A candle is 6 tall after burning for one hour. After 3 h, it is 5. 5 tall. Write a linear equation to model the hh () of the candle after burning () h.

Answers

Answer 1

Answer:

h(t) = -0.25t + 6.25

Step-by-step explanation:

Given that :

Height of candle after burning for 1 hour = 6

Height of candle after burning for 3 hours = 5.5

The linear model to show the height ight of candle after burning for h hours :

The height change per hour of burn ; this is the slope ;

Change in height / Change in time ;

Time = 1 hour ; height = 6

Time = 3 hours ; height = 5.5

Slope = (5.5 - 6) / (3 - 1) = - 0.5 / 2 = - 0.25

This means candle height decreases ; - 0.25 ft per hour :

Based on the linear, slope, intercept equation ;

y = mx + c

Candle height, h

h(t) = mt + c

c = intercept, we can obtain this thus ;

Using the height at 1 hour and slope;

After an hour burn :

6 = - 0.25t + c

t = 1

6 = - 0.25(1) + c

6 = - 0.25+c

6+0.25 =, c

c = 6.25

Hence ; to calculate height, h after burn time &

h(t) = -0.25t + 6.25


Related Questions

116,02 LC)
Which of the triangles shown are obtuse triangles? (2 points)
A. Triangle A and Triangle B
B. Triangle B and Triangle D
C. Triangle C
D. Triangle A, Triangle B, and Triangle C

Answers

B. Triangle B and Triangle D
Triangle A has all equal sides and Triangle C is a right triangle.

Answer:

Trangle B and D

Step-by-step explanation:

They look more than 90 degrees

From a stick 2y metres long, I cut a piece of length 4y centimetres. What fraction of the original stick remains?

Answers

Answer: [tex]\dfrac{49}{50}[/tex]

Step-by-step explanation:

Given

Length of the stick is [tex]2y\ m[/tex]

A piece of [tex]4y\ cm[/tex] is cut

We know, 1 m=100 cm

So, [tex]2y\ m[/tex] in cm is [tex]200y\ cm[/tex]

Remaining length after cut is

[tex]\Rightarrow 200y-4y=196y[/tex]

Fraction of length that is left after the cut is

[tex]\Rightarrow \dfrac{196y}{200y}\\\\\Rightarrow \dfrac{49}{50}[/tex]

Thus, [tex]\frac{49}{50}[/tex] fraction of original stick remains after cut

Pedro y su socia Karina vendieron 520 calendarios en el mes de Diciembre. Pedro vendió 120 calendarios más que su socia. ¿Cuántos calendarios vendió cada uno?

Answers

Answer:

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

Step-by-step explanation:

Dejemos que el número de calendarios

Pedro vendió = x

Katrina vendió = y

Pedro y su compañera Karina vendieron 520 calendarios en diciembre.

x + y = 520 .... Ecuación 1

Pedro vendió 120 calendarios más que su socio.

x = y + 120

Sustituimos y + 120 por x

y + 120 + y = 520

2 años = 520 - 120

2 años = 400

y = 400/2

y = 200 calendarios

Resolviendo para x

x = y + 120

x = 200 + 120

x = 320 calendarios

Por lo tanto,

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

What statement is NOT true about the pattern shown below? 2/3, 4/6, 8/12, 16/24 Choices: Each fraction is greater than the previous fraction. Each fraction is equal to the previous fraction in the pattern multiplied by 2/2 Each fraction is equivalent to 2/3 The next fraction in the pattern is 32/48. Plsss help me out I need the answer like, rn. (That means SAY THE ANSWER RIGHT NOW!)

Answers

Answer: Each fraction is greater than the previous fraction.

Step-by-step explanation:

The fractions given are:

2/3, 4/6, 8/12, 16/24

Note that

2/3 = 4/6 = 8/12 = 16/32

The Fractions are all equal. Each fraction is equivalent to 2/3

The pattern used here is:

2/3 × 2/2 = 4/6

4/6 × 2/2 = 8/12

8/12 × 2/2 = 16/24

16/24 × 2/2 = 32/48

Each fraction is equal to the previous fraction in the pattern multiplied by 2/2

Also, the next fraction in the pattern is 32/48.

