a 200 ohm resistor is connected to a 12 v car battery. if the resistor is then removed and connected to a battery with 6 v or potential difference, what happens to the current passing through the resistor?

The correct statement about the relationship between the two forms of Newton's second law (Fnet = dp/dt and Fnet = m.a) is option D "Fnet = m.a reduces to Fnet = dp/dt if the momentum of the object does not change with time.

Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. In other words, Fnet = m.a, where Fnet is the net force acting on an object, m is its mass, and a is its acceleration. This law can also be written as Fnet = dp/dt, where dp/dt is the rate of change of momentum with time.

Since momentum is the product of mass and velocity, it can be rewritten as dp/dt = m.dv/dt + v.dm/dt, where v is the velocity of the object. If the mass of the object remains constant over time, then v.dm/dt is zero and dp/dt reduces to m.dv/dt, which is equal to Fnet.

Therefore, Fnet = dp/dt reduces to Fnet = m.a if the object's acceleration does not change with time. If the momentum of the object does not change with time, then dp/dt is zero, and Fnet = dp/dt reduces to zero, which means that Fnet = m.a is also zero. Therefore, Fnet = m.a reduces to Fnet = dp/dt if the momentum of the object does not change with time.

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The volume of the gas varies inversely with pressure, and the correct answer is (b) P/3.

According to Boyle's Law, at a constant temperature, the volume of a gas is inversely proportional to its pressure. Mathematically, this can be expressed as:

PV = k

where P is the pressure of the gas, V is its volume, and k is a constant.

If we assume that the mass of the gas remains constant, then k is also constant. So we can write:

[tex]P_1V_1 = k and P_2V_2 = k[/tex]

where[tex]P_1 and V_1[/tex] are the initial pressure and volume, and [tex]P_2 and V_2[/tex] are the final pressure and volume.

If we divide these two equations, we get:

[tex]P_1V_1/P_2V_2 = 1[/tex]

Since[tex]V_1[/tex] is inversely proportional to [tex]P_1[/tex], we can write:

[tex]V_1 = k/P_1[/tex]

Similarly, [tex]V_2 = k/P_2.[/tex]

Substituting these values in the above equation, we get:

[tex](k/P_1)/(k/P_2) = 1[/tex]

Simplifying this, we get:

[tex]P_2/P_1 = V_1/V_2[/tex]

Since we are given that the temperature remains constant, we can assume that k is constant, and therefore:

[tex]V_1/P_1 = V_2/P_2[/tex]

If we let [tex]P_2 = 3P_1[/tex], then we get:

[tex]V_1/P_1 = V_2/(3P_1)[/tex]

Simplifying this, we get:

[tex]V_1/V_2 = 1/3[/tex]

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The speed of the sports car at impact when kinetic friction between tires and road is 0.80 is 15.55 m/s.

It is given that Mass of sports car, ms = 910 kg, Mass of SUV, mSUV = 2100 kg, and Initial velocity of sports car, us = ?, Final velocity of sports car, v = 0, Initial velocity of SUV, uSUV = 0, Final velocity of SUV, vSUV = 0, and Coefficient of kinetic friction, μk = 0.80. Distance covered before stopping, s = 2.5 m.

We know that the total momentum of the system remains conserved, we can write:

ms * us + mSUV * uSUV = (ms + mSUV) * v

Thus,

ms * us = (ms + mSUV) * v

The speed of the sports car at impact when kinetic friction between tires and road is 0.80 is 15.55 m/s.

It is given that Mass of sports car, ms = 910 kg, Mass of SUV, mSUV = 2100 kg, and Initial velocity of sports car, us = ?, Final velocity of sports car, v = 0, Initial velocity of SUV, uSUV = 0, Final velocity of SUV, vSUV = 0, and Coefficient of kinetic friction, μk = 0.80. Distance covered before stopping, s = 2.5 m.

