A 40kg steel casting (Cp=0.5kJkg-1K-1) at a temperature of 4500C is quenched in 150kg of oil (Cp=2.5kJkg-1K-1) at 250C. If there are no heat losses, what is the change in entropy of?
(i) The casing.
(ii) The oil.
(iii) Both considered.

Answers

Answer 1
Of the oil I hope this help

Related Questions

In the construction of a large reactor pressure vessel, a new steel alloy with a plane strain fracture toughness of 55 MPa-m1/2 and a Y value of 1.0. An in-service stress level of 200 MPa has been calculated. What is the length of a surface crack (in mm) that will lead to fracture

Answers

Answer:

[tex]l=24mm[/tex]

Explanation:

From the question we are told that:

Plane strain fracture toughness of [tex]T=55 MPa-m1/2[/tex]

Y value [tex]Y=1.0[/tex]

Stress level of[tex]\sigma =200 MPa[/tex]

Generally the equation for length of a surface crack is mathematically given by

[tex]l=\frac{1}{\pi}(\frac{T}{Y*\sigma})^2[/tex]

[tex]l=\frac{1}{3.142}(\frac{55}{1*200})^2[/tex]

[tex]l=0.024m[/tex]

Therefore

in mm

[tex]l=24mm[/tex]

Which of the following is not a part sympathetic activation during the fight or flight response?

Answers

The parasympathetic division functions with actions that do not require immediate reaction. The sympathetic division initiates the fight-or-flight response and the parasympathetic initiates the rest-and-digest or feed-and-breed responses.

Answer:

Digestion functions become more active

Explanation:

I just took the text!

A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?


122 cm


182 cm


82 cm


22 cm


108.2 cm

Answers

Answer: (b)

Explanation:

Given

Original length of the rod is [tex]L=100\ cm[/tex]

Strain experienced is [tex]\epsilon=82\%=0.82[/tex]

Strain is the ratio of the change in length to the original length

[tex]\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm[/tex]

Therefore, new length is given by (Considering the load is tensile in nature)

[tex]\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm[/tex]

Thus, option (b) is correct.

Technician A says that all electric motors are DC motors. Technician B says that two types of brushless motors use AC current. Which technician is correct

Answers

Answer:

Technician B only.

Explanation:

It is not necessary that all electric motors will use Direct current, some may also use Alternative current. Some electric motors that use DC may use brushes. There are two types of brushless motors that use alternative current.

A network has three independent file servers, each with 90 percent reliability. The probability that the network will be functioning correctly (at least one server is working) at a given time is:

Answers

Answer:

The correct answer is "99.9%".

Explanation:

According to the information given in the question,

[tex]P(1 \ fail) = 0.1[/tex]

The probability of all fail will be:

[tex]P(all \ fail) = (0.1)^3[/tex]

                  [tex]=0.001[/tex]

hence,

[tex]P(not \ all \ fail)= 1-P(all \ fail)[/tex]

                        [tex]=0.999[/tex]

                        [tex]=99.9[/tex] (%)

Thus the above is the right answer.

Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?

Answers

Answer:

[tex]V_{pp}=2V[/tex]

Explanation:

Source Voltage [tex]V= 120V[/tex]

Frequency [tex]f=60Hz[/tex]

Peak output voltage [tex]Vp=15V[/tex]

Peak Output Voltage with filter [tex]V_p'=14V[/tex]

Generally the equation for Peak to peak voltage is mathematically given by

[tex]V_p'=V_p-\frac{V_{pp}}{2}[/tex]

Therefore

[tex]V_{pp}=2(V_p-v_p')[/tex]

[tex]V_{pp}=2(15-14)[/tex]

[tex]V_{pp}=2V[/tex]

Water is boiled in a pot covered with a loosely fitting lid at a location where the pressure is 85.4 kPa. A 2.61 kW resistance heater with 84.5% efficiency supplies heat to the pot. How many minutes will it take to boil 6.03 kg of water?

Answers

Answer:

t = 6179.1 s = 102.9 min = 1.7 h

Explanation:

The energy provided by the resistance heater must be equal to the energy required to boil the water:

E = ΔQ

ηPt = mH

where.

