A chewing gum consists of 30% corn syrup and 40% sugar. The rest was made up by gum Arabic. Find the weight of the Gum Arabic in a 25gm piece of the chewing gum. Max points pls just bloody answer it

Answer:

0.77

Step-by-step explanation:

Given that:

P(A) = 0.64

P(B) = 0.25

P(AnB) = 0.12

Probability that customer buys either pet or baby supplies ; P(AuB)

P(AuB) = P(A) + p(B) - p(Ann)

P(AuB) = 0.64 + 0.25 - 0.12

P(AuB) = 0.77

Step-by-step explanation:

x-14y=0

x=0/14y

x=14y

14y

Answer:

Step-by-step explanation:

angle 2 is also 60 degree (being vertically opposite angles)

angle 3 is also 60 degree (being corresponding angles)

angle 4 is also 60 degree (being corresponding angles ) . sice angle 2 is 60 degree and relation between  angle 2 and 4 is corresponding angle , angle 4 will also be 60 degree.

Answer:

option 3 : (2x - 7 )

Step-by-step explanation:

ax + bx = x(a+ b)

a(x+ y) + b(x+y) = (x+y)(a+b)

[tex](3x - 8 ) ( 2x + 5) - (x + 1)(2x + 5)\\\\(2x+5)[ (3x - 8) - (x+1) ][/tex]      [ (2x + 5) is common is both terms ]

[tex](2x+ 5)(3x -8 -x + 1)\\\\(2x+ 5)(2x - 7)[/tex]

Therefore , the binomial is ( 2x - 7)

Answer:

Percent * base = Amount

660 g = 660 g

3kg = 3000g

percent(3000) = 660

percent = 660/3000

percent = .22

.22 = 22%

Step-by-step explanation:

Answer: 11 because it all works out.

Answer:

sinB = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

sinB = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{12}{13}[/tex]

The Trigonometric ratios is 12/13

The branch of mathematics concerned with specific functions of angles and their application to calculations.

We have,

H= 13, B= 5 and P=12

So,

sin B= Perpendicular/ Hypotenuse

        = 12/13

hence, sin B=  12/13

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Answer:

The probability is 32/81

Step-by-step explanation:

We know that:

The probability that the team wins is p = 2/3

Then the probability of not winning is q = 1 - p = 1 - 2/3 = 1/3

The team plays 4 matches.

We want to find the probability that the team wins 1 more than half of the number of matches played.

So if there are 4 matches, the half is 2 matches

one more than half is then 3 matches.

Let's assume that the team wins the first 3 matches, and does not win the last match.

match one, the team wins with prob: P₁ = 2/3

match two, the team wins with prob: P₂ = 2/3

match three, the team wins with prob: P₃ = 2/3

match four, the team wins with prob: P₄ = 1/3

The joint probability is the product of all the individual probabilities:

P = (2/3)*(2/3)*(2/3)*(1/3)

Now we must also considerate the permutations, we have the cases:

the team does not win the fourth match

the team does not win the third match

the team does not win the second match

the team does not win the first match

So we have just four permutations, then the total probability is:

probability = 4*P = 4*(2/3)*(2/3)*(2/3)*(1/3) = 4*(8/81) = (32/81)

Answer:

x = -7       y = 35

Step-by-step explanation:

-5x = -7x - 14

2x = -14

x = -7

y = -5(-7)

y = 35

Answer:

1.2 km/min

Step-by-step explanation:

ROC? rate of change? if not rate of change than my answer may not be correct

24km/20min = 1.2 km/min

24km/20min * 60min/1 hr= (24*60)/20=120 km/hr

Answer:

TH is an element on the sample space for first rolling a die and then tossing a coin. A coin has both heads and tails.

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

The elements can be any of the elements in the sample space.

It is the total number of possible outcomes from a given set.

We have,

The sample space for rolling a number cube and then tossing a coin consists of all possible outcomes from rolling the number cube and tossing the coin.

Each outcome is a pair consisting of a number from 1 to 6 (the possible outcome from rolling the number cube) and a head or tail (the possible outcome from tossing the coin).

Therefore, an element in the sample space can be represented as an ordered pair (n, h/t), where n is the number rolled on the number cube and h/t is the outcome of the coin toss (either head or tail).

So,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

For example, (3, H), (6, T), (1, H), and (4, T) are all elements in the sample space.

Thus,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

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Answer: is b

Step-by-step explanation:

Answer:

[tex]A \approx 1.488[/tex]

Step-by-step explanation:

Por definición de razones trigonométricas, tenemos las siguientes identidades:

[tex]\tan \theta = \frac{y}{x} = \sqrt{2}[/tex] (1)

[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (3)

Si [tex]\theta[/tex] es agudo, entonces [tex]x, y > 0[/tex].

De (1), suponemos [tex]x = 1[/tex] que [tex]y = \sqrt{2}[/tex], entonces los valores de las funciones seno y coseno:

[tex]\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }[/tex]

[tex]\sin \theta = \frac{\sqrt{10}}{5 }[/tex]

[tex]\cos \theta = \sqrt{\frac{1}{5} }[/tex]

[tex]\cos \theta = \frac{\sqrt{5}}{5}[/tex]

Por último, calculemos [tex]A[/tex]:

[tex]A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}[/tex]

[tex]A \approx 1.488[/tex]

Answer:

Empty square = +

Empty Circle = ÷

Step-by-step explanation:

In order to eliminate the extra numbers from the equation you have to do the opposite of the problem. So...

-6x-1=5

-6x -1+1 = 5+1 (eliminating the 1 from the -6x side and adding it to the other side)

-6x = 6

-6x ÷ -6 = 6 ÷ -6 ( eliminating the-6 so that one side just has x)

so... x= -1

Answer: Option B is your correct answer.

Answer:

13

Step-by-step explanation:

-2x + 6 = -20

Step 1 subtract 6 from both sides

6 - 6 cancels out

-20 - 6 = -26

We now have -2x = -26

Step 2 divide both sides by -2

-2x/-2 = x

-26/-2 = 13

We're left with x = 13

Answer: (C) 308 cm^2

Step-by-step explanation: Flat surface area is the surface area that is not curved; in this case, it would be the two circular bases. The height is arbitrary as the height is not needed to calculate the area of the bases. The formula for the area of circular bases is πr^2. Let's plug the given values into the formula. (22/7)(7)^2=(22/7)(49)=154. 154 cm^2 is the area of one base. To find the area of both bases, simply multiply the area of one base by two. 154*2 is 308, therefore the answer is (C) 308 cm^2.

Answer:

i think it would be y=x+3

Step-by-step explanation:

Please click on the above picture and view the full answer.

Step-by-step explanation:

Hope it helps you.^_^

Answers:

=======================================

Explanation:

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123} \times \frac{1.998}{333} = [/tex]

[tex] = > 9 \times 6[/tex]

[tex] = 45[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123}*\frac{1.998}{333}= 0.009 * 0.006 = 0.000054[/tex]

1107÷ 123 = 9

The dividend has 3 decimal places. So, take 3 decimal places from the right towards left in the result  0.009

1.107 ÷ 123 = 0.0009

0.009 * 0.006

First multiply 9 * 6 = 54

Now, count the number of decimal place in the multiplicands. 0.009 has 3 decimal places and 0.006 has 3 decimal places. So totally, 3+ 3 = 6 decimal places in the result

0.009 * 0.006 = 0.000054

Answer:

{F, G, H, I, J, K, L, M, N, O, P}

are the points between segment EQ :)

Answer:

5 pints of milk

Step-by-step explanation:

took the test

answer:

the answer is 40 because any expression divides itself is equals to 1

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\frac{1}{x^3}[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the Answer...}}\\\\x^5\div x^8\\---------\\\rightarrow \text{Rewrite as:} \frac{x^5}{x^8}\\\\\rightarrow \text{Recall the exponent rule: } \frac{x^a}{x^b}=x^{a-b}\\\\\rightarrow \frac{x^5}{x^8} = x^{-3}\\\\\rightarrow \text{Recall the exponent rule: }x^{-b}=\frac{1}{x^b}\\\\\rightarrow x^{-3}\\\\\rightarrow \boxed{\frac{1}{x^3}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

x=-9/10

Step-by-step explanation:

2x+8x+16=7

Step 1: Simplify both sides of the equation.

2x+8x+16=7

(2x+8x)+(16)=7(Combine Like Terms)

10x+16=7

10x+16=7

Step 2: Subtract 16 from both sides.

10x+16−16=7−16

10x=−9

Step 3: Divide both sides by 10.

10x/10

=

−9/10

x=-9/10

Answer:

x = - 4 ± [tex]\sqrt{7}[/tex]

Step-by-step explanation:

Given

x² + 8x + 16 = 7 ( subtract 16 from both sides )

x² + 8x = - 9

Using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(4)x + 16 = - 9 + 16

(x + 4)² = 7 ( take the square root of both sides )

x + 4 = ± [tex]\sqrt{7}[/tex] ( subtract 4 from both sides )

x = - 4 ± [tex]\sqrt{7}[/tex]

Then

solutions are x = - 4 - [tex]\sqrt{7}[/tex] , x = - 4 + [tex]\sqrt{7}[/tex]

Answer:

The LCM of 306 and 657 is 22338

Step-by-step explanation:

We know that

HCF (a, b) × LCM (a, b) = a × b

⇒ HCF (306, 657) x LCM (306, 657) = 306 × 657

⇒ 9 × LCM = 306 × 657

⇒ LCM (306, 657) = 306 × 657 / 9

                              =  201042 / 9

∴ LCM = 22338

Thus, the LCM of 306 and 657 is 22338.

Answer:

The answer is E.

Step-by-step explanation:

A quadrilateral that has only one pair of parallel sides is called a Trapezoid.