Answer:
We know that the carousel does a complete rotation in 45 seconds.
Then the frequency of this carousel will be f = 1/45 seconds.
And the angular frequency will be 2*pi times the frequency, then we have:
angular frequency = w = 2*3.14*(1/45s) = 0.1396 s^-1
Now, the linear speed of an object that rotates with a radius R, and an angular frequency W is:
S = R*W
then:
a) in this case the radius is 2.75m, then the linear speed is:
S = 2.75m*0.1396 s^-1 = 0.3839 m/s
b) in this case the radius is 1.75m, then the linear speed here is:
S = 1.75m*0.1396 s^-1 = 0.2443 m/s
(a) The linear speed of an outer horse on the carousel is 0.384 m/s.
(b) The linear speed of an inner horse on the carousel is 0.244 m/s.
Given data:
The time interval for the rotation of carousel is, t = 45 s.
The distance of the outer horse from the axis of rotation is, r = 2.75 m.
The distance of an inner horse from the axis of rotation is, r' = 1.75 m.
(a)
The linear speed in this problem can be obtained from the concept of rotational mechanic, in which the ratio of the circumference and the time gives required linear speed. So,
v = 2 π r/t
Solving as,
v = 2 π (2.75) / 45
v = 0.384 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.384 m/s.
(b)
Now similarly the linear speed of an inner horse is calculated as,
v' = 2 π r' / t
Solving as,
v' = 2 π (1.75) / 45
v' = 0.244 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.244 m/s.
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WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain distance from the radio station transmitter, the magnitude of the magnetic field of the electromagnetic wave is 3.0x10^-11T.
a. Calculate the wavelength
b. What is the angular velocity?
c. Find the wave number of the wave.
d. What is the amplitude of the electric field at this distance from the transmitter?
Answer:
a
[tex]\lambda = 202.7 \ m[/tex]
b
[tex]w = 9.3 *10^{6} \ rad/s[/tex]
c
[tex]k = 0.031 m^{-1}[/tex]
d
[tex]E_{max} = 9.0 *10^{-3} \ V/m[/tex]
Explanation:
From the question we are told that
The frequency of the radio station is [tex]f= 1480 \ kHz = 1480 *10^{3}\ Hz[/tex]
The magnitude of the magnetic field is [tex]B = 3.0* 10^{-11} \ T[/tex]
Generally the wavelength is mathematically represented as
[tex]\lambda = \frac{c}{f}[/tex]
Here c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
So
[tex]\lambda = \frac{3.0 *10^{8}}{ 1480 *10^{3}}[/tex]
=> [tex]\lambda = 202.7 \ m[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi * f[/tex]
=> [tex]w = 2 * 3.142 * 1480 *10^{3}[/tex]
=> [tex]w = 9.3 *10^{6} \ rad/s[/tex]
Generally the wave number is mathematically represented as
=> [tex]k = \frac{2 \pi }{\lambda}[/tex]
=> [tex]k = \frac{2 * 3.142 }{ 202.7}[/tex]
=> [tex]k = 0.031 m^{-1}[/tex]
Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as
[tex]E_{max} = c * B[/tex]
=> [tex]E_{max} = 3.0 *10^{8} * 3.0* 10^{-11}[/tex]
=> [tex]E_{max} = 9.0 *10^{-3} \ V/m[/tex]
1. According to paragraph 3 in the text, MOST of the electromagnetic waves from
the sun that reach Earth are: *
O A. microwaves, x rays and visible light
O B. radio waves, infrared waves and visible light
O C. infrared waves, visible light and ultra-violet radiation
D. gamma rays, ultra-violet radiation and microwaves
Answer:
Most of the EM waves from the sun that reach Earth are infrared waves, visible light, and UV radiation.
Explanation:
I hope this helps! Have a good day!
The amplitude of a pendulum is doubled. This means:
a
the pendulum will have twice its original mass.
b
the frequency of the pendulum will be twice as high.
c
the pendulum will swing twice as far away from the center.
d
the period of the pendulum will be twice as long.
Answer:
the period of the pendulum will be twice as long.
Explanation:
because i looked it up
Which is an example of balanced forces acting on an object?
a kangaroo jumping
a car turning a corner
a cyclist slowing down
a leaf lying on the grass
Answer:
a leaf lying on the grass
Explanation:
there is no movement (unbalanced forces) acting on the leaf so that's why it is still lying down and not changing its motion
When the force acting on a body is zero is called balanced force. Option D is correct.