η = efficiency = 84.5 % = 0.845

P = Power = 2.61 KW = 2610 W

t = time = ?

m = mass of water = 6.03 kg

H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg

Therefore,

(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)

[tex]t = \frac{1.362\ x\ 10^7\ J}{2205.45\ W}[/tex]

t = 6179.1 s = 102.9 min = 1.7 h

Given : x² + 200x = 166400 The current park is a square, and the addition will increase the width by 200 meters to give the expanded park a total area of 166,400 square meters To Find : the side length of the current square park. Solution: x² + 200x = 166400 => x(x + 200) = 166400 166400 = 320 * 520 => (320)(320 + 200) = 166400 => x = 320 side length of the current square park. = 320 m Learn More: Which expression is a possible leading term for the polynomial ... brainly.In/question/13233517

Answers

Answer:

320 m

Explanation:

To find the side length of the current park, x, we solve the quadratic equation for the area of the park

x² + 200x = 166400

x² + 200x - 166400 = 0

We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x

So, we re-write the expression as

x² + 200x - 166400 = 0

x² + 520x - 320x - 166400 = 0

We write out the factors of the expression,

x² + 520x - 320x - 320 × 520 = 0

Factorizing the expression, we have

x(x + 520) - 320(x + 520) = 0

(x + 520)(x - 320) = 0

x + 520 = 0 or x - 320 = 0

x = -520 or x = 320

Since x is not negative, we take the positive answer.

So, x = 320 m

Determine the resistance values for a voltage divider that must meet the following specifications:_______.
a. The current drawn from the source under unloaded condition is not to exceed 5 mA.
b. The sourcevoltage is to be 10 V, and the required outputs are to be 5 V and 2.5 V.
c. Sketch the circuit.
d. Deter-mine the effect on the output voltages if a load is connected to each tap one at a time.

Answers

Answer:

i) when circuit is unloaded : R1 + R2 = 2kΩ.

ii) when 5V output voltage is applied :  R1 = 1 kΩ , R2 =  1 kΩ

iii) when 2.5 v output voltage is applied : R1 = 1500 Ω,  R2 = 500 Ω

iv) when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

Explanation:

Current drawn from source under loaded condition ≤ 5 mA

source voltage = 10 v ,  required output = 5 v , 2.5 v

attached below is the sketch of the circuit

Resistance values

i) when the circuit is unloaded

Req = R1 + R2 = 2 kΩ  ( Req = Vs / I  = 10 / 5*10^-3 = 2 kΩ )

ii) when  output voltage = 5 v

we will apply voltage divider rule

R1 = 1 kΩ ,

R2 =  1 kΩ

iii) When the output voltage = 2.5 v

applying voltage divider rule

R1 = 1500 Ω

R2 = 500 Ω

iv) when the load is connected to each tap one at a time

i.e. when the resistance are in parallel

when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

attached below is the detailed solution to the given problem

a video inspection snake is use

Answers

Answer:

very good thx

Explanation:

A pinion and gear pair is used to transmit a power of 5000 W. The teeth numbers of pinion
and gear are 20 and 50. The module is 5 mm, the pressure angle is 20o
and the face width is 45 mm. The
rotational speed of pinion is 300 rev/min. Both the pinion and the gear material are Nitralloy 135 Grade2 with a hardness of 277 Brinell. The quality standard number Qv is 5 and installation is open gearing
quality. Find the AGMA bending and contact stresses and the corresponding factors of safety for a
pinion life of 109
cycles and a reliability of 0.98

Answers

Answer:

mark me as a brainleast

Explanation:

209781

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more ________________ than bypass and absorb the energy of the transient.

Answers

Answer:

I think ( MOV Metal oxide varistors )

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.

Elliptic curve cryptography is considered as the latest and probably the one with a future. Having seen RSA in earlier modules, in which ways do YOU think elliptic cryptography is more advanced than RSA. You may read other material or get this information from the internet to answer this question. But make sure to provide necessary references when you do cite others.

Answers

Answer:

The answer is below.

Explanation:

Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:

1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.

2. ECC can work well and at a faster rate on a small-capacity device compared to RSA

3. It uses offer speedier SSL handshakes that enhance security

4. It offers fast signatures

5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.

6. Relatively quick encryption and decryption

The main water line into a tall building has a pressure of600kPaat 5mbelow ground level. Apump brings the pressure up so the water can be delivered at 200kPaat the top floor 150maboveground level. The volumetric flow rate is 0.01m3/s. Consider the liquid water as an incompressiblesubstance. Assume steady state operation, negligible changes in kinetic energy, and the water temperature remains constant. Determine the required pumpingpower [kW, hp].

Answers

Answer:

Required pump power = - 11.205 kW

Explanation:

Pi = 600 kPa

Zi ( initial height ) = - 5m

P2 = 200 kPa

Ze ( top floor above ground level ) = 150m

Flowrate = 0.01 m^3/s = 10 kg/s

Temperature = 10°C  ( assumed value )  remains constant

calculate the value of pumping power required ( i.e. work done )

Applying the energy equation

Hi + 1/2(vi)^2 + gZi = He + 1/2(Ve)^2 + gZe + W

given negligible internal/kinetic  energy  difference in "h's = the pv terms

W = ( Pi Vi - Pe V2 ) + g( Zi - Z2 )

   = ( (600 * 0.001)  - (200 * 0.001) ) + (9.81/1000) ( - 5 - 150 )

   = - 1.1205 Kg/kJ

required pump power = flowrate * -1.1205

                                     = 10 * ( - 1.1205 ) = - 11.205 kW

Explain ROLAP, and list the reasons you would recommend its use in the relational database environment.

Answers

Answer:

ROLAP  is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )

Very fast to access and also fast in processing queries provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databases

Explanation:

ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).

Advantages of ROLAP ( reasons for the use of ROLAP )

Very fast to access ( fast in processing queries )provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databases

An ideal gas within a piston-cylinder assembly undergoes a Carnot refrigeration cycle. The isothermal compression occurs at 325 K from 2 bar to 4 bar. The isothermal expansion occurs at 250 K. Determine:

a. the coefficient of performance
b. the heat transfer to the gas during the isothermal expansion, in kj per kmol of gas
c. the magintude of the net work input, in kj per kmol of gas.

Answers

Answer:

a) [tex]\mu=3.3[/tex]

b)  [tex]Q=1440.7KJ/Kmol[/tex]

c)  [tex]W=1872.9KJ/Kmol[/tex]

Explanation:

From the question we are told that:

Initial Temperature [tex]T_1=325k[/tex]

initial Pressure [tex]P_1=2 bar[/tex]

Final Pressure [tex]P_2=4 bar[/tex]

iso-thermal expansion [tex]T_2=250k[/tex]

a)

Generally the equation for Coefficient of performance is mathematically given by

[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]

[tex]\mu=\frac{250}{325-250}[/tex]

[tex]\mu=3.3[/tex]

b)

Generally the equation for Heat Expansion is mathematically given by

[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]

Where

R=Gas constant

[tex]R=8.314462618[/tex]

Therefore

[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]Q=1440.7KJ/Kmol[/tex]

c)

Generally the equation for work input is mathematically given by

[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]

[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]W=1872.9KJ/Kmol[/tex]

The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol

Given Data:

T1 = 325KP1 = 2 barP2 = 4 barT2 = 250K

Isothermal expansion occurs at 250K.

a) The coefficient of performance

This is calculated as

COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]

b) Heat Transfer in isothermal expansion

[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]

Therefore; In isothermal process du = 0

R = 8.314 AkJ/K.mol

Q = 8.314 * 250 In(4/2)

Q = 1440.71kJ/K.mol

c) Work Input

W[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]

The work input is 1872.92kJ/K.mol

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Apart from the type of emergency, what factors affect the decision on weather to evacuate or shelter in place?

Answers

Answer:

. 1. Type of building

2. Location of emergency

3. Extent of emergency

Explanation:

1. The kind of building in which people find themselves could be a factor that can be used to make this decision. a lot of buildings can be easily affected by disasters such as explosions or tornadoes the extent of the effect is dependent on how the building is constructed. in some situations it is better to shelter in, while in others it is best to evacuate.

2. Another factor to be considered is the location or area where this is happening it is good to consider this so that people can be safely moved given that help can be easily accessed or if best to stay in.

3. The last is the extent of what is happening. The risk involved is one way of making the choice to evacuate or to stay.

The factors that affect the decision on whether to evacuate or shelter in place include:

Type of building.Location of emergency.Extent of emergency

It should be noted that the building where an individual lives play a vital role during emergencies. Buildings that have poor foundations can easily be affected during emergencies.

Another factor that should be considered is the location where the emergency is taking place. Lastly, the extent of the emergency can determine if the person should stay or not.

Learn more about emergencies on:

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A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?


122 cm


182 cm


82 cm


22 cm


108.2 cm

Answers

Answer:

The new length of the rod is 182 cm.

Explanation:

Given that a rod that was originally 100-cm-long experiences a strain of 82%, to determine what is the new length of the rod, the following calculation must be performed:

100 x 1.82 = X

182 = X

 

Therefore, the new length of the rod is 182 cm.

In heavy traffic areas you should wave pedestrians across the street if there is no crosswalk

Answers

The answer is yes ......

In heavy traffic areas, you should wave pedestrians across the street if there is no crosswalk: False.

What is a crosswalk?

A crosswalk can be defined as the marked or specially paved part of a road that is characterized by heavy traffic, so as to enable pedestrians have right of way to cross the street because drivers are required by traffic law to stop for them.

However, a driver or other road users in heavy traffic areas shouldn't wave pedestrians across the street if there is no crosswalk

Read more on traffic laws here: https://brainly.com/question/22768531

A investor will invest in mutual fundwith a probability of 0.6, will invest in government fundwith a probability of 0.3, and will invest in both fundswith a probability of 0.15. Find the probability that the investor will invest in either mutual fundor government fund.

Answers

Answer:

0.75

Explanation:

From this question above we have the following information

A = probability of investment in mutual fund= 0.6

B = probability of investment in government fund = 0.3

C = probability of investing in both the mutual fund and the government= 0.15

Where to find the probability of this investor investing in either of these two

= Prob(a) + prob(b) - prob(c)

= 0.6 + 0.3 - 0.15

= 0.9 - 0.15

= 0.75

A moving-coil instrument, which gives full-scale deflection with 0.015 A has a copper coil having resistance of 1.5 Ohm at 15°C and a temperature coefficient of 1/234.5 at 0 degree C in series with a swamp resistance 3.5 Ohm having a negligible temperature coefficient. Determine the resistance of shunt required for a full-scale deflection of 20 A and the resistant required for a full-scale deflection of 250 V. If the instrument reads correctly at 15°C, determine the percentage error in each case when the temperature is 25°C.

Answers

Answer: check answers in pictures (2 p)

The resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

What is resistance?

Resistance is a measure of an electrical circuit's resistance to current flow. Resistance is measured in ohms, which is represented by the Greek letter omega.

Full-scale deflection current = 0.015 A

Full-scale deflection current for 20 A = 20/0.015 = 1333.33 times full-scale deflection current

The current through the meter coil is given by:

Ic = Im * (Rm / (Rm + Rs))

At full scale, Ic = 1333.33 * 0.015 A = 20 A, Rm = 1.5 Ohm, and Rs = 3.5 Ohm.

Therefore:

20 A = Im * (1.5 Ohm / (1.5 Ohm + 3.5 Ohm))

Im = 20 A * (3.5 Ohm / 5 Ohm)

Im = 14 A

The current through the shunt resistor is therefore:

Ish = Im - Ic

Ish = 14 A - 20 A

Ish = -6 A

Since the shunt resistor is in parallel with the meter, its resistance can be calculated using the following formula:

Rs = Rm * (Im / Ish - 1)

Substituting the values, we get:

3.5 Ohm = 1.5 Ohm * (14 A / (-6 A) - 1)

3.5 Ohm = 1.5 Ohm * (-1.333 - 1)

3.5 Ohm = 1.5 Ohm * (-2.333)

Rs = 1.5 Ohm * (14 A / (-6 A) - 1) / (-2.333)

Rs = 2.528 Ohm

Therefore, the resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

Now, let's find the resistance required for a full-scale deflection of 250 V:

Full-scale deflection current = 0.015 A

Resistance required for full-scale deflection of 250 V = 250 V / 0.015 A

Resistance required for full-scale deflection of 250 V = 16666.67 Ohm

This resistance is in parallel with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm || Rext

