A can of soda is placed inside a cooler. As the soda cools, its temperature T(x) in degrees Celsius is given by the following exponential function, where is the number of minutes since the can was placed in the cooler.

T(x)=-22+44e^-0.03x

Find the initial temperature of the soda and its temperature after 18 minutes.

Answers

Answer 1

Answer:

Ans: -21.87 ≅ -22°C

Step-by-step explanation:

T(x)=-22+44e^-0.03x

 

Initial temperature (x = 0):

 

T(0) = = -22 + 44e-0.03(0) = -22 + 44(1) = 22°C

 

After 18 minutes (x = 18):

 

T(18) = -22 + 44e-0.03(18) = -21.87°C ≅ -22°C


Related Questions

01:15:51 Differential equation of the family of circles touching the y-axis at origin is

Answers

Step-by-step explanation:

Correct option is

B

x

2

−y

2

+2xy

dx

dy

=0

The system of circles touching Y axis at origin will have centres on X axis. Let (a,0) be the centre of a circle. Then the radius of the circle should be a units, since the circle should touch Y axis at origin.

Equation of a circle with centre at (a,0) and radius a

(x─a)²+(y─0)²=a²

That is,

x²+y²─2ax=0 ─────► (1)

The above equation represents the family of circles touching Y axis at origin. Here 'a' is an arbitrary constant.

In order to find the differential equation of system of circles touching Y axis at origin, eliminate the the arbitrary constant from equation(1)

Differentiating equation(1) with respect to x,

2x+2ydy/dx─2a=0

or

2a=2(x+ydy/dx)

Replacing '2a' of equation(1) with the above expression, you get

x²+y²─2(x+ydy/dx)(x)=0

That is,

─x²+y²─2xydy/dx=0

or

x²─y²+2xydy/dx=0



The diagram shows a wooden prism of height 5cm.
The cross section of the prism is a sector of a circle with sector angle 25º.
The radius of the sector is 15 cm.
Calculate the total surface area of the prism.

Answers

Answer:

280.8997

Step-by-step explanation:

cross section = 2*15*5+2*(25/360)*15*15*pi+5*(25/360)*2*pi*15

= 280.8997

Total surface area of prism is 280.890cm²

What is surface area?

A solid object's surface area is a measurement of the overall space that the object's surface takes up, and it is always expressed in square units.

The term "surface area" is sometimes used to refer to "total surface area".

Find the sector angle in radians

α = 25× (π/180)

α = (25π)/(180) rad

Find the area of the prism:

A = 2×15×5 + 15×15×α + 5×15×α

A = 150 + 15×15×(25π)/(180) + 5×15×(25π)/(180)

A = 280.890cm²

To know more about total surface area please visit:

https://brainly.in/question/15911106

#SPJ2

If we decrease a dimension on a figure, how is the figure’s area affected?
The area decreases.
The area increases.
The area becomes 0.
The area remains the same.

Answers

The area decreases :)

An oil company is going to issue new ID codes to its employees. Each code will have one letter, followed by one digit, followed by three letters. The letters w, x, y, and z will not be used. So, there are 22 letters and 10 digits that will be used. Assume that the letters can be repeated. How many employee ID codes can be generated?

Answers

Answer:

2342560 combos

Step-by-step explanation:

so its 1 letter*1number*1 letter*1 letter*1 letter, or 22x10x22x22x22 which should equate to 2342560 possible ID codes, hope this helps :)

A recipe calls for 4 cups of flour and 6 cups of sugar. How many cups of sugar per cup of flour does the recipe require?

Answers

Answer:

3 cups of sugar per 2 cups of flour

Step-by-step explanation:

just flip and simplify the fraction

4/6 = 6/4 = 3/2

Jenny has borrowed K2500from a bank at 9.25% p.a. invested for 185 days. How much will she pay back to the bank?​

Answers

Answer:

115.625

PRT/100

y = 95°, find the measure of x

Answers

9514 1404 393

Answer:

  x = 100°

  y = 95°

Step-by-step explanation:

It is probably easier to find y first. Opposite angles of an inscribed quadrilateral are supplementary, so ...

  y = 180° -85° = 95°

The measure of an arc is double the measure of the inscribed angle subtending it. The arc subtended by angle y is ...

  90° +x = 2y

  x = 190° -90° = 100°

_____

Additional comment

The rule cited above regarding opposite angles of an inscribed quadrilateral comes from the theorem regarding inscribed angles. In the given diagram, the diagonal from the bottom vertex to the top one is a chord that divides the circle into two arcs. Their sum is 360°. The inscribed angle theorem tells you ...

  2y +2(85°) = 360°

  y + 85° = 180° . . . . . . . divide by 2; opposite angles are supplementary

Hello! Please help thanks

Answers

Answer:

A. [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is [tex]\frac{opposite}{hypotenuse}[/tex]

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be [tex]\frac{PR}{PQ}[/tex]

Substituting the values of PR and PQ gives sin(Q) as [tex]\frac{5}{13}[/tex], which is A

Hope this helps!

How much more area does a large pizza with a 12 in. diameter have than a small pizza with an 8 in. diameter? Round your answer to the nearest square inch.

Answers

Answer: About 63 in²

Step-by-step explanation:

Area of circle = π · r²

r = radius lengthπ ≈ 3.14

Area of large pizza:

[tex]\pi *r^{2} =3.14*6^{2} =3.14*36=113.04[/tex]

Area of small pizza:

[tex]\pi *r^{2} =3.14*4^{2} =3.14*16=50.24[/tex]

Difference in area:

[tex]113.04-50.24=62.8[/tex]

y you work from 7 a.m. to 4 p.m. The state you live in requires that you take a 30-minute break during any shift longer than 6 hours. This break does not count towards your hours. How many hours did you work today? Remember 30 minutes is equal .5 hours​

Answers

Answer:

You’ve worked 7 hours and 30 minutes

Step-by-step explanation:

For the function G defined by G(x) = 5x + 3, find G(2)

Answers

G(x)=5x+3

[tex]\\ \sf\longmapsto G(2)[/tex]

[tex]\\ \sf\longmapsto 5(2)+3[/tex]

[tex]\\ \sf\longmapsto 10+3[/tex]

[tex]\\ \sf\longmapsto 13[/tex]

Option c is correct

13, replace x as 2 and then solve, 5(2)+3 which is 10+3 which equals 13.

20 POINTS! The answer is x=4 and x= -5, how should I word it, saying how he is wrong?

Answers

Answer:

The student took the numbers for the factors 5, -4 for the zeros  instead of solving the equation

The zeros are -5, 4

Step-by-step explanation:

x^2 +x - 20=0

What 2 number multiply to -20 and add to 1

5*-4 = -20

5+-4 = 1

(x+5)(x-4) =0

Using the zero product property

x+5 = 0  x-4 =0

x=-5  x=4

Answer:

Solution given:

equation is:

x²+x-20=0

doing middle term factorisation

note:we need to get 1 while subtracting factor of the product of constant and coefficient of x².

20*1=20=2*5*2*1

we get 1 while subtracting 5-2*2=5-4

now substitute value 5-4 at coefficient of x

we get

x²+(5-4)x-20=0

now

distribute

x²+5x-4x-20=0

taking common from each two term

x(x+5)-4(x+5)=0

again taking common (x+5) and keeping remaining at another bracket

(x+5)(x-4)=0

either

x+5=0

x=-5

or

x-4=0

x=4

Error is:

x= 4 not -4

x=-5 not 5.

A.Yes, since the slopes are the same and the y-intercepts are the same.
B.No, since the y-intercepts are different.
C.Yes, since the slopes are the same and the y-intercepts are different.
D.No, since the slopes are different.

Answers

Answer:

C

Step-by-step explanation:

one line is

y = 3x/7 + 11

its slope is 3/7

the y-intercept is, of course, when x=0. there y=11

the other is

-3x + 7y = 13

7y = 3x + 13

y = 3x/7 + 13/7

its slope is 3/7 (the same as the other line)

the y-intercept (x=0) is y = 13/7 (different to the other line)

Answer:

C. Yes, since the slopes are the same and the y-intercepts are different.

Step-by-step explanation:

[tex]y=\frac{3}{7} x+11[/tex]  and [tex]-3x+7y=13[/tex]

→ Rearrange the second equation to make y the subject

7y = 3x + 13

→ Divide everything by 7

[tex]y=\frac{3}{7} x+\frac{13}{7}[/tex]

A polynomial function has real coefficients, a leading coefficient of 1, and the zeros -6, 1, and 1. Write a polynomial function of least degree in standard form.​

Answers

Answer:

[tex]{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}[/tex]

Step-by-step explanation:

[tex](x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6[/tex]

A four digit password is a number that begins with a 3. If digits can be repeated how many possible passwords are there? show and explain your work

Answers

Answer:

The answer is 1,000

SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)

What is the derivative of (x + 1) sin x?

