24w-256=0

3w(w-8)+32(w-8)=0

(3w+32)(w-8)=0

w=-32/3, 8

w=8 inch

l=3*8+8

l=32 inch

The dimensions for the poster are 32 inch and 8 inch when area of the poster is 256 square inches.

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Lucy wants to buy a small car. She speaks to her bank and they offer her a loan of £5000 over 5 years at a simple interest rate of 5%. How much simple interest will Lucy have to pay back in total?

Answers

Simple interest at a rate of 5% per year for five years on a principle of $5,000 has resulted in a total accrual of $6,250.00, which includes both the principal and interest.

What is simple interest?

To calculate simple interest, multiply the daily interest rate by the principle and the number of days between payments. Consumers that make on-time or early monthly loan payments benefit from simple interest. Most loans with simple interest rates are auto loans and short-term personal loans.

A = $6,250.00

I = A - P = $1,250.00

Formula: A = P(1 + rt)

First, convert R percent to r decimal, which is equal to 5%/100 or 0.05 per year.

Fixing our equation

A = 5000(1 + (0.05 × 5)) = 6250 \sA = $6,250.00

Simple interest at a rate of 5% per year for five years on a principle of $5,000 has resulted in a total accrual of $6,250.00, which includes both the principal and interest.

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The enrollment at MSU is described by the function
f(x) = 250x + 6000, where x is the number of years since 2010.

I. Find the enrollment in 2016.

II. In what year will the enrollment reach
10,000?

Answers

1) The enrollment in 2016 will be 7500.

2) In 2026 year the enrollment reach 10,000.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The function f(x) represents the number of enrollment.

Defined as;

⇒ F(x) = 250x + 6000

Where x represents year since 2010.

(1) Now for finding the enrollment in 2016;

Put x = 2016 - 2010 = 6 in the function

⇒ F(6) = 250x6 + 6000

          = 7500

Thus, The required number of enrollment = 7500

(2) Now we have to find the year in which enrollment reach 10,000;

i.e f(x) = 10,000

=> 250x + 6000 = 10000

=> 250x = 4000

=> x = 16

Thus, The required year = 2010 + 16

                                     = 2026 answer.

1) The enrollment in 2016 will be 7500.

2) In 2026 year the enrollment reach 10,000.

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use the data above to test the claim that marble color preference and club membership are related, as follows: (2 pts) carefully state the hypotheses. Hypothesis is
H0: marble color preference and income class are independent
H1: marble color preference and income class are dependent

Answers

The Null Hypothesis, H0 is "Marble color preference and income class are independent" and the Alternate Hypothesis, H1 is "Marble color preference and income class are dependent".

The null and alternative are always claims about the population. That’s because the goal of hypothesis testing is to make inferences about a population based on a sample. Often, we infer whether there’s an effect in the population by looking at differences between groups or relationships between variables in the sample. It’s critical for your research to write strong hypotheses.

We can use a statistical test to decide whether the evidence favors the null or alternative hypothesis. Each type of statistical test comes with a specific way of phrasing the null and alternative hypotheses. However, the hypotheses can also be phrased in a general way that applies to any test.

We are given that to test the claim that marble color preference and club membership are related.

Thus, the Null Hypothesis, H0 is "Marble color preference and income class are independent" and the Alternate Hypothesis, H1 is "Marble color preference and income class are dependent".

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A sinusoidal function whose period is π2
, maximum value is 10, and minimum value is −4 has a y-intercept of 10.

What is the equation of the function described?


Responses

f(x)=7cos(4x)+3
f ( x ) = 7 cos ( 4 x ) + 3

f(x)=7sin(4x)+3
f ( x ) = 7 sin ( 4 x ) + 3

f(x)=7cos(4πx)+3
f ( x ) = 7 cos ( 4 π x ) + 3

f(x)=7sin(4πx)+3

Answers

The equation of the function described as;  y = 7 sin ( 4x + π/2 ) + 3

The general equation of the sine curve can be written as;

y = a sin ( nx + α ) + b

where : a is the amplitude, n = 2π/period, b = shift in the direction of y

            α°= shift in the direction of x

We are Given period = π/2 the maximum value is 10, the minimum value is −4 and y-intercept of 10.

