Answer:
There are 325 seats in each row
Step-by-step explanation:
78 × 325 = 25,350
[100 Points]
SHOW YOUR WORK, PLEASE!
Answer:
691 251/256
Step-by-step explanation:
So basically exponents is how much time you time the same number
First on the top is 2 exponent 4. that is 2x2x2x2=16
Second is 3 exponent 3. 3x3x3=27
Third is 9 exponent 7. 9x9x9x9x9x9x9=4782969
Fourth is 4 exponent 6. 4x4x4x4x4x4=4096.
All together is 16/27x4782969/4096=691 251/256
The temperature on a winter was -23 °F. The temerature rise by 5 °F when the sun came up. When the sun set again, the temperature dropped by. 7°F. Write and evaluate an exspression to find the temperature after the sun set.
Answer:
-25
Step-by-step explanation:
First, add 5 to -23 since the temperature is getting hotter.
so -23 +5= -18
Second, minus the answer by 7 since the temperature is now falling down after the sunset.
so -18 -7 = -25
or...
this step can be simplified as:
-23 +5 -7 =. -25
Which pair of polygons is congruent?
Answer:
C
Step-by-step explanation:
Polygon 3 and 5 are congruent cause they have the same length of side
Ive never really understood 8th-9th grade volume, could use some help
The answer is B
Eplanation:
V = pi * r² * (h/3)
Then from here you just make h the subject of the formula:
h = (V * 3)/(pi * r²)
h = (393*3)/[3.14* (10/2)²]
h = 15.01910828 ft
which is rounded to 15 ft...B
:)
Rectangle ABCD is similar to rectangle JKLM. AB = 12, BC = 8, CD = 12, DA = 8, and JK = 15. What is the scale factor from JKLM to ABCD? Reduce all answers.
Answer:
4/5 or 0.8
Step-by-step explanation:
this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.
I assume J and K correlate to A and B, and JK is a long side of JKLM.
so, we are going from JKLM to ABCD.
that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).
what is the scale factor to go from 15 to 12 ?
15 × x = 12
x = 12/15 = 4/5 or 0.8
There is a $30 fee to rent a tool from the local hardware store plus $6 per day. If Joe rents a jackhammer for 5 days, what is his total bill? The correct function for this situation is f(x) = 30x + 6.
O False
O True
instructions find the value of x
Answer:
Given two equal chords. Since the line from the centre is always equal, thus the lines that bisect the two chords are also equal. X=5
Solve the following, where 0° < θ < 360°.
If cos θ=2/3 and tan θ<0
Find θ.
Answer:
The angle θ = 312°.
Step-by-step explanation:
0° < θ < 360°
If cos θ = 2/3 and tan θ < 0
As cos θ is positive and tan θ is negative so the angle is in fourth quadrant.
cos θ = 2/3
θ = 312°
If a translation of (x,y) (x+6,y-10) is applied to figure ABCD, what are the coordinates of D?
Image of figure ABCD is missing and so i have attached it.
Answer:
D_new = (-1, - 12)
Step-by-step explanation:
From the figure attached, the current coordinates of D are; (-5, -2)
Now, we are told the figure undergoes a translation of (x,y) (x+6,y-10)
Thus, this means we add 6 to the x value and subtract 10 from the y-value.
Thus, new coordinate of D is;
> (-5 + 6, -2 - 10)
> (-1, - 12)
Answer:
1, -12
Step-by-step explanation:
D = -5, -2
|
-5 + 6 = 1
|
-10 and -2 is -12
1, -12
did it on edge, got it right.
pls help graph of function
Answer:
i: -1.3
ii: 1.3
Step-by-step explanation:
You literally have it.
I hope this helps!
pls ❤ and give brainliest pls
Find the value of x in Circle O.
Answer:
x=8
Step-by-step explanation:
x^2+15^2=17^2, x=sqrt(64)=8
Trevor spent $27 and now has no money left. He had $___ before his purchase. He had $__before his purchase
Answer:
27
Step-by-step explanation:
Câu 2. Cho hình thang cân ABCD (AB // CD, AB CD). Gọi O là giao điểm của AD và BC, E là giao điểm của AC và BD. Chứng minh rằng: | a) Tam giác AOB cân ở O.
b) Các tam giác ABD và BAC bằng nhau. C) EC = ED
d) OE là trung trực của AB và CD.
Answer:
Step-by-step explanation:
For what values of k does the equation (2k + 1)x^2 + 2x = 10x – 6 have two
real and equal roots?
