Answer:
The momentum of the ball at the maximum height is zero (0 kg.m/s).
Explanation:
Given;
mass of the ball, m = 0.17 kg
initial velocity of the ball, u = 12 m/s
acceleration due to gravity, g = 9.81 m/s²
At maximum height the final velocity of the ball, v = 0
Momentum of the ball at the maximum height is given as;
P = mv
P = (0.17)(0)
P = 0 kg.m/s
Therefore, the momentum of the ball at the maximum height is zero (0).
When you push a box with 20 N of force, what force does the box apply back on you?
Please do all of i will give you brainlest and thanks to best answer plz do it right
Answer:
winter solstice i think
Explanation:
Answer:
a/ solar eclipse
Explanation:
because the moon is on the left side of earth
100 points if u help me and get it right this needs to be done in 3 min hurry to get ur 100 points
Calculate the kinetic energy of a 50 kg cart moving at a speed of 6.9 m/s.
Answer:
35
Explanation:
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Nore ordered an ice cream cone.
Answer:
okay
Explanation:
okay
Answer:
Cool
Explanation:
6th grade science I mark as brainliest.
Answer:
divide 10 by 50.
Explanation:
Because its time over speed 10/50
5 meter/ second
I think it's helpful
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3. What does doubling the number of coils do to the strength of the electromagnet?
4. What does doubling the voltage do to the strength of the electromagnet?
5. Using the graph, predict how many paper clips a 7.5 V battery would pick up for both the 25-
coil electromagnet and the 50-coil electromagnet.
6. Calculate the slope of the 25-coilline and the 50-coil line to determine the average number of
paper clips that a 1 V battery would pick up.
Answer:
3. When the number of turns, N is doubled, the strength of the electromagnet is also doubled
4. Doubling the voltage, doubles the strength of the electromagnet
5. The number of paper clips a 7.5 V battery would pick is approximately 28 paper clips
The number of paper clips a 7.5 V battery would pick is 59 paperclips
6. For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is approximately 7 paperclips
For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is 16 paperclips
Explanation:
3. The Magnetomotive Force, MMF = The Number of Turns on the Coil, N × The Current I Flowing in the Coil, I
∴ MMF = N × I
When the number of turns, N is doubled, the magnetomotive force, MMF is also doubled, and the strength of the electromagnet is doubled
4. Given that the voltage, V applied to the coil = The current, I flowing × The resistance, R of the coil, we have
V = I × R
Therefore, for a given constant resistance in the coil, doubling the voltage, doubles the current and therefore doubles the strength of the electromagnet
5. The average slope for the 25-coil electromagnet = (23 - 12)/(6 - 3) = 3.[tex]\bar 6[/tex]
The number of paper clips a 7.5 V battery would pick = 12 + (7.5 - 3) × 11/3 = 28.5 paperclips ≈ 28 paper clips
The average slope for the 50-coil electromagnet = (48 - 26)/(6 - 3) = 7.[tex]\bar 3[/tex]
The number of paper clips a 7.5 V battery would pick = 26 + (7.5 - 3) × 22/3 = 59 paperclips
6. The slope calculated from a start point of approximately 0.4 V, is given as follows;
The slope for the 25-coil electromagnet = (12 - 6)/(3 - 0.4) = 30/13
Therefore, for the 25-coil electromagnet, the average number of paper clips a 1 V battery would pick = 6 + (1 - 0.4) × 30/13) = 96/13 ≈ 7 paperclips
The slope for the 50-coil electromagnet = (26 - 13)/(3 - 0.4) = 5
Therefore, for the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick = 13 + (1 - 0.4) × 5 = 16 paperclips
3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well.
4. Doubling the voltage doubles the electromagnet's strength.
5. The number of paper clips selected by a 7.5 V battery is 59.
6. For a 50-coil electromagnet, a 1 V battery would pull up around 7 paperclips on average. The average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.
What is electromagnet?The magnetic field of an electromagnet is created by an electric current. Electromagnets are caused from conducting wire wriggled into a coil.
A magnetic field is created in the hole by a current passing through the wire.
The magnetic field production is increased by;
1) increasing the number of turns
2) increase the area of the loop
3) by moving the magnet faster
Answer for the following given options as follows;
3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well. Because the no of coils in the circuit is directly proportional to the strength of electromagnet.
4. From the ohm's law principal doubling the voltage twice the current and hence the electromagnet's strength for a given constant resistance in the coil increases.
5. For the 25-coil electromagnet, the average slope is ;
[tex]\rm m_{avg}= \frac{23-12}{6-3} \\\\ m_{avg}= 3[/tex]
The number of paper clips selected by a 7.5 V battery is;
[tex]\rm n = 12+ (7.5-+3)\times \frac{11}{3}\\\\n = 28.5[/tex]
For the 50-coil electromagnet, the average slope;
[tex]\rm (m_{avg})_{50}= \frac{48-26}{6-3} \\\\\ \rm (m_{avg})_{50}= 7[/tex]
The number of paper clips selected by a 7.5 V battery is;
[tex]\rm N = 26+(7.5-3) \times \frac{22}{3} \\\\ N= 59[/tex]
The following is the slope determined from a starting position of around 0.4 V:
For the 25-coil electromagnet, the slope is;
[tex]\rm m_{25}=\frac{12-6}{3-0.4} \\\\\ m_{25}=\frac{6}{2.6} \\\\ m_{25}=\frac{30}{13}[/tex]
As a result, the average number of paper clips a 1 V battery would choose for the 25-coil electromagnet is;
[tex]\rm N_{25}=6+ (1-0.4)\times \frac{30}{13} \\\\ N_{25}=\frac{96}{13} \\\\ N_{25}= 7 \ paperclip[/tex]
For the 50-coil electromagnet, the slope is;
(26 - 13)/(3 - 0.4) = 5.
As a result, the average number of paper clips picked by a 1 V battery is;
[tex]\rm N'_{50}= 13+ (1-0.14)\times 5 \\\\ N'_{50}=16[/tex]
Hence,the average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.
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How does a salt differ from an acid or base?
Answer:
An acid is defined as a substance whose water solution tastes sour, turns blue litmus red and neutralizes bases. A substance is called base if its aqueous solution tastes bitter, turns red litmus blue or neutralizes acids. Salt is a neutral substance whose aqueous solution does not affect litmus
18. Which would be the most reliable source of information to use for a history report? (2 points)
O An encyclopedia
O A magazine article
O A newspaper
A TV show
Answer:
encyclopedia most reliable I think
A 0.85-kg arrow flies through the air at a speed of 19 m/s. What is the momentum of the arrow?
16 kg m/s
22 kg m/s
160 kg m/s
360 kg m/s
Answer:
16 kg m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.85 × 19 = 16.15
We have the final answer as
16 kg m/sHope this helps you
why does diamond sparkles stars twinkles?
Answer:
Because they want attention
2.
Mass of car = 200 kg and g = 10 m/s? or 10 N/kg (approx. value)
position of car
GPE (J) = mgh KE (J) =
GPE + KE
0.5mv2
(height)
60.000
top (30 m) before
ride starts so v=0
Halfway (15 m)
30,000
34 way down (7.5
4,000
m)
bottom(0 m)
0
3.
Select the correct answer.
Which equation correctly relates kinetic energy, mass, and velocity?
Answer:
B
Explanation:
I just took the test and got 100%
4. What does doubling the voltage do to the strength of the electromagnet?
Answer:
it can make it stronger!
Answer:
The strength of the magnet in this case is directly proportional to the total voltage sum of all of the batteries
4. A Ferrari travels 350km in 2 hours. What was it's
s speed?
Which type of energies make up the mechanical energy of a roller coaster moving along a track?
Answer:
gravitational potential energy and kinetic energy
Explanation:
I need help with all of these questions
Answer:
This was my best estimation of the answers
plzzzz help me this is due today. only need help with these two questions and the element is oxygen.
How do protons, neutrons, and electrons differ in terms of their electrical charges and locations within the atom?
Describe the four fundamental forces. Which of these forces are involved in chemical bonding?
Answer: thanks for the point
Explanation:
Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a 20.0° with the horizontal. If the 7.0-kg sled is pulled across 10.0 meters, what is the work done by Karla?
Answer:
W = 1418.9 J = 1.418 KJ
Explanation:
In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:
W = F.d
W = Fd Cosθ
where,
W = Work Done = ?
F = Force = 151 N
d = distance covered = 10 m
θ = Angle with horizontal = 20°
Therefore,
W = (151 N)(10 m) Cos 20°
W = 1418.9 J = 1.418 KJ
A fish that lives near the surface of the ocean most likely has a swim bladder (or a body cavity) that is full of
Answer:
A fish that lives near the surface of the ocean most likely has a swim bladder (or body cavity) that is full of oxygen
Explanation:
The swim bladder is the organ present in the majority of bony fishes that provides buoyancy. The swim bladder is a bladder filled with oxygen and found in the in the body of the fish
The function of the swim bladder is to provide adequate ballast or hydrostatic balance to enable a fish to keep to a certain depth in a body of water thereby the fish does not float to the surface or sinks further
The swim bladder is also used as a sound communicating organ.
which apparatus Is used to determine the volume of a small block of unknown material
Options are;
A: measuring cylinder, metre rule
B: measuring cylinder, stopwatch
C: metre rule, balance
D: metre rule, stopwatch
Answer:
A: measuring cylinder, metre rule
Explanation:
Usually, when measuring volume of a small material, we make use of a piece of laboratory apparatus known as measuring cylinder which is also known as graduated cylinder.
Since it is a graduated cylinder, it means we will make use of metre rule.
Thus, the correct option is option A.
The apparatus which can be used to determine the volume of a small block of unknown material is: measuring cylinder; meter rule.
A measuring cylinder can be defined as a graduated cylinder that is typically designed and developed for the measurement of the volume of an irregularly shaped piece of object or a small block of unknown material.
Basically, a measuring cylinder is typically marked with horizontal lines on its side as units of measurement for volume.Similarly, a meter rule refers to an apparatus that is used for the measurement of the length of an object.
Hence, the meter rule would be used in measuring the length, width and height of the small block of unknown material, in order to determine its volume while using this formula:[tex]Volume =length\times width \times height[/tex]
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A block is released from rest at the top of a hill of height h. If there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed v.
Answer:
v / √2
Explanation:
A blocked from rest at the top of a hill of height h it there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed. The block is released from rest at the top of another hill with a rough surface and height h. if one-half of the initial mechanical energy of the block Earth System is lost due to friction as the block descends the hill, the block will reach the bottom of the hill with a speed of?
Solution:
For the first block block, its potential energy at the top of the hill when it is at rest is converted to kinetic energy after release with a velocity v.
The kinetic energy = (1/2)mv², where m is the mass of the block.
For the other block placed on the top of the rough hill, the mechanical energy (kinetic energy) is halved due to the roughness of the hill. If u is the speed of this block at the bottom of the hill then:
kinetic energy of block on the rough hill = (1//2)mu²
Hence:
(1//2)mu² = half of main system kinetic energy
(1//2)mu² = 1/2 * (1/2)mv²
mu² = (1/2)mv²
u² = (1/2)v²
u = √(v²/2)
u = v / √2
Hence the speed at the bottom of the rock of the block placed on the rough surface is v / √2
A red 120 kg bumper car moving at 4 m/s collides with a green 100 kg bumper car moving at 3 m/s. The red bumper car bounces off at 2 m/s. What is the green car's final velocity?
A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answer:
8
Explanation:
240 divided by 30 = 8
an object increases its velocity from 22 m/s to 36 m/s in 5s.what is the acceleration of the object
Answer:
2.8 m/s²
Explanation:
v=v0+at <=> 36 = 22 + a×5 <=> 5a = 36-22 <=> 5a = 14 <=> a = 14/5 <=>
<=> a = 2.8 m/s²
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
A eureka can of mass 100g and cross-section area 100cm2 is filled with water of density 1g/cm3. A piece of metal of mass 20g and density 8g/cm3 is lowered into the can. ( height of can 10cm ) calculate:
a) the total mass of can before the metal was lowered.
b) the volume of water that overflowed
c) the final mass of can and its content
Answer:
Explanation:
a)
Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.
100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]
Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....
[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg
Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....
1000g + 100g = 1100g or 1.1kg
b)
The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....
20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]
c)
Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.
[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.
100g + 997.5g + 20g = 1117.5g or 1.1175kg
A car tyre is pumped to a pressure of 20000 Nm-2 in the morning when the temperature is 23 oC. Later in the day, the temperature rises to 34 oC. Calculate the new pressure in the tyre. The volume is kept constant.
Answer:
20743.24 Nm¯²
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P1) = 20000 Nm¯²
Initial temperature (T1) = 23 °C
Final temperature (T2) = 34 °C
Final pressure (P2) =?
Volume = constant
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T1) = 23 °C
Initial temperature (T1) = 23 °C + 273 = 296 K
Final temperature (T2) = 34 °C
Final temperature (T2) = 34 °C + 273 = 307 K
Finally, we shall determine the final (i.e the new) pressure of the tyre.
Initial pressure (P1) = 20000 Nm¯²
Initial temperature (T1) = 296 K
Final temperature (T2) = 307 K
Final pressure (P2) =?
Volume = constant
Since the volume is constant, the final (i.e the new) pressure of the tyre can be obtained by using the following formula:
P1/T1 = P2/T2
20000 / 296 = P2 /307
Cross multiply
296 × P2 = 20000 × 307
Divide both side by 296
P2 = (20000 × 307) /296
P2 = 20743.24 Nm¯²
Therefore, the new pressure of the tyre is 20743.24 Nm¯²
Will mark brainiest!!!
1. A __ is caused by a sudden shift in the ocean crust which displaces the water. *
2. A tsunamis is possible, but unlikely at a __ plate boundary where two plates are moving sideways past each other. *
3. A Shallow __ is a good indicator of tsunamis, but sends data very slowly and cannot detect earthquakes. *
4. Tsunamis are common at __ plate boundaries, since large earthquakes release the built up pressure, resulting in a quick vertical movement of the plate. *
5. The Indonesian Earthquake of 2004 had a 9.1__, which was the third largest ever recorded in human history. *
All possible answers:
A. Earthquake
B. Tsunami
C. Magnitude
D. Sensor
E. Transform
F. Convergent
G. Divergent
Answer:
1. Tsunami
2.Divergent
3.Sensor
4.Convergent
5.Magnitude
Explanation:
A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)
Explanation:
It is given that,
A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)
i. Total distance = total path covered
= 14 km + 43 km
= 57 km
ii. Let east is positive and west is negative.
Displacement = final position-initial position
= 43-14
= 29 km
iii. If time taken in the entire trip = 3.2 hours
Average speed = distance/time
[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]
1 km/h = 0.2777 m/s
17.81 km/h = 4.94 m/s
iv. If time taken in the entire trip = 2.5 hours
Average velocity = displacement/time
[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]
1 km/h = 0.621 mph
11.6 km/h = 7.2 mph
Henc, this is the required solution.
*NEED THIS ANSWERED ASAP*
run this moving man simulation to get a visual understanding of all that you learned in this lesson about position velocity and acceleration during this activity you will explain these Concepts first click the introduction tab, and answer the question. set a small constant V on the velocity slider and check the velocity Vector box. click play, watch, and describe the motion in terms of what you see happening with the man's displacement, velocity and acceleration.
Answer:
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero
Explanation:
plato
When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
What is Velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.What is Acceleration?Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.
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A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the ground. How far, in meters, from the deck does the ball land on the ground?
Answer:
2.605m
Explanation:
Using the formula for calculating Range (distance travelled in horizontal direction)
Range R = U√2H/g
U is the speed = 4.8m/s
H is the maximum height = ?
g is the acc due to gravity = 9.8m/s²
R = 3.5m
Substitute into the formula and get H
3.5 = 4.8√2H/9.8
3.5/4.8 = √2H/9.8
0.7292 = √2H/9.8
square both sides
0.7292² = 2H/9.8
2H = 0.7292² * 9.8
2H = 5.21
H = 5.21/2
H = 2.605m
Hence the height of the ball from the ground is 2.605m