We know that the total momentum of the system remains conserved, we can write:

ms * us + mSUV * uSUV = (ms + mSUV) * v

Thus,

ms * us = (ms + mSUV) * v

Since the two cars skid together, the frictional force provides the reduction to the motion of the cars. The reduction force F = μk * N where N is the normal force acting on the cars, N = (ms + mSUV) * g where g is the acceleration due to gravity, g = 9.8 m/s².

We have to find the speed of the sports car at impact i.e. us. So, using the equations of motion with constant acceleration, we can write:

us² - 2 * μk * (ms + mSUV) * g * s / (ms + mSUV) = v²

us² = 2 * μk * (ms + mSUV) * g * s / ms

us = sqrt [2 * 0.80 * (910 + 2100) * 9.8 * 2.5 / 910]

us = 15.55 m/s

Therefore, the speed of the sports car at impact is 15.55 m/s.

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Answer:

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Explanation:

I don't think so it helped but through this you can do the question exactly like this ( in this way) ...

The magnitude of the magnetic force experienced by proton 2 will be less than the force experienced by proton 1. This is because the force experienced by a proton is related to the direction of its motion relative to the direction of the magnetic field.

As proton 1 is travelling from east to west, its motion is parallel to the magnetic field, which is aligned in a north-south direction in the continental United States. This means that proton 1 will experience a greater force due to the magnetic field than proton 2, which is travelling in a north-south direction and thus has a motion perpendicular to the magnetic field.
To understand this more clearly, we can consider the equation for the magnetic force:

F = qvB sin θ.

In this equation, the force experienced by a particle is related to the charge (q), velocity (v), and magnetic field strength (B). The sine of the angle between the velocity and magnetic field (θ) is also important as it determines how much of the force will be experienced by the particle. As proton 1's motion is parallel to the magnetic field, it will experience the full force due to the magnetic field, whereas proton 2's motion is perpendicular to the magnetic field and it will only experience a fraction of the force. The magnitude of the force experienced by proton 2 will be lower than the force experienced by proton 1.

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According to the International System of Units, Newton (N) is used to measure force. Thus Newton is the correct response.

A force is defined as a physical quantity that causes a change in the state of motion of a body.

Force is a vector quantity that has both magnitude and direction.

Newton is the unit of force in the International System of Units (SI).

One newton (N) is the amount of force required to give a mass of 1 kg and an acceleration of 1 m/s².

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A set of beliefs can be said to be pseudoscientific if it lacks one or more of the three features of science and empirical evidence.

Pseudoscience is a set of claims, beliefs, or practices that are presented as scientific but lack empirical evidence, are inconsistent with scientific facts, or are based on incorrect assumptions. Pseudoscience can be seen in a variety of fields, including medicine, psychology, and the paranormal.

Science is defined by three characteristics: empiricism, theory construction, and parsimony or simplicity. Empiricism is the use of evidence to establish scientific facts, while theory construction is the development of a conceptual framework that explains and predicts these facts.

Parsimony is the principle that the simplest explanation is the best one, meaning that theories should not include unnecessary assumptions or complexity. However, pseudoscientific practices often lack one or more of these characteristics. They may fail to use empirical evidence or instead rely on anecdotal evidence or personal experience. Their theories may not be testable or may be inconsistent with established scientific facts. They may also be unnecessarily complex or based on assumptions that have no basis in reality.

Hence, a set of beliefs can be said to be pseudoscientific if it lacks one or more of the three features of science and empirical evidence.

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Water droplets that act as prism are phenomenon known as : b) rainbow.

When light enters water droplet and is refracted, it is dispersed into its component colors due to difference in the index of refraction of each color of light. This results in band of colors in the shape of arc with red on outer edge and violet on inner edge, with other colors of spectrum in between. This is the same effect as prism which disperses light in the same way.

Rainbows appear in seven colors because water droplets break sunlight into seven colors of spectrum and you get the same result when sunlight passes through prism. Water droplets in the atmosphere act as prism though traces of light are very complex.

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The acceleration of the cart at this instant is calculated to be 5.17 m/s² to the right.

Newton's second law explains that acceleration of any object is directly related to net force and inversely related to the mass.

