99 boys and 1 girl are in a lecture theatre. how many boys must leave the theatre so that the percentage of boys becomes 98%?​

Answer:

57.2

Step-by-step explanation:

This is a right triangle so we can use trig ratios.

We are asked to find a side when we know a angle adjacent to that side. And we are given a side opposite of that angle. We can use Tangent to find the side length.

[tex] \tan(40) = \frac{48}{x} [/tex]

Take the reciprocal of both sides.

[tex] \frac{1}{ \tan( 40) ) } = \frac{x}{ 48} [/tex]

Multiply both sides by 48.

[tex] x = \frac{1}{ \tan(40) } \times 48[/tex]

[tex]x = 57.2[/tex]

The length of the line segments WX and XY will be 2 and 9, resprectively.

A line segment in mathematics has two different points on it that define its boundaries. A line segment is sometimes referred to as a section of a path that joins two places.

The three points are W, X, and Y on the line.

From the diagram, the distance between the points W and X which is the line segment WX will be 2.

Similarly, from the diagram, the distance between the points W and Y which is the line segment WY will be 9.

More about the line segment link is given below.

https://brainly.com/question/25727583

#SPJ2

Answer:

[tex]x=10[/tex]

Step-by-step explanation:

A secant is a line segment that intersects a circle in two places. One property of a secant is the product of the lengths ratio. This ratio can be described as the following, let ([tex]inside[/tex]) refer to the part of the secant that is inside the circle, and ([tex]outside[/tex]) refer to the part that is outside of it. ([tex]total[/tex]) will refer to the entirety of the secant or ([tex]inside+outside[/tex]). The numbers (1) and (2) will be used as subscripts to indicate that there are two different secants.

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

Substitute,

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

[tex](outside_1)(inside_1+outisde_1)=(outside_2)(inside_2+outside_2)[/tex]

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

Simplify,

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

[tex]6(x+11)=7(x+8)[/tex]

[tex]6x+66=7x+56[/tex]

Inverse operations,

[tex]6x+66=7x+56[/tex]

[tex]66=x+56[/tex]

[tex]10=x[/tex]

Answer:

Let the two equal angles be x . Hence the third angle is 3x . But the sum of the interior angles of a triangle always adds up to 180∘ . ∴x=1805=36∘

Answer:

Angle 1 = 36°

Angle 2 = 36°

Angle 3 = 108°

Step-by-step explanation:

Sum of all angles in any triangle is 180°

angle 1 = angle 2 = X

angle 3 = 3×X

angle 1 + angle 2 + angle 3 = 180°

X + X + 3×X = 5×X = 180°

X = 180° / 5 = 36°

Angle 1 = 36°

Angle 2 = 36°

Angle 3 = 108°

Answer:

Parallel: AC and DB, BA and CD

Perpendicular: AC and CD, DB and CD, DB and BA, BA and AC

Neither: None

Step-by-step explanation:

Step 1: Find Slopes

Let's first find the slopes of each side of the rectangle, as that will helps us determine which sides are parallel, perpendicular, or neither.

Recall that the formula for finding the slope between two points is [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex] where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the two points. To avoid confusion, I will be taking the first point I list as [tex](x_1,y_1)[/tex] and the second point as [tex](x_2,y_2)[/tex].

Slope of [tex]BA[/tex]:

[tex]\frac{-7-(-3)}{-1-(-4)}\\=\frac{-7+3}{-1+4} \\= -\frac{4}{3}[/tex]

Slope of [tex]AC[/tex]:

[tex]\frac{-4-(-7)}{3-(-1)} \\=\frac{-4+7}{3+1} \\=\frac{3}{4}[/tex]

Slope of [tex]CD[/tex]:

[tex]\frac{0-(-4)}{0-3} \\=\frac{4}{-3} \\=-\frac{4}{3}[/tex]

Slope of [tex]DB[/tex]:

[tex]\frac{-3-0}{-4-0} \\=\frac{-3}{-4} \\=\frac{3}{4}[/tex]

Step 2: Determine which sides are parallel, perpendicular, or neither

Now that we found the slopes of the sides, we can determine which sides are parallel, perpendicular, or neither.

Recall that parallel lines have the same slope. [tex]\bf AC[/tex] and [tex]\bf DB[/tex], along with [tex]\bf BA[/tex]and [tex]\bf CD[/tex], have the same slope, so they are parallel. No other pair of sides has the same slope, so these are our only parallel pairs.

For two lines to be perpendicular, the product of their slopes must be [tex]-1[/tex]. [tex]\bf AC[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf BA[/tex], and [tex]\bf BA[/tex] and [tex]\bf AC[/tex] [tex]\bf[/tex]meet that criteria, so they are perpendicular. No other pair of sides meets the criteria, so these are our only perpendicular pairs. Hope this helps!

