7. Draw an equilateral triangle of side 6.5 cm and after locating its circumcentre. Draw its circumcircle. send it with image​

Answer:

Table B

Step-by-step explanation:

correct on edge :)

Answer:

Option B

Step-by-step explanation:

From the question we are told that:

Demand point [tex]m=5[/tex]

Supply Point [tex]n=6[/tex]

Generally the equation for fixed-requirement constraints is mathematically given by

 [tex]X=m+n[/tex]

 [tex]X=5+6[/tex]

 [tex]X=11[/tex]

Therefore the correct option is

Option B

Answer:

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 520 hours.

This means that [tex]\sigma = 15, \mu = 520[/tex]

Find the probability of a bulb lasting for at most 528 hours.

This is the p-value of Z when X = 528. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{528 - 520}{15}[/tex]

[tex]Z = 0.533[/tex]

[tex]Z = 0.533[/tex] has a p-value of 0.7031

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Answer:

o (h,k)

Step-by-step explanation:

Answer:

y = 2x

Step-by-step explanation:

Given that , the line passes through the point (0,0) and has a slope of 2. So here we can use the point slope form of the line as ,

[tex]\implies y- y_1 = m( x - x_1) \\\\\implies y - 0 = 2( x - 0 ) \\\\\implies y = 2(x) \\\\\implies \underline{\underline{y = 2x }}[/tex]

Answer: About 6.71 units

Step-by-step explanation:

You use the distance formula: [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex].

Assign the the two points to the variables:

[tex](x_{1}, y_{1}) = (1, 3)\\(x_{2}, y_{2}) = (4, -3)[/tex]

Substitute them in the formula:

[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}[/tex]

And solve it:

[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}\\=\sqrt{(3)^{2}+(-6)^{2}}\\=\sqrt{9+36}\\=\sqrt{45}\\=6.71[/tex]

Answer:

I got the answer as 6.70 .here's how

Step-by-step explanation:

c= ( 1,3)

d=(4,-3)

Now , formula of distance

√(x2 - x1)^2 +(y2 - y1)^2

or, √(4-1)^2+(-3-3)^2

or, √(3)^2+(-6)^2

or,√9+36

or√45

√45 = 6.70 units approx

Answer:

a. -3

Step-by-step explanation:

-2 turns into 6 by multiplying it by -3.

the same from 6 to -18, from -18 to 54, ...

so, an/an+1 = -3

Answer:

The volume (density) of cement that will be needed to cover this hollow pipe is:

= 50,000 kg/m³

Step-by-step explanation:

Length of a cylindrical pipe = 5m

Width of the cylindrical pipe = 4m

Depth of the cylindrical pipe = 2.5m

The cubic meters of the cylindrical pipe = 5 * 4 * 2.5 = 50m³

1 cubic meter is equal to 1,000 kilogram

Therefore, the volume (density) of cement that will be needed to cover this hollow pipe is:

= 50 * 1,000

= 50,000 kg/m³

Answer:

.33x = 105.60

$371

Step-by-step explanation:

Answer:

63.44

Step-by-step explanation:

its 63.44697 but you round so its 63.44

Answer:

0.015

Step-by-step explanation:

1.5% = means 1.5 per 100 or simply 1.5/100.if you divide 1.5 by 100 you will get 0.015

Answer:

Step-by-step explanation:

Frt7v6c87buhinjomp,l.;

Answer:

56"

Step-by-step explanation:

Answer:

The call more is cheaper than talk-now.

Step-by-step explanation:

The companies charge a flat fee plus an added cost for each minute or part of a minute used for two companies are as follows :

Call-More: C = 0.40t + 25 Talk-Now: C = 0.15t + 40

We need to find which company is cheaper if a customer talks for 50 minutes.

For call more,

C = 0.40(50) + 25 = 45 units

For talk-now,

C = 0.15(50) + 40 = 47.5 units

So, it can be seen that call more is cheaper than talk-now.

If the slope of the line y = mx − 4 is  less than the slope of the line y = x − 4, this shows that m will be any values less than 1 i.e. m < 1. This gives a true statement

The slope of a line defines the steepness of such a line. It is the ratio of the rise to the run of a line.

The general formula for calculating an equation of a line is expressed as:

[tex]y = mx + b[/tex] where:

m is the slope of the line

Given the equation of the line, [tex]y=x-4[/tex] the slope of the line will be derived through comparison as shown:

[tex]mx=1x\\[/tex]

Divide through by x

[tex]\dfrac{mx}{x} = \dfrac{1x}{x}\\ m=1[/tex]

Hence the slope of the line y = x - 1 is 1.

According to the question, since we are told that the  slope of the line

y = mx − 4 is  less than the slope of the line y = x − 4, this shows that m will be any values less than 1 i.e. m < 1. This gives a true statement

Learn more about the slope of a line here: https://brainly.com/question/16949303

Answer:

Step-by-step explanation:

Answer:

Buy 2 lollipops for $2.

Step-by-step explanation:

If you divide the total price by total items purchased, you get the price per unit. 2/2=1 or around $1, while 40/30=4/3 or around $1.3. You are paying 1$ per lollipop for the 2 lollipop choice and paying 1.3 dollars per lollipop for the 30 lollipop choice.

Answer:

a) The bullet hits the ground after 64 seconds.

b) The bullet hits the ground 113,511.7 feet away.

c) The maximum height attained by the bullet is of 16,384 feet.

Step-by-step explanation:

Equations of motion:

The equations of motion for the bullet are:

[tex]x(t) = (v_0\cos{\alpha})t[/tex]

[tex]y(t) = (v_0\sin{\alpha})t - 16t^2[/tex]

In which [tex]v_0[/tex] is the initial speed and [tex]\alpha[/tex] is the angle.

Initial speed of 2048 ft/s at an angle of 30o to the horizontal.

This means that [tex]v_0 = 2048, \alpha = 30[/tex].

So

[tex]x(t) = (v_0\cos{\alpha})t = (2048\cos{30})t = 1773.62t[/tex]

[tex]y(t) = (v_0\sin{\alpha})t - 16t^2 = (2048\sin{30})t - 16t^2 = 1024t - 16t^2[/tex]

(a) After how many seconds will the bullet hit the ground?

It hits the ground when [tex]y(t) = 0[/tex]. So

[tex]1024t - 16t^2 = 0[/tex]

[tex]16t^2 - 1024t = 0[/tex]

[tex]16t(t - 64) = 0[/tex]

16t = 0 -> t = 0 or t - 64 = 0 -> t = 64

The bullet hits the ground after 64 seconds.

(b) How far from the gun will the bullet hit the ground?

This is the horizontal distance, that is, the x value, x(64).

[tex]x(64) = 1773.62(64) = 113511.7[/tex]

The bullet hits the ground 113,511.7 feet away.

(c) What is the maximum height attained by the bullet?

This is the value of y when it's derivative is 0.

We have that:

[tex]y^{\prime}(t) = 1024 - 32t[/tex]

[tex]1024 - 32t = 0[/tex]

[tex]32t = 1024[/tex]

[tex]t = \frac{1024}{32} = 32[/tex]

At this instant, the height is:

[tex]y(32) = 1024(32) - 16(32)^2 = 16384[/tex]

The maximum height attained by the bullet is of 16,384 feet.

Answer:

About 4 minutes and 3 seconds

Step-by-step explanation:

If I have 55 invitations to be created in four hours.

4 hours × 60 =240 minutes

240/55= 4.36 minutes

So if I spend 4 minutes and 3 seconds on an invitation, I should be able to fill the order.

Answer:

All of these

Step-by-step explanation:

Given

[tex]f(5) = 11[/tex]

[tex]f(x)[/tex] at [tex](5,11)[/tex]

Required

Interpret

[tex]f(5) = 11[/tex] mean that: the function is at [tex](5,11)[/tex]

In other words:

[tex]x = 5; y = 11[/tex]

It also means:

Substitute 5 for x and the result will be 11

Hence, all options are true

Answer:  Choice D.  (-7, 14)

Work Shown:

[tex](x,y) \to (x-3, y+7)\\\\(-4,7) \to (-4-3, 7+7)\\\\(-4,7) \to (-7, 14)\\\\[/tex]

The point has moved 3 units to the left and 7 units up. See the diagram below.

Answer:

0.52 = 52% probability that an email is detected as spam.

Step-by-step explanation:

Probability that an email is detected as spam:

99% of 50%(are spam).

5% of 100 - 50 = 50%(false positives, that is, e-mails that are not spam but are detected as spams).

What is the probability that an email is detected as spam?

[tex]p = 0.99*0.5 + 0.05*0.5 = 0.52[/tex]

0.52 = 52% probability that an email is detected as spam.