The statement that "Each fraction is greater than the previous fraction" is incorrect. The fractions are all equal.

Simplify the expression. 7(-2-7k) +4 Show all work below
(yo please help me im failing math and I have 1 day left of school. ;-;)​

Answers

Answer:    -49k - 10

==================================================

Work Shown:

7(-2-7k) + 4

7(-2) + 7(-7k) + 4

-14 - 49k + 4

-49k + (-14+4)

-49k - 10

In the second step, I distributed the outer 7 to each term inside. From there, I grouped and combined like terms, which were the -14 and 4.

The amount of ice cream dispensed from a machine at an ice cream shop is normally
distributed. If the machine is used 800 times in a day, how many times did the
machine dispense an amount that falls within three standard deviations from the
mean amount?
A 798
B 760
C 544
D 267

Answers

The answer is no one can answer me lol lol yeah I’m gonna be there for so the rest is

158.46

I think of a number subtract 5 and then multiply by 2 my awnser is 80 what is my number

Answers

Answer:

45

Step-by-step explanation:

45-5= 40

40*2= 80

Answer
45
45-5=40
40x2=80

Zx5+3 please help me

Answers

Answer: 5z + 3

-Use P.E.M.D.A.S
(Parentheses, Exponents, Multiply or divide, Add or subtract)

-Multiply z times 5 first
z x 5 = 5z

-Then add 5z to 3
5z + 3

Find the 94th term of the arithmetic sequence -26, -37, -48

Answers

Answer:

-1049

Step-by-step explanation:

Let's assume it's a arithmetic sequence

a_1 = -26

d = a_2-a_1 = -11

==> a_94 = a_1+93*d = -1049

Answer:

-1071

Step-by-step explanation:

Let the common difference be 'd'.

d is 11

Find the difference from a (first term) and 11

Then use (n-1)

Factor the common factor out of each expression: 18u^2v^5-27uv^5+54uv^4

Answers

Answer:

9uv⁴

Step-by-step explanation:

9uv⁴(2v-3v+6)

Answer:

Factor out 9uv^4 from the expression

9uv^4(2uv - 3v + 6)

If you need more steps just ask :)

Let z be inversely proportional to the cube root of y. When y =.064, z =3
a) Find the constant of proportionality k.
b) Find the value of z when y = 0.125.​

Answers

Given:

z be inversely proportional to the cube root of y.

When y =0.064, then z =3.

To find:

a) The constant of proportionality k.

b) The value of z when y = 0.125.​

Solution:

a) It is given that, z be inversely proportional to the cube root of y.

[tex]z\propto \dfrac{1}{\sqrt[3]{y}}[/tex]

[tex]z=k\dfrac{1}{\sqrt[3]{y}}[/tex]              ...(i)

Where, k is the constant of proportionality.

We have, z=3 when y=0.064. Putting these values in (i), we get

[tex]3=k\dfrac{1}{\sqrt[3]{0.064}}[/tex]

[tex]3=k\dfrac{1}{0.4}[/tex]

[tex]3\times 0.4=k[/tex]

[tex]1.2=k[/tex]

Therefore, the constant of proportionality is [tex]k=1.2[/tex].

b) From part (a), we have [tex]k=1.2[/tex].

Substituting [tex]k=1.2[/tex] in (i), we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{y}}[/tex]

We need to find the value of z when y = 0.125.​ Putting y=0.125, we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{0.125}}[/tex]

[tex]z=\dfrac{1.2}{0.5}[/tex]

[tex]z=2.4[/tex]

Therefore, the value of z when y = 0.125 is 2.4.

Proportional quantities are either inversely or directly proportional. For the given relation between y and z, we have:

The constant of proportionality k = 1.2, andWhen y = 0.125 , z = 2.4

What is directly proportional and inversely proportional relationship?

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

[tex]p = kq[/tex]

where k is some constant number called constant of proportionality.

This directly proportional relationship between p and q is written as

[tex]p \propto q[/tex]  where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n are two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n}[/tex]

or

[tex]n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n}\\\\or\\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

For the given case, it is given that:

[tex]z \propto \dfrac{1}{^3\sqrt{y}}[/tex]

Let the constant of proportionality be k, then we have:

[tex]z = \dfrac{k}{^3\sqrt{y}}[/tex]

It is given that when y = 0.064, z = 3, thus, putting these value in equation obtained above, we get:

[tex]k = \: \: ^3\sqrt{y} \times z = (0.064)^{1/3} \times (3) = 0.4 \times 3 = 1.2[/tex]

Thus,  the constant of proportionality k is 1.2. And the relation between z and y is:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}[/tex]

Putting value y = 0.0125, we get:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}\\\\z = \dfrac{1.2}{(0.125)^{1/3} } = \dfrac{1.2}{0.5} = 2.4[/tex]

Thus, for the given relation between y and z, we have:

The constant of proportionality k = 1.2, andWhen y = 0.125 , z = 2.4

Learn more about proportionality here:

https://brainly.com/question/13082482

solve for x please !URGENT!

Answers

Answer:

It is x=908.

Might be wrong tho so dont jump me

Answer: 908

Step-by-step explanation:

x/4 = 89 + 138

x/4 = 227

x = 227 x 4

x = 908

Ethan is installing a new tile backsplash in his kitchen. The tile he likes costs $3.50 per square foot. The area he is tiling is 36.5 square feet. How much will Ethan pay for the tile for his backsplash?

Answers

Answer:

$127.75

Step-by-step explanation:

Multiply the cost by the area to find the total cost

36.5*3.5= $127.75 .. you just had to multiply the total square feet and each tile cost to get the result! If this helps can I please have brainliest as I’m one point closer to moving to the next level..

Escreva os números abaixo em notação científica:
1) 5 000 000 000 000 =
2) 0,000 007 =
3) 58 600 000 000 000 =
4) 0,000 005 874 =

Answers

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

╭═══════ღ❦ღ══╮

Os números em notação científica são os seguintes : -

1) 5,000,000,000,000 [tex]\boxed{5 × 10^{12}}[/tex]

2) 0,000,007 [tex]\boxed{7 × 10^{0}}[/tex]

3) 58,600,000,000,000 [tex]\boxed{5.86 × 10^{13}}[/tex]

4) 0,000,005,874 [tex]\boxed{5.874 × 10^{3}}[/tex]

╰══ღ❦ღ═══════╯

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# [tex]\large\boxed{RainbowSalt2^{2}2^{2}}[/tex]

Use the Distributive Property to expand
the expression:
2 (y + 5x - 3)

Answers

2y+10x-6, just distribute the 2!

Hello please help asap, thanks!

Answers

Answer:

Last image.

Step-by-step explanation:

So, we know that the orginal graph is of [tex]\sqrt[7]{x}[/tex]

We need to find the graph of [tex]-\sqrt[7]{x}-8[/tex]

First off, we see a negative in front of the root.

This means that all the values will be flipped across the x axis.

This removes the first two answer graphs, for they are of the postive root.

Next, we have a -8 following the root.

So, when another number is inside of the root(example: [tex]\sqrt[7]{x-6}[/tex]) You are going to add 6 to the x axis, basically shifting everything to the right(postive). If it was a postive 6 inside the root, we would move it left(negative)

This is not what is being done in our graph, I just wanted to explain this for future graphing.

Now, when a number is outside the root, such as the one above, then it shifts the y axis. In this case we have a -8 outside the root. This means that the graph will be shifted down(negative) by 8.

This eliminates the 3rd graph image, leaving the last graph answer shown below.

Hope this helps!

3/4x × 12/11 ÷ 3x/22​

Answers

Answer:

242/48

Step-by-step explanation:

Max bought three items for $18.95 each and two items for $26.71 each. How much change would he get from $500 ?

Answers

Answer:

$389.73 in change

Step-by-step explanation

500-( (18.95 x 3)+(26.71 x 2) )=

500-(56.85+53.42)=

500-110.27=

389.73

CAN YOU PLS HELP ME WITH THIS I NEED THIS NOW!! I WILL GIVE BRAINLY TO BEST ANSWER THANK YOU!!
A rental car agency has 2 car rental plans. When will Plan A cost more than Plan B?

Plan A: $35 a day plus a fee of $32

Plan B: $25 a day plus a fee of $68

Write an inequality that expresses this real-world scenario.

Answers

Answer:

35d+ 32 > 25d+68

Step-by-step explanation:

Plan A: $35 a day plus a fee of $32

35d+ 32

Plan B: $25 a day plus a fee of $68

25d+68

We want to know when A costs more than B

35d+ 32 > 25d+68

Simplify the expression. 4^0

be careful i think this is a trick question

Answers

Answer:

1

Step-by-step explanation:

4^0

Any number raised to the 0 power is 1.

Answer:

1

Step-by-step explanation:

Anything raised to  0  is  1.

a study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. the study seeks to determine if the proportions of men and women who dislike anchovies are different. a sample of 41 men was taken and the p^ estimate for the true proportion of men who dislike anchovies was determined to be 0.67. a sample of 56 women was also taken and the p^ estimate for the true proportion of women who dislike anchovies was determined to be 0.84. are the requirements satisfied to perform this hypothesis test

Answers

Answer:

d. No because n·(1 - [tex]\hat p[/tex]) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·[tex]\hat p[/tex] > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - [tex]\hat p[/tex]) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, [tex]\hat p_1[/tex] = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, [tex]\hat p_2[/tex] = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·[tex]\hat p[/tex] ≥ 10, and n·(1 - [tex]\hat p[/tex]) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·[tex]\hat p[/tex]₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - [tex]\hat p[/tex]₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·[tex]\hat p[/tex]₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - [tex]\hat p[/tex]₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - [tex]\hat p[/tex]₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - [tex]\hat p[/tex]₂) = 8.96 is less than 10

There are 5 red, 4 blue, and 3 green marbles in a bag. What are the odds of randomly pulling a blue marble out of the bag and then randomly pulling a green marble out of the bag? The blue marble is NOT replaced.

A - 7/2
B - 12/24
C - 1/12
D - 1/11

Answers

C -1/12 is the answer

4 1/2 ounces per 3/4 miles
_____ ounces per 1 mile

Answers

Answer:

6 ounces

Step-by-step explanation:

Create a proportion where x is the number of ounces per 1 mile:

[tex]\frac{4.5}{0.75}[/tex] = [tex]\frac{x}{1}[/tex]

Cross multiply and solve for x:

4.5 = 0.75x

6 = x

So, the answer is 6 ounces

6 ounces

Step-by-step explanation:

Let the unknown number be x

[tex]4 \frac{1}{2} \: \: ounces = \frac{3}{4} \: \: miles \\ x = 1 \: \: mile[/tex]

Now simply use cross multiplication to solve it

[tex]4 \frac{1}{2} \times 1 = \frac{3}{4} x \\ \frac{9}{2} \times 1 = \frac{3}{4} x \\ \frac{9}{2} = \frac{3x}{4} \\ [/tex]

Now make x as the Subject

[tex] \frac{9}{2} = \frac{3x}{4} \\ \frac{9 \times 4}{2 \times 3} = x \\ \frac{36}{6} = x \\ 6 = x[/tex]

So the answer is

6 ounces

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+165x+69

Answers

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is given by the equation:

[tex]y=-16x^2+165x+69[/tex]

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let y = 0 and solve for x:

[tex]0=-16x^2+165x+69[/tex]

We can use the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = -16, b = 165, and c = 69.

Substitute:

[tex]\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}[/tex]

Hence, our solutions are:

[tex]\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40[/tex]

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

Answer:

10.71

Step-by-step explanation:

the person below was correct!

Use the chart to multiply the binomial by the trinomial.

The expression (y + 3)(y squared minus 3 y + 9) is shown above a blank table with 3 columns and 2 rows.
What is the product?

y3 + 27
y3 – 27
y3 – 6y2 + 27
y3 + 6y2 + 27

Answers

Answer:

A. y^3 + 27

Step-by-step explanation:

Ed22

Answer: A. y3+27

Step-by-step explanation:

y-(-4) =m(x-(-5)) solve for m

Answers

Answer:

m = [tex]\frac{y+4}{x+5}[/tex]

Step-by-step explanation:

y-(-4) = m(x-(-5))

Simplify, distribute the negative sign outside of the parenthesis, remember negative times negative equals positive

y + 4 = m (x + 5)

Inverse operations, divide the equation by the value inside of the parenthesis

[tex]\frac{y+4}{x+5}[/tex] = m

Answer:

m=y+4x/x+5 your welcome !!

