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QUESTION 1: Miranda found four different bottles filled with unknown pure liquids. She measured the mass, volume, and boiling point of these liquids, and calculated the density which are displayed in Table 1.

What conclusion can you make on whether any of the liquids are the same. Explain based on the information in the table.

QUESTION 2: After showing the different states of water (ice, water, and water vapor) in lab to the class, Carl's teacher asked students to create models to explain how ice, water, and water vapor are different. Carl's models and description appear in the diagram below.

Describe what is good and what might be improved about Carl's models in explaining how the three states of water are different in the arrangement of their water molecules.

Answer:

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

Answer:

yes its okay i think so it is the correct answer

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

Answer:

F = E q

E = 2.18E-14 / 1.6E-19 = 1.36E5 N/C

The direction of the field will be the same as force on the proton - southerly

Answer:

is 6

Explanation:

h

Answer: William Thomson, better known as Lord Kelvin

Answer:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

Explanation:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

Answer:

you have patience the distance.

Explanation:

the train leaves at 6.30.

The first law is used to visualize this. The ball is at a consistent velocity, unless acted on by another force, when the ball goes upwards and there's no force acting on it, it keeps going upwards, but there is gravity. When the ball is going up, you do not interact with it, thus only gravity is the only force, making the ball go downwards.

To examine this, apply the first law. When the ball is moving upward and there is no force acting on it, it continues to move higher but there is gravity. The ball is at a constant velocity unless pushed upon by another force.

According to Newton's law of gravity, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.

Anything that can alter an object's motion is a force. When you toss a ball, you apply force in a direction that determines the direction in which it will move. The ball travels farther the harder you toss it because it is under greater stress.

The ball continues to go upward even though there is no force pushing against it because of gravity. Unless another force pushes on it, the ball is moving at a steady speed.

Thus, this way, when ball thrown vertically into the air shows Newton's first law.

For more details regarding Newton's laws of motion, visit:

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We have that for the Question, it can be said that

From the question we are told

From,

[tex]tan\theta = \frac{h}{2}[/tex]

differentiate with respect to h

[tex]sec^2\theta * \frac{do}{dz} = \frac{1}{2} * \frac{dh}{dz}\\\\\frac{dh}{dz} = 2 sec^\theta * \frac{d\theta}{dz}\\\\\theta = \frac{\pi}{6} and \frac{d\theta}{dz} = 0.1rad/min\\\\\frac{dh}{dz} = 2sec^2 (\frac{\pi}{6}) * (0.1)\\\\= 0.266miles/min[/tex]

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Explanation:

let v1 = 4.3 m/s

v2 = 12.9 m/s

t = 2 seconds

v2 = v1 + at

12.9 = 4.3 + a×2

2a = 12.9 - 4.3 = 8.6

a = 8.6/2

a = 4.3 m/s^2

[tex]\mu = 0.306[/tex]

Explanation:

Assume that the direction down the incline is the +x-direction. We can apply Newton's 2nd law along the x-axis as

[tex]x:\:\:\:\:\:mg\sin17° - f_s = ma[/tex]

[tex]\Rightarrow mg\sin17° - \mu N = 0[/tex]

where m is the mass of the bear and g is the acceleration due to gravity and acceleration a is zero since the bear is moving with a constant velocity. Along the y-axis, we can write Newton's 2nd law as

[tex]y:\:\:\:\:\:N - mg\cos17° = 0 \Rightarrow N = mg\cos17°[/tex]

Combining these two equations together, we get

[tex]mg\sin17° = \mu(mg\cos17°)[/tex]

Solving for [tex]\mu, [/tex]

[tex]\mu = \dfrac{\sin17°}{\cos17°} = \tan17° = 0.306[/tex]

Answer:

Friction acts in the opposite direction of the velocity. As static friction acts in the opposite direction to the acceleration. (opposite way)

Explanation:

Answer:

Explanation:

Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.

Each half will have a mass of 770/2 = 385 kg

Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s

Now add back the reference frame velocity to get velocity relative to earth.

Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s

Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s

In the moving reference frame, each half will have kinetic energy which could only come from the explosion

KE = ½(385)(1.3 x 10³)² = 325,325,000 J

2(325,325,000) = 650,650,000 J released in the explosion.

Rounding to the three significant figures of the problem numerals

E = 6.50 x 10⁸ J or 650 MJ released

Answer:

RNA polymerase reads a template strand of DNA 5' to 3'

Explanation:

RNA polymerase is the enzyme accountable for the transcription of the DNA. It shows one coast of the DNA and transcribed within the RNA. It combines the nucleotide to the 3' conclusion of the expanding series of the RNA. It commences the method by connecting to the promoter area of the gene. The enzyme increases nucleotide, not ribonucleotide.

Therefore, A. RNA polymerase reads a template strand of DNA 5' to 3' is false.

Answer:

RNA polymerase reads a template strand of DNA 5' to 3'.

Explanation:

RNA synthesis is less processive during elongation than during initiation. Synthesis begins with the polymerase binding two rNTP molecules. The polymerase frequently releases the nascent transcript before it reaches 8-10 nucleotides in length.

Answer:

Explanation:

Power is the rate of doing work

P = 72 / 1.2 = 60 Watts

Answer:

A vacuole is in both, plant and animal cells. It's main purpose is to isolate waste products, or in other words making sure that harmful materials won't damage the cell.

Answer:

In animal cells, they help sequester waste. In plants, they help maintain water balance.

Answer:

Its velocity would be

15 km per hour

or

0.00416667 per second

The wavelength of the light is 550 nm

For a double slit interference pattern with slit spacing, d we have

dsinθ = mλ where d = slit spacing = 0.22 mm = 0.22 × 10⁻³ m, m = number of maximum fringe = 2(from the picture) and λ = wavelength of light.

Thus sinθ = mλ/d

Also, tanθ = L/D where L = distance between central maximum and fringe = 2.0 cm/2 = 1.0 cm = 1 × 10⁻² m and D = distance between slit and screen = 2.0 m

Since θ is small, sinθ ≅ tanθ

So, mλ/d = L/D

Making λ subject of the formula, we have

λ = dL/mD

Substituting the values of the variables into the equation, we have

λ = dL/mD

λ = 0.22 × 10⁻³ m × 1 × 10⁻² m/(2 × 2.0 m)

λ = 0.22 × 10⁻⁵ m²/4.0 m

λ = 0.055 × 10⁻⁵ m

λ = 0.55 × 10⁻⁶ m

λ = 550 × 10⁻⁹ m

λ = 550 nm

So, the wavelength of the light is 550 nm

Learn more about double slit interference here:

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Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm

The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√[tex]\frac{l}{g}[/tex]

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √[tex]\frac{0.302}{10}[/tex]

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

Learn more here:

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Answer:

No, it is closer to 1.30

Explanation:

Answer:

speed

Explanation:

its the speed

because the formula for deriving speed is distance/time

the unit for distance is metre

the unit for time is seconds

so speed is metre/seconds

so speed us m/s.

Answer:

it would remain the same speed

Explanation: the rock isnt going down a hill or anything so therefore if gravity isnt pulling it down a slope then it would remain the same pace

Answer:

Hi there

The water acquires a vertical velocity component during the fall equal to

Vy = sqrt(2gH) = 25.5 m/s. Its velocity at the bottom is 25.8 m/s, so the horizontal component at the bottom must be sqrt[(25.8)^2 - (25.5)^2] = 3.9 m/s

That must be the horizontal component at the top also, since it does not change during the fall. It is the velocity magnitude there.

Brainliest pls

Answer:

Since impedance = omega * L we can use the equation for resistance:

20 + 12 + 10 in parallel with 7 we have

J1 = 42 * 7 / 49 = 6 H for the combination on the right

4 H + 6 H + 8 H = 18 H for the entire combination

Answer: Varies

Explanation: It became more relied upon, technology is responsible for this.

Answer: In ridge push, the mantle wells upward because of the convection and elevates the edges of spreading oceanic plates. Because these plates are higher at the spreading center, they are forced downhill due to gravity and eventually flatten out to the ocean floor.

the answer I need points for my math test