A 8 kg body moves towards the west with a momentum of 30 kg m s¹. A 20 N force to the east acts on the body for a period of 15 s. Determine the magnitude of i) the impulse of the force. ii) the change in the momentum of a body. iii) the final momentum of the body. iv) the final velocity of the body, [5 marks]​

Answers

Answer 1

Mass of body = 8kg

Momentum of body = [tex]30kgms^{-1}[/tex]

Force = 20N

Time for which force acts = 5s

Impulse of the force = Force × time for which force acts

= 20 × 5= 100Ns

Change of momentum = Impulse of the force= 100Ns

Therefore, the impulse of the force= 100Ns

Change of momentum is 100Ns

The final momentum of the body = 100Ns
The final velocity of the body is 5m/s

What is momentum?

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction.

According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

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Related Questions

Explain the difference between Pavlov's classical Conditioning, and Skinner's Operant
Conditioning, give examples to illustrate how behavior can be learned according to each
one of those conditioning. Explain the example after explaining the process.

Answers

Skinner's Operant Conditioning focus stressed that the  consequences of a behavior will indicate if there is  possibility of it being repeated and also  the human behavior  can be attributed to something in a person's environment.

Pavlov's classical Conditioning stressed that two stimuli can be linked  together  so that there can be new learned response in indivisuals .

Example of Pavlov's classical Conditioning  is that a dogs could be conditioned to salivate at the sound of a bell if it was programmed to ring at the time of food.

Example of Skinner's Operant Conditioning is that of negative reinforcement which was demonstrated by placing a rat in  Skinner box  which then subjected to unpleasant electric current  and make it to experience some discomfort.

What is Classical conditioning?

Classical conditioning can as well be described as the Pavlovian or respondent conditioning which is the learning that do take place when two stimuli are linked together  and they can bring about new learned response in a person or animal.

Operant conditioning  was the one that stressed that the cause of human behavior  can be linked to the something in a person's environment.

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which best explains the law of conservation of mass

Answers

The law of conservation of mass emphasizes the fact that it is not possible to create or destroy the mass in this universe. Mass just changes its form from one to another, it is never created nor destroyed.

The statement mentioned above states that the mass of reactants and products have equal mass irrespective of the physical state.

If the mass of reactants and products becomes unequal, then it would contradict the law of conservation. However, it is clearly mentioned that the mass of reactants and products will remain the same, hence complimenting the law of conservation of motion.

Therefore, the law of conservation of mass is best described by - The mass of the reactants and products is equal and this mass is not dependent on the physical state of the substances.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Which best describes the law of conservation of mass?

(A) The coefficients in front of the chemicals in the reactants should be based on the physical state of the products.

(B) Products in the form of gases are not considered a part of the total mass change from reactants to products.

(C) When reactants contain both a solid and a liquid, the solid counts toward the overall mass and the liquid does not.

(D) The mass of the reactants and products is equal and is not dependent on the physical state of the substances.]

A coin is tossed vertically upward and reaches a maximum height of 0.90 m before it comesback down. With what velocity was it thrown, and how long was it in the air?
with explanation please

Answers

Answer:

how long the coin was in the air was about 45 how I got your answer was by dividing 900 by 20 bc when u divide u have to add a 0 so that's how I got 900 then I just divided and got 45

Questions 14-16
The following diagrams each show an object of mass m moving with instantaneous velocity v. in
each case, F is the applied force, and f is the frictional force exerted on the object. In case I, the
object moves in a circle with constant speed.
(A) None
(B) I only
(C) II only
(D) III only
(E) I, II, and III
14. In which of these cases are velocity and the acceleration in the same direction at the
instant shown?
15. In which of these cases are the velocity and acceleration in opposite directions at the
instant shown?
16. In which of these cases are the velocity and the net force perpendicular to each other at
the instant shown?

Answers

14. None of these cases are velocity and the acceleration in the same direction at the instant.

15. I, II, and III of these cases are the velocity and acceleration in opposite directions at the instant

16. case I of these cases are the velocity and the net force perpendicular to each other at the instant.

When is acceleration and velocity in same direction?

If the velocity and acceleration are in the same direction (both have the same sign and both positive or negative), the object is accelerating. If the velocity and acceleration are opposite (with opposite signs), the object is slowing down.

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Microwave ovens operte at 2.45 GHz, Bluetooth electronics and internet routers work at2.4 GHz.Predict which object has the longer wavelength, showing your calculations evidence, to support your prediction .

Answers

Answer:

The object with the longer wavelength is the microwave oven. This can be determined using the equation λ = c/f, where λ is the wavelength, c is the speed of light (3 x 10^8 m/s), and f is the frequency.