Answers

Answer:

By the Sum Rule, the derivative of 1−sin(x) 1 - sin ( x ) with respect to x x is ddx[1]+ddx[−sin(x)] d d x [ 1 ] + d d x [ - sin ( x ) ] .

find x on this special right triangle, 45 is not an option!!!!

Answers

let the line between 2 tria be y

sin 60/8√2 = sin 90/y

y=13.06

sin 45/13.06 = sin 90/x

x=18.46

Answer:

First, find the hypotenuse of the right triangle with the 60° & 30°.

Hypotenuse = hsin(x) = opposite side/hypotenuse

[tex]sin(60) = \frac{8\sqrt{2}}{h} \\\\sin(60)h=8\sqrt{2}\\\\\frac{\sqrt{3}}{2} h=8\sqrt{2}\\\\h=\frac{8\sqrt{2}}{\frac{\sqrt{3}}{2}}=8\sqrt{2}*\frac{2}{\sqrt{3}} =\frac{16\sqrt{2} }{\sqrt{3}} =\frac{16\sqrt{2}(\sqrt{3}) }{\sqrt{3}(\sqrt{3})} =\frac{16\sqrt{6} }{3}[/tex]

Use that side length to find x.

sin(x) = opposite side/hypotenuse

[tex]sin(45)=\frac{\frac{16\sqrt{6}}{3}}{x}\\\\sin(45)x=\frac{16\sqrt{6}}{3} \\\\\frac{\sqrt{2}}{2}x=\frac{16\sqrt{6}}{3} \\\\x=\frac{\frac{16\sqrt{6}}{3}}{\frac{\sqrt{2}}{2}}=\frac{16\sqrt{6}}{3}*\frac{2}{\sqrt{2}}=\frac{16\sqrt{2}\sqrt{3}(2)}{3\sqrt{2} }=\frac{32\sqrt{3} }{3}[/tex]

Operations and scientific notation math project need to know how to find the scientific notation

Answers

Answer:

how did not orderstan that

6) Frazer cycles the first 20 miles at an average speed of 21mph. The second
part is more uphill, and he only manages 13mph. By what percentage did his
speed decrease?
How to solve

Answers

9514 1404 393

Answer:

  38.1% decrease

Step-by-step explanation:

A percentage change is found from ...

  % change = (change)/(original amount) × 100%

  = (new value - original amount)/(original amount) × 100%

  = (13 -21)/21 × 100% = -8/21 × 100% ≈ -38.1%

Frazer's speed decreased by 38.1% during the second part.

_____

Additional comment

A negative % change represents a decrease; a positive % change represents an increase.

Which side of the pentagon on the right corresponds to
side KJ on the pentagon on the left.

Answers

Answer:

side st.

Step-by-step explanation:

st corresponds to kj since a it has five sides.

Write each percent as a fraction in simple form 15 3/5%

Answers

Answer:

39/250

Step-by-step explanation:

15 3/5 = 78/5 and percent means per 100, so

(78/5)/100 = (78/5)(1/100)

=78/500 = 39/250

Please
Help me asap!!

Answers

Answer:

z -2 = 10

Step-by-step explanation:

11z-9-10z+7 = 10

Combine like terms on the left side

11z -10z     -9+7  =10

z -2 = 10

Answer: z=12

Step-by-step explanation:

[tex]11z-9-10z+7=10\\z-9+7=10\\z-2=10\\z=12[/tex]

12 workers take 4 hours to complete a job. How long would it take 15 workers to complete the job?

Answers

Answer:

3.2 hours

Step-by-step explanation:

12 workers * 4 hours = 48 worker hours

15 workers  * x hours = 48 worker hours

48 /15 =3.2 hours

Answer:

3 hours and 12 minutes.

Step-by-step explanation:

12 Workers complete a job in 4 hours

1 worker complete a job 12 × 4 = 48

15 workers complete a job = 48/15 = 3³/¹⁵ = 3¹/⁵

= 3 hours + 1/5 × 60  minutes = 3 hours 12 minutes.