To determine the acceleration of the cart, we need to calculate the net force acting on it.

The net force is the vector sum of the two forces:

Net force = Force a + Force b = 77 N to the right - 15 N to the left = 62 N to the right

Using Newton's second law, F = ma, where F is the net force and m is the mass of the cart, we can calculate the acceleration:

a = F/m = 62 N / 12 kg = 5.17 m/s

Therefore, the acceleration of the cart at this instant is 5.17 m/s² to the right.

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The point at which the warning will do no good is 7.50 m above the man's ears.

When a water-filled balloon is released from rest at a height of 10.0 m above the ears of a man, the warning will do no good if shouted after the balloon reaches a certain point. Assuming that the air temperature is 20°C and ignoring the effect of air resistance, this point is 7.50 m above the man's ears.

The vertical displacement (d) can be determined using the equation [tex]d = \frac{vf2}{2g}[/tex], where vf is the final velocity and g is the acceleration due to gravity (9.81 m/s2).

Since the balloon was released from rest, the initial velocity is 0 m/s. Therefore, [tex]d = \frac{02 }{ 2} (\frac{9.81 m}{s2} ) = 0[/tex]m. Since the initial height was 10.0 m, the final height is 10.0 m + 0 m = 10.0 m.

The point at which the warning will do no good is 7.50 m above the man's ears, so the final height of the balloon must be 10.0 m - 7.50 m = 2.50 m.

Therefore, the point at which the warning will do no good is 7.50 m above the man's ears.

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The final velocity of the skater (with the child on their shoulders) is 3.08 m/s.

A skater of mass 70.0 kg initially moves in a straight line at a speed of 4.80 m/s.

When the skater lifts a child of mass 39.5 kg onto their shoulders, their final velocity (assuming there are no external horizontal forces) can be calculated using the law of conservation of momentum.

Momentum is defined as the product of mass and velocity. Therefore, the final momentum of the skater and child can be expressed as:

Final Momentum = (70.0 kg x 4.80 m/s) + (39.5 kg x 0 m/s) = 336 kg m/s

To find the final velocity, we must first find the total mass of the skater and child:

Total Mass = 70.0 kg + 39.5 kg = 109.5 kg

Using the law of conservation of momentum and the total mass, the final velocity of the skater can be expressed as:

Final Velocity = Final Momentum / Total Mass = 336 kg m/s / 109.5 kg = 3.08 m/s

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A 1 kg box falls two metres from a shelf and lands on the ground after 0.021 seconds. The box impacted the ground with a force of around 524.7 N.

The box impacted the ground with a force of around 524.7 N.

Explanation: We can determine the force using the equation F = m * (v/t), where m is the box's mass, v is the velocity change (which is the ultimate velocity because the box starts at rest and comes to a halt), and t is the time it takes for the box to stop.

Given that the box falls 2 metres and its terminal velocity is 0 m/s, v = 2 m/s.

524.7 N is equal to F = 1.1 kg * (2 m/s / 0.021 s).

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Option (A) "sound waves arrive more frequently" is the correct answer. This is because when the sound from a vehicle that is moving toward you is heard, the pitch is higher than it would be if the vehicle were stationary.

Pitch is defined as the highness or lowness of a sound. In other words, pitch is a perception of the frequency of a sound. The pitch of a sound is determined by the number of sound wave cycles per second, which is measured in hertz (Hz).

Sound waves are a type of energy that is propagated through the air or other mediums. Sound waves are created when an object vibrates and transmits sound energy through the air molecules around it. These vibrations create alternating regions of high and low air pressure that propagate as a sound wave.

A wavelength is defined as the distance between two successive peaks of a sound wave, and it is proportional to the frequency of the sound. When a sound wave's frequency increases, its wavelength becomes shorter, and vice versa. Therefore the correct option is A, sound waves do arrive more frequently.

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The change in the distance between the friends changing when the distance between them is 200 m is 7.85m.

Consider a right-angled triangle with the radius of the circular track as one side of the right angle. Then the other two sides are the distance covered by the runner (in a single lap) and the distance between the runner and his friend.

