A city of Punjab has a 15 percent chance of wet weather on any given day. What is the probability that it will take a week for it three wet weather on 3 separate days? Also find its Standard Deviation

Answers

Answer 1

Answer:

The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

Explanation:

Probability of wet weather = 0.15

Probability of not being a wet weather = 1-0.15

We are supposed to find probability that it will take a week for it three wet weather on 3 separate days

Total number of days in a week = 7

We will use binomial over here

n = 7

p =probability of failure = 0.15

q = probability of success=1-0.15

r=3

Formula :[tex]P(r=3)=^nC_r p^r q ^{n-r}[/tex]

[tex]P(r=3)=^{7}C_{3} (0.15)^3 (1-0.15)^{7-3}\\P(r=3)=\frac{7!}{3!(7-3)!} (0.15)^3 (1-0.15)^{7-3}\\P(r=3)=0.06166[/tex]

Standard deviation =[tex]\sqrt{n \times p \times q}[/tex]

Standard deviation =[tex]\sqrt{7 \times 0.15 \times (1-0.15)}[/tex]

Standard deviation =0.9447

Hence The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447


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Answer:

Mean would increase, median will stay the same.

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Your academic calendar has been distracted by the global pandemic, such that, you are to teach your class from the house. Outline specific hardware and software and the various teaching and learning tools you will deploy to enable you continue to teach your pupils from home. Discuss four (4) ways you will use to reach all pupils who are living at a​

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The correct answer to this open question is the following.

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Answer:

All of the members of the community watch group gave their availability to volunteer over the summer.

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In this scenario, all of the members of the community watch group making known their availability to volunteer over the summer is an example of a parameter.

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B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you! ​

Answers

Answer:

The additional words is [tex]2^n[/tex]

Explanation:

Given

[tex]B(n) = 2^n[/tex]

Required

Determine the additional words; i.e. [tex]B(n + 1) - B(n)[/tex]

From the given parameters, we have that;

B is a function of n

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[tex]B(n) = 2^n[/tex]

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[tex]B(n) = 2^n[/tex]

[tex]B(n + 1) = 2^{n + 1}[/tex]

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[tex]B(n + 1) = 2^{n} * 2^1[/tex]

[tex]B(n + 1) = 2^{n} * 2[/tex]

[tex]B(n + 1) = 2(2^{n})[/tex]

Calculating Additional Binary Code;

[tex]B(n + 1) - B(n)[/tex]

Substitute values for B(n + 1) and B(n)

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n[/tex]

Express [tex]2^n[/tex] as [tex]2^ n * 1[/tex]

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n * 1[/tex]

Express 1 as [tex]2^0[/tex]

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0[/tex]

Factorize

[tex]B(n + 1) - B(n) = 2^n(2 - 2^0)[/tex]

[tex]B(n + 1) - B(n) = 2^n(2 - 1)[/tex]

[tex]B(n + 1) - B(n) = 2^n(1)[/tex]

[tex]B(n + 1) - B(n) = 2^n[/tex]

Hence, the additional words is [tex]2^n[/tex]

The official record of a high school student’s performance is called:

Answers

Answer:

A High School Transcript

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