A candle is 6 tall after burning for one hour. After 3 h, it is 5. 5 tall. Write a linear equation to model the hh () of the candle after burning () h.

Answer:

9uv⁴

Step-by-step explanation:

9uv⁴(2v-3v+6)

Answer:

Factor out 9uv^4 from the expression

9uv^4(2uv - 3v + 6)

If you need more steps just ask :)

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

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Os números em notação científica são os seguintes : -

1) 5,000,000,000,000 ⟹ [tex]\boxed{5 × 10^{12}}[/tex]

2) 0,000,007 ⟹ [tex]\boxed{7 × 10^{0}}[/tex]

3) 58,600,000,000,000 ⟹ [tex]\boxed{5.86 × 10^{13}}[/tex]

4) 0,000,005,874 ⟹ [tex]\boxed{5.874 × 10^{3}}[/tex]

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ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# [tex]\large\boxed{RainbowSalt2^{2}2^{2}}[/tex] ღ

Answer:

$127.75

Step-by-step explanation:

Multiply the cost by the area to find the total cost

Answer:

[tex]\bar x = 260.1615[/tex]

[tex]\sigma = 70.69[/tex]

The confidence interval of standard deviation is: [tex]53.76[/tex] to [tex]103.25[/tex]

Step-by-step explanation:

Given

[tex]n =20[/tex]

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}[/tex]

[tex]\bar x = \frac{5203.23}{20}[/tex]

[tex]\bar x = 260.1615[/tex]

[tex]\bar x = 260.16[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

[tex]\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}[/tex][tex]\sigma = \sqrt{\frac{94938.80}{19}}[/tex]

[tex]\sigma = \sqrt{4996.78}[/tex]

[tex]\sigma = 70.69[/tex] --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

[tex]c =0.95[/tex]

So:

[tex]\alpha = 1 -c[/tex]

[tex]\alpha = 1 -0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the degree of freedom (df)

[tex]df = n -1[/tex]

[tex]df = 20 -1[/tex]

[tex]df = 19[/tex]

Determine the critical value at row [tex]df = 19[/tex] and columns [tex]\frac{\alpha}{2}[/tex] and [tex]1 -\frac{\alpha}{2}[/tex]

So, we have:

[tex]X^2_{0.025} = 32.852[/tex] ---- at [tex]\frac{\alpha}{2}[/tex]

[tex]X^2_{0.975} = 8.907[/tex] --- at [tex]1 -\frac{\alpha}{2}[/tex]

So, the confidence interval of the standard deviation is:

[tex]\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }[/tex] to [tex]\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }[/tex]

[tex]70.69 * \sqrt{\frac{20 - 1}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{20 - 1}{8.907}[/tex]

[tex]70.69 * \sqrt{\frac{19}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{19}{8.907}[/tex]

[tex]53.76[/tex] to [tex]103.25[/tex]

Answer:

6 ounces

Step-by-step explanation:

Create a proportion where x is the number of ounces per 1 mile:

[tex]\frac{4.5}{0.75}[/tex] = [tex]\frac{x}{1}[/tex]

Cross multiply and solve for x:

4.5 = 0.75x

6 = x

So, the answer is 6 ounces

6 ounces

Step-by-step explanation:

Let the unknown number be x

[tex]4 \frac{1}{2} \: \: ounces = \frac{3}{4} \: \: miles \\ x = 1 \: \: mile[/tex]

Now simply use cross multiplication to solve it

[tex]4 \frac{1}{2} \times 1 = \frac{3}{4} x \\ \frac{9}{2} \times 1 = \frac{3}{4} x \\ \frac{9}{2} = \frac{3x}{4} \\ [/tex]

Now make x as the Subject

[tex] \frac{9}{2} = \frac{3x}{4} \\ \frac{9 \times 4}{2 \times 3} = x \\ \frac{36}{6} = x \\ 6 = x[/tex]

So the answer is

6 ounces

Answer: [tex]\dfrac{49}{50}[/tex]

Step-by-step explanation:

Given

Length of the stick is [tex]2y\ m[/tex]

A piece of [tex]4y\ cm[/tex] is cut

We know, 1 m=100 cm

So, [tex]2y\ m[/tex] in cm is [tex]200y\ cm[/tex]

Remaining length after cut is

[tex]\Rightarrow 200y-4y=196y[/tex]

Fraction of length that is left after the cut is

[tex]\Rightarrow \dfrac{196y}{200y}\\\\\Rightarrow \dfrac{49}{50}[/tex]

Thus, [tex]\frac{49}{50}[/tex] fraction of original stick remains after cut

Answer:

Last image.