Since the radius is perpendicular to the line connecting the friend and the center of the track, we can call it the hypotenuse of the triangle.

Let x be the distance between the runner and his friend. We are given that x = 200 m.Using the Pythagorean theorem, we can find the distance covered by the runner in a single lap of the track.

e can now differentiate the above expression with respect to time to find the rate of change of the distance covered by the runner (this will also be the rate of change of the distance between the runner and his friend).Hence,

2x(dx/dt) = 2 (distance covered by runner)(d(distance covered by runner)/dt)

dx/dt = (distance covered by runner)

(d(distance covered by runner)/dt) / x

Substituting x = 200 m and d(distance covered by runner)/dt = 7 m/s, we get:

dx/dt = (223.6 m)(7 m/s) / 200 m = 7.85 m/s.

Rounding off to two decimal places, we get:

dx/dt = 7.85 m/s.

Therefore, the answer is 7.85.



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Jake's speed relative to the ground along a train flatcar which is moving in the opposite direction with 10m/s is 14 m/s.

Relative motion refers to the movement of an object with respect to some other object, point, or medium, rather than measuring it in isolation.

The train flatcar moves in the opposite direction to Jake, and the question asks for Jake's speed with respect to the ground. So, by using vector subtraction the relative velocity of Jake with respect to the ground can be determined. The relative velocity can be calculated using the formula:

Relative velocity = velocity of object A - velocity of object B

here, A is Jake, and B is the train flatcar. Therefore, the relative velocity of Jake with respect to the ground is:

Relative velocity of Jake = Jake's speed - Velocity of train flatcar

The velocity of the train flatcar is given as 10 m/s, but we need to use its opposite direction as the train is moving in the opposite direction. So, the velocity of the train flatcar is -10 m/s.

By substituting the values, we get:

Relative velocity of Jake = 4 m/s - (-10 m/s)

Relative velocity of Jake = 4 m/s + 10 m/s

Relative velocity of Jake = 14 m/s

Therefore, Jake's speed relative to the ground is 14 m/s.

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An airplane flies due west at an airspeed of 425 mph and the wind is blowing from the northeast at 40 mph, the ground speed of the airplane is 385 mph, and the bearing of the airplane is 285°.

We can use the equation

GS = AS + (Wind x cos(Θ)),

Where GS is the ground speed, AS is the airspeed, and Θ is the angle between the wind and the heading of the airplane. the airspeed is 425 mph, the wind is blowing from the northeast at 40 mph, and the heading of the airplane is due west. The angle Θ is 90°. Plugging these values into the equation, we get

GS = 425 + (40 x cos(90°)) = 385 mph.

To calculate the bearing of the airplane, we can use the equation

Bearing = 180° - (Θ + (Wind ÷ AS) x 180°).

Θ is 90°, the wind is 40 mph, and the airspeed is 425 mph.

Plugging these values into the equation, we get

Bearing = 180° - (90° + (40 ÷ 425) x 180°) = 285°.

Hence , airplane flies due west at an airspeed of 425 mph and the wind is blowing from the northeast at 40 mph, the ground speed of the airplane is 385 mph, and the bearing of the airplane is 285°.

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Total work done is Wnet = 1/2mv₂² - 1/2mv₁²

Let the mass of the sled be m and the magnitude of the net force acting on the sled be Fnet .

The sled starts from rest. Consider an interval of time during which the sled covers a distance s and the speed of the sled increases from v₁ to v₂ . We will use this information to find the relationship between the work done by the net force (otherwise known as the net work) and the change in the kinetic energy of the sled.

Use W = F s cos (theta) to find the net work Wnet done on the sled. Express your answer in terms of some or all of the variables m ,v₁ and v₂.Using the work-energy principle, we can calculate the work done on an object in terms of its change in kinetic energy. Consider the sled being acted upon by a force Fnet.

W = ΔK is used to calculate the work done on the sled as it moves from rest to velocity v₁ and then to velocity v₂ over a distance s.

Considering the sled to be the system under study, we can write the net work done on the sled as Wnet = ΔK.Wnet = 1/2mv₂² - 1/2mv₁² = Fnet s cos θWnet = Fnet s cos θ = 1/2mv₂² - 1/2mv₁²

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The standard number of bones in the appendicular skeleton varies slightly among individuals, but it is generally accepted that there are 126 bones in the appendicular skeleton of an adult human.

The appendicular skeleton includes all the bones that are attached to the axial skeleton, which includes the skull, vertebrae, and ribcage. The appendicular skeleton consists of the bones of the arms, legs, pelvis, and shoulder girdle. Here is a breakdown of the number of bones in each part of the appendicular skeleton: Arms: 60 bones (30 in each arm) Legs: 60 bones (30 in each leg) Pelvis: 2 bones Shoulder girdle: 4 bones Adding up these numbers gives a total of 126 bones in the appendicular skeleton. However, this number can vary slightly among individuals due to differences in bone structure and development.

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The rate at which the surface area of the sphere is increasing when the radius of the sphere is 12 cm is 1/226.5 cm/s.

The volume of a sphere is increasing at the rate of 8 cm³/s.

Radius of the sphere is 12 cm.

So, we need to find the rate at which its surface area is increasing.

Let, V be the volume of the sphere and r be the radius of the sphere. The volume of a sphere of radius r is given by:

V = (4/3)πr³

Differentiating with respect to time t, we get:

dV/dt = 4πr²(dr/dt) ...(1)

Also, the surface area of the sphere is given by:

A = 4πr²

Differentiating with respect to time t, we get:

dA/dt = 8πr(dr/dt) ...(2)

From equations (1) and (2), we can write:

dr/dt = dV/dt ÷ 4πr²

dr/dt = 8 / (4π × 12²)

dr/dt = 8 / 1808

dr/dt = 1 / 226.5 cm/s

Therefore, the rate at which the surface area of the sphere is increasing when the radius of the sphere is 12 cm is 1/226.5 cm/s.

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Based on the given question, the resistance will: increase with the increase in voltage.

The reason behind this is that resistance and voltage have a direct relationship. As the voltage increases, the resistance also increases. This can be explained by Ohm’s Law which states that V= IR where V is voltage, I is current and R is resistance. As per the second part of the question, it is implied that the resistance varies with temperature.

The resistance of any material depends upon temperature, and a rise in temperature increases the resistance of the material. The light bulb acts as a resistor, and its resistance will increase as the temperature increases due to an increase in the temperature of the filament of the bulb.

The resistance is directly proportional to the temperature of the bulb, and it is represented by the equation

R = R₀ (1 + αt),

where R is resistance, R₀ is the resistance at a particular temperature, α is the temperature coefficient of resistance, and t is the temperature difference in Celsius.

Therefore, based on the data provided, it can be concluded that resistance increases with the increase in temperature which results in the heating of the light bulb, which is a resistor.

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Two people of unequal mass are initially standing still on ice with negligible friction. They then simultaneously push each other horizontally. Then, the statement which is true is the momenta of the two people are of equal magnitude. Thus, the correct option is C.

Momentum is the mass of an object multiplied by its velocity. It is represented by the symbol p. Momentum is a vector quantity and has the same direction as velocity. When the direction of velocity changes, so does the direction of momentum.

The law of conservation of momentum states that the total momentum of an isolated system is constant when no external forces act on the system. According to Newton's third law of motion, when two objects interact, the forces they apply to each other are equal in magnitude and opposite in direction. This implies that the forces on the two people are equal but opposite. Therefore, their momenta are also equal and opposite, so the net momentum of the system is zero after the push.

Kinetic energy is the energy possessed by an object in motion. It is represented by the symbol K. Kinetic energy is a scalar quantity, and it depends on the mass and velocity of the object. When an object moves, it gains kinetic energy, and when it stops, its kinetic energy becomes zero. The kinetic energies of the two people are not equal in this case.

