Answer:
The appropriate solution is Option D (22 m/sec).
Step-by-step explanation:
The given equation is:
[tex]s(t)= -(t-15)^2 + 225[/tex]
Now,
The instantaneous velocity at t = 4 will be:
= [tex][-2(t-15)(1)+0][/tex]
= [tex]-2(4-15)[/tex]
= [tex]-2\times (-11)[/tex]
= [tex]22 \ m/sec[/tex]
Thus, the above is the correct option.
What is the 5th term in the geometric sequence described by this explicit
formula?
an = 30 • (-2)(n-1)
Answer:
-240
Step-by-step explanation:
n = 5
a₅ = 30* (-2)(5 - 1)
= 30 * (-2)*4
= 30 * (-8)
= - 240
Alexia veut préparer un cocktail original
Answer:
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Which lists all the factors of 78?
A. 1, 2, 3, 6, 13, 26, 39, 78
B. 1, 2, 4, 19, 39, 78
C. 1, 2, 6, 13, 39, 78
D. 2, 3, 6, 13, 26, 39
Answer:
1, 2, 3, 6, 13, 26, 39, 78
Answer:
Factors of 78: 1, 2, 3, 6, 13, 26, 39, and 78.
Step-by-step explanation:
I hope this helps!!!!!
Determine the radius of a cone that has a volume of 155.521 cubic inches and a height of 9 inches.
Answer:The answer is 4.06
Step-by-step explanation:
Okay I am 98% sure my math could be wrong since I don’t know what the possible answers to the question are but this is what I got.
Find the volume of the cubes or rectangular prisms in cubic centimeters.
SS
8
125 cm
126cm
ਹੈ।
135cm
rectangular prism with a length,
width and height of 5 cm. 5 cm.
and 5 cm, respectively
cube with a side length of 5 cm
of a
cube with a side length of 5 cm
rectangular prism with a length,
width and height of 5 cm 5 cm.
and 5 cm, respectively
Answer:
ans : it is order wise
a) 6/125 cm³
b) 8/125 cm³
c) 1/125 cm³
d) 36/125 cm³
Step-by-step explanation:
a)
for rectangular prism = length × width × height
= (1/5) × (2/5) × (3/5)
= 6/125 cm³
b)
for cube = length³
= (2/5)³
= 8/125 cm³
c)
for cube = (1/5)³
= 1/125 cm³
d)
for rectangular prism = (3/5) × (4/5) × (3/5)
= 36/125 cm³
TEST I - Reading and Writing Numbers. (15 points) (15 minutes)
A. Read these numbers. (1 point per item=5 points) (5 minutes)
1.) 3/4
2.) P 12 131 267. 25
3.) 75%
4.) 1256
5.) 12:26
Answer:
Step-by-step explanation:
1)
Three-Fourth
2)
Twelve Million One Hundred Thirty One Thousand Two Hundred Sixty Seven and Twenty Five Hundredths
3)
Seventy Five Percentage
4)
One Thousand Two Hundred and Fifty Six
5)
Twelve is to Twenty Six
Jim records the number of cars his team sells
each month for a year. What percent of the
months does his team sell more than 6 cars?
Quick pld
Answer:
50%
Step-by-step explanation:
There are 12 months in a year.In the problem there are six months the number of cars his team sells more than 40%.=6/12x100%=0.5x100%=50%.Therefore his team sold 50%.
Hope this helped!
3) A bag contains 5 yellow marbles, 2 blue marbles, 3 red
marbles. What is the probability you pull out a yelow marble?
Fraction:
Decimal:
Percent:
Answer:
fraction- 1/2
decimal- .5
percent 50%
Step-by-step explanation:
The manager of the dairy section of a large supermarket chose a random sample of 250 egg cartons and found that 30 cartons had at least one broken egg. let p denote the proportion of all cartons which have at least one broken egg. Find a point estimate for p and also construct a 90% confidence interval for p.
Answer:
The point estimate for p is of 0.12.
The 90% confidence interval for p is 0.0862 < p < 0.1538.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The manager of the dairy section of a large supermarket chose a random sample of 250 egg cartons and found that 30 cartons had at least one broken egg.
