A car travels the distance between logan airport and the town of framingham in 20 min. The logan express bus travels this distance in 30 min. After how long do the car and bus meet if they leave at the same time, and one travels from framingham to the airport while the other travels from the airport to framingham?.

Answers

Answer 1

The time the car and bus will meet if they leave at the same time, and one travels from Framingham to the airport while the other travels from the airport to Framingham is 12 minutes.

let

the distance between Logan airport and the town of Framingham = a

Car speed:

speed = distance / time

speed = a / 20

Logan express bus speed

speed = distance / time

speed = a / 30

let

the distance travelled by the car by the time they met = b

Then

the distance travelled by the bus the time they met = a - b

Therefore,

The time they met will be as follows:

speed  = distance / time

time = distance / speed

b / a / 20 = a - b / a / 30

20b / a = 30(a - b) / a

cross multiply

20ab = 30(a - b)a

20ab = 30a²- 30ab

50ab = 30a²

5b = 3a

b = 3 / 5 a

Therefore,

b / a / 20  =  3 / 5 a / a / 20  = 3 / 5 a × 20 / a = 60a / 5a = 12 minutes

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Answer 2

Answer:

12 minutes

Explanation:


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Answer:

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We can write the equation as follows;

(93 × p) + 84 = (8593  × p) + 84 = 85

We can solve the equation in parts as follows;

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Answers

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Explanation:

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From the standard normal tables:

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