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The point on the x-axis between the two charges where the electric field is zero is 0.747 m, when the charges -2.1 μC and -5.6 μC are located at (-0.50 m , 0) and (0.50 m , 0), respectively.

An electric field is defined as the electric force per unit charge. It is a field of force surrounding electrically charged particles, such as electrons or protons in motion, that exerts force on surrounding matter. It is represented by the symbol E.

The electric field E at any point (x,y) on the x-axis due to the charge Q1 at (-0.50 m, 0) is

[tex]E1 = k * Q1 / r1^2[/tex]

where, k = Coulomb's constant = [tex]9 x 10^9 Nm^2/C^2[/tex]

Q1 = charge = -2.1 μC

r1 = distance between Q1 and

(x,y) = (0.50 + x) m

The electric field E at any point (x,y) on the x-axis due to the charge Q2 at (0.50 m, 0) is

[tex]E2 = k * Q2 / r2^2[/tex]

where,

Q2 = charge = -5.6 μC

r2 = distance between Q2 and (x,y) = (0.50 - x) m

The total electric field E at any point (x,y) on the x-axis due to both the charges is

[tex]E = E1 + E2 = k * Q1 / r1^2 + k * Q2 / r2^2[/tex]

[tex]E = k * (-2.1 * 10^-6) / (0.5 + x)^2 + k * (-5.6 * 10^-6) / (0.5 - x)^2[/tex]

At the point on the x-axis between the two charges where the electric field is zero,

[tex]E = 0k * (-2.1 * 10^-6) / (0.5 + x)^2 + k * (-5.6 * 10^-6) / (0.5 - x)^2 = 0[/tex]

Simplifying, we get [tex](0.5 + x)^2 / (0.5 - x)^2 = 2.667x^2 + 2.667x - 0.50 = 0[/tex]

Solving for x, we get

x = -1.74 m or

x = 0.747 m

We cannot have a negative value of x as the point has to be between the two charges. So, the location of the point where the electric field is zero is x = 0.747 m.

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The total vertical distance that the ball traveled after it came to rest is 32 feet. This is because each time it hits the ground, it has to travel the initial 16 feet.

Given, a ball is dropped from a height of 16ft. When it hits the ground each time, it bounces back to a height of 8ft. Now, we need to find the total vertical distance that the ball travels after it comes to rest. After the first drop, the ball travels a total distance of 16ft + 8ft = 24ft. After the second drop, the ball travels a total distance of 8ft + 8ft = 16ft.

After the third drop, the ball travels a total distance of 8ft + 8ft = 16ft. After the fourth drop, the ball travels a total distance of 8ft + 8ft = 16ft.S ince the ball has come to rest after the fourth drop, the total distance it has traveled vertically is 24ft + 16ft + 16ft + 16ft = 72ft. The ball travels a total vertical distance of 72ft in four drops.

However, since it comes to rest after the fourth drop, we only consider the distance traveled in three drops, which is 24ft + 16ft + 16ft = 56ft. Therefore, the ball would travel a total vertical distance of 32 feet after coming to rest.

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The velocity of wreckage immediately after impact = 9.68 m/s and the compass heading is 45 deg (for the second answer).

Mass of 1950 kg Oldsmobile = 1950 kg

Velocity of Oldsmobile = 15.4 m/s

Mass of a truck hauling animal feed = 3992 kg

Velocity of a truck hauling animal feed = 9.9 m/s

Conservation of Momentum Formula Used,

Momentum before collision = Momentum after collision(m1 × v1) + (m2 × v2) = (m1 + m2) × V'

Calculation for Momentum before Collision = (m1 × v1) + (m2 × v2)

Momentum before Collision = (1950 kg × 15.4 m/s) + (3992 kg × 9.9 m/s)

Momentum before Collision = 30129 + 39560.8

Momentum before Collision = 69689.8 kg-m/s

Let V' be the velocity of the wreckage immediately after the impact.