This means that [tex]n = 250, \pi = \frac{30}{250} = 0.12[/tex]
The point estimate for p is of 0.12.
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.12 - 1.645\sqrt{\frac{0.12*0.88}{250}} = 0.0862[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.12 + 1.645\sqrt{\frac{0.12*0.88}{250}} = 0.1538[/tex]
The 90% confidence interval for p is 0.0862 < p < 0.1538.
SOMEONE HELP ME PLEASE
Answer:
x=8
Step-by-step explanation:
the y-value in the first pair decreased by half, so the x-value must double due to inverse variation.
What would be the correct answer for this?
First let's understand the discriminant. Discriminant is an equation of D = b²-4ac. Discriminant is to find how many solutions do the equation have. In case for Quadratic Equation, there are 3 types of solutions which are:
No solutions or D < 0 — When D < 0, the equation does not have real roots.One solution or D = 0 — When D = 0, the equation has one real root. Two solutions or D > 0 — When D > 0, the equation has two real roots.To find discriminant graphically, we need to know that the x-axis plane represents the solutions to the equations. All equations can be drawn as a graph. Some graphs do not intersect x-axis while some graph do.
If a graph intersects x-axis, the equation for that graph has solutions. If a graph doesn't intersect x-axis, the equation doesn't have any real solutions.You may also notice that some graphs intersect x-axis more than one point. Like I said that the x-axis represents the roots or the solutions. Intersecting x-axis "n" times means that the equation has "n" roots.
For example, if a graph intersects x-axis 8 points - the equation has 8 roots or solutions.
From the graph, the parabola intersects on x-axis just only one point. That means there is only one solution. The question asks to find the discriminant of the function. Recall that if D = 0, there's only one real root. Therefore the discriminant for the function is zero.
Answer
The discriminant for function is zero.Let me know if you have any doubts!
Initially 100 milligrams of a radioactive substance was present. After 8 hours the mass had decreased by 2%. If the rate of decay is proportional to the amount of the substance present at time t, determine the half-life of the radioactive substance. (Round your answer to one decimal place.)
For initial 100 milligrams of a radioactive substance was if decreased by 2% in 8 hours, then half-life of the radioactive substance is 108.3 hours.
Rate of change is the change in one variable due to change in other.
Given the following:
Amount of a radioactive substance initially present=100mg
After 8 hours, mass decreased by 2%
Mass after 8 hours= 100-(2% of 100)
=100-(2*100/100)
=100-2
=98
The rate of decay is proportional to the amount of the substance present at time t.
Mathematically,
Let the amount of radioactive substance is A and at time t,
[tex]\dfrac d{dt}A\ \alpha\ A\\\\[/tex]
[tex]\dfrac d{dt}A= kA\\\\\\dA=kAdt[/tex]
On integrating both sides,
[tex]\int \frac {1}{kA}dA=\int dt\\\\[/tex]
[tex]\dfrac {ln A}{k}=t +ln \ c_1\\ln A =kt+k\ ln \ c_1\\[/tex]
On taking antilogarithm both sides,
[tex]e^{ln A} =e^{kt+k\ ln \ c_1\\A=e^{kt}e^{k\ ln \ c_1}\\A=e^{kt}e^{\ ln \ c_1^k}\\A=e^{kt}c_1^k \\[/tex]
Let, [tex]c_1^k=c[/tex]
[tex]A =e^{kt}c[/tex].................................1
At t=0, A=100
Substituting values in 1
[tex]100= e^0c\\c=100[/tex]
At t= 8, A=98
[tex]98=e^{k8}100\\0.98=e^{8k}\\8k=ln0.98[/tex]
k=-0.0064.
To determine the half time of the decay.
At half time A became A/2=50 mg
Substituting in 1.
[tex]50=e^{-0.0064t}100\\ln 0.5=-0.0064t\\t=\frac{ln 0.5}{-0.0064}\\t=108.3042\\t=108.3[/tex]....................................rounded to one decimal place.
Thus, The half-life of the radioactive substance is 108.3 hr.