Rtotal = (Rm * Rext) / (Rm + Rext)

Substituting the values, we get:

Rtotal = (1.5 Ohm * 16666.67 Ohm) / (1.5 Ohm + 16666.67 Ohm)

Rtotal = 1.43 Ohm

This resistance is in series with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm + Rext + Rs

Substituting the values we get:

1.43 Ohm = 1.5 Ohm + 16666.67 Ohm + Rs

Rs = 1.43 Ohm - 1.5 Ohm - 16666.67 Ohm

Rs = -16666.74 Ohm

Thus, the calculated value of Rs is negative, it means that the shunt resistor must be used instead of a series resistor to achieve a full-scale deflection of 250 V.

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A force measuring instrument comes with a certificate of calibration that identifies two instrument errors and assigns each an uncertainty at 95% confidence over its range. Provide an estimate of the instrument design-stage uncertainty.
Resolution: 0.25 N
Range: 0 to 100 N
Linearity error: within 0.20 N over range
Hysteresis error: within 0.30 N over range

Answers

Answer:

[tex]U=\pm 0.382N[/tex]

Explanation:

From the question we are told that:

Resolution: 0.25 N

Range: 0 to 100 N

Linearity error: within 0.20 N over range

Hysteresis error: within 0.30 N over range

Generally the equation for Stage Uncertainty is mathematically given by

[tex]U=\sqrt{u_0^2+u_T^2}[/tex]

Where

[tex]u_0=Zero\ order\ uncertainty[/tex]

[tex]u_0=\pm 0.5*0.25[/tex]

[tex]u_0=\pm=0.125[/tex]

And

u_T=Total instrumental Uncertainty

[tex]u_T=\sqrt{l_e^2+h_e^2}[/tex]

Where

l_e=Error of linearity

h_e=Error due to hysteresis

Hence

[tex]u_T=\sqrt{0.20^2+0.30^2}[/tex]

[tex]u_T=\pm 0.36[/tex]

Therefore

[tex]U=\sqrt{(0.125)^2+0.36^2}[/tex]

[tex]U=\pm 0.382N[/tex]

Please help me:
Use the Node analysis to find the power of all resistors

Answers

‘Politics and planning are increasingly gaining prominence in contemporary urban and regional planning debates’. Using relevant examples, discuss this assertion reflecting on the critical success factors for the successful implementation of the land reform program in South Africa.

Air enters a diffuser operating at steady state at 540°R, 15 lbf/in.2, with a velocity of 600 ft/s, and exits with a velocity of 60 ft/s. The ratio of the exit area to the inlet area is 8. Assume that The air is the ideal gas model for the air and ignoring heat transfer, determine

Answers

Answer: Hello the question is incomplete below is the missing part

Question:  determine the temperature, in °R, at the exit

answer:

T2= 569.62°R

Explanation:

T1 = 540°R

V2 = 600 ft/s

V1 = 60 ft/s

h1 = 129.0613  ( value gotten from Ideal gas property-air table )

first step : calculate the value of h2 using the equation below

assuming no work is done ( potential energy is ignored )

h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778

∴ h2 = 136.17 Btu/Ibm

From Table A-17

we will apply interpolation

attached below is the remaining part of the solution

Which of the following would make a column more likely to buckle?


Increase its ultimate compressive strength


Increase its length


Increase its Young’s modulus


Increase its cross-sectional area


Increase its area moment of inertia


True or false: Increasing a material’s ultimate compressive strength makes it less likely to crush under its own weight (assuming all other things equal).

True

False

True or false: The area moment of inertia of an object only depends on its shape, not its size.

True

False

Answers

Answer:

1) B: Increase its length

2) True

3) True

Explanation:

1) Columns are compressive members and are subjected to primarily compressive stresses.

Now, there is what we call slender Ness ratio in columns which is basically used to check the ability of a column to resist buckling.

The formula is;

Slenderness ratio = Effective length of column/radius of gyration

Thus, the longer the column the more the Slenderness ratio and the more likely it is to buckle.

Thus, increasing the length is what makes columns likely buckle.

2) Compressive strength is the ability of a material to withstand loads that may reduce size or make the material crush under load.

Now, increasing the compressive strength simply means more ability to withstand loads that may lead to crushing under load.