Velocity after Collision is V'

Calculation for Velocity after Collision = (m1 × v1) + (m2 × v2) / (m1 + m2)V'

= (1950 × 15.4) + (3992 × 9.9) / (1950 + 3992)V'

= 57606.8 / 5942V'

= 9.68 m/s

Given, the 1950 kg car was traveling East on Saginaw Street which means the wreckage was moving North-East (45 degrees)

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The correct option is D; The cart moved at a constant velocity of 0.5m/s for the entire 7 seconds.

Constant acceleration is represented as a horizontal line on the acceleration graph. The slope of the velocity graph represents the acceleration. On the velocity graph, constant acceleration Equals constant slope = straight line.

Acceleration is represented in a velocity-time graph by the slope, or steepness, of the graph line. If the line slopes upward, as seen in the figure between 0 and 4 seconds, velocity increases, and acceleration is positive. The velocity-time graph will be a curve when the acceleration increases with time, as anticipated by the equation: v = u + at.

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Burl and Paul have a total weight of 1300 N. The tensions in the ropes that support the scaffold they stand on add to 1800 N. The weight of the scaffold itself must be 500 N.

A scaffold is a temporary structure that is erected to support workers and their equipment when they are performing a job at a height above the ground. In the construction sector, it is widely used, and it is made up of one or more platforms that are supported by a system of frames and poles.

In order to solve the given problem, we'll have to use some mathematical concepts such as addition and subtraction. The total weight of Burl and Paul = 1300 N

The tensions in the ropes that support the scaffold they stand on = 1800 N

Let us suppose that the weight of the scaffold is x.

So, from the given data, we can write down the following equation:

Total weight of Burl, Paul, and the scaffold = Tensions in the ropes + weight of the scaffold

1300 + x = 1800x = 1800 - 1300= 500 N

Therefore, the weight of the scaffold is 500 N.

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As a positively charged glass rod is brought near the knob of the electroscope, the separation of the leaves will increase.

What is Charge?

Charge is a fundamental property of matter that determines how objects interact with each other through the electromagnetic force. It is a physical property that can be positive or negative and can be measured in coulombs (C).

This is because the positively charged glass rod will induce a negative charge on the metal knob of the electroscope. The negative charges will repel the electrons in the metal leaves, causing them to move away from each other and increasing their separation. The greater the amount of charge on the glass rod, the greater the separation between the leaves will be.

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ans= train Q

Sol= 4.5×60= 270

6×60= 360

270÷180=1.5

360÷270=1.3...

1.3... <1.5

Explanation:

Planets closer to the sun will appear to transit from time to time

   = 2      Venus and Mercury     ( I suppose you could include the Moon..an eclipse ....haha)

All of the planets further from the sun than earth will not transit

Potentially ALL of the planets could transit the sun (earth included)  if observed outside solar system   HOWEVER if you are not observing from near the orbital plane of

the planets NONE of them would transit

For maximum transits, the planets should all be in the same orbital plane and the observer should be very close to this plane also.

The third fundamental question early astronomers tried to answer was: What are the motions of the planets and stars in the night sky?

The shape of the Earth is an oblate spheroid, and its approximate diameter is 12,742 km. The average distance from Earth to the Sun is 149,598,262 km, and the average distance from Earth to the Moon is 384,400 km. 3) What are the motions of the planets? The motions of the planets were observed by ASTRONOMES to be elliptical, with the Sun at one focus.
Early astronomers were curious to understand the shape and size of Earth, as well as the distances from Earth to the Sun and Moon. Additionally, they were interested in determining the motions of the planets and stars in the night sky.
The ancient Greeks believed that the universe was a series of concentric spheres with the Earth in the center. Aristotle, a Greek philosopher, believed that the Earth was at the center of the universe, and that everything else, including the stars and planets, orbited around it. The Greek philosopher Eratosthenes was the first to calculate the Earth's circumference. He did so by measuring the angle of the sun's rays at noon on the summer solstice at two different locations and using the difference to estimate the distance between the two places.

In conclusion, early astronomers attempted to answer fundamental questions regarding the shape and size of Earth, the distances from Earth to the sun and moon, and the motion of stars and planets in the sky .

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