A 50.0 kg object is moving east at an unknown velocity when it collides with a 60.0 kg stationary object. After collision, the 50.0 kg object is traveling at a velocity of 6.0 m/s 50.0degree N of E and the 60.0 kg object is traveling at a velocity of 6.3 m/s 38degree S of E.

What was the velocity of the 50.0 kg object before collision?

p=m•v is the formula.

Answers

Answer 1
Based on the principle of conservation of momentum,  the velocity of the 50.0 kg object before collision was 13.56 m/s.

What was the velocity of the 50.0 kg object before collision?

The principle of conservation of momentum states that:

momentum before collision = momentum after collisionMomentum = mass * velocity

Momentum before collision:

Velocity of 50.0 kg object = v m/s

Momentum of 50.0 kg object = 50 * v

Momentum after collision:

Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E

Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.

Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s

Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s

Total momentum after collision = 678 kgm/s

From the principle of conservation of momentum:

50 kg * v = 678 kgm/s

v = 678 kgm/s / 50 kg

velocity, v = 13.56 m/s

Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.

Learn more about conservation of momentum at: https://brainly.com/question/7538238


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Answer:

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Answers

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Answer:

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Answers

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Answers

Answer:

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r = 0.5

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Answers

Answer:

We know that the length is 79 (there are no units of length in the question, so i will leave it as it is written, without units) when the temperature is 2°C.

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Answers

Answer:

i. 2.5 kHz ii. 5 kHz

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= v/2L

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= 2500 /s

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Answers

Answer:

C

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The correct answer should be the micrometer.

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Answers

Answer:

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Explanation:

Force= mass × acceleration

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make m subject of the formula...

m=50/8

m=6.25kg

Answer:

[tex]\boxed {\boxed {\sf 6.25 \ kilograms}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= m \times a[/tex]

We know the force is 50 Newtons and the acceleration is 8 meters per second squared. Let's convert the units to make the problem and unit cancellation easier.

1 Newton is equal to 1 kilogram meter per square second (1 kg*m/s²), so the force of 50 N is equal to 50 kg*m/s².

Now we know 2 values:

F= 50 kg*m/s²a= 8 m/s²

Substitute the values into the formula.

[tex]50 \ kg *m/s^2= m \times 8 \ m/s^2[/tex]

Since we are solving for the mass, we must isolate the variable, m. It is being multiplied by 8 meters per square second and the inverse of multiplication is division. Divide both sides by 8 m/s².

[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= \frac{m \times 8 \ m/s^2}{8 \ m/s^2}[/tex]

[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= m[/tex]

The units of meters per square second (m/s²) cancel.

[tex]\frac {50 \ kg }{8 }=m[/tex]

[tex]6.25 \ kg =m[/tex]

The mass is 6.25 kilograms.

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