A 1,000 kg truck initially had a velocity of 9 m/s. A force acts on it for a duration of time. After that force, the truck now has a velocity of 17 m/s. What is the impulse that the truck experienced?

Answers

Answer 1

Answer:

8000Ns

Explanation:

Given parameters:

Mass of the truck  = 1000kg

Initial velocity  = 9m/s

Final velocity  = 17m/s

Unknown:

Impulse  = ?

Solution:

The impulse experienced by the truck is the the change in momentum of the body.

  Impulse  = Ft

        Momentum  = m(v  - u)

        Ft  = m( v - u )

 F is the force

 t is the time

 m is the mass

  v is the final velocity

 u is the initial velocity

     Impulse  = 1000(17 - 9) = 8000Ns


Related Questions

diffrence between:- movable pulley and fixed pully​

Answers

Answer:

fixed pulley: A pulley system in which the pulley is attached to a fixed point and the rope is attached to the object. ... movable pulley: A pulley system in which the pulley is attached to the object; one end of the rope is attached to a fixed point and the other end of the rope is free.

Explanation:

What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. transmission​

Answers

slight reflect but most goes through because glass is transparent

Most of the light waves that strike a clear pane of glass reflects. Details about reflection can be found below.

What is reflection?

Refection in physics is the property of a propagated wave being thrown back from a surface such as a mirror.

Mirror is an example of an object that could be hit by an incumbent wave, however, most of the light waves that hit the mirror surface gets reflected back.

Therefore, most of the light waves that strike a clear pane of glass reflects.

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Why do astronomers use spectroscopes to analyze light from distant objects?

Answers

Spectroscopy — the use of light from a distant object to work out the object is made of — could be the single-most powerful tool astronomers use, says Professor Fred Watson from the Australian Astronomical Observatory. ... "It lets you see the chemicals being absorbed or emitted by the light source.

If the angle between the net force and the displacement of an
object is greater than 90 degrees, then which option holds
true?
aThe object stops
b Kinetic energy decreases
C Kinetic energy increases
d Kinetic energy remains the same

Answers

Answer: kinetic energy decreases

Explanation:

When the angle between the net force and the displacement of an

object is greater than 90 degree, the Kinetic energy decreases.

The work done by a net force in moving an object over a given distance is given as;

[tex]W = F \times d \ cos(\theta)[/tex]

where;

θ is the angle between the net force and the displacement

The value of cos(θ) decreases from 0 to 180, consequently, the value of work-done will decrease as well.

Based on work-energy theorem, the work done on the object is equal to kinetic energy of the object.

[tex]W = K.E[/tex]

Thus, we can conclude that when the angle increases, the Kinetic energy decreases.

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5) Choose the best revision of the following statement: "All the isotopes of a particular element decay radioactively by
emitting electrons."
A. All the isotopes of a particular element are stable and do not decay.
B. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting various subatomic
particles and radiation
C. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting protons or
electrons.
D. The statement is correct as it is currently written.

Answers

Answer:

B. some isotopes are stable and others are unstable. unstable isotopes decay by emitting various subatomic particles and radiation.

Explanation:

test gave me the answer so yeah :/ XD

HELP ASAP!
Everything on screenshot!

Answers

This is a divergent plate boundary because the two tectonic plates are colliding together.

A block of mass m is hung from the ceiling by the system of massless springs consisting of two layers. The upper layer consists of 3 strings in paralle, and the lower layer consists of 2 strings in parallel. The horizontal bar between the two layers has negligible mass. The force constants of all springs are k. Calculate the period of the vertical oscillations of the block.

Answers

Answer:

  T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex]           T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀

Explanation:

When the block is oscillating it forms a simple harmonic motion, which in the case of a spring and a mass has an angular velocity

        w = [tex]\sqrt{k/m}[/tex]

To apply this formula to our case, let's look for the equivalent constant of the springs.

Let's start with the springs in parallels.

