Answer:
B. 29.75 meters
Explanation:
Distance = speed x time
Distance = 3.5 x 8.5
Distance = 29.75 m/s
A 4,155 kg car moving at 28.3 m/s hits a stationary truck with a mass of 3,172 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?
Answer:
Approximately [tex]16.0\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object will be [tex]p = m\, v[/tex].
In this example, the momentum of the car before the collision will be:
[tex]\begin{aligned}p &= m\, v \\ &= (4155\; {\rm kg})\, (28.3\; {\rm m\cdot s^{-1}}) \\ &\approx 1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}} \end{aligned}[/tex].
Since the truck was initially not moving, the initial momentum of the truck will be [tex](3172\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex].
Momentum is conserved in collisions. In other words, the sum of the momentum of the truck and the car will be the same right before and after the collision.
The sum of the momentum of the truck and the car was approximately [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}[/tex] right before the collision. By the conservation of momentum, the sum of the momentum of the two vehicles right after the collision will also be [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}\![/tex].
The velocity of the two vehicles right after the collision will be the same since the vehicles are stuck together. Let [tex]v[/tex] denote this velocity.
The sum of the mass of the two vehicles is [tex]m = (4155\; {\rm kg}) + (3172\; {\rm kg}) = 7327\; {\rm kg}[/tex]. Divide the total momentum of the two vehicles by their total mass to find the velocity:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &\approx \frac{1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}}{7327\; {\rm kg}} \\ &\approx 16.0\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
A 8 kg body moves towards the west with a momentum of 30 kg m s¹. A 20 N force to the east acts on the body for a period of 15 s. Determine the magnitude of i) the impulse of the force. ii) the change in the momentum of a body. iii) the final momentum of the body. iv) the final velocity of the body, [5 marks]
Mass of body = 8kg
Momentum of body = [tex]30kgms^{-1}[/tex]
Force = 20N
Time for which force acts = 5s
Impulse of the force = Force × time for which force acts
= 20 × 5= 100Ns
Change of momentum = Impulse of the force= 100Ns
Therefore, the impulse of the force= 100Ns
Change of momentum is 100Ns
The final momentum of the body = 100Ns
The final velocity of the body is 5m/s
What is momentum?
Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction.
According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
To know more about momentum, click the link given below:
https://brainly.com/question/16076524
#SPJ9
