A 4-N object object swings on the end of a string as a simple pendulum. At the bottom of the swing, the tension in the string is 9 N. What is the magnitude of the centripetal acceleration of the object at the bottom of the swing? Give the answer as a function of the acceleration due to gravity, g.

Answer:

(II). The fractions in simplest form

[tex]\dfrac{31}{35}[/tex], [tex]\dfrac{91}{165}[/tex] and [tex]\dfrac{13}{5}[/tex]

(III). The fractions in ascending order

[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]

Explanation:

Given that,

(I). Represent the fractions in pictorial form

(II). Write the fractions in simplest form.

(III). Arrange them in ascending order.

Suppose, The fractions in pictorial form

(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}[/tex]

(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}[/tex]

(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}[/tex]

We need to write in simplest form

Using given fraction

(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}[/tex]

(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}[/tex]

[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}[/tex]

[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}[/tex]

(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}[/tex]

We need to arrange them in ascending order

Using simplest form

The simplest fraction in ascending order

[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]

Hence, This is required solution.

Answer: C

Explanation: It's a lot of math.

The option that gives the correct value for the angle theta above the horizontal axis of the velocity of the body, v is option C.

C. 53.1°

The given parameters are;

The velocity of the body relative to the horizontal axis, vₓ = 6 m/s

The velocity of the body relative to the vertical axis, [tex]v_y[/tex] = 8 m/s

Required;

The measure of the angle theta above above the horizontal axis of the velocity of the body, v

Solution:

The velocity of the body can be represented vectorially as follows;

v = 6·i + 8·j

The vectoral form gives the legs of the right triangle that has the magnitude and direction as the hypotenuse side

Therefore;

[tex]\theta = arctan \left(\dfrac{8}{6} \right) \approx \underline{53.1^{\circ}}[/tex]

Learn more about the vectors here:

https://brainly.com/question/16854117

https://brainly.com/question/16958684

https://brainly.com/question/17097378

Answer:

Hope you like it please thank me and follow me

Answer:

the final statements the correct one is. The second

The iron piece exerts a force of 1 N on the magnet in the opposite direction

Explanation:

In this exercise they give us the force exerted by a magnet on an iron bar and ask us the force that the iron bar exerts on the magnet. We can see that these are action and reaction forces, which by Newton's third law must be of equal magnitude and opposite direction, each applied to one of the bodies.

the final statements the correct one is. The second

The iron piece exerts a force of 1 N on the magnet in the opposite direction

Answer:

1. Urea,                    (d)Fertilizer

2. Combines,          (c) Harvesting and threshing

3. Silos,                   (b) Storage of grains

4. Seed drills,          (a) Sowing seeds

5. Irrigation,             (f) Sprinklers

6. Tilling,                  (e) Preparation of soil

Explanation:

1) Urea is a widely used and important fertilizer in the agricultural industry

2) The combine harvester combines three categories of harvesting grain drops such as threshing reaping and winnowing

3) Silos are used to store grains

4) A seed drill is a seed planting mechanism for burying seeds to a particular depth during seed planting

5) Irrigation is the application of required volume of water to plants

6) Tilling is the digging, turning, and staring operations meant to prepare the soil.

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

[tex]\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}[/tex]

Lo que da;

[tex]\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m[/tex]

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

[tex]\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}[/tex]

Lo que da;

[tex]\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N[/tex]

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

[tex]tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right ) = 38.9^{\circ}[/tex]

La dirección del plano viene dada por la siguiente fórmula;

[tex]tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right ) = 38.9^{\circ}[/tex]

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

Answer:

0.66*10^-6m

Explanation:

We know that the bright fringes are placed on the screen as follows

Ym= m*(lambda xL/d)

But we are given

L= 5.05

Deta Y= 1.59

d = 0.21

1.59* 10^-2m= lambda * 5.05m/2.1*10^-4m

So lambda=

1.59* 10^-2m x 2.1*10^-4m/ 5.05m

= 0.66*10^-6m

Answer:

K.E of truck > K.E of car

Explanation:

Mass of the truck = 8000Kg

K.E=[tex]\frac{1}{2} mv[/tex]

K.E =[tex]\frac{1}{2}*8000*v\\ 4000v[/tex]

Mass of the car = 1000 Kg

K.E of the car =[tex]\frac{1}{2}*1000*v\\ 500v[/tex]

Therefore Kinetic energy of the truck is greater than that of the car

Answer:

1.) Sowing

2.) Respiration

3.) Soil preparation or cultivation or ploughing

4.) Fertility

5.) 2, 4 -D

6.) winnowing threshers

7.) Surface irrigation and sprinkler irrigation

8.) Weeds

9.) Transplantation

10.) Aeration

Explanation:

1.) Seed drill sows crop seed

2.) Ploughing assist in the respiration and penetration of the roots of a growing plants

3.) Tilling the soil is breaking of the soil lumps and turning of the soil

4.) Manure and fertilizers supply nutrient to the soil for the uptake by plant in food production

5.) 2, 4 -D are a range of weedicide containing 2,4-D as the active ingredient

6.) Winnowing is the separation of grain from straw

Threshers remove seeds from husks and stalks

7.) Surface irrigation -gravity enables the flow of the water

and sprinkler irrigation- Use of preset tools for irrigation

8.) Weeds are the unwanted, in situ, growing plants close to the crops

9.) Transplantation is the method of relocating plants

10.) Excess water limits access of the roots and seeds to atmospheric oxygen

Answer:

12.3 m/s

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr)/(c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 894 Hz

fr = 926 Hz

c = 343 m/s

vs = 0 m/s

Find: vr

926 = 894 (343 + vr) / (343 + 0)

vr = 12.3

The speed of the car is 12.3 m/s.

Answer:

* if the spring force is greater than the maximum of the static friction force,  

               Fe = m (a + μ_k g)

* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient

              Fe =μ_s m g

Explanation:

For this exercise we must apply Newton's second law to the system

X axis

         Fe -fr = m a

         Fe = m a + fr

Y axis  

        N-W = 0

        N = W = mg

the roe force is given by

        fr = μ N

        fr = μ mg

we substitute

      Fe = m a + μ m g

      Ee = m (a + μ g)

Let's analyze the solution. We have several possibilities

* if the spring force is greater than the maximum of the static friction force, the system acquires an acceleration and the result is with the kinetic friction coefficient

               Fe = m (a + μ_k g)

* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient

              Fe =μ_s m g

Answer:

speed

Explanation:

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

Answer:

The comic microwave background

Explanation:

The cosmic microwave background is said to be part of the remnant of the Big Bang that happened which resulted in the formation of the universe. This is because the universe was thought to be a very hot place which resulted in the expansion of it.

The heat was said to have resulted in the cooling of gases present and the remnant of the heat is what formed the radiation called the cosmic wave background.

Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

Answer: 0.1

Explanation: The wire size is very important when making decisions on the wiring of any equipment,house and other things. It has also been found that the size of the wire determines the load that can be allowed through it.

The right wire size application chart should always be considered before selecting the wiring diagram or system for any building or equipment as it can help to determine the amount of voltage that can be effectively carried through it.

Answer:

the photo is a bit blur

Answer:

The definition of the particular circumstance consists provided in the subsection on the interpretation elsewhere here.

Explanation:

Answer:

The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.

Answer:

Goldilocks zone of habitability.

