6 1/8 qt = ___ c please help

Answer:

Sorry if this is wrong, but seeing the question I think the best answer following the question would be answer B, because for A it shows that 1 hour is 35 miles when it says 70 miles in 1 hour, not C because as the time rises so does the distance, and I checked D and it's wrong.

Step-by-step explanation:

Answer:

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Answer:

m<F = 95°

Step-by-step explanation:

We'll begin by calculating the value of x. This can be obtained as follow:

m<C = 50

m<A = (10x – 5)

m<B = m<G = (2x + 15)

m<C + m<A + m<B = 180 (Sum of angles in a triangle)

50 + (10x – 5) + (2x + 15) = 180

50 + 10x – 5 + 2x + 15 = 180

50 – 5 + 15 + 10x + 2x = 180

60 + 12x = 180

Collect like terms

12x = 180 – 60

12x = 120

Divide both side by 12

x = 120 / 12

x = 10

Finally, we shall determine the value of m<F. This can be obtained as follow:

m<F = m<A

But

m<A = 10x – 5

x = 10

Therefore,

m<F = 10x – 5

m<F = 10(10) – 5

m<F = 100 – 5

m<F = 95°

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Answer:

  x = 142

Step-by-step explanation:

You want to find x such that ...

  [tex]\sqrt{x+2} -15=-3\qquad\text{given}\\\\\sqrt{x+2} =12\qquad\text{add 15}\\\\x+2=144\qquad\text{square both sides}\\\\\boxed{x=142}\qquad\text{subtract 2 to get x by itself}[/tex]

Answer:

a

Step-by-step explanation:

Answer:

C. [tex]\frac{}{AB}[/tex]

Step-by-step explanation:

You can solve this in two ways, firstly by eliminating all the wrong answers, and secondly by just knowing that the horizontal line in [tex]_[/tex][tex]\frac{}{AB}[/tex] means that we are talking about a line.

This is how we solve this question by using the eliminating process.

(A. ∠C) is not the right answer because the ∠ sign lets us know that this answer represents an angle, not a line

(B. B) is not the right answer because it represent a point, not a line (in math we use a singular capital letter to represent points)

(D. ΔABC) is not the right answer because the Δ sign lets us know that the answer represents a triangle, not a line.

Therefore, the only option left is C. [tex]\frac{}{AB}[/tex]

Answer:

A) 0.7696

B) 0.0474

C) Yes it's unusual

D) 0.05746

E) No, it is not unusual

F) No, it is not unusual

Step-by-step explanation:

This is a binomial probability distribution question.

We are told that 92.4% of those admitted graduated.

Thus; p = 92.4% = 0.924

From binomial probability distribution, q = 1 - p

Thus;

q = 1 - 0.924

q = 0.076

Formula for binomial probability distribution is;

P(x) = nCx × p^(x) × q^(n - x)

A) At least 11 graduated out of 12.

P(x ≥ 11) = P(11) + P(12)

P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)

P(11) = 0.3823

P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)

P(12) = 0.3873

P(x ≥ 11) = 0.3823 + 0.3873

P(x ≥ 11) = 0.7696

B) that exactly 9 of them graduated out of 12. This is;

P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)

P(9) = 0.0474

C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.

Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.

We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate

D) that at most 9 of them out of 12 graduated.

P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)

This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.

Thus, we have;

P(0) = 0

P(1) = 0

P(2) = 0

P(3) = 0.00000001468

P(4) = 0.00000040161

P(5) = 0.00000781232

P(6) = 0.00011081163

P(7) = 0.00115477385

P(8) = 0.00877476184

Thus;

P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256

P(x ≤ 9) = 0.05746

E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.

F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual

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Answer:

  B

Step-by-step explanation:

If the probability of event "A" is 'p', then the probability of the event "not A" is

  P(not A) = 1 - P(A) = 1 - p

For p=0.5, this is ...

  P(not A) = 1 -0.5 = 0.5 . . . . . matches choice B

Answer:

○B. 0.5 is the proof the outcome (not A).

Answer:

60m^2 is the answer im pretty sure

Step-by-step explanation:

yeah man thats it

9514 1404 393

Answer:

  7 1/75 football fields

Step-by-step explanation:

Multiply it out. The units of feet and yards cancel, leaving football fields.

  = (2104·1·1)/(3·100) football fields ≈ 7.0133... football fields

  = 7 1/75 football fields

Answer:

T = k * (A/W)

Step-by-step explanation:

Answer:alternate exterior angles

Step-by-step explanation:

Since they’re on the outside of the parallel lines that makes them exterior

Answer:

-5 is the answer

Step-by-step explanation:

Answer:

-5 corresponds to the coldest temperature here.

Step-by-step explanation:

-5 is to the left of -1 on a number line and is therefore smaller than -1.