What is balanced force?Force is defined as a push or pull of an object. Balanced forces are equal and opposite in direction. In balanced forces, there is no change in motion. In balanced force, the object is in equilibrium( i.e : the object is not moving with change in speed).
Unbalanced force is a force that can change the state of uniform motion or the rest of the body. If an object is moving with change in speed, it is said to be unbalanced.
From the given, some of them like kangaroo jumping, car turning a corner, cyclist slowing down shows motion except leaf lying on the grass. The leaf lying on the grass does not show any movement or motion, it is an example of balanced force.
Hence, the correct option is D) Leaf lying on the grass.
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What is the average speed of the toy car in the investigation?
0.25 m/s
4.0 m/s
5.0 m/s
20 m/s
Answer:
I would got with A or B because they seem more reasonable. Hope this helps and good luck :)
Which statement places events during the Space Race in the correct order from the earliest to the most recent?
1.NASA was established, US satellite Explorer launched, first man walked on the moon, first man orbited the Earth
2.first man walked on the moon, first man orbited the Earth, NASA was established, US satellite Explorer launched
3.US satellite Explorer launched, NASA was established, first man orbited the Earth, first man walked on the moon
4. first man orbited the Earth, first man walked on the moon, US satellite Explorer launched, NASA was established
Answer:
3,1,4,2
Explanation:
Answer:C
Explanation:
Lab - Wave Properties in a Spring
11-05
The wave characteristics you will observe in this lab are common to all waves (water, light, sound,
etc.). Use your prior knowledge and the book to fill in the following blanks, then go in the hall and
perform the lab.
A wave is a disturbance that moves through (propagates) through empty space or through a
_____________. There are two types of waves. A _____________________ wave requires
matter to travel. List some examples of this type:
A _____________________ wave does not require a medium. Examples include:
In order to start and transmit a mechanical wave, a source of _____________ and an
_______________ medium are required. A single disturbance is referred to as a
_______________, and a series of disturbances is a wave __________.
The questions in bold are those you should observe directly. Others will be answered using the book.
A. TYPES OF MECHANICAL WAVES: In the hall, stretch the slinky on the floor until it is
stretched (but still loose). Practice sending single pulses down the slinky by popping your wrist
from the center to the side and back to the center. Then send a continuous wave train along as
your partner holds the other end still. A piece of ribbon should be tied to one coil. Watch the
motion of this ribbon (representing a particle) as the wave travels through the spring.
In this type of wave, the particles move (perpendicular, parallel)
to the direction the wave travels. This type of wave is called a __________________ wave.
Its pulses are called ________________ and ________________.
Now send a pulse by quickly pushing the spring forward and pulling
it back, as shown. This type of wave is called _______________. Watch the motion of the ribbon.
In this type, the particles move _____________ to the direction the wave travels. Its pulses
are called _____________ and _____________. Label each.
Note that all waves transfer _____________ without transferring _______________. In
mechanical waves, particles of the medium vibrate back and forth in simple harmonic motion while
the disturbance (or _____________) moves from one place to another.
B. WAVE SPEED
Send a large pulse, followed by a small one. Does one pulse catch up to the other? ______
(Hint: The person who sends these waves should watch how the waves look when they return. Make
sure that both pulses are large enough initially to make it back to the sender!) The size of the
pulse is called the __________________ of the wave. Did the size affect the speed? ______
Generate a single transverse pulse in the slinky, keeping the stretch constant. Using a stopwatch,
time the journey of the pulse from one end to the other and back again. Take the average of
several trials. _________
Without changing your positions on the floor (therefore keeping the _____________ the pulse
travels the same), pull the slinky tighter using only about 3/4 of the coils. This makes a completely
different medium through which the pulse will travel. Time the journey as before. ___________
Does the kind of medium affect the speed of the pulse? ___________
Lab – Wave Properties in a Spring ____________________
PHYSICSFundamentals
© 2004, GPB
11-06
C. WAVELENGTH AND FREQUENCY
Shake the slinky back and forth steadily to send a
transverse wave train while your partner holds the other end still. On the diagram, label wavelength
(- Greek letter lambda). The frequency of the wave depends on how fast you shake the slinky.
Shake it regularly but slowly, then regularly but rapidly.
Higher frequency waves are generated by shaking the spring (slowly, rapidly). High frequency
waves have (short, long) wavelengths, and low frequency waves have __________.
The speed of a wave in any medium is equal to the _______________ of the wave X
________________. This wave equation ___________________ shows that f and are
______________ proportional. Write the units for each of the variables in this equation.
The exercise involves filling in the gaps with the possible wave
properties that can be obtained from a spring.
How is the Wave Properties in a Spring Lab exercise correctly completed?The correctly completed exercise is presented as follows;
A wave is a disturbance that moves through a medium. There are two
types of waves. A mechanical wave requires matter to travel. List some
examples of this type: sound wave, water wave, spring waves.
A electromagnetic wave does not require a medium. Examples include: Light waves
In order to start and transmit a mechanical wave, a source of
disturbance and a physical medium are required. A single disturbance is
referred to as a pulse, and a series of disturbance is a wave train.
This type of wave is called transverse wave. Its pulses are called crest
and troughs.
Now send a pulse by quickly pushing the spring forward and pulling it
back, as shown. This type of wave is called longitudinal wave. Watch the
motion of the ribbon. In this type, the particles move parallel to the
direction the wave travels. Its pulses are called compression and
rarefactions. Note that all waves transfer energy without transferring
matter. In mechanical waves, particle of the medium vibrate back and
forth in simple harmonic motion while the disturbance (or energy)
moves from one place to another.
B. Wave speed
Does the pulse catch up to the other? yes. The size of the pulse is called
the amplitude of the wave.
Did the size of the pulse affect the speed? No.
The average time wave it takes the wave to travel
Without changing your positions therefore keeping the distance the
pulse travels the same), pull the slinky tighter using only about 3/4 of
coils. This makes a completely different medium through which the
pulse will travel. Time the journey as before time record. Does the kind
of medium affect the speed of the pulse? Yes
C. Wavelength and Frequency
High frequency waves have short wavelengths and low frequency waves
have long wavelengths.
The speed of a wave in any medium is equal to the frequency of the wave × the wavelength. This wave equation [tex]\underline{f = \dfrac{v}{\lambda } }[/tex] shows that f and λ are
inversely proportional. The units of the variables are;
Units of the frequency, f is hertz unit HzUnits of the velocity, v, is m/sUnits of the wavelength, λ, is meters (m)Learn more about waves here:
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a wandering dog walks 1 km due east, 1 km due south, then runs 2 km due west. the magnitude of the dogs displacement is closest to
a. 0 km
b. 1.4 km
c. 3.4 km
d. 4.0 km
Answer:
b) 1.4km
Explanation:
A string of length 10.0 m is tied between two posts and plucked. This sends a wave down the string moving at a speed of 130 m/s with a frequency of 215 Hz. How many complete wavelengths of this wave will fit on the string?
Answer:
16.
Explanation:
In any wave, by definition, there exists a fixed relationship between the speed v, the frequency f , and the wavelength λ, as follows:[tex]v = \lambda * f (1)[/tex]
In our case, v = 130 m/s and f= 215 Hz, so solving for λ in (1), we get:[tex]\lambda = \frac{v}{f} = \frac{130m/s}{215 hz} = 0.61 m (2)[/tex]
In order to know how many wavelengths of this wave will fit on the string, we need just do divide the length of the string (10.0 m) over one single wavelength, as follows:[tex]n = \frac{L}{\lambda} = \frac{10.0m}{0.61m} = 16.4 (3)[/tex]
Since we need to take the integer value from this expression, the number of complete wavelengths that will fit on this string is just 16.A school bus has a mass of 18,200 kg. The bus moves at 13.5 m/s. How fast must a 0.142-kg baseball move in order to have the same momentum as the bus?
Answer:
bus momentum
p_bus= m_bus x v_bus
=18,200 x 16.5
basball momentum
pball=mball x vball
=0.142 x v
p_bus = pball
18200 x 16.5 = 0.142 x v
v=(18200 x 16.5)/0.142
v is the answer for baseball
Explanation:
⚠️not my answer tryna be honest here⚠️
The momentum of the bus of 18200 kg and velocity of 13.5 m/s is 245700 Kg m/s. To have equal momentum the base ball with 145 g have to throw in a speed of 1.7 × 10 ⁶ m/s.
What is momentum?Momentum of a moving body is the product of mass and velocity. Thus it have the unit of g m/s or Kg m/s. Momentum is a vector quantity and thus having magnitude and direction.
Given that one bus is having a mass of 18200 Kg and 13.2 m/s speed. The momentum is:
p = mv
=18200 kg × 13.5 m/s
= 245700 Kg m/s
To have a momentum of 245700 Kg m/s the base ball with 0. 142 g have to have a velocity = 245700 Kg m/s / 0.142 g
=1.7 × 10 ⁶ m/s
Hence, the baseball weighs0. 142 g have to move in 1.7 × 10 ⁶ m/s
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A mass oscillates on a spring, bouncing up and down 5 times per second. From the highest position to the
lowest position of the mass is a distance of 16 cm.
Answer:
i kinda dnt knw srry wanted the points for the answer
Explanation:
A peregrine falcon dives at a pigeon. The falcon starts with zero downward velocity and falls with the acceleration of gravity. If the pigeon is 76.0 m below the initial height of the falcon, how long does it take the falcon to intercept the pigeon?
Answer:
t = 3.94 s
Explanation:
This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:
[tex]h = v_{i}t + \frac{1}{2}gt^2[/tex]
where,
h = height = 76 m
vi = initial speed of falcon = 0 m/s
t = time required = ?
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]76\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\t^2 = \frac{(2)(76\ m)}{9.8\ m/s^2}\\\\t = \sqrt{ 15.49\ s^2}\\[/tex]
t = 3.94 s
The kinematics allows to find the result for the time it takes the falcon to reach the pigeon is:
Time is t = 3.94 s
Kinematics studies the motion of bodies looking for relationships between position, velocity and acceleration.
A reference system is a coordinate system with respect to which to carry out the measurements. In the attachment we set a reference system in the pigeon with the vertical direction upwards as positive.
They indicate that the height of the hawk is I = 76 m and its initial vertical velocity is zero.
y = y₀ + v₀ t - ½ g t²
0 = y₀ - ½ g t²
[tex]t = \sqrt{\frac{2y_o}{g} }[/tex]
Let's calculate.
[tex]t = \sqrt{\frac{2 \ 76.0}{9.80} }[/tex]
t = 3.94 s
In conclusion using kinematics we can find the result for the time it takes the falcon to reach the pigeon is:
Time is t = 3.94 s
Learn more about kinematics here: brainly.com/question/24760588
Angelica inhaled deeply into a plastic cup. Why did the cup collapse?
Answer:
Air vacuum.
Explanation:
Air may seem like nothing, but there are tons of molecules in it. Air takes up space. When Angelica inhales, the air rushes into into and escapes the cup. Since theres no air anymore, the cup collapses because thereis no more space in it. She removes the air from the cup and it creates a vacuum inside, sucking the sides of the cup in.
Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
Answer:
The current is 11 Amperes
Explanation:
Electric Current
The electric current is defined as a stream of charged particles that move through a conductive path.
The current intensity can be calculated as:
[tex]\displaystyle I=\frac{Q}{t}[/tex]
Where:
Q = Electric charge
t = Time taken by the charge to move through the conductor
The current intensity is often measured in Amperes.
The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:
[tex]\displaystyle I=\frac{55}{5}[/tex]
I = 11 Amp
The current is 11 Amperes
When will the human brain be fully developed?
A. By age 15
B. The early 20s
C. The late 20s
D. The 30s
Answer:
C.
Explanation:
The human brain isn't fully developed until 25 years of age. Everything is there except for the frontal cortex, which is the last thing to mature. An immature frontal cortex explains the spectrum of teenage behaviors: it's what makes adolescents adolescent, says Sapolsky.
Answer:
25!
Explanation:
can someone help me with a 6th grade science test please
Answer:
whats the question?
Explanation:
i can help you
QUESTION 23
How much electric energy will be used by a 115 V, 60 W Eghtbulb in one minute
69.
2215
5800
6900)
*
Xpwe-
Answer:
E = 3600 J
Explanation:
Given that,
Voltage, V = 115 V
Power of electric bulb, P = 60 W
We need to find the electric energy used in 1 minute. The electric energy use is given by :
[tex]E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J[/tex]
Hence, the electrical energy is 3600 J.
The most cost effective solution to energy shortages is energy
conservation.
Question 25
Which of the following objects would have the greatest kinetic energy?
А
a 100kg car going 50m/s.
B
a 100kg car going 100m/s
С
a 50kg car going 50m/s
D
a 50kg car going 100m/s
If the social distancing length between two students is doubled from two metered to four meters, does the gravitational force between the two students increase or decrease?
Explain your reasoning!
Answer:
the gravitational force decreases
Details
A 70 kg student rides the Gravitron at a carnival. The
Gravitron has a radius of 2.75 meters. The student feels
a centripetal force of 2100 N. How fast is the Gravitron
spinning?
Answer:
1400 math quiz
Explanation:
40s n shorty's
A car of mass 1200 kg travels at a steady dpeed of 22 m/s around a bend of radius 50 m. Find the centripetal force required?
Compute the magnitude of the centripetal acceleration a :
a = (22 m/s)² / (50 m) = 9.68 m/s²
Then the magnitude of the centripetal force is
F = (1200 kg) (9.68 m/s²) = 11,616 N ≈ 12,000 N
The truck needs 11,616 N of centripetal force to bend around a radius 50 m.
From the centripetal acceleration,
[tex]a = \dfrac{v^2}{r}[/tex]
Where,
[tex]a[/tex]- Centripetal acceleration
[tex]v[/tex]- velocity = 22 m/s
[tex]r[/tex]- radius = 50 m
Put the values,
[tex]a =\dfrac { (22 \rm \ m/s)^2}{(50\rm \ m)}\\\\a = 9.68\rm \ m/s^2[/tex]
So, the centripetal force is
[tex]F = ma[/tex]
Where, m is the mass = 1200 kg
So,
[tex]F= 1200\rm \ kg\times 9.68\rm \ m/s^2 \\\\F = 11,616\rm \ N[/tex]
Therefore, the truck needs 11,616 N of centripetal force to bend around a radius 50 m.
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What would be the magnitude of a star with a temperature of 25,000 located on
the main sequence?
Answer:
hvkhvkhvkvlhvgjvgv
Explanation:
A tennis ball is traveling at 50 m/s and has a kinetic energy of 75J. Calculate the mass of the tennis ball.
A particular engine has a power output of 2 kW and an efficiency of 27%. If the engine expels 9085 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.
Answer:
12445 J
Explanation:
Given that
Power output, P = 5 kW
efficiency of the engine, e = 27% = 0.27
Thermal energy expelled, Q(c) = 9085 J
Heat absorbed, Q(h) = ?
Using the formula
e = W/Q(h)
e = [Q(h) - Q(c)] / Q(h)
e = 1 - Q(c)/Q(h)
Now, substituting the values into the formula, we have
0.27 = 1 - 9085/Q(h)
9085/Q(h) = 1 - 0.27
9085/Q(h) = 0.73
Q(h) = 9085 / 0.73
Q(h) = 12445 J
Thus, the heat absorbed is 12445 J
What is the Potential Energy of a roller coaster if it has a velocity of 35 m/s and a mass of 2000 kg and is at a height of 200 m? Please answer fast
A.) 137,200,000 J
B.) 12,005,000 J
C.) 3,920,000 J
D.) 1,400,000 J
Answer:
C
Explanation:
It cant be A or D, meaning your left with B and C. there cant be an answer in the 1000's place eather
The average speed of a car that drives 140 kilometers in 2 hours
Answer:
240 kilometer
Explanation:
ur just mutipling the number by 2
Your average speed was 70.0 Kilometers per hour (km/h)
This question looks so simple , but I don’t want to get it won’t could I get help .
Answer:
I would think a vector but double check that before turning it in
Explanation:
What type of electromagnetic wave is a TV remote and a cloud
Answer: Kids learn about the types of electromagnetic waves in the science of physics ... Microwaves are useful in communication because they can penetrate clouds, ... These are the infrared waves that are used in your TV remote to change channels
Explanation:
characteristics of projectile motion.
Answer:
Objects experiencing projectile motion have a constant velocity in the horizontal direction and a constantly changing velocity in the vertical direction. The trajectory resulting from this combination always has the shape of a parabola.
Explanation:
