A buffer solution is prepared by adding 13.74 g of sodium acetate (NaC2H3O2) and 15.36 g of acetic acid to enough water to make 500 mL (three significant figures) of solution. Calculate the pH of this buffer.

Answer:

See explanation and image attached

Explanation:

Alkenes undergo hydrogenation to give the corresponding alkanes. Where the structure of the original alkene is unknown, we can deduce the structure of the alkene from the structure of the products obtained when it undergoes various chemical reactions.

Now, the fact that we obtained 2-methylhexane upon hydrogenation and the two compounds had different heats of hydrogenation means that the two compounds were geometric isomers. The original compounds must have been cis-2-methyl-3-hexene and trans-2-methyl-3-hexene.

When reacted with HCl, the same compound C7H15Cl is formed because the stereo chemistry is removed.

However, we know that the trans isomer is more stable than the cis isomer hence the cis isomer always has a higher heat of hydrogenation than the trans isomer. Thus X is cis-2-methyl-3-hexene.

Answer:

pH = 13.1

Basic

Explanation:

Step 1: Given data

Hydrogen ion concentration ([H⁺]): 6.7 × 10⁻¹⁴ M

Step 2: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺]

pH = -log 6.7 × 10⁻¹⁴ = 13.1

Since pH > 7, the solution is basic.

It was formed 15,000 to 20,000 years ago from andesite flows and was later intruded by a hornblende dacite dome. Since the end of the last ice age, Shastina cone was built by mostly pyroxene andesite lava flows.

Explanation:

Answer:

1st structure - Meso

2nd structure - Chiral

3rd structure - achiral

Explanation:

In the 1st structure there is nitrogen atom bonded with 4 different groups. It is Meso compound. In the second structure a carbon atom is attached with hydroxide molecule OH and has four different environment. It is Chiral compound. In the third structure no atom have different atom or group surrounding it. Therefore it is Achiral compound.

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M = 3.0 mol/L

V = 4 L

n

M = n / V

n = MV

n = (3.0 mol/L)(4 L)

n = 12 mol

Therefore, the number of moles of NaCl present is 12 mol.

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Answer 12 mol

Explanation: [tex]C_{M} = \frac{n}{V} ==> n = C_{M} *V=4*3=12 mol[/tex]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

[tex]M=\frac{1.29mol}{0.350L}\\\\M=3.69M[/tex]

Which gives molar units, M, or just mol/L.

Regards!

Answer:

it is released and absorbed:)

Answer:

a. Na₃PO₄

b. NH₄Cl

c. FeCl₃

d. KClO₃

Explanation:

a. Sodium tetraoxophosphate(V) Na₃PO₄

3Na⁺ + PO₄³⁻ → Na₃PO₄

b. Ammonium Chloride NH₄Cl

NH₄⁺ + Cl⁻ → NH₄Cl

c. Iron(III)chloride

Fe³⁺ + Cl⁻ → FeCl₃

d. Potassium trioxochlorate(V) KClO₃

K⁺ + ClO₃⁻ → KClO₃

Answer:

Chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.

Explanation:

The balanced equation of the chemical reaction is given below:

Cl2(g) + 2KBr(aq) → 2KCl(aq)+ Br2(l)

According to the above equation, it can be said that chlorine in its gaseous form (Cl2) reacts with pottasium bromide (reactants) to form pottasium chloride (KCl) and bromine, which is a liquid at room temperature.

Answer:

D: Chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.

Answer:

Cracking.

Explanation:

A chemical reaction can be defined as a reaction in which two or more atoms of a chemical element react to form a chemical compound. An example of a chemical reaction involving hydrocarbons is cracking.

Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only.

In Organic chemistry, cracking refers to the process of lowering the boiling point of a heavy, complex or long-chain hydrocarbon such as kerogens by exposing it to different environmental treatments such as hydrogen enriched catalysts, pressure or high temperatures, in order to produce smaller, lighter and more useful molecules (alkanes and alkenes) such as gasoline, diesel fuel, etc.

Answer:

You find a separatory funnel set up in a fume hood. There are clearly two visible layers. Describe a method you could use to determine which layer is the aqueous layer.

Explanation:

In the separating funnel, the liquid with less density exists at the top layer and the liquid with greater density will exist at the bottom layer.

To identify the aqueous layer, add a bit of water to the separating funnel.

Then, observe where the water will go and mix.

If it mixes with the bottom layer, then the bottom layer is the aqueous layer.

If water mixes with the top layer, then top layer is the aqueous layer.

A method we could use to determine which layer is the aqueous layer is by adding 2-4 drops of water in the separatory funnel.

Explanation:

So, from this, we can conclude that a method we could use to determine which layer is the aqueous layer is by adding 2-4 drops of water in the separatory funnel.

Learn more about separatory funnel here;

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Answer: D.) The volume of stock solution used was more than 5 liters

Explanation:

Answer:

b

Explanation:

i got it

Answer:

There isn't enough information to answer you're question.

Explanation:

Have a great day!!!

Explanation:

Do đó cấu hình electron của canxi là: 1s2 2s2 2p6 3s2 3p6 4s2.

Answer:

c. NO2

b. NH3

d. SO4 ^2 -

a. HPO4 ^ 2 -

Explanation:

Acid is a compound which ionizes to produce hydrogen ions. The Ph value for acid is below 7. Base is a compound which ionizes to produce hydroxide ions.  The Ph value for base is above 7. The Conjugate base accepts a proton or releases a hydrogen ion.