Answer:

[tex]b = 74^o[/tex] --- acute base

Step-by-step explanation:

Given

See attachment for the figure

Required

The acute base angle of the trapezoid

From the question, the isosceles triangle and the trapezoid share the same base.

Represent the base angle with b.

So:

[tex]b + b + 32^o = 180^o[/tex] --- angles in a triangle

[tex]2b = 180^o-32^o[/tex]

[tex]2b = 148^o[/tex]

Divide by 2

[tex]b = 74^o[/tex]

Step-by-step explanation:

A. 2(x+4)=2x+8

=G

B. 3(2x-1)=6x-3

=I

C. 4(x+2)=4x+8

=J

D. 2(x+3)=2x+6

=K

E. 3(4x+1)=12x+3

=H

A - G

B - I

C - J

D - K

E - H

HOPE IT HELP

Answer:

[tex]P(x < 4) = \frac{9}{50}[/tex]

Step-by-step explanation:

Given

[tex]n(S) = 50[/tex]

See attachment for distribution

Required

[tex]P(x < 4)[/tex]

This is calculated as:

[tex]P(x < 4) = \frac{n(1) + n(2) + n(3)}{n(S)}[/tex]

Using the data on the frequency distribution table, we have:

[tex]P(x < 4) = \frac{4 + 2 + 3}{50}[/tex]

[tex]P(x < 4) = \frac{9}{50}[/tex]

Completing the square gives

[tex]x^2-2x-2=(x-1)^2-3[/tex]

and comparing to [tex]y=x^2[/tex], the graph of [tex]y=x^2-2x-2[/tex] would be a horizontal shift to the right by 1 unit, and a vertical shift down by 3 units.

Hope this help!!!

Have a nice day!!!

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]Reason \to Frequency[/tex]

[tex]Congestive\ heart\ failure \to 990[/tex]

[tex]Coronary\ atherosclerosis\to 1400[/tex]

[tex]Heart\ attack \to 744[/tex]

[tex]Infant\ birth\to 3800[/tex]

Solving (a): Frequency bar graph

To do this, we simply plot the reasons (on the x-axis) against the frequency (on the y-axis).

See attachment

Solving (b): Relative frequency distribution

The relative frequency is calculated as:

[tex]RF = \frac{F}{Total}[/tex]

Where

[tex]Total = 990+1400+744+3800[/tex]

[tex]Total = 6934[/tex]

So, we have:

[tex]Congestive\ heart\ failure \to \frac{990}{6934} = 0.1427[/tex]

[tex]Coronary\ atherosclerosis\to \frac{1400}{6934} = 0.2019[/tex]

[tex]Heart\ attack \to \frac{744}{6934} = 0.1073[/tex]

[tex]Infant\ birth\to \frac{3800}{6934} = 0.5481[/tex]

So, the relative distribution is:

[tex]Reason \to Frequency \to Relative\ Frequency[/tex]

[tex]Congestive\ heart\ failure \to 990 \to 0.1427[/tex]

[tex]Coronary\ atherosclerosis\to 1400 \to 0.2019[/tex]

[tex]Heart\ attack \to 744 \to 0.1073[/tex]

[tex]Infant\ birth\to 3800 \to 0.5481[/tex]

Solving (c): Relative frequency bar graph

To do this, we simply plot the reasons (on the x-axis) against the relative frequency (on the y-axis).

See attachment

Solving (d): Relative frequency Pareto chart

First, calculate the cumulative relative frequency

This is done by adding up the previous relative frequency,

So, we have:

[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]

[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]

[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.2019+0.1427=0.3446[/tex]

[tex]Heart\ attack \to 0.1073\to 0.3446+0.1073 = 0.4519[/tex]

[tex]Infant\ birth \to 0.5481 \to 0.5481+4519 =1[/tex]

So, we have:

[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]

[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]

[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.3446[/tex]

[tex]Heart\ attack \to 0.1073\to 0.4519[/tex]

[tex]Infant\ birth \to 0.5481 \to 1[/tex]

Next, we simply plot the reasons (on the x-axis) against the cumulative relative frequency (on the right) and the left of the Pareto chart.

See attachment

Answer:

well,

it's more than (20ft)²

bc 20*20 =400

21² = 21 * 21 = 441

getting closer...

22² = 22 * 22 = 484

[tex] \sqrt{484} = {22}^{2} [/tex]

yet, we arrived, short trip tough, pls leave the bus in an orderly manner

Answer:

x=-10

Step-by-step explanation:

2(x+3)=x-4

2*x+2*3=x-4

2x+6=x-4

2x-x=-4-6

x=-10

Answer:

[tex]x = - 10[/tex]

Step-by-step explanation:

Let's solve:

[tex]2(x+3)=x−4[/tex]

Step 1: Simplify both sides of the equation.