 Thus,

a = (maximum - minimum)/2 = (10 - -4)/2

a = 7

 n = 2π/period = 2π/(π/2)

n = 4

 b = maximum - a = 10 - 7

b= 3

To find α as y-intercept = 10

y = 10 at x = 0

Substitute in the general function;

y = a sin ( nx + α ) + b

10 = 7 sin ( 4*0 + α ) + 3

Thus, we have;

sin α = 1

α = π/2

So, the equation of the function described is;

 y = 7 sin ( 4x + π/2 ) + 3

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One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor. (a) Write a differential equation that is satisfied by y. (Use k for the constant of proportionality.) dy dt = ky 1-y. (b) Solve the differential equation. Assume y(0) = C. y = 1-ce-kt +1 (c) A small town has 1300 inhabitants. At 8 AM, 100 people have heard a rumor. By noon half the town has heard it. At what time will 90% of the population have heard the rumor? (Do not round k in your calculation. Round the final answer to one decimal place.) hours after the beginning

Answers

(a) The differential Equation that is satisfied by y is dy/dt = k × y × (1 - y)   ,

(b) Solution of the differential equation assuming y(0) = c is y = [tex]\frac{1}{(\frac{1-c}{c})e^{-kt} +1 }[/tex] .

In the question ,

Part (a)

let the fraction of people who heard the rumor is = y

So , the fraction who have not heard the rumor is = 1 - y .

the rate of rumor spread is ⇒ dy/dt = k×y(1 - y)

dy/y(1-y) = k.dt     ...where k is the constant of proportionality .

So , the differential equation is ..

dy/dt = k × y × (1 - y)

Part (b)

So , 1/y(1-y) = 1/y + 1/(1 - y)       ....equation(1)

integrating equation(1) , we get

∫dx/(1 + ax) = ㏑(1 + ax)/a     ,....where a is the constant

㏑y + ㏑(1-y)/(-1) = kt + d     ,.....where d is the constant

By using , ㏑a - ㏑b = ㏑(a/b) and taking exponential . we get ,

y/(1 - y) = c₁[tex]e^{k\times t}[/tex]

for t = 0 and y(0) = c

solving further , we get

c₁ = c/(1 - c)

So , y = (1-y)c₁[tex]e^{k\times t}[/tex]

y(1 + c₁[tex]e^{k\times t}[/tex]) = c₁[tex]e^{k\times t}[/tex]

y = c₁[tex]e^{k\times t}[/tex]/(1 + c₁[tex]e^{k\times t}[/tex])

taking c₁[tex]e^{k\times t}[/tex] common , and substituting the value of c₁ we get ,

the solution as , y = [tex]\frac{1}{(\frac{1-c}{c})e^{-kt} +1 }[/tex]    .

Therefore , (a) the differential equation is dy/dt = k × y × (1 - y)   and

(b) the solution is y = [tex]\frac{1}{(\frac{1-c}{c})e^{-kt} +1 }[/tex]   .

The given question is incomplete , the complete question is

One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor.

(a) Write a differential equation that is satisfied by y. (Use k for the constant of proportionality.)

(b) Solve the differential equation. Assume y(0) = C.

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After a snowstorm in the town of Golden Glen, the morning temperature was

10°F. But by the afternoon, the temperature had risen by 17°F.

Answers

The change in temperature based on the information is 27°F.

How to illustrate the relationship?

It should be noted that temperature simply means the degree of coldness and hotness in a body. In this case, after a snowstorm in the town of Golden Glen, the morning temperature was -10°F. But by the afternoon, the temperature had risen by 17°F.

Let the change in temperature be represented by x.

Therefore, -10 + x = -17

x = 17 + 10

x = 27

The Temperature is 27°F.

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After a snowstorm in the town of Golden Glen, the morning temperature was -10°F. But by the afternoon, the temperature had risen by 17°F. What was the change in temperature?

Is 5x-8+7y=y-6 linear or nonlinear

Answers

Answer:

Step-by-step explanation:

The equation 5x-8+7y=y-6 is linear because it contains only terms with the variables x and y raised to the power of 1. In a linear equation, the highest power of any variable is 1. Nonlinear equations contain exponents that are higher than 1 on one or more variables.