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Which algebraic expression is equivalent to the expression below? 2(3 + 5x) + 24 A. 10x - 30 B. 10x + 18 C. 5x + 30 D. 10x + 30
Answer:
10x +30
Step-by-step explanation:
2(3 + 5x) + 24
Distribute
2*3 + 2*5x+24
6+10x+24
Combine like terms
10x +30
Please help . Stuck
Answer:
[tex] - \frac{9}{2} [/tex]
Step-by-step explanation:
Rate of change of y with respect to x
[tex] = \frac{60 - 96}{ - 12 - ( - 20)} \\ \\ = \frac{ - 36}{ - 12 + 20} \\ \\ = \frac{ - 36}{ 8} \\ \\ = - \frac{9}{2} [/tex]
Que número es menor que 2 1/2?
a-6/3
b-7/2
c-3
d-4
Multiply.
3,672 × 4
Enter your answer
Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (2), 3rd base (3), shortstop (S), left field (L), center field (C), and right field (R). a. Construct frequency and percent frequency distributions to summarize the data. Position Frequency Percent Frequency (to one decimal) Pitcher % Catcher % 1st base % 2nd base % 3rd base % Shortstop % Left field % Center field % Right field % b. What position provides the most Hall of Famers
Answer:
a. See below for the Frequency and Relative frequency Table.
b. Pitcher (P) is the position provides the most Hall of Famers.
c. 3rd base (3) is the position that provides the fewest Hall of Famers.
d. R is the outfield position that provides the most Hall of Famers.
e. Th number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.
Step-by-step explanation:
Note: This question not complete. The complete question is therefore provided before answering the question as follows:
Data for a sample of 55 members of the Baseball Hall of Fame in Cooperstown, New York, are shown here. Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (2), 3rd base (3), shortstop (S), left field (L), center field (C), and right field (R).
L P C H 2 P R 1 S S 1 L P R P
P P P R C S L R P C C P P R P
2 3 P H L P 1 C P P P S 1 L R
R 1 2 H S 3 H 2 L P
a. Use frequency and relative frequency distributions to summarize the data.
b. What position provides the most Hall of Famers?
c. What position provides the fewest Hall of Famers?
d. What outfield position (L, C, or R) provides the most Hall of Famers?
e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).
The explanation of the answers is now provided as follows:
a. Use frequency and relative frequency distributions to summarize the data.
The frequency is the number of times a position occurs in the sample, while the relative frequency is calculated as the frequency of each position divided by the sample size multiplied by 100.
Therefore, we have:
Frequency and Relative frequency Table
Position Frequency Relative frequency (%)
P 17 30.91%
H 4 7.27%
1 5 9.09%
2 4 7.27%
3 2 3.64%
S 5 9.09%
L 6 10.91%
C 5 9.09%
R 7 12.73%
Total 55 100%
b. What position provides the most Hall of Famers?
As it can be seen from the frequency table in part a, Pitcher (P) has the highest frequency which is 17. Therefore, Pitcher (P) is the position provides the most Hall of Famers.
c. What position provides the fewest Hall of Famers?
As it can be seen from the frequency table in part a, 3rd base (3) has the lowest frequency which is 2. Therefore, 3rd base (3) is the position that provides the fewest Hall of Famers.
d. What outfield position (L, C, or R) provides the most Hall of Famers?
As it can be seen from the frequency table in part a, we have:
Frequency of L = 6
Frequency of C = 5
Frequency of R = 7
Since R has the highest frequency which is 7 among the outfield position (L, C, or R), it implies that R is the outfield position that provides the most Hall of Famers.
e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).
Total frequency of infielders = Frequency of 1 + Frequency of 2 + Frequency of 3 + Frequency of S = 5 + 4 + 2 + 5 = 16
Total frequency of outfielders = Frequency of L + Frequency of C + Frequency of R = 6 + 5 + 7 = 18
The calculated total frequencies above imply that number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.
what is the circumference of circle with a diameter of 9 feet? Use 3.14 for tt
Answer:
28.26
Step-by-step explanation:
The formula for calculating diameter is πd (pi times the diameter), so 3.14 times 9 is 28.26.