* the three springs in the upper part, when stretched, lengthen the same distance, therefore the total force is

       F_total = F₁ + F₂ + F₃

the springs fulfill Hooke's law and indicate that the spring constant is the same for all three,

       F_total = - k x - k x - kx = -3k x

         

therefore the equivalent constant for the combination of the springs at the top is

      k₁ = 3 k

* the two springs at the bottom

following the same reasoning the force at the bottom is

        F_total2 = - 2 k x

the equivalent constant at the bottom is

         k₂ = 2 k

now let's work the two springs are equivalent that are in series

the top spring is stretched by an amount x₁ and the bottom spring is stretched x₂

            x₂ = x -x₁

            x₂ + x₁ = x

if we consider that the springs have no masses we can use Hooke's law

            [tex]-\frac{F_{1} }{k_{1} } - \frac{F_{2}}{k_{2} } = \frac{F}{k_{eq} }[/tex]

therefore the equivalent constant is the series combination is

             [tex]\frac{1}{k_{eq} } = \frac{1}{k_{1} } + \frac{1}{k_{2} }[/tex]

we substitute the values

             \frac{1}{k_{eq} }  = \frac{1}{3k } + \frac{1}{2k }  

             \frac{1}{k_{eq} }  = \frac{5}{6k} }  

              k_eq = [tex]\frac{6k}{5}[/tex]  

therefore the angular velocity is

             w = [tex]\sqrt{\frac{6k}{5m} }[/tex]  

           

angular velocity, frequency, and period are related

           w = 2π f = 2π / T

           T = 2π / w

            T = 2π [tex]\sqrt{\frac{5m}{6k} }[/tex]

           T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex]

           T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀

a string attached to a 60.0 Hz vibr.ator creates a standing wave with 5 loops. What frequency would make 7 loops? (Unit = Hz)

Answers

Answer:

F=84.0 Hz

Explanation:

Using the equation f= n (v/2L),  frequency equals number of loops times velocity over 2 times the length, in order to get 60.0 Hz of frequency from 5 loops, v/2L would have to equal 12. (12*5=60) v/2L is constant, so to find the frequency of 7 loops you would times 7 by 12 to get 84.0.

Hope this helped! :)

How can land that was formerly used as dumps, mines, or factory sites be.
rehabilitated?

Answers

Answer:

clear out the junk, and plant some stuff

Explanation:

clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.

What is the standard form for 2 × 10−3 ?

Answers

Answer:

17

Explanation:

2 x 10 = 20

20-3 = 17

Your answer is 17 bc you have to use PEMDAS multiplication is before subtraction

A 47.5-g ball moves at 30.0 m/s. If its speed is measured to an accuracy of 0.20%, what is the minimum uncertainty in its position

Answers

Answer:

The minimum uncertainty in its position is 1.85 x 10⁻³² m.

Explanation:

Given;

mass of the ball, m = 47.5 g = 0.0475 kg

speed of the ball, v = 30 m/s

measuring accuracy of the speed, = 0.2% = 0.002

The uncertainty in measurement of momentum;

ΔP = mΔv

ΔP = (0.0475)(30 x 0.002)

ΔP = 2.85 x 10⁻³ kgm/s

The uncertainty in position is calculated as;

[tex]\delta x \geq \frac{h}{4\pi (\delta P)}[/tex]

where;

h is Planck's constant

[tex]\delta x \geq \frac{6.626 \ \times \ 10^{-34}}{4\pi (2.85 \ \times \ 10^{-3})} \\\\\delta x \geq 1.85 \ \times \ 10^{-32} \ m[/tex]

Thus, the minimum uncertainty in its position is 1.85 x 10⁻³² m.

the force of an electric field is proportional to to electric charge? True or False

Answers

Answer:True

Explanation:

Answer:

I am going to say true not too sure

How long does it take for a bee traveling 11.34 m/s to fly 120 m?

Answers

It’s takes them about 10.59 seconds to fly 120 meters.

Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through flourite. The wavelength of the light from the laser is 632.8 nm in air and the index of refraction of flourite is 1.434.

Answers

Answer and Explanation:

The computation is shown below:

As we know that

Frequency = Speed ÷ wavelength

= (3 × 10^8 )÷ (632.8 × 10^-9)

= 4.74 × 10^14 Hz

Speed in flourite is

= Vaccum speed ÷ refraction index

= 3 × 10^8 ÷ 1.434

= 2.092 × 10^8 m/s

wavelength is

= Speed in flourite ÷ frequency

= (3 × 10^8 × 632.8 × 10^-9) ÷ (1.434 × 3 × 10^8)

= 441.28nm

Do you know how to do this clever ones hmmm?? Describe and explain the motion of a small ball floating on a pond when waves travel across the pond.​

Answers

Answer:

Ball moves up and down repeatedly on surface because waves consist of successive crests and troughs moving across surface, each crest pushes ball up and each trough allows it to move down.