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room at a four-star hotel, beverages, breakfast, taxi fares, and incidental costs. Click on the datafile logo to reference the data. City Daily Living Cost ($) City Daily Living Cost ($) Bangkok 242.87 Mexico City 212.00 Bogota 260.93 Milan 284.08 Cairo 194.19 Mumbai 139.16 Dublin 260.76 Paris 436.72 Frankfurt 355.36 Rio de Janeiro 240.87 Hong Kong 346.32 Seoul 310.41 Johannesburg 165.37 Tel Aviv 223.73 Lima 250.08 Toronto 181.25 London 326.76 Warsaw 238.20 Madrid 283.56 Washington, D.C. 250.61 a. Compute the sample mean (to 2 decimals). b. Compute the sample standard deviation (to 2 decimals). c. Compute a confidence interval for the population standard deviation (to 2 decimals).

Answers

Answer:

[tex]\bar x = 260.1615[/tex]

[tex]\sigma = 70.69[/tex]

The confidence interval of standard deviation is: [tex]53.76[/tex] to [tex]103.25[/tex]

Step-by-step explanation:

Given

[tex]n =20[/tex]

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}[/tex]

[tex]\bar x = \frac{5203.23}{20}[/tex]

[tex]\bar x = 260.1615[/tex]

[tex]\bar x = 260.16[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

[tex]\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}[/tex][tex]\sigma = \sqrt{\frac{94938.80}{19}}[/tex]

[tex]\sigma = \sqrt{4996.78}[/tex]

[tex]\sigma = 70.69[/tex] --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

[tex]c =0.95[/tex]

So:

[tex]\alpha = 1 -c[/tex]

[tex]\alpha = 1 -0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the degree of freedom (df)

[tex]df = n -1[/tex]

[tex]df = 20 -1[/tex]

[tex]df = 19[/tex]

Determine the critical value at row [tex]df = 19[/tex] and columns [tex]\frac{\alpha}{2}[/tex] and [tex]1 -\frac{\alpha}{2}[/tex]

So, we have:

[tex]X^2_{0.025} = 32.852[/tex] ---- at [tex]\frac{\alpha}{2}[/tex]

[tex]X^2_{0.975} = 8.907[/tex] --- at [tex]1 -\frac{\alpha}{2}[/tex]

So, the confidence interval of the standard deviation is:

[tex]\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }[/tex] to [tex]\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }[/tex]

[tex]70.69 * \sqrt{\frac{20 - 1}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{20 - 1}{8.907}[/tex]

[tex]70.69 * \sqrt{\frac{19}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{19}{8.907}[/tex]

[tex]53.76[/tex] to [tex]103.25[/tex]

What is the measure of KPN?

Answers

Answer:

angle KPN=95 degree

Step-by-step explanation:

angle KPN = angle JPO (because they are vertically opposite angles)

Now,

angle JPO+angle LOP=180 degree(being co interior angles)

angle JPO + 85 =180

angle JPO =180-85

angle JPO =95

since angle JPO is equal to KPN ,angle KPN is 95 degree

Graph the image of the figure using the transformation given.

Answers

Answer:

B

Step-by-step explanation:

The question says reflection across y = 1 so first find this line on the graph. It will be a horizontal line.

The Y axis is the vertical axis and so the 1 is the line right above the X axis.

So to reflect, it will be the same number away from the line when reflected as when it began on the opposite side of the line. So, S is one under the reflection line so it will be one above making its new point ( 2 , 2 )

Q is right on the line so it will not move.

R is two above the line so it will now be two below the line to have ( 3 , - 1 )

What are the vertices of the resulting image A'B'C'D'E' after rotating the figure 90° about the origin? ty A 4 B 2. E D 0 0 N 4​

Answers

Answer:

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

Step-by-step explanation:

If the figure is rotated about the origin by 90 degrees, then the values of the co-ordinates of all the vertices will be as follows -

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

Other Questions
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