linar system in variables
-x-3y-2z=8,
-x+y+6z=,
x-9y-2z=4
Answer:
-x+y+6z=? You did not spcify so I just made it 0
x = -22/5, y = -4/5, z = -3/5
Step-by-step explanation:
Solve the following system:
{-x - 3 y - 2 z = 8 | (equation 1)
-x + y + 6 z = 0 | (equation 2)
x - 9 y - 2 z = 4 | (equation 3)
Subtract equation 1 from equation 2:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x+4 y + 8 z = -8 | (equation 2)
x - 9 y - 2 z = 4 | (equation 3)
Divide equation 2 by 4:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x+y + 2 z = -2 | (equation 2)
x - 9 y - 2 z = 4 | (equation 3)
Add equation 1 to equation 3:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x+y + 2 z = -2 | (equation 2)
0 x - 12 y - 4 z = 12 | (equation 3)
Divide equation 3 by 4:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x+y + 2 z = -2 | (equation 2)
0 x - 3 y - z = 3 | (equation 3)
Swap equation 2 with equation 3:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x - 3 y - z = 3 | (equation 2)
0 x+y + 2 z = -2 | (equation 3)
Add 1/3 × (equation 2) to equation 3:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x - 3 y - z = 3 | (equation 2)
0 x+0 y+(5 z)/3 = -1 | (equation 3)
Multiply equation 3 by 3:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x - 3 y - z = 3 | (equation 2)
0 x+0 y+5 z = -3 | (equation 3)
Divide equation 3 by 5:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x - 3 y - z = 3 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Add equation 3 to equation 2:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x - 3 y+0 z = 12/5 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Divide equation 2 by -3:
{-x - 3 y - 2 z = 8 | (equation 1)
0 x+y+0 z = -4/5 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Add 3 × (equation 2) to equation 1:
{-x + 0 y - 2 z = 28/5 | (equation 1)
0 x+y+0 z = -4/5 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Add 2 × (equation 3) to equation 1:
{-x+0 y+0 z = 22/5 | (equation 1)
0 x+y+0 z = -4/5 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Multiply equation 1 by -1:
{x+0 y+0 z = -22/5 | (equation 1)
0 x+y+0 z = -4/5 | (equation 2)
0 x+0 y+z = -3/5 | (equation 3)
Collect results:
Answer: {x = -22/5, y = -4/5, z = -3/5
Mike works h hours in a week. To find his weekly pay he multiplies his hours by his pay of $24 per
hour and adds $6 for his sales bonus. He's decided that he wanted to take one-sixth of his weekly
pay and place it in his savings. Which simplified expression represents the amount that will go into
his savings each week?
Step-by-step explanation:
let n be the number of working hour
so total income is 24n + 6
now 1/6 of the income will be into saving
so the saving is (24n + 6) /6
The expression representing the amount that will go into his savings each week is $4h + $1.
What is Expression?An expression is combination of variables, numbers and operators.
Mike's weekly pay is given by:
Pay = (hourly rate) x (hours worked) + sales bonus
Pay = $24h + $6
To find one-sixth of his weekly pay, we can multiply his pay by 1/6:
Savings = (1/6) x Pay
Savings = (1/6) x ($24h + $6)
Savings = $4h + $1
Therefore, the simplified expression representing the amount that will go into his savings each week is $4h + $1.
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The following stem-and-leaf plot represents the times in minutes required for 26 co-workers to commute to work. Use the data provided to find the quartiles. Commute Times in Minutes Stem Leaves 2 1 3 5 5 5 8 3 1 5 6 7 8 9 4 2 3 4 6 6 6 8 5 2 2 4 5 7 7 8 Key: 2|1
Answer:
Q1 = 30.25 minutes
Q2 = 42.5 minutes
Q3 = 40 minutes
Step-by-step explanation:
Given, In Question
The stem and leaf diagram (key 2 I 1)Stem | Leaves
2 | 1 3 5 5 5 8
3 | 1 5 6 7 8 9
4 | 2 3 4 6 6 6 8
5 | 2 2 4 5 7 7 8
We need to find the quartiles Q1, Q2 and Q3. We know that,Q1 = (1/4)*(n+1)th value
Q2 = (1/2)*(n+1)th value
Q3 = (3/4)*(n+1)th value
where n is the total number of co-workers 26.