In a class activity, all the 15 students wear hats. 7 students wear red hats, 6 students wear green hats and 2 students wear white hats. (I) two of the 15 students are picked at random. Show that the probability that these two students wear hats of the the same colour is 37/105. (I) three of the 15 students are picked at random. Find the probability that at least 2 of these students wear red hats.

Answers

The probabilities, using the hypergeometric distribution, are given as follows:

i) Two wear the same color: 37/105: 0.35238 = 37/105.

ii) At least 2 wear red: 0.4461.

What is the hypergeometric distribution formula?

The mass probability formula is presented as follows:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are presented as follows:

x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.

The probability of two red is given as follows:

[tex]P(X = 2) = h(2,15,2,7) = \frac{C_{7,2}C_{8,0}}{C_{15,2}} = 0.2[/tex]

The probability of two green is given as follows:

[tex]P(X = 2) = h(2,15,2,6) = \frac{C_{6,2}C_{9,0}}{C_{15,2}} = 0.14286[/tex]

The probability of two white is given as follows:

[tex]P(X = 2) = h(2,15,2,2) = \frac{C_{2,2}C_{13,0}}{C_{15,2}} = 0.00952[/tex]

Then the probability of two wearing the same color is given as follows:

0.2 + 0.14286 + 0.00952 = 0.35238 = 37/105.

The probability that out of 3 people, at least 2 wear red, is given as follows:

[tex]P(X = 2) = h(2,15,3,7) = \frac{C_{7,2}C_{8,1}}{C_{15,3}} = 0.3692[/tex]

[tex]P(X = 3) = h(3,15,3,7) = \frac{C_{7,3}C_{8,0}}{C_{15,3}} = 0.0769[/tex]

Hence:

0.3692 + 0.0769 = 0.4461.

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Which of the following equations have only one solution? Select all correct answers. x 2 - x - 6 = 0 5 x 2 + 20 x + 20 = 0 9 x 2 - 25 = 0 4 x 2 + 4 x = 0 x 2 + 6 x + 9 = 0

Answers

Answer: wutttttttttt

Step-by-step explanation: i jus need points

Let the discrete random variable X have the geometric distribution with parameter p. (a) Give a real-life example in which the geometric distribution can be applied. (b) Use the definition of the expected value to show that: E[X] = 1/p. (c) Explain why it makes sense that the expected value of X is inversely proportional to p.

Answers

a) A discrete random variable is a variable that can take only a countable number of distinct values, such as 0, 1, 2, 3, 4, and so on.

b) Examples of discrete random variables are the number of children in a family, the number of people who go to the cinema on Friday nights, etc.

c) E(x) = 1/p

Discrete Random Variable:

A discrete random variable can be defined as a type of variable whose value depends on the numerical outcome of some random phenomenon. Also called a random variable. Discrete random variables are always easily countable integers. A probability mass function is used to describe the probability distribution of a discrete random variable.

Discrete random variables are used to quantify the results of random experiments. A discrete random variable takes on an infinite number of possible outcomes. In general, discrete random variables can be counted as 0, 1, 2, 3, 4, ...

Geometric Distribution :

The geometric variate is the variate that specifies the number of consecutive failures before the first success in Bernoulli trials. The probability of success of a Bernoulli trial is given by p and the probability of failure is 1 - p.

The Geometric Random Variable can be written as X ~ G(p).

The probability mass function is P(X = x) = (1  - p)ˣ⁻¹ p

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In the last 24 days, it rained 18 days. What is the ratio of rainy days to total days written as a percent?

Answers

The ratio of rainy days to total days written as a percent will be 75%.

How to illustrate the ratio?

Ratio demonstrates how many times one number can fit into another number. Ratios contrast two numbers by ordinarily dividing them. A/B will be the formula if one is comparing one data point (A) to another data point (B).

Ratio is used to compare two or more numbers. It is also used to indicate how big or small a quantity is when it is compared to another. It should be noted that in a ratio, two quantities are compared using division.

Since in the last 24 days, it rained 18 days.

Number of rainy days = 18.