Answer:

200m

Step-by-step explanation:

Width=60m

Length=4000cm=40m

[PERIMETER OF RECTANGLE= 2(l+b)]

2(40+60)

2×100

200cm

Answer:

D. y = -5x + 6

Step-by-step explanation:

If we replace the values of x in the expressions we can find y. By replacing the values of x we see that the only option that has the correct values of y is the option D.

Answer:

D) 20°

Step-by-step explanation:

Using the triangle sum theorem, you know that every triangle's interior angles add up to 180°. Therefore the bottom triangle's missing angle can be found by giving it the variable x.

57° + 30° + x = 180°

Simplify: 87° + x =180°

x=93°

By the vertical angles theorem, the vertical angle directly across this angle is congruent to this one. Meaning that the top triangle's angle are 67°, 93°, and unknown, which we can assign y. We can use the same method from above here.

67° + 93° + y = 180°

Simplify: 160° + y = 180°

y=20°

Answer:

(C). 26°

Step-by-step explanation:

Answer:

I think this will help you

Answer:

1) I know that if the two integers have the same sign: Add their absolute values and give the answer the same sign as the two original integers. Also, I know that If the two integers have different signs: Subtract the lesser absolute value from the greater absolute value.

2) To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values. The result takes the sign of the integer with the larger absolute value. The sum of any integer and its opposite is equal to zero.

3) First, draw a number line. Then, find the location of the first integer on the number line. Next, if the second integer is positive, move that many units to the right from the location of the first integer. If the second integer is negative, move that many units to the left from the location of the first integer.

4) 205 dollars

5) The fish’s location relative to the surface of the ocean is -85

6) Honestly, I'm not so sure about this now, but I believe yes.

Step-by-step explanation:

there are a lot of resources, here on this app, that i used to help answer your question. If I helped, it would be nice if you rated this brainliest, give 5 stars, and the 50 points :)

1) I know that if the two integers have the same sign: Add their absolute values and give the answer the same sign as the two original integers. Also, I know that If the two integers have different signs: Subtract the lesser absolute value from the greater absolute value.

2) To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values. The result takes the sign of the integer with the larger absolute value. The sum of any integer and its opposite is equal to zero.

3) First, draw a number line. Then, find the location of the first integer on the number line. Next, if the second integer is positive, move that many units to the right from the location of the first integer. If the second integer is negative, move that many units to the left from the location of the first integer.

4) $205

5) The fish’s location relative to the surface of the ocean is -85 or -25 if the fish is 25 feet deeper from surface of ocean

6) Yes if both the temperatures are in Degree Fahrenheit

please click thanks and mark brainliest if you like :)

Hi there!

2|x - 1| + 5 < 13

Begin by subtracting 5 from both sides:

2|x - 1| < 8

Divide both sides by 2:

|x - 1| < 4

Find both the positive and negative solutions:

x - 1 < 4

x < 5

-(x - 1) < 4

-x + 1 < 4

-x < 3

x > -3

[tex]Hello[/tex] [tex]There![/tex]

Let's solve your inequality step-by-step.

[tex]2(|x-1|)+5<13[/tex]

Step 1:

You must add -5 both sides.

[tex]2(|x-1|)+5+-5<13+-5[/tex]

[tex]2(|x-1|)<8[/tex]

Step 2:

You must divide both sides by 2.

[tex]\frac{2(|x-1|)}{2}[/tex] [tex] \leq \frac{8}{2}[/tex]

[tex]|x-1|<4[/tex]

Step 3:

Solve the Absolute Value.

[tex]|x-1|<4[/tex]

We know that x−1<4 and x−1>−4.

[tex]x-1<4[/tex] Condition 1.

[tex]x-1+1<4+1[/tex] (Add 1 to both sides)

[tex]x<5[/tex]

[tex]x-1>-4[/tex] (Condition 2)

[tex]x-1+1>-4+1[/tex] (Add 1 to both sides)

[tex]x>-3[/tex]

[tex]ANSWER![/tex]

[tex]x<5[/tex] [tex]and[/tex] [tex]x>-3[/tex]

Hopefully, this helps you!!

[tex]AnimeVines[/tex]

Answer:

Is this suppose to be math question??

