Answer:
Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature
Explanation:
Which layer is the igneous rock type?
options:
A
B
C
D
You need low pressure to walk on
snow and ice. True or faulse
Answer:
True
Explanation:
Answer: false please give brainliest
Explanation: Reducing air pressure will not give you more traction and your tires could become seriously underinflated, affecting steering.
Select the correct answer.
Planet A Planet B
Distance from Sun 0.72 AU 9.54 AU
Planet composition rocky mantle, iron core hydrogen, helium
Gases in atmosphere very dense atmosphere that is 96.5% poisonous carbon dioxide and 3.5% nitrogen mostly hydrogen and helium
Number of moons 0 62
Rings no rings visible rings
Which planet is planet A?
A.
Mars
B.
Saturn
C.
Uranus
D.
Venus
Answer:
D, Venus
Explanation:
Using the facts
What is the Scientific name for Ectoparasites?
Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.
Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.
Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.
Please mark me brainliest.
What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Answer:
60 meters
Explanation:
If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply
3meters/second*20seconds
cross out the seconds and you have
3 meters*20
60 meters
Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE
Answer:
A - Juan
Explanation:
I took the test!
A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.
Answer:
[tex]V_{2.2} =2.2V[/tex]
Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V
With Ohm's Law
The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]
PLEASE HELP!!!!
1. Suppose a planet orbits a star at the same distance
as Earth (1 AU) but with a period of roughly 200
Earth days. The mass of the central star is:
a. less than the mass of our sun.
b. the same as the mass of our sun.
c.greater than the mass of our sun.
d. impossible to determine without
knowing the mass of the planet.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C
According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:
The squared of the period is directly proportional to the cube of the radius. That is,
[tex]T^{2} \alpha r^{3}[/tex]
The orbital period formula is expressed as :
[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex] ÷ GM
Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.
In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.
Therefore, the correct answer is option C
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