Which of the following ordered pairs is a solution to the equation 4x+6y=12? Select all that apply. Select all that apply: (−3,4) (1,3) (−6,6) (−13,10) (0,2)
help no links or any other stuff please
Answer:
z = 2.2
Step-by-step explanation:
[tex]-\frac{z}{0.5} + 1.4 = -3\\\\-\frac{z \times 10}{0.5 \times 10} + 1.4 = -3\\\\-2z + 1.4 = -3\\\\-2z = -3 - 1.4\\\\-2z = -4.4\\\\z = \frac{-4.4}{-2}\\\\z = 2.2[/tex]
Integers help me with this question
9514 1404 393
Answer:
5196 m
Step-by-step explanation:
The difference in elevation is found by subtracting one elevation from the other. Usually, we're interested in the positive difference, so we subtract the smaller number from the larger.
5040 -(-156) = 5040 +156 = 5196
The difference in elevation is 5196 meters.
WILL GIVE BRAINLIST! PUT THESE NUMBERS ON THE PLOT
Answer:
"fair" srry im only in 8th so im d.u.m
Step-by-step explanation:
Which of the following represents the factorization of the trinomial below?
x2 - 17x+ 30
A. (x-3)(x-10)
B. (x-2)(x+15)
C. (x-2)(x-15)
D. (x-3)(x +10)
Two circles are concentric if they have the same center.
On a coordinate plane, a circle has center (4, 6) and has a radius of 2 units.
Which equation represents a circle that is concentric with the circle shown but has a radius that is twice as large?
9514 1404 393
Answer:
(b) (x – 4)^2 + (y – 6)^2 = 16
Step-by-step explanation:
The equation for a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
You want the equation for a circle with center (4, 6) and radius 4. That equation is ...
(x -4)^2 +(y -6)^2 = 16
Answer:
B; (x – 4)2 + (y – 6)2 = 16
Step-by-step explanation:
correct on edge
What is the 8th term of a(n)=6•3^(n-1)
Answer:
13122
Step-by-step explanation:
a(n) = 6 * 3^(n -1)
a(8) = 6* 3^7
3^7 = 2187
a(8) =6 * 2187
a(8) = 13122
(4-i)-(3-i) in standard form
Answer:
ifeywifheb
Step-by-step explanation:
hkefewib
Write the following expression in standard place-value form.
Answer:
3408
Step-by-step explanation:
What is the value of log E 100
Answer:
4.605170185988091
Step-by-step explanation:
ln 100 = 4.605170185988091
e^4.605170185988091 = 100
Step-by-step explanation:
100=1 log 10(1)=0
I hope this is helpful for you
Find the Area of the Shaded Region.
Round to the nearest tenth if necessary.
14 cm
25 cm
11 cm
Answer:
[tex]Shaded = 212.5cm^2[/tex]
Step-by-step explanation:
Given
See attachment
Required
The shaded region
First, calculate the area of the complete rectangle
[tex]Area =Length * Width[/tex]
[tex]Area = 14cm * 25cm[/tex]
[tex]Area = 350cm^2[/tex]
Next, calculate the area of the triangle
[tex]Area = \frac{1}{2} * Base * Height[/tex]
[tex]Area = \frac{1}{2} *25cm * 11cm[/tex]
[tex]Area = 137.5cm^2[/tex]
Subtract the area to calculate the shaded region area
[tex]Shaded = 350cm^2 - 137.5cm^2[/tex]
[tex]Shaded = 212.5cm^2[/tex]
Five less than Greg's age is less than 23
Answer:
Greg is 28.
Step-by-step explanation:
Greg's age is y.
y - 5 = 23
y - 5 + 5 = 23 + 5
y = 28
The owner of a football team claims that the average attendance at games is over 74,900, and he is therefore justified in moving the team to a city with a larger stadium. An independent investigator will conduct a hypothesis test to determine whether his claim is accurate. This test is ________. Group of answer choices Two-sided Lower-tailed Upper-tailed
Answer:
Option c (Upper tailed) is the correct choice.
Step-by-step explanation:
Given that:
The average attendance is:
= 74,900
We will have to test:
⇒ [tex]H_0:\mu \leq \mu_0[/tex]
or,
[tex]H_0: \mu \leq 74,900[/tex]
Verses,
⇒ [tex]H_1: \mu> \mu_0[/tex]
or,
[tex]H_1: \mu >74,900[/tex]
The other given alternatives aren't connected to the given scenario. So the above is the correct one.
1 . ( m →(N v Q)) →((M→N) v (M→Q))
2.((T v U) → V) → (T → (U → V))
. ( m →(N v Q)) →((M→N) v (M→Q))
2.((T v U) → V) → (T → (U → V)) wut tyhe hell is this
Choose the pair of sets which is equivalent.
Answer and I will give you brainiliest
A researcher studying a memory enhancing technique had participants memorize nonsense words and definitions. Out of a list of 10 words, 57 participants were able to quickly learn 6.24 words on average with a standard deviation of 1.24. If it is known the mean number of words memorized in general is 5.65, is there sufficient evidence at that the memory enhancing technique helped participants learn more words?
a. What are the null and alternative hypotheses?
b. What is the value of the test statistic?
c. What is the critical value?
d. What is the decision?
e. What is the conclusion?
Answer:
A.
Null:
H0: u= 5.65
Alternative:
H1: u > 5.65
B.
The test statistic
Xbar = 6.24
u = 5.65
S = 1.24
N = 57
T = 6.24-5.65/(1.24/√57)
= 0.59/(1.24/7.5498)
= 0.59/0.1642
Test statistic = 3.593
C.
With alpha = 0.05
Df = n-1 = 57-1 = 56
T critical = 1.673
D.
If t test > 1.673 reject the null hypothesis
3.593>1.673, reject the null hypothesis
We conclude that there is enough evidence that the technique helped the participants to learn more.
what pairs of degree measures NOT belong to the
group?
Answer:
B. 56° and 38°
Step-by-step explanation:
The sum of each of the two angles sums up to 90° ;
A.) 13° and 77°
Sum of A ; (13 + 77)° = 90°
B.) 56° + 38°
Sum = 56° + 38° = 94°
C) 37° and 53°
Sum = 37° + 53° = 90°
D.) 42° and 48°
Sum = 42° + 48° = 90°
Hence, the pair of degree measure which does not belong is B. 56° and 38°
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
prove triangle ACD and BCE are congruent
Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
[tex]AC=BC[/tex] (Given)
[tex]AC\cong BC[/tex]
[tex]\angle C\cong m\angle C[/tex] (Common angle)
[tex]CD=CE[/tex] (Given)
[tex]CD\cong CE[/tex]
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
[tex]\Delta ACD\cong \Delta BCE[/tex] (SAS congruence postulate)
Hence proved.
Answer:
Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD
Given AB=AC∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)
Given BE=CDThen BE−DE=CD−DE
ORBC=CE......................................(2)
In ΔABD and ΔACE
∠ABD=∠ACE ( From 1)
BC=CE (from 2)
AB=AC ( GIven)
∴ΔABD≅ΔACE
So AD=AE [henceproved]
I need help solving for x
Answer:
x = 25
Step-by-step explanation:
Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is
[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )
24x = 600 ( divide both sides by 24 )
x = 25
Identify the relationship between the graphs of these two equations. y = 5/6x + 5 y = 5/6x - 1
parallel
perpendicular
neither
Answer:
parallel
Step-by-step explanation:
the slope of each line is 5/6 which means the lines are parallel
Write the equivalent of the fraction using a dominator of 35 4/14
Answer:
10/35
Step-by-step explanation:
4*2.5=10
14*2.5=35
4/14=10/35
PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!
Answer:
216
Step-by-step explanation:
outcome of one die is 1 out of 6 and if you roll 3 dices, the outcome is 216 possible outcomes because 6 times 6 times 6 is 6 cubed or 216
Which is an equation for the line that passes through (0, 2) and (-2, 0)?
Answer:
Step-by-step explanation:
(0,2). y=mx+b or 2=-2 × 0+b, or solving for b: b=2-(-2)(0).
Answer:
the required equqtion is x-y=2
What is the equation of the line that passes through (-3,-1) and has a slope of
2/5. Put your answer in slope intercept
Answer:
y = 2/5x + 1/5
Step-by-step explanation:
First, plug in the slope.
y = mx+b
y = 2/5x + b
Then, plug in the point given, in order to find b.
-1 = 2/5(-3) + b
-1 = -6/5 + b
1/5 = b
So the final equation is:
y = 2/5x + 1/5
Which choice shows (40+10)+30 correctly rewritten using the associative property and then correctly simplified?
40 + (10 + 30) = 40 + 40 = 80
40 + 30 + 10 = 70 + 10 = 80
40 + (10 +30) = 50 + 30 =80
(10 +40) + 30 = 50 + 30 =80
What is the decimal multiplier to increase by 4.3%?
Answer:
1.043
Step-by-step explanation:
Decimal multiplier to increase by x% is computed as:-
100% + x%
The decimal multiplier to increase by 4.3% would be
100% +4.3% = 104.3%
To remove% we divide the number by 100, so the number will become
Hence, The decimal multiplier to increase by 4.3% = 1.043
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Hope this Helps
A restaurant with 25 tables has 4 tables by the window. Parties are seated randomly at the tables as they come in.
What is the probability that the first 3 parties of the night are all seated at window seats?
Answer:
50/50
Step-by-step explanation:
It's random
What should my answer be?
Plz help me solve this algebra problem
Answer:
Exact Form:
x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3
Decimal Form:
x = 2.49509379 , − 3.16176045
Step-by-step explanation:
Simplify the decimals as needed
When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4 = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm^3 and the pressure is 80 kPa and is decreasing at a rate of 10 kPa/min. At what rate is the volume increasing at this instant?
Answer:
The volume increases at 35.71cm^3/min
Step-by-step explanation:
Given
[tex]PV^{1.4} = C[/tex]
[tex]V = 400cm^3[/tex]
[tex]P =80kPa[/tex]
[tex]\frac{dP}{dt} =-10kPa/min[/tex]
Required
Rate at which volume increases
[tex]PV^{1.4} = C[/tex] [tex]V = 400cm^3[/tex] [tex]P =80kPa[/tex]
Differentiate: [tex]PV^{1.4} = C[/tex]
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]
By differentiating C, we have:
[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]
Rewrite as:
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]
Solve for [tex]\frac{dV}{dt}[/tex]
[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]
[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]
Substitute values
[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]
[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]
[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]
[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]