Answer:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]

Step-by-step explanation:

Given

[tex]f(x,y) = \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]

Required

[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex]

[tex]\lim_{(x,y) \to (0,0)} f(x,y)[/tex] becomes

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}[/tex]

Multiply by 1

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2}\cdot 1[/tex]

Express 1 as

[tex]\frac{y^2}{y^2} = 1[/tex]

So, the expression becomes:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} \cdot \frac{y^2}{y^2}[/tex]

Rewrite as:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} \cdot \frac{\sin^2y}{y^2}[/tex]

In limits:

[tex]\lim_{(x,y) \to (0,0)} \frac{\sin^2y}{y^2} \to 1[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2} *1[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 y^2}{x^2+2y^2}[/tex]

Convert to polar coordinates; such that:

[tex]x = r\cos\theta;\ \ y = r\sin\theta;[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{(r\cos\theta)^2 (r\sin\theta;)^2}{(r\cos\theta)^2+2(r\sin\theta;)^2}[/tex]

Expand

[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2\cos^2\theta+2r^2\sin^2\theta}[/tex]

Factor out [tex]r^2[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^4\cos^2\theta\sin^2\theta}{r^2(\cos^2\theta+2\sin^2\theta)}[/tex]

Cancel out [tex]r^2[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+2\sin^2\theta}[/tex]

Express [tex]2\sin^2 \theta[/tex] as [tex]\sin^2\theta+\sin^2\theta[/tex]

So:

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{\cos^2\theta+\sin^2\theta+\sin^2\theta}[/tex]

In trigonometry:

[tex]\cos^2\theta + \sin^2\theta = 1[/tex]

So, we have:

[tex]\lim_{(x,y) \to (0,0)} \frac{r^2\cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

Evaluate the limits by substituting 0 for r

[tex]\frac{0^2 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

[tex]\frac{0 \cdot \cos^2\theta\sin^2\theta}{1+\sin^2\theta}[/tex]

[tex]\frac{0}{1+\sin^2\theta}[/tex]

Since the denominator is non-zero; Then, the expression becomes 0 i.e.

[tex]\frac{0}{1+\sin^2\theta} = 0[/tex]

So,

[tex]\lim_{(x,y) \to (0,0)} \frac{x^2 \sin^2y}{x^2+2y^2} = 0[/tex]

Answer:

Area swept by the blade = 448[tex]in^{2}[/tex]

Step-by-step explanation:

The arc the wiper wipes is for 135 degrees angle.

So, find area of sector with radius 24 inches. And the find area of arc with r=14 inches.

Then subtract the area of sector with 14 inches  from area of sector with radius as 24 inches.

So, area of sector with r=24 in =[tex]\frac{135}{360} *\pi *24^{2}[/tex]

Simplify it,

                                                  =216[tex]\pi[/tex]

Now, let's find area of sector with radius 14 inches

Area of sector with r=14 in = [tex]\frac{135}{360} *\pi *14^{2}[/tex]

Simplify it

                                          =73.5[tex]\pi[/tex]

So, area swept by the blade = 216[tex]\pi[/tex] -73.5[tex]\pi[/tex]

Simplify it and use pi as 3.14.....

Area of swept =678.584 - 230.907

                               =447.6769

Round to nearest whole number

So, area swept by the blade = 448[tex]in^{2}[/tex]

Answer:

1100 ft³

Step-by-step explanation:

Use the formula for the volume of a cylinder. For height, use the average of the minimum and maximum depths.

V = πr²h

r = d/2 = 20 ft/2 = 10 ft

h = (1 ft + 6 ft)/2 = 3.5 ft

V = π(10 ft)²(3.5 ft)

V = 1100 ft³

Answer:

[tex]option \: d \: 4.2 \times {10}^{ - 3} [/tex]

Step-by-step explanation:

Multiplication,

[tex] = 8.4 \times {10}^{ 8 } \times 5 \times {10}^{ - 11} \\ = 8.4 \times 5 \times {10}^{8 + ( - 11)} \\ = 4.2 \times {10}^{8 - 11} \\ = 4.2 \times {10}^{ - 3} [/tex]

Answer:b

Step-by-step explanation:

Ive done this

Answer:

2nd Graph

Step-by-step explanation:

Bases off the graphs, you gave me, I assume your the equation is

[tex]f(x) = - 4(2) {}^{x} [/tex]

The parent equation of this function is

[tex]f(x) = b {}^{x} [/tex]

Let say x=0

Using the rules of exponets, the y value must be 1 so a critical point is

(0,1)

The function is multiplied by -4.

This means the function is stretched in the y direction by 4 and reflected over the x axis. So our new point will be

(0,-4).

The base 2 the function will get compressed by 1/2.

The best graph that represents this is the second graph