Number of total days = 24

The ratio of rainy days to total days written as a percent will be:

= Number of rainy days / Total days × 100

= 18/24 × 100

= 3/4 × 100

= 75%

Therefore, the ratio is 3:4 which is 75%.

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. Find the solution(s) to the systems of equations algebraically
{(y=x^2-2x+4),(y=3x):} (Use Substitution and factoring)
(multiple choice)
A.(0,0)
B.(4,12)
C.(4,1)
D.(0,4)
E.(1,3)

Answers

The solution to the systems of equations is (4,1). Option C. is the answer

How to find the solution(s) to the systems of equations algebraically?

An algebraic equation is when two expressions are set equal to each other, and at least one variable is included

Given the: equations {(y=x²-2x+4), (y=3x):}

y= x²-2x+4 and y = 3x

substitute y = 3x into y= x²-2x+4. That is:

y= x²-2x+4

3x =  x²-2x+4

x²-2x -3x+4 = 0

x²-5x+4 = 0

By factoring:

x²-4x -1x+4 = 0

x(x-4) -1(x-4) = 0

(x-4)(x-1) = 0

x-4 = 0 or x-1 = 0

x= 4 or x = 1

Thus, the solution is (4,1)

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A racetrack charges $85 for each seat in the lower section, $60 for each seat in the upper sections, and $35 for field tickets. There are three times the amount of seats in the upper section as compared to the lower section. The revenue from selling all 22,800 seats is $948,000. How many seats are in the upper section of the racetrack?

Answers

Using a system of equations, the number of seats in the upper section of the racetrack is 3,600.

What is a system of equations?

A system of equations, also called simultaneous equations, is two or more equations solved concurrently.

We can use any of the following methods to solve simultaneous equations:

GraphicalSubstitutionEliminationMatrix.

In this situation, after forming the equations, we can use substitution and elimination methods to solve them.

Racetrack charge per lower seat = $85

Racetrack charge per upper seat = $60

Racetrack charge per field ticket = $35

Let lower seats = x

Let upper seats = 3x

Let field tickets = y

4x + y = 22,800 ... Equation 1

y = 22,800 - 4x ...Equation 3

85x + 60(3x) + 35y = 948,000

85x + 180x + 35y = 948,000 ... Equation 2

Substitute Equation 3 in Equation 2 to eliminate y:

85x + 180x + 35(22,800 - 4x) = 948,000

85x + 180x + 798,000 - 140x = 948,000

125x = 948,000 - 798,000

125x = 150,000

x = 1,200

Determining the number of seats:

Seats in the Lower section = 1,200

Seats in the Upper section = 3,600 (1,200 x 3)

Field tickets, y = 22,800 - 4x

y = 22,800 - 4(1,200)

= 18,000

Check:

85x + 180x + 35y = 948,000

85(1,200) + 180(1,200) + 35(18,000) = 948,000

102,000 + 216,000 + 630,000 = 948,000

948,000 = 948,000

Thus, based on simultaneous equations, there are 3,600 seats in the upper section of the racetrack.

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find the volume of the largest right circular cylinder that can be inscribed in a sphere of radius r.

Answers

The volume of the largest right circular cylinder is [tex]=\frac{4\pi r^3}{3\sqrt{3} }[/tex] cu. unit

Now, According to the question:

The given sphere is of radius R.

Let h be the height and r be the radius of the cylinder inscribed in the sphere.

We know that:

Volume of cylinder

V = [tex]\pi R^2h[/tex]    .....(1)

In right Triangle OBA

[tex]AB^2 + OB^2 = OA^2[/tex]

[tex]R^2 + \frac{h^2}{4} = r^2[/tex]

So, [tex]R^2 = r^2 - \frac{h^2}{4}[/tex]

Putting the value of [tex]R^2[/tex] in equation (1), We get

V = [tex]\pi (r^2 - \frac{h^2}{4} )h[/tex]

V = [tex]\pi (r^2h - \frac{h^3}{4} )[/tex]   ....(2)

dV/dh = [tex]\pi (r^2 - \frac{3h^2}{4} )[/tex] .....(3)