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:
[tex]ax^2 + bx + c = 0[/tex]
has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.
------------------------------------
In this question:
The equation is:
[tex](2k+1)x^2 + 2x = 10x - 6[/tex]
Placing in the correct format:
[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]
[tex](2k+1)x^2 - 8x + 6 = 0[/tex]
Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]
------------------------------------
Delta:
We want it to be positive, so:
[tex]\Delta = b^2 - 4ac[/tex]
[tex]\Delta = 0[/tex]
[tex]b^2 - 4ac = 0[/tex]
[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]
[tex]64 - 48k - 24 = 0[/tex]
[tex]-48k + 40 = 0[/tex]
[tex]-48k = -40[/tex]
[tex]48k = 40[/tex]
[tex]k = \frac{40}{48}[/tex]
[tex]k = \frac{5}{6}[/tex]
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
A similar question is found at https://brainly.com/question/12144265
The question is "find the lowest common multiple of 4 and 6"
with step by step explaination
Answer:
12
Step-by-step explanation:
4s multiples:
4,8,12,16,20,24
6s multiples:
6,12,18,24,30,36
lowest number that is a common multiple between both 4 and 6:
12
Answer: 2
Step-by-step explanation:
please help me to solve this
Answer:
Step-by-step explanation:
a) 3x^2
b) (512)^-2/3=2^n
1/64=2^n
n=-6
common ratio of the geometric sequence 6,42,294
9514 1404 393
Answer:
7
Step-by-step explanation:
If there is a common ratio, it can be found by finding the ratio of any two adjacent terms:
42/6 = 7
The common ratio is 7.
HELPPPP
You invest $2700 in an account at 1.5% per year simple interest. The equation
that represents this scenario is:
A(n) = 2700 + (n - 1)(0.015. 2700)
How much will you have in the account in year 5? Round your answer to the
nearest dollar.
Evan is on holidays in Beijing, China. He took a taxi from the airport to his hotel. It cost him 375 Chinese yuan. He went $15 AUD over his travel budget on the taxi ride. How much Chinese yuan does Evan get for every Australian dollar if he budgeted $60 for the taxi ride?
This question is solved using proportions, and doing this, it is found that Evan gets 5 Chinese yuans for every Australian dollar.
-----------------------------------------
Evan budgeted $60 for the taxi ride.He went $15 over, thus, the taxi ride cost $75.In Chinese yuans, the cost was 375.-----------------------------------------
75 dollars are worth 375 yuans. How much yuans is a dollar worth?
1 dollar - x yuans
75 dollars - 375 yuans
Applying cross multiplication:
[tex]75x = 375[/tex]
[tex]x = \frac{375}{75}[/tex]
[tex]x = 5[/tex]
Evan gets 5 Chinese yuans for every Australian dollar.
A similar question is given at https://brainly.com/question/23352001
The length, breadth and thickness of a brick is 18 cm, 8 cm, and 5 cm respectively. Find the area of the widest part of the brick. Also find the volume of the brick.
Answer:
area = 8 × 18 = 144 cm^2
volume 8×18×5 = 720cm^3
a. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.
Answer:
Step-by-step explanation:
Decide !!!!!!!!!!!!!!!!!!!!!!!!
Answer:
[tex]\displaystyle [CQF]=5[/tex]
Step-by-step explanation:
Note that [tex][n][/tex] refers to the area of some polygon [tex]n[/tex].
Diagonal [tex]\overline{AC}[/tex] forms two triangles, [tex]\triangle ABC[/tex] and [tex]\triangle ADC[/tex]. Both of these triangles have an equal area, and since the area of parallelogram [tex]ABCD[/tex] is given as [tex]210[/tex], each triangle must have an area of [tex]105[/tex].
Furthermore, [tex]\triangle ADC[/tex] is broken up into two smaller triangles, [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex]. We're given that [tex]\frac{DF}{FC}=2[/tex]. Since [tex]DF[/tex] and [tex]FC[/tex] represent bases of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] respectively and both triangles extend to point [tex]A[/tex], both triangles must have the same height and hence the ratio of the areas of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] must be [tex]2:1[/tex] (recall [tex]A=\frac{1}{2}bh[/tex]).