Explanation:

the combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
cm what is the focal length of the other​

Answers

Answer: f = -12 cm

Explanation: Combined lenses is an array of  simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.

When two lenses are in contact and are thin, focal lengths are related as:

[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]

If there is a distance between the lenses, the focal length will be:

[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}[/tex]

Since the lenses in the question above are thin and in contact, the focal length of one of them will be:

[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]

[tex]\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}[/tex]

[tex]\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}[/tex]

[tex]\frac{1}{f_{2}} =\frac{-2}{24}[/tex]

[tex]f_{2}=[/tex] -12

The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.

What is the speed of a commercial jet which travels form New York to Los Angeles (4800) in 6 hours

Answers

Answer:

[tex]Speed = 800km}/hr[/tex]

Explanation:

Given

[tex]Distance = 4800km[/tex]

[tex]Time = 6hr[/tex]

Required

Determine the speed of the jet

The speed is calculated as:

[tex]Speed = \frac{Distance}{Time}[/tex]

Substitute 4800 km for Distance and 6hr for Time

[tex]Speed = \frac{4800km}{6hr}[/tex]

[tex]Speed = 800km}/hr[/tex]

Hence, the speed of the commercial jet is 800km/hr

Using a pulley, you apply a force of 10 Newtons to life an object that weighs 100 Newtons. What is the mechanical advantage of that pulley?

Answers

Answer: 10

Explanation:

The mechanical advantage of that pulley is 10.

What is mechanical advantage?

The force amplified by utilizing a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this.

Mechanisms are machine parts made to control forces and motion in this way.

Given that: the weighs of the object: W = 100 Newton.

Applied force: F = 10 N.

For using a pulley, you have to apply a force of 10 Newtons to lift  an object that weighs 100 Newtons.

Hence, the mechanical advantage of the pulley is

= Weighs of the object/applied force

= 100 Newton / 10 Newton.

= 10.

The mechanical advantage of it is 10.

Learn more about mechanical advantage here:

https://brainly.com/question/16617083

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fill in the blank:

the more people (greater mass) you load into a car, the ___ (more or less) it will accelerate with the same force applied by the engine.

Answers

the more people (greater mass) you load into a car, the more it will accelerate with the same force applied by the engine.

Question 3 (1 point)
here were 2cars racing a quarter mile. The green car had a mass of 1200kg and crossed the finish line with a velocity of 53m/s. The red car had
a mass of 1100Kg and crossed the finish line with a velocity of 55m/s.,Which car had the great momentum?

Black car
Blue car
Green car
Red car

Answers

Answer:

The green car had the greatest momentum

Explanation:

Momentum

Momentum can be defined as "mass in motion" and is calculated as the product of the mass of the object by its velocity.

Being v the magnitude of the velocity and m the mass of the object, the momentum is calculated with:

p = mv

The green car had a mass of m1=1200 kg and crossed the finish line at v1=53 m/s. Hence, its momentum was:

p1 = 1200 Kg * 53 m/s = 63600 Kg.m/s

The red car had a mass of m2=1100 kg and crossed the finish line at v2=55 m/s. Hence, its momentum was:

p2 = 1100 Kg * 55 m/s = 60500 Kg.m/s

Since p1 > p2, then the green car had the greatest momentum

why does the force of air resistance affect the motion of a person traveling at high speed more than a person walking across the room?

Answers

Answer:

yes .

Explanation:

...

;-; :) have a good day

Answer:

because on air the speed is high compared to walking

1. Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s,​

Answers

Answer:

104653.13J

Explanation:

Given parameters:

Mass of roller coaster  = 625kg

Speed  = 18.3m/s

Unknown:

Kinetic energy  = ?

Solution:

The kinetic energy is the energy due to the motion of a body.