[tex]2(x+3)=x−4 \\ (2)(x)+(2)(3)=x+−4(Distribute) \\ 2x+6=x+−4 \\ 2x+6=x−4[/tex]

Step 2: Subtract x from both sides.

[tex]2x+6−x=x−4−x \\ x+6=−4[/tex]

Step 3: Subtract 6 from both sides.

[tex]x+6−6=−4−6 \\ x=−10[/tex]

Answer:

x = 1/4

y = -1/2

z = 9/4

Step-by-step explanation:

Here we have a system of 3 equations with 3 variables:

4*x + 2*y + 1 = 1

2*x - y = 1

x + 3*y + z = 1

The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:

2*x - y = 1

2*x - 1 = y

Now that we have an expression equivalent to "y", we can replace this in the other two equations:

4*x + 2*(2*x - 1) + 1 = 1

x + 3*(2*x - 1) + z = 1

Now let's simplify these two equations:

8*x - 1 = 1

7*x - 3 + z = 1

Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:

8*x - 1 = 1

8*x = 1 + 1 = 2

x = 2/8 = 1/4

Now that we know the value of x, we can replace this in the other equation to find the value of z.

7*(1/4) -3 + z = 1

7/4 - 3 + z = 1

z = 1 + 3 - 7/4

z = 4 - 7/4

z = 16/4 - 7/4 = 9/4

z = 9/4

Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:

y = 2*(1/4) - 1

y = 2/4 - 1

y = 1/2 - 1

y = -1/2

Then the solution is:

x = 1/4

y = -1/2

z = 9/4

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Answer:

  160 cm³

Step-by-step explanation:

The ratio of the linear dimensions is the square root of the ratio of areas:

  scale factor B/A= √(64/144) = 8/12 = 2/3

The ratio of volumes is the cube of the scale factor:

  (volume B)/(volume A) = (2/3)³ = 8/27

Then the volume of pyramid B is ...

  volume B = (volume A) × (volume B)/(volume A)

  = (540 cm³) × (8/27) = 160 cm³ . . . . volume of pyramid B

_____

Equivalently, the ratio of volumes is the 3/2 power of the ratio of areas.

 Vb = Va(64/144)^(3/2) = (540 cm³)(4/9)^(3/2) = (540)(8/27) cm³ = 160 cm³

Answer:

w ≈ 21.053 inches

l ≈ 28.353 inches

Step-by-step explanation:

Answer:

$5900

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Simple Interest Rate Formula: A = P(1 + rt)

Step-by-step explanation:

Step 1: Define

Identify variables

P = 5000

r = 3% = 0.03

t = 6

Step 2: Find Interest

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Answer:

  B.  (-5, -2)

Step-by-step explanation:

That point is ...

  A + 1/5(B - A)

  = (-7, -4) + 1/5(3 -(-7), 6 -(-4)) = (-7, -4) +1/5(10, 10)

  = (-7, -4) +(2, 2) = (-5, -2)

The point (-5, -2) is 1/5 of the way from A to B.

Answer:

0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.

Step-by-step explanation:

The buckets are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

8 covered buckets, so N = 8.

4 buckets are selected, so n = 4.

2 contain a ball, which means that k = 2.

Find the probability that a contestant wins the game if he/she gets to select 4 of the buckets.

This is P(X = 2). So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,8,4,2) = \frac{C_{2,2}*C_{6,2}}{C_{8,2}} = 0.2143[/tex]

0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.

Answer:

.101501615

.84982392

.901244701

Step-by-step explanation:

For this question use a binomial distribtuion

a.

12C3*.44³*(1-.44)⁹= .101501615

b.

to find at least 4 find the probability of less than 4 and take its compliment

12C0*(1-.44)¹²+12C1*.44*(1-.44)¹¹+12C2*.44²*(1-.44)¹⁰+12C3*.44³*(1-.44)⁹= .15017608

1-.15017608=.84982392

c.

To find less than eight's probability find the proability of at least 8 and take its compliment

12C8*.44⁸(1-.44)⁴+12C9*.44⁹(1-.44)³+12C10*.44¹⁰(1-.44)²+12C11*.44¹¹*(1-.44)+12C12*.44¹²= .098755299

1-.098755299= .901244701

Answer: the required sample size =1658944

Step-by-step explanation:

When the prior population proportion for the study is unknown , then the formula for sample size is [tex]Sample \ size = 0.25(\dfrac{z^*}{Margin\ of \ error})^2[/tex]

z-value for 99% confidence = 2.576

[tex]Sample \ size = 0.25(\dfrac{2.576}{0.001})^2\\\\=0.25(2576)^2\\\\=1658944[/tex]

Hence, the required sample size =1658944