7. A quadrilateral has vertices W(-3,5), X(8,6),
Y(3,-6), and Z(-4,1). The preimage is mapped
onto quadrilateral W'X'Y'Z' through a dilation by
scale factor and then a reflection over the line
y = x. What are the coordinates of W'?

Step-by-step explanation:

[tex]{x}^{2} - 15x + 26[/tex]

Factorize : What two numbers when added will give - 15 and when multiplied will give 26.

the number is - 13 and - 2

[tex] {x}^{2} - 2x - 13x + 26[/tex]

Factor out x

[tex]x(x - 2) - 13(x - 2) \\ (x - 13)(x - 2)[/tex]

Answer:

(x-13)(x-2)

Step-by-step explanation:

Factoring :

(x-13)(x-2)

[tex]x^2-13x-2x+26[/tex]  combine like terms

Because -13-2 gives you -15 and -13 mutiply -2 gives you positive 26

[tex]x^2-15x+26[/tex]

I hope this helps you

Answer:

ok for this problem lets subtract 25 for 100 to get 75 so know we know we have to multiple 20 by 0.75 to get 15 dollars for the reduced price

The standard deviation of the distribution of sample proportions is rounded to the nearest hundredth.60 Are taken but the single is 1.

The population proportion is .6. If samples of size 60 are taken, determine the standard deviation of the distribution of sample proportions rounded to the nearest hundredth.

The Sampling Distribution of the Sample Proportion

and standard deviation σˆP=√pq/n.

This is given by the formula Z=(X-m)/s where Z is the z-score, X is the value you are using, m is the population means and s is the standard deviation of the population. Consult a unit normal table to find the proportion of the area under the normal curve falling to the side of your value.13

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Given:

The measure of one angle in the figure is 50 degrees.

To find:

The missing angle in the figure.

Solution:

Let x be the measure of the missing angle. Then

[tex]x+50^\circ=180^\circ[/tex]                     [Supplementary angles]

[tex]x=180^\circ-50^\circ[/tex]

[tex]x=130^\circ[/tex]

Therefore, the measure of the missing angle in the figure is 130 degrees. Hence, the correct option is B.

Answer:

45°

Step-by-step explanation:

Reference angle is defined as The smallest angle that the standard position of a given angle will make with the x-axis.

Now, the given angle 225 lies in third quadrant. So, for us to find the reference angle, we will have to subtract 180 from it to get;

225 - 180 = 45°

Answer:

20/3=6.6666666666

Step-by-step explanation:

mark me brainliest

Answer:

a) 140000

b) 1000000

c) 9000000

Step-by-step explanation:

a) 687x164

700 * 200 =140000

b) 476x2354

500*2000=1000000

c) 8612x1497

9000*1000=9000000

Answer:

29120

Step-by-step explanation:

if 5.6 × 0.52 = 2912

then,

0.56 × 520 = 29120

Answer:

Step-by-step explanation:

B. Because adding 2 moves you to the left when inside the parentheses.

Given:

A cube has square sides with area [tex]x^2+24x+144[/tex].

To find:

The expression that represents the surface area of the cube.

Solution:

We have

The area of each side of cube = [tex]x^2+24x+144[/tex]

Number of sides of a cube = 6

We know that, the total surface area of the cube is the product of number of sides of the cube and the area of each side. So, the total surface area of the cube is

[tex]SA=6(x^2+24x+144)[/tex]

[tex]SA=6(x^2)+6(24x)+6(144)[/tex]

[tex]SA=6x^2+144x+864[/tex]

Hence, the expression that represents the surface area of the cube is [tex]6x^2+144x+864[/tex].

Answer:

a. 74°

Step-by-step explanation:

Angle BCD and angle ACB are supplementary because they form a straight line. This means they add up to 180. We can write an equation to model the situation:

m<BCD + m<ACB = 180

106 + m<ACB = 180

m<ACB = 74

Since we are given two sides of the triangle are congruent, the triangle is isosceles. The base angles of an isosceles triangle are congruent, so we can say:

m<ACB = m<A

This means m<A is equal to 74°

Answer:

[tex]p(x) = {4x}^{3} - {7x}^{2} - 5x + 43 \\ \\ p( - 3) = {4( - 3)}^{3} - {7( - 3)}^{2} - 5( - 3) + 43 \\ p( - 3) = - 113[/tex]

Answer:

- 113

Step-by-step explanation:

Substitute x = - 3 into p(x) and evaluate , that is

p(- 3) = 4(- 3)³ - 7(- 3)² - 5(- 3) + 43

         = 4(- 27) - 7(9) + 15 + 43

         = - 108 - 63 + 58

         = - 171 + 58

         = - 113

Answer:

2103 bags

Step-by-step explanation:

8412/4=2103

Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Given:

The functions are:

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

To find:

The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Solution:

We have,

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

Now,

[tex](a+b)(x)=a(x)+b(x)[/tex]

[tex](a+b)(x)=4x+9+3x-5[/tex]

[tex](a+b)(x)=7x+4[/tex]

Similarly,

[tex](a-b)(x)=a(x)-b(x)[/tex]

[tex](a-b)(x)=4x+9-(3x-5)[/tex]

[tex](a-b)(x)=4x+9-3x+5[/tex]

[tex](a-b)(x)=x+14[/tex]

And,

[tex](ab)(x)=a(x)b(x)[/tex]

[tex](ab)(x)=(4x+9)(3x-5)[/tex]

[tex](ab)(x)=12x^2-20x+27x-45[/tex]

[tex](ab)(x)=12x^2+7x-45[/tex]

And,

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]

Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].

Answer:

6

Step-by-step explanation:

So here are the numbers that are factors of 34 and multiples of 7

1,2,14,17,56,91

So count the numbers, 6. And that's ur answer, believe me

Answer:

10cm+5cm+3cm+3cm+7cm+2cm=30cm

[tex]\huge\bold{Given :}[/tex]

Product of two integers = - 112

One of the integer = -8

[tex]\huge\bold{To\:find :}[/tex]

The other integer.

[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]

[tex]\sf\blue{The \:other \:integer\:is\: 14.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

Let the other integer be [tex]x[/tex].

As per the question, we have

[tex]Product \: \: of \: \: two \: \: integers = - 112[/tex]

➼ [tex] \: - 8 \times x = - 112[/tex]

➼ [tex] \: x = \frac{ - 112}{ - 8} [/tex]

➼ [tex] \: x = 14[/tex]

[tex]\sf\purple{Therefore,\:the\:other\:integer\:x\:is\:14.}[/tex]

[tex]\huge\bold{To\:verify :}[/tex]

[tex] - 8 \times 14 = - 112[/tex]

➺ [tex] \: - 112 = - 112[/tex]

➺ L. H. S. = R. H. S

Hence verified.

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}[/tex]

Answer:

If the product of two integers is -112 and one of them is -8, that means the value of the second integer would be 14.

Step-by-step explanation:

The product of two integers equals -112 means that there are two numbers that, when multiplied, were equivalent to -112. Since you know one of the integers is -8, you can infer that the second integer is both a positive number AND the remainder of [tex]\frac{-112}{-8}[/tex] or 14.

Answer:

The family of lines that are parallel to [tex]2\cdot x + y = 6[/tex] is of the form [tex]2\cdot x + y = k, \,k\neq 6[/tex]. A possible solution is [tex]2\cdot x + y = -2[/tex].

Step-by-step explanation:

Let be [tex]2\cdot x + y = 6[/tex] the equation of a line, another line is parallel to it if and only if it is of the form:

[tex]2\cdot x + y = k, \,k\neq 6[/tex]  (1)

Then, a possible solution is [tex]2\cdot x + y = -2[/tex].

Answer:

8 books were in each box

Step-by-step explanation:

According to the Question,

Assume X is the Number of Books In Each Box.

Algebraic Expression,

4X + 3 = 35

4X = 35 - 3

4X = 32  ⇔  X=8 books in Each Box.

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to  the product of two segments of second chord.

In the given circle,

[tex]AE\times CE=BE\times DE[/tex]

[tex](3x-11)\times (5x-4)=(x+2)\times (-x+17)[/tex]

[tex]15x^2-12x-55x+44=-x^2+17x-2x+34[/tex]

[tex]15x^2-67x+44+x^2-15x-34=0[/tex]

[tex]16x^2-82x+10=0[/tex]

Divide both sides by 2.

[tex]8x^2-41x+5=0[/tex]

Splitting the middle term, we get

[tex]8x^2-40x-x+5=0[/tex]

[tex]8x(x-5)-1(x-5)=0[/tex]

[tex](8x-1)(x-5)=0[/tex]

Using zero product property, we get

[tex](8x-1)=0[/tex] or [tex](x-5)=0[/tex]

[tex]x=\dfrac{1}{8}[/tex] or [tex]x=5[/tex]

For [tex]x=\dfrac{1}{8}[/tex], the side AE is negative. So, [tex]x=\dfrac{1}{8}[/tex] is not possible.

Therefore, the required solution is [tex]x=5[/tex].

Answer:

C

Step-by-step explanation:

if you divide both sides by ax+b you get 1=1 which is not a solution for x.

Answer:

Step-by-step explanation:

a) -14 , -9 , -4 , 1 ................

Common difference = d = 2nd term - 1st term

           = -9-[-14]

           = -9 + 14

          d = 5

The next term can be got by adding 5 to the previous term

5th term = 1 + 5 = 6

6th term = 6 + 5 = 11

7th term = 11 + 5 = 16

Next 3 terms are : 6 , 11 , 16

[tex]b) \frac{5}{6},\frac{2}{3},\frac{1}{2},\frac{1}{3},.....\\\\d = \frac{2}{3}-\frac{5}{6}\\\\=\frac{2*2}{3*2}-\frac{5}{6}\\\\=\frac{4}{6}-\frac{5}{6}\\\\=\frac{-1}{6}\\\\a_{5} = \frac{1}{3}+\frac{-1}{6}=\frac{1*2}{3*2}+\frac{-1}{6}=\frac{2}{6}+\frac{-1}{6}=\frac{1}{6}\\\\a_{6}=\frac{1}{6}+\frac{-1}{6}=0\\\\a_{7}=0+\frac{-1}{6}=\frac{-1}{6}\\\\\\Next 3 terms : \frac{1}{6},0,\frac{-1}{6}[/tex]

Answer:

24 servngs

Step-by-step explanation:

3 cups makes 9 servings.

The rate of servings to cups is 9 servings to 3 cups which is a unit rate of 3 servings per cup.

1 quart = 4 cups

2 quarts = 2 * 4 quarts = 8 cups

3 serviongs/cup * 8 cups = 24 servings

Answer: 24 servings

Answer:

Hdujshshshddhdh

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

8x^2y^3 24

degree of monomial is power of x + power of x

2 + 3= 5

Answer:

5

Step-by-step explanation:

What is that 24 doing there?

If the monomial is

[tex] 8x^2y^3 [/tex]

then the degree is 5.

The degree of a monomial is the sum of the exponents of all the variables of the monomial.

Answer:

the answer would be 1/22 = x/3

Step-by-step explanation:

because 1 gallon of gasoline got him to travel 22 miles so your trying to solve for x for 3 gallons

Answer:

The two column proof is presented as follows;

Step [tex]{}[/tex]     Statement               Reason

1 [tex]{}[/tex]            [tex]\overline {AC}[/tex] ≅ [tex]\overline {BD}[/tex]                Given

[tex]{}[/tex]              ∠CAB ≅ ∠DBA  

2  [tex]{}[/tex]          [tex]\overline {AB}[/tex] ≅ [tex]\overline {AB}[/tex]                Reflexive property

3 [tex]{}[/tex]          ΔABC ≅ ΔBAD        SAS rule of congruency

Step-by-step explanation:

Given that we have;

Segment [tex]\overline {AC}[/tex] of ΔABC being congruent to (≅) segment  [tex]\overline {BD}[/tex] on ΔBAD and angle ∠CAB on ΔABC is congruent to angle ∠DBA on ΔBAD, and also that the two triangles share a common side, which is segment [tex]\overline {AB}[/tex], we have;

Segment [tex]\overline {AB}[/tex] is congruent to itself by reflexive property, therefore;

Two sides and an included angle on ΔABC are congruent to the corresponding two sides and an included angle on ΔBAD, which by Side-Angle-Side, SAS, rule of congruency, ΔABC is congruent to ΔBAD

Answer:

32.7 degrees

Step-by-step explanation:

This polygon has 11 sides.

The measure of all exterior angles adds up to 360.

Find the measure of a single exterior angle by dividing 360 by the number of sides.

360/11 ≈ 32.7

The measure of a single exterior angle of the given regular polygon is 32.5 degrees

We have given that the diagram of regular polygon shown below

and, we have to find the measure of a single exterior angle.

Therefore we have the given polygon has 11 sides.

The angle between a side of a rectilinear diagram and adjacent side extended outward.

The measure of all exterior angles adds up to 360.

We have to find the measure of a single exterior angle by dividing 360 by the number of sides

So we get,[tex]360/11 = 32.7[/tex]

Therefore, the measure of a single exterior angle of the given regular polygon is 32.5 degrees.

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