     Kinetic energy  = [tex]\frac{1}{2}[/tex] x m x v²  

m is the mass

v is the speed

    Kinetic energy  =  [tex]\frac{1}{2}[/tex]  x 625  x  18.3²   = 104653.13J

Find the applied voltage of a telephone circuit that draws 0.017A through a resistance Of 5,000 ohms

Answers

Following ohms law ( V=IR ) Therefore the voltage will be = 0.017 x 5000 =85 volts

A volleyball experiences 494 Ns of impulse over a time period of 7 seconds. What was the magnitude of the force that acted on the volleyball during this time period?

Answers

Answer:

70.6N

Explanation:

Given parameters:

Impulse  = 494Ns

Time  = 7s

Unknown:

Force applied = ?

Solution:

To solve this problem, we use the formula of impulse;

      Impulse = Force x time

Now insert the parameters and solve;

       494  = Force x 7

            Force  = [tex]\frac{494}{7}[/tex]  

          Force  = 70.6N

A water molecule has 2 hydrogen atoms and 1 oxygen atom. If you were to add an additional oxygen atom to the molecule, would it still be water? If not, what would it be?

Answers

Answer:

No, it would not still be water. it would be hydrogen peroxide

Explanation:

water is [tex]H_{2} O[/tex]. Adding another oxygen would make it [tex]H_{2} O_{2}[/tex], which is hydrogen peroxide

Answer:

It would be Hydrogen peroxide

Explanation:

Atoms actually prefer being configured as water (H2O). Adding on the extra oxygen takes a lot of energy (and other chemicals). That's why we see lots of water and not much hydrogen peroxide around in nature. The reason hydrogen peroxide (H2O2) is dangerous is because it actually wants to drop off that extra oxygen and become water. Anything that does this is called an oxidising agent. An oxygen atom on it's own is pretty unstable and really wants to snatch up electrons from somewhere. First it'll probably gobble up some free floating hydrogen and make some more water with it. In our bodies we don't have much free floating hydrogen, so it runs out pretty quick. The oxygen atom army then has to start breaking up bigger molecules to steal the hydrogens and sometimes even the nitrogens. This breaks up the molecules that form the structures of your body and leaves you with a jumble of random configurations of atoms where the oxygen atoms passed through. Now, before you ask, normally oxygen doesn't do it to you because it exists in the air as O2, bonded to itself. The isolated oxygen atoms only exist for a brief time after they've split up from the hydrogen peroxide.

Suppose that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat. The change in internal energy of the spring is? ​

Answers

Answer: 85J

Explanation:

From the question, we are informed that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat.

Therefore, the change in internal energy of the spring will be calculated as:

ΔU = q + w

where, q = -15J

w = 100J

ΔU = -15J + 100J

= 85J

A dynamite blast blows a heavy rock straight up from the ground with a launch velocity of 160ft/sec. a) Write the height function.

Answers

Answer:

y = 160t - 16t²

Explanation:

Using y = ut -1/2gt² where y = height of heavy rock above the ground, u = initial launch velocity of rock = 160 ft/s, g = acceleration due to gravity = 32 ft/s² and t = time.

So, substituting the values of the variables into y, we have

y = (160 ft/s)t -1/2 × 32 ft/s² × t²

y = (160 ft/s)t - (16 ft/s²)t²

y = 160t - 16t²

So, the height function is y = 160t - 16t²

A bullet has a mass of 0.06 kg. Starting from rest, after the gun's trigger is pulled, a constant force acts on the bullet for the next 0.025 seconds until the bullet leaves the barrel of the gun with a speed of 992 m/s.

What is the change in momentum of the bullet?

Answers

The change in momentum of the bullet : 59.52 kg m/s

Further explanation

Given

m=0.06 kg

Δt=0.025 s

vo=0(from rest)

vt= 992 m/s

Required

The change in momentum

Solution

The change in momentum  = ΔP

ΔP  =m(vt-vo)

ΔP =0.06(992-0)

ΔP =59.52 kg m/s

Which of these is another name for Newton's
first law?
A. the law of action-reaction
B. the law of force and acceleration
C. the law of gravity
D. the law of inertia

Answers

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
D. The law of inertia

which is true about the way air flows

A. high pressure to low pressure

B. low pressure to high pressure

C. cold air to hot air

D. hot air to cold air

Answers

Answer:

A High-to-Low

Explanation:

its like water running down a hill.

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