Step-by-step explanation:

So, we know that the orginal graph is of [tex]\sqrt[7]{x}[/tex]

We need to find the graph of [tex]-\sqrt[7]{x}-8[/tex]

First off, we see a negative in front of the root.

This means that all the values will be flipped across the x axis.

This removes the first two answer graphs, for they are of the postive root.

Next, we have a -8 following the root.

So, when another number is inside of the root(example: [tex]\sqrt[7]{x-6}[/tex]) You are going to add 6 to the x axis, basically shifting everything to the right(postive). If it was a postive 6 inside the root, we would move it left(negative)

This is not what is being done in our graph, I just wanted to explain this for future graphing.

Now, when a number is outside the root, such as the one above, then it shifts the y axis. In this case we have a -8 outside the root. This means that the graph will be shifted down(negative) by 8.

This eliminates the 3rd graph image, leaving the last graph answer shown below.

Hope this helps!

Answer:

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

Step-by-step explanation:

If the figure is rotated about the origin by 90 degrees, then the values of the co-ordinates of all the vertices will be as follows -

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

Answer:

Trangle B and D

Step-by-step explanation:

They look more than 90 degrees

Answer:

-1049

Step-by-step explanation:

Let's assume it's a arithmetic sequence

a_1 = -26

d = a_2-a_1 = -11

==> a_94 = a_1+93*d = -1049

Answer:

-1071

Step-by-step explanation:

Let the common difference be 'd'.

d is 11

Find the difference from a (first term) and 11

Then use (n-1)

Answer: Each fraction is greater than the previous fraction.

Step-by-step explanation:

The fractions given are:

2/3, 4/6, 8/12, 16/24

Note that

2/3 = 4/6 = 8/12 = 16/32

The Fractions are all equal. Each fraction is equivalent to 2/3

The pattern used here is:

2/3 × 2/2 = 4/6

4/6 × 2/2 = 8/12

8/12 × 2/2 = 16/24

16/24 × 2/2 = 32/48

Each fraction is equal to the previous fraction in the pattern multiplied by 2/2

Also, the next fraction in the pattern is 32/48.

The statement that "Each fraction is greater than the previous fraction" is incorrect. The fractions are all equal.

Answer:

A. y^3 + 27

Step-by-step explanation:

Ed22

Answer: A. y3+27

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

45-5= 40

40*2= 80

Answer:

$389.73 in change

Step-by-step explanation

500-( (18.95 x 3)+(26.71 x 2) )=

500-(56.85+53.42)=

500-110.27=

389.73

Answer:

m = [tex]\frac{y+4}{x+5}[/tex]

Step-by-step explanation:

y-(-4) = m(x-(-5))

Simplify, distribute the negative sign outside of the parenthesis, remember negative times negative equals positive

y + 4 = m (x + 5)

Inverse operations, divide the equation by the value inside of the parenthesis

[tex]\frac{y+4}{x+5}[/tex] = m

Answer:

m=y+4x/x+5 your welcome !!

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is given by the equation:

[tex]y=-16x^2+165x+69[/tex]

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let y = 0 and solve for x:

[tex]0=-16x^2+165x+69[/tex]

We can use the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = -16, b = 165, and c = 69.

Substitute:

[tex]\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}[/tex]

Hence, our solutions are:

[tex]\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40[/tex]

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

Answer:

10.71

Step-by-step explanation:

the person below was correct!

Answer:

35d+ 32 > 25d+68

Step-by-step explanation:

Plan A: $35 a day plus a fee of $32

35d+ 32

Plan B: $25 a day plus a fee of $68

25d+68

We want to know when A costs more than B

35d+ 32 > 25d+68

Given:

z be inversely proportional to the cube root of y.

When y =0.064, then z =3.

To find:

a) The constant of proportionality k.

b) The value of z when y = 0.125.​

Solution:

a) It is given that, z be inversely proportional to the cube root of y.

[tex]z\propto \dfrac{1}{\sqrt[3]{y}}[/tex]

[tex]z=k\dfrac{1}{\sqrt[3]{y}}[/tex]              ...(i)

Where, k is the constant of proportionality.

We have, z=3 when y=0.064. Putting these values in (i), we get

[tex]3=k\dfrac{1}{\sqrt[3]{0.064}}[/tex]

[tex]3=k\dfrac{1}{0.4}[/tex]

[tex]3\times 0.4=k[/tex]

[tex]1.2=k[/tex]

Therefore, the constant of proportionality is [tex]k=1.2[/tex].

b) From part (a), we have [tex]k=1.2[/tex].

Substituting [tex]k=1.2[/tex] in (i), we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{y}}[/tex]

We need to find the value of z when y = 0.125.​ Putting y=0.125, we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{0.125}}[/tex]

[tex]z=\dfrac{1.2}{0.5}[/tex]

[tex]z=2.4[/tex]

Therefore, the value of z when y = 0.125 is 2.4.

Proportional quantities are either inversely or directly proportional. For the given relation between y and z, we have:

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

[tex]p = kq[/tex]

where k is some constant number called constant of proportionality.

This directly proportional relationship between p and q is written as

[tex]p \propto q[/tex]  where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n are two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n}[/tex]

or

[tex]n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n}\\\\or\\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

For the given case, it is given that:

[tex]z \propto \dfrac{1}{^3\sqrt{y}}[/tex]

Let the constant of proportionality be k, then we have:

[tex]z = \dfrac{k}{^3\sqrt{y}}[/tex]

It is given that when y = 0.064, z = 3, thus, putting these value in equation obtained above, we get:

[tex]k = \: \: ^3\sqrt{y} \times z = (0.064)^{1/3} \times (3) = 0.4 \times 3 = 1.2[/tex]

Thus,  the constant of proportionality k is 1.2. And the relation between z and y is:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}[/tex]

Putting value y = 0.0125, we get:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}\\\\z = \dfrac{1.2}{(0.125)^{1/3} } = \dfrac{1.2}{0.5} = 2.4[/tex]

Thus, for the given relation between y and z, we have:

Learn more about proportionality here:

https://brainly.com/question/13082482

Answer:

B

Step-by-step explanation:

The question says reflection across y = 1 so first find this line on the graph. It will be a horizontal line.

The Y axis is the vertical axis and so the 1 is the line right above the X axis.

So to reflect, it will be the same number away from the line when reflected as when it began on the opposite side of the line. So, S is one under the reflection line so it will be one above making its new point ( 2 , 2 )

Q is right on the line so it will not move.

R is two above the line so it will now be two below the line to have ( 3 , - 1 )

Answer:

d. No because n·(1 - [tex]\hat p[/tex]) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·[tex]\hat p[/tex] > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - [tex]\hat p[/tex]) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, [tex]\hat p_1[/tex] = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, [tex]\hat p_2[/tex] = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·[tex]\hat p[/tex] ≥ 10, and n·(1 - [tex]\hat p[/tex]) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·[tex]\hat p[/tex]₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - [tex]\hat p[/tex]₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·[tex]\hat p[/tex]₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - [tex]\hat p[/tex]₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - [tex]\hat p[/tex]₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - [tex]\hat p[/tex]₂) = 8.96 is less than 10

Answer:

It is x=908.

Might be wrong tho so dont jump me

Answer: 908

Step-by-step explanation:

x/4 = 89 + 138

x/4 = 227

x = 227 x 4

x = 908

Answer:

242/48

Step-by-step explanation:

==================================================

Work Shown:

7(-2-7k) + 4

7(-2) + 7(-7k) + 4

-14 - 49k + 4

-49k + (-14+4)

-49k - 10

In the second step, I distributed the outer 7 to each term inside. From there, I grouped and combined like terms, which were the -14 and 4.

Answer:

angle KPN=95 degree

Step-by-step explanation:

angle KPN = angle JPO (because they are vertically opposite angles)

Now,

angle JPO+angle LOP=180 degree(being co interior angles)

angle JPO + 85 =180

angle JPO =180-85

angle JPO =95

since angle JPO is equal to KPN ,angle KPN is 95 degree

Answer:

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

Step-by-step explanation:

Dejemos que el número de calendarios

Pedro vendió = x

Katrina vendió = y

Pedro y su compañera Karina vendieron 520 calendarios en diciembre.

x + y = 520 .... Ecuación 1

Pedro vendió 120 calendarios más que su socio.

x = y + 120

Sustituimos y + 120 por x

y + 120 + y = 520

2 años = 520 - 120

2 años = 400

y = 400/2

y = 200 calendarios

Resolviendo para x

x = y + 120

x = 200 + 120

x = 320 calendarios

Por lo tanto,

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

Answer:

1

Step-by-step explanation:

4^0

Any number raised to the 0 power is 1.

Answer:

1

Step-by-step explanation:

Anything raised to  0  is  1.