For a microwave oven:

λ = (3 x 10^8 m/s) / (2.45 GHz)

λ = 1.22 x 10^-2 m

For a Bluetooth electronic/internet router:

λ = (3 x 10^8 m/s) / (2.4 GHz)

λ = 1.25 x 10^-2 m

Therefore, the microwave oven has a longer wavelength.

Explanation:

is lithium batteries a limited quantity item

Answers

Lithium and lithium-ion batteries are transported in both large and small volumes.

For instance, a single box could contain as little as five batteries, whereas a pallet could hold over 1,000, or the batteries could be enclosed in or packed with equipment.

On the other hand, lithium batteries, which contain lithium metal, cannot be recharged. Lithium-ion batteries can be recharged but do not contain lithium metal.

Lithium and lithium-ion batteries are mostly utilized in consumer applications and are exempt from dangerous goods/hazardous materials rules. Small lithium batteries are often used in timepieces and cameras. Lithium-ion batteries are extensively used in laptops and cell phones.

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1000 cm³ of air at 20 °C and 101.35 kPa is heated at constant pressure until its volume doubles. a) Use the ideal gas equation to calculate the final temperature of the gas.​

Answers

From Charles's law, the magnitude of the final temperature is 586 K

What is an Ideal Gas ?

An Ideal gas is a gas which obeys ideal gas equation at all pressures, volumes and temperatures. The ideal gas equation can be express as

PV = nRT

Where

P = pressureV = volumen = number of moleR = universal molar gas constantT = Temperature

Given that 1000 cm³ of air at 20 °C and 101.35 kPa is heated at constant pressure until its volume doubles.

From the ideal gas equation,

P1 = P2 = 101.35 kPaV1 = 1000 cm³V2 = 2000 cm³T1 = 20 + 273 = 293 KT2 = ?

To calculate the final temperature of the gas, we will use the formula below

V1/T1 = V2/T2

Since Pressure is constant

Substitute the necessary parameters into the formula

1000/293 = 2000/T2

Cross multiply

1000T2 = 586,000

T2 = 586,000/1000

T2 = 586 K

Therefore, the final temperature of the gas is 586 K

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Obtain an expression for the viscous force acting on a sphere of radius r moving in a viscous fluid with velocity v, if the viscosity coefficient is η. ​

Answers

The force of viscosity is F = k r v η. Spherical balls of radius R are falling in a viscous fluid of viscosity η with a velocity v.

What is viscous force?

Viscosity refers to a material's capacity to resist movement between its layers. It is the force that resists relative motion between the layers. It is also known as viscous force.

What is viscous force formula?

In the above equation, the shear force is the viscous force, which is the only internal resistance that causes shear stress to develop along with the fluid layers. As a result, the viscous force formula will be given as. F=Aμdudy.

Hence  F = k r v η is a correct answer.

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A mass on the end of a length of rope is being swung in a circle of radius 3.2 m at an angular velocity of 0.71 rad/s. How fast is it moving?​

Answers

Answer:

[tex]\huge\boxed{\sf v = 2.27\ m/s}[/tex]

Explanation:

Given data:

Angular velocity = ω = 0.71 rad/s

Radius = r = 3.2 m

Required:

Linear velocity = v = ?

Formula:

v = rω

Solution:

v = (3.2)(0.71)

v = 2.27 m/s

[tex]\rule[225]{225}{2}[/tex]

A 4,155 kg car moving at 28.3 m/s hits a stationary truck with a mass of 3,172 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?

Answers

Answer:

Approximately [tex]16.0\; {\rm m\cdot s^{-1}}[/tex].

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object will be [tex]p = m\, v[/tex].

In this example, the momentum of the car before the collision will be:

[tex]\begin{aligned}p &= m\, v \\ &= (4155\; {\rm kg})\, (28.3\; {\rm m\cdot s^{-1}}) \\ &\approx 1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}} \end{aligned}[/tex].

Since the truck was initially not moving, the initial momentum of the truck will be [tex](3172\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex].

Momentum is conserved in collisions. In other words, the sum of the momentum of the truck and the car will be the same right before and after the collision.

The sum of the momentum of the truck and the car was approximately [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}[/tex] right before the collision. By the conservation of momentum, the sum of the momentum of the two vehicles right after the collision will also be [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}\![/tex].

The velocity of the two vehicles right after the collision will be the same since the vehicles are stuck together. Let [tex]v[/tex] denote this velocity.

The sum of the mass of the two vehicles is [tex]m = (4155\; {\rm kg}) + (3172\; {\rm kg}) = 7327\; {\rm kg}[/tex]. Divide the total momentum of the two vehicles by their total mass to find the velocity:

[tex]\begin{aligned}v &= \frac{p}{m} \\ &\approx \frac{1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}}{7327\; {\rm kg}} \\ &\approx 16.0\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

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