Answer:

hard work will define who wins

It is the 3rd answer

[tex]\large\textsf{Hey there!}[/tex]

[tex]\large\textsf{\# 1.}[/tex]

[tex]\large\textsf{4x} \times\large\textsf{3x}[/tex]

[tex]\large\text{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{4x}\times\large\textsf{3x = \bf 12x}\mathsf{\bf ^2}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \bf 12x}\bf ^2}}\huge\checkmark[/tex]

[tex]\large\text{\# 2.}[/tex]

[tex]\mathsf{\dfrac{2}{3}+\dfrac{1}{4}}[/tex]

[tex]\mathsf{= \dfrac{2\times4+1\times3}{3\times4}}[/tex]

[tex]\mathsf{2 \times 4 = \bf 8}[/tex]

[tex]\mathsf{1 \times 3 = \bf 3}[/tex]

[tex]\mathsf{3\times 4 = \bf 12}[/tex]

[tex]\mathsf{= \dfrac{8 + 3}{12}}[/tex]

[tex]\mathsf{8 + 3 = \bf 11}[/tex]

[tex]\mathsf{= \dfrac{11}{12}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{11}{12}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer: I can’t help with that because there should be a graph

Step-by-step explanation:

Answer:

cd a gimem ?

Step-by-step explanation:

Answer:

the answer is 5

Step-by-step explanation:

11 substract 6 is equal to 5

Answer:

When you multiply radical expressions you multiply the numbers under the radical symbols.3–√×7–√=21−−√

When you add radical expression you CANNOT add the numbers under the radical symbols.

3–√+7–√≠10−−√

Step-by-step explanation:

Answer:

The quadratic formula: (-b+-sqrtb^2-4ac)/2a

Plugging in the values of a=1, b=9, and c=10, the roots of the equation are: -7.7 and -1.3.

So, the first option is correct.

Let me know if this helps!

Answer:

B

Step-by-step explanation:

Hypotenuse=sqrt(Side^2+side^2)=sqrt(14^2+14^2)=14*sqrt(2)

Answer:  

B  

Step-by-step explanation:  

Hypotenuse=sqrt(Side^2+side^2)=sqrt(14^2+14^2)=14*sqrt(2)

Answer:

its letter c so 80

Step-by-step explanation:

I hope this help

Answer:

5/2

Step-by-step explanation:

tan&= 2/5(p/b)

here,

p=2,b=5

cot&=b/p

=5/2

Answer:

[tex]\cos \left(90 ^\circ - x\right) \approx 0.1688[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \tan x = \frac{3}{7}[/tex]

And we want to find the value of:

[tex]\displaystyle \cos \left(90^\circ - x\right)[/tex]

Recall that by definition, tan(θ) = sin(θ) / cos(θ). Hence:

[tex]\displaystyle \frac{\sin x }{\cos x} = \frac{3}{7}[/tex]

And by definition, sin(θ) = cos(90° - θ). Hence:

[tex]\displaystyle \frac{\cos \left(90^\circ - x\right)}{\cos x} = \frac{3}{7}[/tex]

Multiply:

[tex]\displaystyle \cos \left(90 ^\circ - x\right) = \frac{3}{7} \cos x[/tex]

Find cosine. Recall that tangent is the ratio of the opposite side to the adjacent side. Therefore, the opposite side is 3 and the adjacent side is 7.

Thus, by the Pythagorean Theorem, the hypotenuse will be:

[tex]\displaystyle h = \sqrt{3^2 + 7^2} = \sqrt{58}[/tex]

Cosine is the ratio of the adjacent side to the hypotenuse. Therefore:

[tex]\displaystyle \cos x = \frac{7}{\sqrt{58}}[/tex]

Thus:

[tex]\displaystyle \cos \left(90 ^\circ - x\right) = \frac{3}{7} \left(\frac{3}{\sqrt{58}}\right)[/tex]

Use a calculator. Hence:

[tex]\cos \left(90 ^\circ - x\right) \approx 0.1688[/tex]

Answer:

[tex]\angle m + \angle t + \angle n = 180[/tex]

Step-by-step explanation:

Required

Show that:

[tex]\angle m + \angle t + \angle n = 180^o[/tex]

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside [tex]\angle m[/tex] are alternate to [tex]\angle t[/tex] and [tex]\angle n[/tex]

i.e.

[tex]\angle 1 = \angle t[/tex]

[tex]\angle 2 = \angle n[/tex]

Using angle on a straight line theorem, we have:

[tex]\angle 1 + \angle m + \angle 2 = 180[/tex]

Substitute values for (1) and (2)

[tex]\angle t + \angle m + \angle n = 180[/tex]

Rewrite as:

[tex]\angle m + \angle t + \angle n = 180[/tex] -- proved

Answer:

DEF = 105

Step-by-step explanation:

The sum of the angles of a triangle is 180

28+47+DEF = 180

Combine like terms

DEF+75=180

Subtract 75 from each side

DEF +75-75 =180-75

DEF = 105

Answer: D

Step-by-step explanation: The answer is D because firstly we know that all right triangles add up to 180 degrees.

Using this knowledge we know 2 sides out of the 3. Therefore 47+28+x=180. Then we would add the first 2 numbers then minus 180 to get 105 as your last angle.

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 1)²

The base graph f(x) has been shifted right 1 unit

Answer: a

Step-by-step explanation: