0.5Ω
Explanation:Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.
Using Ohm's law, the voltage across a resistor in a circuit is given by;
V = I(R + r) -----------(i)
For the 1ohm resistor, the voltage across it is given by;
Where;
I = current passing through the 1 ohm resistor = 0.6A
R = resistance of the 1 ohm resistor = 1Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.6(1 + r) -------------------(ii)
For the 4.0ohm resistor, the voltage across it is given by;
Where;
I = current passing through the 4.0 ohms resistor = 0.2A
R = resistance of the 4.0 ohms resistor = 4.0Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.2(4.0 + r) -------------------(iii)
Now solve equations (ii) and (iii) simultaneously;
V = 0.6(1 + r)
V = 0.2(4.0 + r)
Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;
0.6(1 + r) = 0.2(4.0 + r)
Solve for r
0.6 + 0.6r = 0.8 + 0.2r
0.6r - 0.2r = 0.8 - 0.6
0.4r = 0.2
r = [tex]\frac{0.2}{0.4}[/tex]
r = 0.5
Therefore, the internal resistance of the cell is 0.5Ω
A test car and its driver, with a combined mass of 600 kg, are moving along a straight,horizontal track when a malfunction causes the tires to stop rotating. The car skids to a halt with constant acceleration, leaving skid marks on the road during the whole time it skids. Which two of the following measurements, taken together, would allow engineers to find the total mechanical energy dissipated during the skid?
A. The length of the skid marks
B. The contact area of each tire with the track.
C. The coefficent of static frction between the tires and the track.
D. The coefficent of static frction between the tires and the track.
Answer:
The two of the following measurements, when taken together, would allow engineers to find the total mechanical energy dissipated during the skid
B. The contact area of each tire with the track.
C. The co-efficent of static friction between the tires and the track.
D. The co-efficent of static friction between the tires and the track.
Explanation:
can someone please help
The answer is B. Mono and polyunsaturated fats because the other two are really harmful and they are not healthy whatsoever.
31) A box is pushed, up a ramp, at constant velocity with a force of 14 N.
What is the magnitude of the friction force working on the box? *
The magnitude of the frictional force working on the box is 14 N.
According to Newtons's first law, an object will continue in its state of rest or state of uniform motion unless it is acted upon by an unbalanced force. This means that motion or acceleration is caused by an unbalanced force.
Since the box is moving at constant velocity, the frictional force on the box and the force that moves the box forward are exactly equal in magnitude but opposite in direction.
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What 3 things does the force of gravity depend on?
Answer:
Size of an object, and the distance between the objects.
When the mass of an object increases the force of gravity increases as well.
Explanation:
The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
An organism that is only one cell big and has a nucleus is most likely a member of which kingdom?
Answer:
Protista
Explanation:
Taxonomy can be defined as the process of naming, classification and description of living organisms such as plants and animals. Thus, the biological classification of living organisms based on similarities or characteristics such as eyes, number of legs, etc., is generally referred to as taxonomy.
Basically, taxonomy helps scientist to have a good understanding and knowledge when studying various organisms.
Furthermore, the eight (8) biological classification (taxonomy) used for grouping and organizing organisms are; kingdom, domain, phylum, family, order, class, species and genus.
An organism that has only one cell, big and has a nucleus is most likely a member of Protista. Thus, a Protista such as euglena, paramecium, amoeba, etc., have a nucleus and are unicellular.
A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.
Calcalculate potential energy given to a potato sack having a mass of 2 kg as I raise it to a height of 450 CM
Answer:
8.829 Joules
Explanation:
The potential energy of an object, is the energy it posses (the energy stored within the object) by virtue of its relative elevation or height, position, state, or arrangement
The potential energy of an object raised to a given height, P.E. = m·g·h
Where;
m = The mass of the object
g = The acceleration due to gravity, a constant ≈ 9.81 m/s²
h = The present height of the object
For the potato sack having a mass, m = 2 kg, and raised to a height, h = 450 cm = 0.45 m, we have;
The potential energy given to the potato sack, by raising its height, P.E. is given as follows;
P.E. = 2 kg × 9.81 m/s² × 0.45 m = 8.829 Joules
The potential energy given to the potato sack, P.E. = 8.829 Joules
A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2. The acceleration of the plane is 4.9
What is the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline?
Answer in units of N.
Answer:
Explanation:
What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:
w = mg so
w = (4.04)(9.8) and
w = 4.0 × 10¹ N
The magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
The given parameter are:
mass M = 4.04 kg
Angle of inclination = 30 degree
Acceleration due to gravity = 9.8 m/s^s
To calculate the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the plane, The force will be the weight of the block which is equal to the normal reaction.
Normal N = mgcosФ
N = 4.04 x 9.8 x cos30
N = 34.28 Newtons
At all point in the plane, the magnitude of the perpendicular force that the block exerts on the surface of the plane will be the same.
Therefore, the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
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In the Vector Addition Lab, the following data was collected for determining the displacement from the door of the Physics classroom to another location in the building: 2 m, West; 14.0 m, South; 25.0 m, East; 11.0 m, North; and 2 m, West. The magnitude of the resultant displacement from the physics classroom to the assigned location is closest to ___ meters. (Round to the nearest integer.)
Answer:
21 m
Explanation:
Since the displacement from the door is 2 m West, we have our vector as -2i. The vector representing 14.0 m South is -14.0j. The vector representing 25.0 m East is 25.0i. The vector representing 11.0 m North is 11.0j. And, the vector representing 2.0 m West is -2.0i.
So, to get our position vector at the other location, we add all the vectors together.
So, r = -2i + (-14.0j) + 25.0i + 11.0j - 2i
= -4i + 25.0i - 14.0j + 11.0j
= 21.0i -3j m
Now, if we assume the position vector for the door is at the origin, we have r₀ = 0i + 0j m
So, our displacement from the door is r - r₀ = 21.0i - 3.0j - (0i + 0j) = 21.0i - 3.0j
So, the magnitude of the resultant displacement |r - r₀| = √(21.0² + 3.0²)
= 3.0√(7.0² + 1)
= 3.0√(49 + 1)
= 3.0√50
= 3.0 × 7.0711
= 21.2
≅ 21 m to the nearest integer
Choose the incorrect statement about the proton: Group of answer choices The proton has the atomic mass of 1 amu The proton has the same charge as the neutron. The proton has greater mass than an electron The proton and the neutron have approximately the same atomic mass
Answer:
The proton has the same charge as the neutron.
Explanation:
Because the proton has a positive charge whereas the neutron has no charge at all.
Calculate the capacitance of a system that stores 9.4 x 10-10 C of charge at
Q
50.0 V. Use C=
AV
O A. 1.9 x 10-11 F
OB. 4.7 x 10-8 F
O C. 5.3 x 1010 F
O D. 2.1 x 107 F
Answer:
A. [tex]1.88\times 10^{-11}\,F[/tex].
Explanation:
By definition of Electric Capacitance, the capacitance of the system ([tex]C[/tex]), in farads, is described by the following formula:
[tex]C = \frac{q}{V}[/tex] (1)
Where:
[tex]q[/tex] - Electric charge, in coulombs.
[tex]V[/tex] - Voltage, in volts.
If we know that [tex]q = 9.4\times 10^{-10}\,C[/tex] and [tex]V = 50\,V[/tex], then the capacitance of the system is:
[tex]C = \frac{9.4\times 10^{-10}\,C}{50\,V}[/tex]
[tex]C = 1.88\times 10^{-11}\,F[/tex]
The correct answer is A.
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscillations. What can we say, about these springlike bonds when the charge is first, furthest away and second, closest to the source charge
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source when Furthest away the bond with charge will be less effective
I just... I don't know man I suck at physics :(
A tour guide shouts across a canyon. At a temperature of 20 °C, her echo is heard 2.00 s later. How wide is the canyon?
The answer is 340 m I just don't know how to get that....
Explanation:
Sound travels from the tour guide to the other of the canyon and then back, thus hearing the echo. The time of 2.0 s represents the time it takes the sound to make a round trip, therefore it takes 1.0 s for the tour guide's voice to reach the other side of the canyon. At 20°C, the speed of sound is 343 m/s therefore the width of the canyon is
[tex]x = vt = (343\:m/s)(1.0\:s) = 343\:m[/tex]
The canyon in the given question is 340 m wide.
What is echo?Echo is a reflection of sound that comes to the listener after the direct sound, but with a delay. The delay is inversely proportional to the separation between the source and the listener of the reflecting surface.
To hear the echo, the following conditions must be met:
There must be a minimum of 17 meters between the sound source and the reflecting surface, and there must be at least 0.1 seconds between the original sound and its echo.
Given parameters:
When a tour guide shouts across a canyon, her echo is heard 2.00 s later. That means, in two seconds the sound goes to other wall of canyon and reflected back.
At a temperature of 20 °C, velocity of sound is 340 m/s.
So, the wide is the canyon be = velocity of sound × time/2
= 340 m/s ×2 s/2s = 340 m.
Hence, the wide is the canyon be 340 m.
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As a train starts from rest then accelerates down the track, coming toward an observer faster and faster, the frequency of the sound waves coming toward the observer will be
Answer:
Increase in frequency constantly
Explanation:
This concept can be explained by Doppler shift as per which any form of disturbance spreads out spherically from its point of origin. If the source of sound wave is stationary and the receiver is also stationary, then the frequency remains the same but if the source is moving, then the disturbance caused is closer on one side and distant on the other side thereby producing shorter wavelength in direction the source is moving and longer wavelength in the opposite direction.
A positively charged rod is brought close to a neutral metal sphere. Explain what
happens to the charges in the neutral sphere as the rod comes close, touches the
sphere, and then moves away. Is the metal sphere still neutral at the end of this
encounter?
Answer:
No, the metal sphere becomes positively charged because electrons are transferred from the sphere to the rod.
What produces magnetic fields?
Answer:
flowers
Explanation:
i'm really not sure but i have this gut feeling its flowers
PLSSSSS HELPPPPP
Consider the potential energy diagram shown below. This graph shows the chemical potential energy in a reaction system over time. The y-axis is potential energy in kilojoules. The x-axis is the reaction progress, or time.
The far left part of the curve is horizontal and has an energy value of 50 kJ. The curve then rises to a peak of 250 kJ before falling to a horizontal region at 200 kJ.
Does this graph represent an endothermic or an exothermic reaction? Explain your answer.
What is the enthalpy change, ΔH, for this reaction? Show your work.
What is the activation energy, Ea, for this reaction? Show your work.
In a particular chemical reaction, the energy of the reactants is 30 kJ and the energy of the products is 5 kJ. The maximum energy of the system is 40 kJ.
Sketch a potential energy diagram for this reaction. Make sure to label the energy of the reactants, the energy of the products, the activation energy, and the enthalpy change for the reaction.
What is the activation energy for this reaction?
What is the enthalpy change for this reaction?
Is this reaction endothermic or exothermic? Explain your answer in two ways: first, using the energy values, and second, by referring to the shape of the graph.
The coating on the head of a match is highly flammable. When it burns, it releases a great deal of energy. However, before the match can burn, it must gain a small amount of energy from a spark. That spark is typically produced by striking (rubbing) the match head against a rough surface. Sketch and describe a potential energy diagram that represents the striking and burning of the match. Remember to label the diagram with the energy changes that occur. Your answer must include the potential energy diagram and a written description. (Note: you do not have to use actual energy values.)
Answer:
A. Endothermic reaction.
B. +150KJ.
C. 250KJ.
Explanation:
A. The graph represents endothermic reaction because the heat of the product is higher than the heat of the reactant.
B. Determination of the enthalpy change, ΔH for the reaction. This can be obtained as follow:
Heat of reactant (Hr) = 50KJ
Heat of product (Hp) = 200KJ
Enthalphy change (ΔH) =..?
Enthalphy change = Heat of product – Heat of reactant.
ΔH = Hp – Hr
ΔH = 200 – 50
ΔH = +150KJ
Therefore, the enthalphy change for the reaction is +150KJ
C. The activation energy for the reaction is the energy at the peak of the diagram.
From the diagram, the activation energy is 250KJ.
Why is using the same cutting and knife for both
cooked and uncooked food not a drisable?
Answer:
It spreads diseases.
Explanation:
But when cooked food is kept on the place where uncooked meat or food was kept the germs spread to the cooked food also and as the cooked food cannot be washed it harms us as we directly consume it.
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by the wall?
A. The ball experiences more force than the wall.
B. The ball experiences less force than the wall.
The ball and the wall experience the same force.
D. The ball experiences half the force of the wall.
Reset
Next
Answer:
The ball and the wall experience the same force.
Explanation:
According to the third law of Newton, which states that "for every action, there is an equal and opposite reaction", this means that when an object 1 acts on object 2 with a certain force, object 2 also acts on object 1 with the same magnitude of force but in an opposite direction.
According to this question, a ball hits a wall with a certain force. This means that the wall will react on the ball with the same force magnitude, but in an opposite manner. Hence, the ball and the wall experience the same force.
Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutionsAt what rate is the flywheel spinning when the power comes back on(in rpm)
Complete Question
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?
Answer:
[tex]\theta=274rev[/tex]
Explanation:
From the question we are told that:
Angular velocity [tex]\omega=510rpm[/tex]
Mass [tex]m=40.kg[/tex]
Diameter d [tex]75=>0.75m[/tex]
Off Time [tex]t=40.0s[/tex]
Oscillation at Power off [tex]N=210[/tex]
Generally the equation for Angular displacement is mathematically given by
[tex]\theta_{\infty}=\frac{w+w_0}{t}t[/tex]
[tex]w=\frac{2*\theta_{\infty}}{t}-w_0[/tex]
[tex]w=\frac{28210}{40*(\frac{1}{60})}-510[/tex]
[tex]w=120rpm[/tex]
Generally the equation for Time to come to rest is mathematically given by
[tex]t=(\frac{\omega_0}{\omega_0-\omega})t[/tex]
[tex]t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})[/tex]
[tex]t=0.87min[/tex]
Therefore Angular displacement is
[tex]\theta =(\frac{120+510}{2})0.87[/tex]
[tex]\theta=274rev[/tex]
If youre walking from point a to b, the magnitude of your displacement will always be equal or less than or greater than your distance?
The magnitude of your displacement can be equal to the distance you covered, or it can be less than the distance you covered. But it can never be greater than the distance you covered.
This is because displacement is a straight line, whereas distance can be a straight line, a squiggly line, a zig-zag line, a line with loops in it, a line with a bunch of back-and-forths in it, or any other kind of line.
The straight line is always the shortest path between two points.
You hear the dishwasher with a loudness of 40 dB and a siren outside
with a loudness of 60 dB. How much greater is the amplitude of the
siren's sound than the amplitude of the dishwasher's sound?
Answer:
The ratio of the amplitudes of siren to dishwasher is 10.
Explanation:
loudness of dishwasher = 40 dB
loudness of siren = 60 dB
let the intensity of dishwasher is I an the intensity of siren is I'.
Use the formula of intensity and decibels.
[tex]dB = 10 log\frac{I}{I_o}\\\\40=10 log\frac{I}{I_o}\\\\4 = log\frac{I}{I_o}\\\\I = 10000 I_o[/tex]
And
[tex]60=10 log\frac{I'}{I_o}\\\\60 = log\frac{I'}{I_o}\\\\I' = 1000000 I_o[/tex]
The intensity if proportional to the amplitude.
[tex]\frac{A'}{A}=\sqrt\frac{1000000}{10000}\\\\\frac{A'}{A}= 10[/tex]
A student is building an electric circuit.Which material should she choose for the wires,and why?
If i understand your question clearly, The best choice in most scenarios is copper.
Why?
Its due to copper's high conductive properties, its abundance, its low price compared to its fellow metal conductors, its ductile property, thermal resistance and immunity to oxidation ( rusting ).
Though Silver surpasses copper in conductivity, copper is shown to be more notable than its fellow conductors.
300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me
Answer:
6KW
Explanation:
The computation is shown below:
We know that
Work done= m ×g× h
Here
W= 300×10×10
= 30000 J
= 30 KJ
And
Power= Work done ÷time taken
P = 30000 ÷ 5
= 6000W
= 6KW
The above represent the answer
How much gravitational potential energy does an object have if it is located 20 m above the point that we define as O height and has a mass of 10 kg
Answer:
Explanation:
PE = mgh where m is the mass in kg, g is the pull of gravity which is 9.8, and h is the height of the object above the point to which it could possibly fall, measured in meters. Plugging in:
PE = 10(9.8)(20) so
PE = 1960 J
This should be rounded to 1 sig fig according to the rules of sig fig and your numbers here, but I imagine you're not following them all that much. It should be 2000 J
Thermal physics vs atomic physics ...which is easier?
Answer:
Thermal physics
Explanation:
Because it uses temperature
Answer:
In my opinion both are easier if you'll work hard on it...
The density of dry air at room temperature and atmospheric pressure Is 1.2 kg m-3. What volume would 6 kg of dry air occupy under these conditions?
Answer:
V = 5 m³
Explanation:
The density of air, d = 1.2 kg/m³
Mass of the dry air, m = 6 kg
We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,
[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{6}{1.2}\\\\V=5\ m^3[/tex]
So, the volume of the dry air is 5 m³.
What is the amount of change in an object's momentum equal to?
A.
The amount of mass applied to the object over a certain amount of time
B.
The amount of force applied to the object over a certain amount of time
C.
The amount of acceleration applied to the object over a certain amount of time
D.
The amount of energy applied to the object over a certain amount of time
answer:
Explanation:
the impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it. The impulse-momentum theorem is logically equivalent to Newton's second law of motion (the force law).
According to the impulse-momentum theorem, the amount of change in an object's momentum equal to the amount of force applied to the object over a certain amount of time. So, option B.
According to the impulse-momentum theorem, the impulse that is applied to an item is equal to the change in momentum.
It shows how an object's change in momentum depends on both the strength and duration of the applied forces.
Impulse is defined as the force acting for a short interval of time.
Impulse = F x t
The momentum of the object,
P = mv
So, the rate of change of momentum,
dP/dt = d(mv)/dt
dP/dt = mdv/t
dP/dt = ma = Force
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