Therefore, the area of each of these triangles is:
[tex][ACF]+[ADF]=105,\\[][ACF]+2[ACF]=105,\\3[ACF]=105,\\[][ACF]=35 \implies [ADF]=70[/tex]
With the same concept, the ratio of the areas of [tex]\triangle AQE[/tex] and [tex]\triangle DQE[/tex] must be [tex]2:1[/tex] respectively, from [tex]\frac{AE}{ED}=2[/tex], and the ratio of the areas of [tex]\triangle DQF[/tex] and [tex]\triangle CQF[/tex] is also [tex]2:1[/tex], from [tex]\frac{DF}{FC}=2[/tex].
Let [tex][DQE]=y[/tex] and [tex][CQF]=x[/tex] (refer to the picture attached). We have the following system of equations:
[tex]\displaystyle \begin{cases}2y+y+2x=70,\\y+2x+x=35\end{cases}[/tex]
Combine like terms:
[tex]\displaystyle \begin{cases}3y+2x=70,\\y+3x=35\end{cases}[/tex]
Multiply the second equation by [tex]-3[/tex], then add both equations:
[tex]\displaystyle \begin{cases}3y+2x=70,\\-3y-9x=-105\end{cases}\\\\\rightarrow 3y-3y+2x-9x=70-105,\\-7x=-35,\\x=[CQF]=\frac{-35}{-7}=\boxed{5}[/tex]
Find the volume of each figure. Round your answers to the nearest tenth, if necessary
Answer:
1.92 m³
hopefully this answer can help you to answer the next question.
If someone could help that would really be great. Thank you.!
find the distance of gap d
Answer:
[tex]\displaystyle d \approx 15.8768[/tex]
Step-by-step explanation:
We want to find the distance of d or AB.
From the right triangle with a 35° angle, we know that:
[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]
And from the right triangle with a 42° angle, we know that:
[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]
AB is PA subtracted from PB. Thus:
[tex]\displaystyle d = AB = PB - PA[/tex]
From the first two equations, solve for PB and PA:
[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]
And:
[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]
Therefore:
[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]
Using a calculator:
[tex]\displaystyle d= AB \approx 15.8768[/tex]
Use the points slope formula..
Answer:
y = -5/14 -13/7
Step-by-step explanation:
First find the slope
m = (y2-y1)/(x2-x1)
m = (1 - -4)/(-8 - 6)
= (1+4)/(-8-6)
= 5/-14
=-5/14
Point slope form is
y-y1 = m(x-x1)
y - -4 = -5/14(x-6)
y+4 = -5/14(x-6)
We want the equation in slope intercept form y = mx+b
Distribute
y+4 = -5/14x + 15/7
Subtract 4 from each side
y+4 -4= -5/14x + 15/7-4
y = -5/14x +15/7 - 28/7
y = -5/14 -13/7
Match the range of the function f(x) = x2 + 2x − 1 to its domain.
2 -2 3 -3
2 --
14 --
7 --
-1 --
Answer: (2,7) (-2,-9) (3,11) (-3,-13)
Step-by-step explanation:
(2)(2)+(2)(2)-1 = 7
(2) (-2)+(2)(-2)-1 = -9
(3)(2)+(2)(3)-1 = 11
(-3)(2)+(2)(-3)-1 = -13
What is the factored form of the expression 3x^2 + 6x – 24
Answer:
(3)(x + 4)(x-2)
Step-by-step explanation:
3x^2 + 6x – 24
3(x^2 + 2x - 8)
(3)(x + 4)(x-2)
Answer:
3(x - 2)(x + 4).
Step-by-step explanation:
3x^2 + 6x – 24
= 3(x^2 + 2x - 8)
= 3(x - 2)(x + 4).
Simplify this expression.
I need u again pls
Answer:
The answer is the Second Option
Step-by-step explanation:
Answer:
the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)
Step-by-step explanation:
Please help me
A person starts walking from home and walks: 6 miles East 6 miles Southeast 3 miles South 5 miles Southwest 2 miles East This person has walked a total of 22Correct miles Find the total displacement vector for this walk: If this person walked straight home, they'd have to walk miles
Answer:
1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)
2) The number of miles they'd have to walk is approximately 13.856 miles
Step-by-step explanation:
1) The distance, direction, and location of the path of the walk the person takes, are listed as follows;
Start location, (0, 0)
6 miles East walk to location, (6, 0)
6 miles Southeast to location, (6 + 3·√2, -3·√2)
3 miles South to location, (6 + 3·√2, -3·√2 - 3)
5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)
2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)
(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)
Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)
The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)
d = (16 + √2)/2)·i - (6+11·√2)/2)·j
2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;
[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]
Therefore;
If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]