Simplify the following expression:

Answers

Step-by-step explanation:

[tex]{ \bf{( \frac{ - 10 {a}^{3} {b}^{5} \times 6 {a}^{6} {b}^{2} }{ {12a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{( \frac{ - 60 {a}^{9} {b}^{7} }{12 {a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{(5 {b}^{2}) {}^{3} }} \\ = { \sf{125 {b}^{5} }}[/tex]

Execute the following 18/3+2*8-5.

Answers

I got 17 as my answer

Aakash, Bao Ying, Chris and Donna all live on the same street as their school, which
runs from east to west.
• Aakash lives 5 blocks to the west.
• Bao Ying lives 4 blocks to the east.
• Chris lives 2: blocks to the west. .
• Donna lives 61 blocks to the east.
a. Draw a picture that represents the positions of their houses along the street.
b. Find how far is each house from every other house?
c. Represent the relative position of the houses on a number line, with the school at
zero, points to the west represented by negative numbers, and points to the east
represented by positive numbers.
d. How can you see the answers to part (b) on the number line? Using the numbers
(some of which are positive and some negative) that label the positions of houses on
the number line, represent these distances using sums or differences.
ko

Answers

The distance between each of the students' houses are:

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To solve this question, we represent each with the first letter of their names.

So, we have:

[tex]A= 5\ west[/tex] --- Aakash

[tex]B= 4\ east[/tex] ---- Bao Ying

[tex]C = 2\ west[/tex] --- Chris

[tex]D = 61\ east[/tex] ---- Donna

I've added the picture and the number line that represent the scenario as an attachment.

To calculate how far each lives from each other's, we start by representing west as negative and east as positive.

So, the representations become:

[tex]A = -5[/tex]

[tex]B = 4[/tex]

[tex]C = -2[/tex]

[tex]D = 61[/tex]

The absolute difference of each represents how far they live from one another.

Aakash & Bao Ying         Aakash & Chris                 Aakash & Donna

[tex]AB = |-5 -4| =9[/tex]          [tex]AC = |-5 --2| =3[/tex]         [tex]AD = |-5 -61| =66[/tex]

Bao Ying & Chris                 Bao Ying & Donna

[tex]BC = |4 --2| =6[/tex]                [tex]BD = |4 -61| =57[/tex]

Chris & Donna

[tex]CD = |-2 -61| =63[/tex]

This means that

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To carry out the above computations from the number line, we simply count the numbers from one to the other.

For instance:

There are 3 numbers from Akash to Chris.

This means that: Aakash & Chris live 3 blocks away from each other

Learn more about number line at:

https://brainly.com/question/13189025

k = 2; f(x) = 2x3 + 3x2 - 4x + 4; Lower bound? (1 point)

Answers

f(x) = 2 x 3 +3 x 2 - 4x + 4
0 = 6 + 6 - 4x + 4
0 = 16 - 4x
4x = 16
x = 4
(sorry if that’s not what you’re looking for)

A cement mixture costs $33 a ton. It is composed of Grade A cement at $36 a ton and Grade B cement at
$24 a ton. How were these two cements mixed?

Answers

If we used “a” tons of grade A and “b” tons of grade B we would get a + b tons of mixture.
Converting to costs we get 36a + 24b = 33(a + b)
36a + 24b = 33a + 33b
36a - 33a = 33b - 24b
3a = 9b
a = 3b
This means the mixture contains 3 times as much of grade A than grade B
The ratio of grade A : grade B = 3 : 1

For example if we mixed 3 tons of A with 1 ton of B we would get 4 tons of mixture
The cost would be 3 x 36 + 1 x 24 = 108 + 24 = $132 for 4 tons = $33 per ton

Slide 1.
1) The polygons below ore similor. Find the value of y.
8.
10

Answers

Answer:

y =6

Step-by-step explanation:

We can write a ratio to solve

3           y

----- = ----------

4            8

Using cross products

3*8 = 4y

24 = 4y

Divide by 4

24/4 = 4y/4

6 = y

Which equation results from isolating a radical term and squaring both sides of the equation for the equation
Vc-2-vc=5

Answers

Answer:

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Required

Isolate radical, then square both sides

We have:

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Isolate radical

[tex]\sqrt{c - 2} = 5 + \sqrt c[/tex]

Square both sides

[tex](\sqrt{c - 2})^2 = (5 + \sqrt c)^2[/tex]

[tex]c - 2 = 25 + 2 * 5 * \sqrt c + c[/tex]

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

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