Ultimate compressive strength is the maximum amount of compressive stress that a material can take before it crushes under load. Thus, increasing the ultimate compressive strength means it is less likely to crush under its own weight.

3) There are different factors that affect moment of inertia and they are;

- the mass of the body

- axis of rotation of the body

- shape and size of the body.

However, for area moment of inertia, what is most relevant to us is the shape of the body in question since we are dealing with area and not how big it is.

For an applied transformer with a primary winding of 220, a secondary winding of 113 turns, a core of 45 cm2 cross-section and a rated supply voltage of 220 V, frequency f = 50 Hz, number system Core style K = 1,2.
one. Calculated from the sensor in the core transformer.
NS. Calculate the rated capacity of the transformer application.
C. Calculating no-load voltage and current levels.
NS. If the power point is reduced by 7% from the voltage level; voltage scortation feature.
e. If use the core machine variable on random form; powerpress same as the host variable on; compare the capacity of the random transformer with the capacity of the transformer application.

Answers

Explanation:

https://www.chegg.com/homework-help/questions-and-answers/iron-core-wish-design-transformer-part-dc-power-supply-moderately-high-current-rating-volt-q53186459?trackid=83dbc34cec2e&strackid=3efc9f324415

Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.20 kg; the mass of the liquid is 1.85 kg. Balance D reads 3.10 kg and balance E reads 7.50 kg. The volume of block A is 4.15 × 10−3 m3.
a) What is the density of the liquid?
b) What will the balance D read if block A is pulled up out of the liquid?
c) What will the balance E read if block A is pulled up out of the liquid?

Answers

Answer:

a)  [tex]m_e= 3.05 Kg[/tex]

b)  [tex]\rho=1072.3kg/m^3[/tex]

c)  [tex]m_e= 3.05 Kg[/tex]

Explanation:

From the question we are told that:

Beaker Mass [tex]m_b=1.20[/tex]

Liquid Mass [tex]m_l=1.85[/tex]

Balance D:

Mass [tex]m_d=3.10[/tex]

Balance E:

Mass [tex]m_e=7.50[/tex]

Volume [tex]v=4.15*10^{-3}m^3[/tex]

a)

Generally the equation for Liquid's density is mathematically given by

[tex]m_e=m_b+m_l+(\rho*v)[/tex]

[tex]\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}[/tex]

[tex]\rho=1072.3kg/m^3[/tex]

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

[tex]m_d=m- (\rho *v )[/tex]

[tex]m=3.10+ (1072.30 *4.15*10^{-3}m^3 )[/tex]

[tex]m=18.10kg[/tex]

c)

Generally the equation for E's Reading at A pulled is mathematically given by

[tex]m_e=m_b+m_l[/tex]

[tex]m_e = 1.20 + 1.85[/tex]

[tex]m_e= 3.05 Kg[/tex]

If an elevator repairer observes that cables begin to fray after 15 years, what process might he or she use to create a maintenance schedule for their replacement? fallacious reasoning reductive reasoning inductive reasoning deductive reasoning

Answers

Answer:

inductive reasoning

Explanation:

Inductive reasoning is one of the type of reasoning method in which generalized consequences are derived from limited observations. By observing few data, general conclusions are drawn. The conclusions drawn are false in inductive reasoning. In the given situation, the conclusion drawn by the elevator repairer has been drawn by inductive reasoning. His observation of some cables led him to draw the conclusion about all the cables. The result of the reasoning is false.

Doubling the diameter of a solid, cylindrical wire doubles its strength in tension.

True

False

Answers

Answer:

True ❤️

-Solid by solid can make Cylindrical wire doubles Strengths in tension

On the inner surface of the cylinder, the third principal stress is not zero. The third principal stress acts in the radial direction. Determine the third principal stress. Include the proper sign for your value.

Answers

Answer:

σ1, σ2 and σ3.

Explanation:

The three principal stresses are labelled or written as σ1, σ2 and σ3. The σ1 is the maximum principal stress or most tensile stress, σ2 is the intermediate principal stress and σ3 is the minimum or most compressive principal stress. Principal stresses are the maximum and minimum extensional stresses present in an object. The principal directions have no shear stresses connected with them.

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