Explanation:

Answer:

Explanation:

Initial velocity (u) of the Bullet = 400 m/sec

Final velocity (v) of the Bullet = 100 m/sec

Bullet passed through the block in (t) = 0.0004 sec  

Using 1st Equation of motion :

400 m/s = 100 m/s - a (0.0004)

Deceleration of Bullet = 750,000 m/sec^2

(a) F (force exerted by the wooden block on the bullet) = F (force exerted by the bullet on the wooden block)

F = m * a = 0.008 * 750,000 = 6000 N

(b) Using 3rd Equation of motion :

[tex]v^{2} = u^{2} - 2aS[/tex]

10000 = 160000 - 2 * 750,000 * S

Thickness of wood (S) = 0.1 m

Answer:

Explanation:

First of all we shall calculate the velocity of composite mass . Let it be v . Applying law of conservation of momentum

mu - MU = ( m + M ) v

v = mu - MU /  ( m + M )

loss of kinetic energy

= 1/ 2 mu² + 1/2 MU² - 1/2 ( M +m ) v²

= 1/ 2 mu² + 1/2 MU² - 1/2 ( M +m ) (mu - MU)² / ( m + M )²

= 1/ 2 mu² + 1/2 MU² - 1/2  (mu - MU)² / ( m + M )

= 1/2 [ m²u² + mMu² +mMU² + m²U² - m²u² - M²U² - 2 muMU ] /  ( m + M )

=  1 / 2 [ mMu² + mMU² - 2 muMU ] /  ( m + M )

= 1 / 2mM  [ (u² + U² - 2 uU)  /  ( m + M )]

= 1/2 mM  x k

where

k =  [ (u² + U² - 2 uU)  /  ( m + M )]

Given

m = .004 kg

M = 4 kg

u = 890 ms⁻¹

U = 7 ms⁻¹

k = ( 890² + 7² - 2 x 890 x 7 ) / 4.004

= ( 792100 + 49 - 12460 ) / 4.004

= 194727.52

loss of kinetic energy

= 1/2 mM  x k

= .5 x .004 x 4 x 194727.52

= 1557.82 J .

Answer:

Concave mirror makes someone looking at it look dwarf or short, while convex mirror stretches the person making the person look weird.

Answer:

See explanation below for Newton's third law of "action generates reaction" for this example

Explanation:

From Newton's third law: "For every action there is an equal and opposite reaction."

Frisbee is pulling on the leash with force F which is felt by Dylan as a tension force in the leash trying to pull his arm out of its socket, and Frisbee feels an equal and opposite tension force from the leash chocking him.

Answer:

kinetic energy is 1/2mv^2.

which is 1/2×0.05×3^2

1/2×0.05×9.

1/2×0.45=

0.45÷2=0.225~0.23J

Answer:

3.33 N

Explanation:

First, find the acceleration.

Given:

Δx = 3 m

v₀ = 0 m/s

t = 3 s

Find: a

Δx = v₀ t + ½ at²

3 m = (0 m/s) (3 s) + ½ a (3 s)²

a = ⅔ m/s²

Use Newton's second law to find the force.

F = ma

F = (5 kg) (⅔ m/s²)

F ≈ 3.33 N

Answer:

10N

Explanation:

Applying the Hooke law:

F = kx

F: Force

k: stiffness coefficient

x: stretched distance

F = 10N/m x 1m = 10N

Answer:

mechanical energy or chemical energy

Answer:

In order to be in translational equilibrium, the net force (sum of the forces) must be 0.

Answer:

22.2 m/s or 80 km/h

Explanation:

Given that

Distance travelled by the car, d = 240 km

Time taken by the car, t = 3 hours.

Speed of the car, v = ? m/s

for easy calculations, we will be converting the units to meters and seconds respectively.

240 km to meters would be

240 * 1000 m = 240000 m

3 hrs to seconds would be

3 * 60 mins * 60 seconds = 10800 s

now, we have our distance and time to be

d = 240000 m

t = 10800 s

speed is defined as the ratio of distance with respect to time taken, effectively,

Speed = distance/time

speed, v= 240000 / 10800

v = 22.2 m/s

therefore, the speed of the car during the time is 22.2 m/s, or if the speed is needed in km/h, we can convert it

22.2 * 3600/1000 =

80 km/h