Answer:

[tex]M'=41.3g/mol[/tex]

Explanation:

From the question we are told that:

Time Through first barrier [tex]T_1=3.79min[/tex]

Time Through second barrier [tex]T_2=2.66min[/tex]

Generally the Grahams Law equation for   time of diffusion is mathematically given by

 [tex]T=K\sqrt{M}[/tex]

Where

M=Mass Number of Kr

 [tex]M=83.8[/tex]

Therefore

 [tex]{T}{\sqrt{M}={T}{\sqrt{M'}[/tex]

 [tex]{3.79}{\sqrt{83.8}={2.66}{\sqrt{M'}[/tex]

 [tex]M'=0.645[/tex]

 [tex]M'=41.3g/mol[/tex]

Answer: hello your question has some missing data attached below is the complete question.

answer:

attached below

Explanation:

Attached below is the mechanism for proton transfer

a) HBr

H₃O + Br⁻

b) attached below

c) attached below

Answer:

1 Mole = 84.007 g/mol

Explanation:

Sodium bicarbonate (IUPAC name: sodium hydrogen carbonate), commonly known as baking soda or bicarbonate of soda, is a chemical compound with the formula NaHCO3

Answer:

The correct answer is 0.020 M.

Explanation:

To solve this problem, we can use the equation M1V1 = M2V2, where M represents the molarity of the solution and V represents the volume of solution.  Since we are given that the original solution is 50 mL and 0.40 M, these values are V1 and M1, respectively.  The solution after dilution has a volume of 1000 mL, so this value is V2.  We are solving for the molarity after dilution, which represents M2.

If we plug in the values specified above, we get the following:

M1V1 = M2V2

(0.40 M)(50.0 mL) = (M2)(1000.0 mL)

Solving for M2, we get:

M2 = 0.020 M

Notice that our answer has 2 significant figures because 0.40 has 2 significant figures, the least of any values given in the problem.

Therefore, the answer is 0.020 M.

Hope this helps!

develop a theory. develop a hypothesis. support a hypothesis

Answer:

Acetic acid, carbonic acid and chlorous acid with calcium hydroxide

Ammonia with sulfuric acid

Explanation:

A buffer is an aqueous mixture of a weak acid and its conjugate base or vice versa.

Weak acids reacts with strong bases to produce the conjugate base. In the right amount, you can produce a buffer. In the same way, you can produce a buffer from the mixture of weak bases with strong acids.

In the problem, you have weak acids (acetic acid, carbonic acid, chlorous acid), one weak base (ammonia), one strong base (calcium hydroxide) and one strong acid (Sulfuric acid).

Thus, the mixtures that can produce a buffer are:

Acetic acid, carbonic acid and chlorous acid with calcium hydroxide

And:

Ammonia with sulfuric acid

Answer:

B porque si :) y eso Jsksjs

Answer:A

Because it's an amino acid and all amino acids are key to any part of your body.

Answer: The given chemical reaction can be classified as synthesis and exothermic.

Explanation:

A synthesis reaction is defined as the reaction where two small chemical species combine in their elemental state to form a single large chemical species.

Exothermic reactions are defined as the reactions in which heat is released by the reaction. The heat is written on the product side of the reaction.

For the given chemical reaction:

[tex]Mg(s)+O_2(g)\rightarrow MgO(s)+\text{heat}[/tex]

The above chemical reaction is a type of synthesis and exothermic as two substances in their elemental state are combining. Also, heat is getting released in the reaction.

Hence, the given chemical reaction can be classified as synthesis and exothermic.

Answer:

0.123 mol

Explanation:

Step 1: Convert 250 °C to Kelvin

We will use the following expression.

K = °C + 273

K = 250 + 273 = 523 K

Step 2: Calculate the number of moles of gas (n)

A gas occupies a container with volume (V) 3.2 L at a temperature (T) of 523 K and pressure (P) of 1.65 atm. We can calculate the number of moles of the gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.65 atm × 3.2 L / (0.0821 atm.L/mol.K) × 523 K = 0.123 mol

Answer:

See explanation

Explanation:

Number of moles of Copper sulphate = 0.18 M × 6.5/1000= 1.17 × 10^-3 moles of CuSO4

From;

number of moles = mass/molar mass

Molar mass of copper II sulphate = 160g/mol

1.17 × 10^-3 moles = mass/160g/mol

Mass = 1.17 × 10^-3 moles ×160

Mass = 0.187 g

If 1 mole contains 6.02 × 10^23 molecules

1.17 × 10^-3 moles contains 1.17 × 10^-3 moles × 6.02 × 10^23/1 = 7 × 10^20 molecules

From;

C1 V1=C2 V2

0.18 × 6.5 =C2 × 10.5

C2 = 0.18 × 6.5/10.5

C2=0.11 M

CuSO4(aq) + 2NaOH(aq) ----> Cu(OH)2(s) + Na2SO4(aq)

1 mole of CuSO4 yields 1 mole of Cu(OH)2

1.17 × 10^-3 moles of CuSO4 yields 1.17 × 10^-3 moles of Cu(OH)2

Mass of Cu(OH)2 = 1.17 × 10^-3 moles × 98g/mol= 0.11g of Cu(OH)2

Answer:

Diasteriomers

Stereoisomers

Stereoisomers

Meso compounds

Constitutional isomers

Enantiomers

Enantiomers

Explanation:

Isomers are compounds that posses the same molecular formula but different structural formulas.

Constitutional isomers differ only in atom to atom connectivity while stereoisomers differ in arrangement of atoms in space. Stereo isomers differ in physical and chemical properties of the compounds.

When stereo isomers are non-superimpossible mirror images of each other, they are called enantiomers. Enantiomers have the same chemical and physical properties and differ only in their reaction with chiral substances.

Achiral compounds are compounds that do not exhibit chirality. Some achiral compounds contain stereogenic centers and are called meso compounds.

Answer:

The order of sub-energy levels ( s » p » d » f )

The number of orbitals ( s » 2 ), ( p » 6), ( d» 10), ( f » 14 )