So, Q1 = (1/4)*(26+1)th valueQ1 = 6.75th value
we need to count the leaves in the plot starting from the first one until we reach the 6.75th value. So, by counting, we conclude that the 6.75th value lies between the 6th and 7th value i.e. 28 and 31.
Q1 = 28 + (31-28)*0.75
= 28 + 2.25
Q1 = 30.25 minutes
Now, Q2 = (1/2) * (26+1)th value
= 13.5th value.
From the plot, we find that the 13.5th value lies in the middle of the 13th and 14th values i.e. 42 and 43. So,
Q2 = (42+43)/2
= 85/2
Q2 = 42.5 minutes
And, Q3 = (3/4)*(26+1)th value
= 20.25th value
From the plot. we find that the 20.25th value lies somewhere between the 20th and 21st value i.e. 52 and 52. So,
Q3 = 40 + (52-52)*0.25
= 40 + 0
Q3 = 40 minutes
I need to calculate the surface area and volume of this figure.
but am not pretty sure
the volume of cone is =1/3 pie r² h
I think this is the formula to calculate it
solving equation using the completing the square (a).3p(p+4)=p(p+2)
Answer:
P = 0, -5
Step-by-step explanation:
Answer:
p = 0
p = - 5
Step-by-step explanation:
3p(p + 4) = p(p + 2)
3p² + 12p - (p² + 2p) = 0
3p² + 12p - p² - 2p = 0
3p² + 10p - p² = 0
2p² + 10p = 0
2p(p + 5) = 0
p = 0
p + 5 = 0
p + 5 - 5 = 0 - 5
p = - 5
Amanda is reading a book that has 125 pages. She has read 12 pages a day for 4 days in a row.
How many more pages does Amanda have left to read?
7,35,175, 875,... find the 10th term
Please assist, I'm really bad with word problems
Answer:
The surface area of the balloon is [tex]S(t) = \frac{100}{49} \pi t^8[/tex]
Step-by-step explanation:
Given;
S(r) = 4πr²
where;
S is the surface area of the balloon
r is the radius of the surface
The radius of the balloon at time "t" is given as;
[tex]r(t)= \frac{5}{7} t^4 \ \ \ t\geq 0[/tex]
The surface area of the balloon as a function of time "t" is calculated as;
[tex]S(t) = 4\pi (\frac{5}{7} t^4)^2\\\\S(t) = 4\pi (\frac{25}{49} t^8)\\\\S(t) = \frac{100}{49} \pi t^8[/tex]
Select the correct answer. Which graph represents the solution to the inequality?
Answer:
A
Step-by-step explanation:
First you simplify both sides to get -2.4x+14.4 > 52.8
then you need to subtract the 14.4 from both sides giving -2.4x> 38.4
then divide both sides by -2.4 giving an answer of
x is less than or equal to -16 meaning you point to the left with a closed circle
Simplify Simplify 1 ∙ x - x/1
A. x
B. 1
C. 0
Answer:
0
Step-by-step explanation:
when the term has a coefficient of, it does not have to be written.
x- X/1
The sum of two opposites equals o
So the solution would be o
what is the measure of <B, in degrees.
Answer:
32
Step-by-step explanation:
The base angles of the triangle are the same since the sides are the same
<C = 74
A+B+C = 180 since the sum of the angles of a triangle = 180
74+B+74=180
Combine like terms
148+B =180
B = 180-148
B = 32
Answer:
[tex]\text{A. }32^{\circ}[/tex]
Step-by-step explanation:
From the Isosceles Base Theorem, the two base angles of a isosceles triangle are equal. Therefore, [tex]\angle A=\angle C=74^{\circ}[/tex].
Since the sum of the interior angles of a triangle is always equal to 180 degrees, we can write the following equation:
[tex]\angle A+\angle B+\angle C=180[/tex]
Substitute [tex]\angle A=\angle C=74^{\circ}[/tex] into this equation to solve for [tex]\angle B[/tex]:
[tex]74+\angle B+74=180,\\\angle B=180-74-74=\boxed{32^{\circ}}[/tex]
Find the solutions to 6x2 - 54x = 0
Answer:
14+28
Step-by-step explanation:
Answer:
6x^{2}-54x=0
6x2−54x=0
Step-by-step explanation:
