A 1 250 kg car moving at a velocity of 30 km/hr along EDSA is accelerated by a force of 1 700 N. What will be its velocity after 10 seconds? (Neglect friction)

Answers

Answer 1
The velocity of the car after 10 s is 78.95 km/hr

Explanation:

Given:

m = 1,250 kg

[tex]v_i[/tex] = 30 km/hr

F = 1,700 N

t = 10 s

Required:

Final velocity

Equation:Force

F = ma

where: F - force

m - mass

a - acceleration

Acceleration

a = [tex]\frac{v_f \:-\:v_i}{t}[/tex]

where: a - acceleration

[tex]v_i[/tex] - initial velocity

[tex]v_f[/tex] - final velocity

t - time elapsed

Solution:Solve for acceleration using the formula for force

F = ma

Substitute the value of F and m

(1700 N) = (1250 kg)(a)

a = [tex]\frac{1700\:N}{1250\:N}[/tex]

a = 1.36 m/s²

Solve for final velocity using the formula for accelerationConvert 30 km/hr to m/s

= [tex]\frac{30\:km}{hr}\:×\:\frac{1000\:m}{1\:m}\:×\:\frac{1\:hr}{3600\:s}[/tex]

= [tex] 8.33 m/s [/tex]

Substitute the value of a, [tex]v_i[/tex] and t

a = [tex]\frac{v_f \:-\:v_i}{t}[/tex]

[tex]1.36\: m/s² \:= \:\frac{v_f \:-\:8.33\:m/s}{10\:s}[/tex]

[tex](10 \:s)1.36\: m/s² \:= \:v_f \:-\:8.33\:m/s[/tex]

[tex]v_f\: =\: (10 \:s)1.36 \:m/s²\: + \:8.33\:m/s[/tex]

[tex]v_f \: =\: 13.6 \:m/s \:+\: 8.33\:m/s[/tex]

[tex]v_f\: =\: 21.93\: m/s[/tex]

Convert to km/hr

= [tex]\frac{21.93\:m}{s}\:×\:\frac{1\:km}{1000\:m}\:×\:\frac{3600\:s}{1/:hr}[/tex]

= [tex]78.95\: km/hr[/tex]

Final answerThe velocity of the car after 10 s is 78.95 km/hr

Related Questions

Before turning in a test, it would be best to
O rush through the test and panic.
O make sure that some answers are incomplete.
O check how quickly the test was completed.
O check the grammar and double check the work.

Answers

Answer: D mate

Explanation:

Before turning in a test, it would be best to: D. check the grammar and double check the work.

What is a test?

A test can be defined as a group of questions that are designed and developed to elicit a specific information in the form of answer from an individual such as a student or an interviewee.

Thus, a test is primarily formulated by professionals, so as to assess the understanding of a person and as such, it is very necessary to spend a large amount of time to check the grammar and double check the work before turning in a test for submission.

Read more on test here: https://brainly.com/question/1910346

#SPJ2

Which of the following materials will prevent the flow of electricity?


Copper wire

Gold ring

Metal door

Rubber tires

Answers

Electricity is not good at conducting through rubber materials so rubber tires would be the correct answer

Answer:

rubber tires prevents the flow of electricity bc rubber is not a conductor

Please help meh!!! I appreciate it!

Answers

Answer:

★ The answers ARE B,A,D,D,A !

Explanation:

Hope you have a great day

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