For, Stationary point, dV/dh = 0

[tex]\pi (r^2 - \frac{3h^2}{4} )[/tex] = 0

[tex](r^2 - \frac{3h}{4} )[/tex]   => [tex]h^2 - \frac{4r^2}{3}[/tex] => [tex]h - \frac{2r}{\sqrt{3} }[/tex]

Now, [tex]\frac{d^2V}{dh^2} = \pi (-\frac{6}{4}h )[/tex]

[tex][\frac{d^2V}{dh^2}]_a_t_h_=_\frac{2r}{\sqrt{3} }[/tex]   = x[-3/2 , [tex]2r/\sqrt{3}[/tex]]< 0

Volume is maximum at h = 2r/[tex]\sqrt{3}[/tex]

Maximum volume is :

[tex]= \pi (r^2.\frac{2r}{\sqrt{3} }- \frac{1}{4}.\frac{8r^3}{3\sqrt{3} } )[/tex]

[tex]=\pi (\frac{2r^3}{\sqrt{3} }-\frac{2r^3}{3\sqrt{3} } )[/tex]

[tex]=\pi (\frac{6r^3-2r^3}{3\sqrt{3} } )[/tex]

[tex]=\frac{4\pi r^3}{3\sqrt{3} }[/tex] cu. unit

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Using the above graphic, it takes about _____ years to transition from using no oil to consuming 100 million barrels per day whereas it takes about______ years to transition from using 100 million to 200 million barrels per day.
A. 60, 10
B. 10, 60
C. 120, 50
D. 50, 120

Answers

It takes about 120 years for the graph to reach 100 million barrels per day whereas it takes 50 years to go from 100 million to 200 million.

As per the question the left axis indicates the amount of oil in the earth in trillions of barrels.

The right axis indicates the global consumption rate of oil in millions of barrels per day.

To the left of the red vertical line are model results that approximate reality whereas to the right are model-based predictions of the future.

The bottom axis is time in years.

The graph attached at the end of the solution.

Let the number of years of transition from using no oil to consuming 100 million barrels per day be a.

Let the number of years of transition from using 100 million to 200 million barrels per day be b.

From the given graph, we can see that initial consumption rate is low, and it takes 120 years for the graph to reach 100 million barrels.

But it takes 50 years to go from 100 million to 200 million.

This is known as exponential growth.

Therefore, the value of a is 120 and the value of b is 50.

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In AUVW, m/U = (3x - 10)°, m/V = (6x + 5)°, and m/W = (4x - 10)°. What is the value of x?

Answers

Answer:

  x = 15

Step-by-step explanation:

You have ∆UVW with angles U=(3x-10)°, V=(6x+5)°, and W=(4x-10)°, and you want to know the value of x.

Angle sum theorem

The angle sum theorem tells you the sum of angles in a triangle is 180°.

  U +V +W = 180°

  (3x -10)° +(6x +5)° +(4x -10)° = 180°

  13x -15 = 180 . . . . . . . divide by °, collect terms

  13x = 195 . . . . . . . add 15

  x = 15 . . . . . . . divide by 13

The value of x is 15.

Find the Probability of, A King, ace, jack of clubs or queen of diamonds appears in drawing a single card from a well shuffled ordinary deck of 52 cards.

Answers

The Probability of, a ace, jack of clubs, King or queen of diamonds appears in drawing a single card from a well shuffled ordinary deck of 52 cards is 4/13.

As per the given data,

we need to find out the probability of, King, ace, jack of clubs or queen of diamonds appears in drawing a single card from a well shuffled ordinary deck of 52 cards.

We know that,

Probability(Event) =Number of Favorable Outcomes/Total number of

                                Outcomes = x/n.    

Total number of Outcomes is 52 (given)

So,  we will calculate Number of Favorable Outcomes as follows:

The total no. of King in deck of card is 4

The total no. of queen in deck of card is 4.

The total no. of ace in  deck of card is 4.

The total no. of jack in deck of card is 4.

Therefore, the number of favorable outcomes is 4+4+4+4= 16

Now, putting values in the above stated formula of probability, we get:

Probability= 16/52=4/13

Therefore, the probability of pulling a King, Ace, Jack of Clubs, or Queen of Diamonds from a 52-card standard deck that has been properly shuffled is 4/13.

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